NIACL AO Mains– Quantitative Aptitude Questions Day- 06
Dear Readers, Bank Exam Race for the Year 2019 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for NIACL AO Mains 2019 Exams can practice these questions daily and make your preparation effective.
Are You preparing for Bank exams 2019? Start your preparation with Free Mock test Series.
NIACL AO Mains– Quantitative Aptitude Questions Day- 06
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Average score
Your score
Categories
Not categorized0%
maximum of 10 points
Pos.
Name
Entered on
Points
Result
Table is loading
No data available
Your result has been entered into leaderboard
Loading
1
2
3
4
5
6
7
8
9
10
Answered
Review
Question 1 of 10
1. Question
Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
I) x = [√(24782 – 1678)] × ∜2401 ÷ (5^{2} + 3)
II) y = ∛74088
Correct
Answer: c)
I) x = [√(24782 – 1678)] × ∜2401 ÷ (5^{2} + 3)
X = √23104 × ∜2401 ÷ 28
X = (152*7)/28 = 38
II) y = ∛74088 = 42
X < y
Incorrect
Answer: c)
I) x = [√(24782 – 1678)] × ∜2401 ÷ (5^{2} + 3)
X = √23104 × ∜2401 ÷ 28
X = (152*7)/28 = 38
II) y = ∛74088 = 42
X < y
Question 2 of 10
2. Question
Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
I) 3x^{2} + 33x + 72 = 0
II) 2y^{2} – y – 55 = 0
Correct
Answer: e)
I) 3x^{2} + 33x + 72 = 0
3x^{2} + 24x + 9x + 72 = 0
3x (x + 8) + 9 (x + 8) = 0
(3x + 9) (x + 8) = 0
X = -9/3, -8 = -3, -8
II) 2y^{2} – y – 55 = 0
2y^{2} + 10y – 11y – 55 = 0
2y (y + 5) – 11 (y + 5) = 0
(2y – 11) (y + 5) = 0
Y = 11/2, -5 = 5.5, -5
Can’t be determined
Incorrect
Answer: e)
I) 3x^{2} + 33x + 72 = 0
3x^{2} + 24x + 9x + 72 = 0
3x (x + 8) + 9 (x + 8) = 0
(3x + 9) (x + 8) = 0
X = -9/3, -8 = -3, -8
II) 2y^{2} – y – 55 = 0
2y^{2} + 10y – 11y – 55 = 0
2y (y + 5) – 11 (y + 5) = 0
(2y – 11) (y + 5) = 0
Y = 11/2, -5 = 5.5, -5
Can’t be determined
Question 3 of 10
3. Question
Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
I) 2x^{2} + (52 – 57) x – (132 ÷ 4) = 0
II) 7y^{2} – 16y – 15 = 0
Correct
Answer: e)
I) 2x^{2} + (52 – 57) x – (132 ÷ 4) = 0
2x^{2 }– 5x – 33 = 0
2x^{2 }+ 6x – 11x – 33 = 0
2x (x + 3) -11 (x + 3) = 0
(2x – 11) (x + 3) = 0
X = 11/2, -3 = 5.5, -3
II) 7y^{2} – 16y – 15 = 0
7y^{2} – 21y + 5y – 15 = 0
7y (y – 3) + 5 (y – 3) = 0
(7y + 5) (y – 3) = 0
Y = -5/7, 3 = -0.714, 3
Can’t be determined
Incorrect
Answer: e)
I) 2x^{2} + (52 – 57) x – (132 ÷ 4) = 0
2x^{2 }– 5x – 33 = 0
2x^{2 }+ 6x – 11x – 33 = 0
2x (x + 3) -11 (x + 3) = 0
(2x – 11) (x + 3) = 0
X = 11/2, -3 = 5.5, -3
II) 7y^{2} – 16y – 15 = 0
7y^{2} – 21y + 5y – 15 = 0
7y (y – 3) + 5 (y – 3) = 0
(7y + 5) (y – 3) = 0
Y = -5/7, 3 = -0.714, 3
Can’t be determined
Question 4 of 10
4. Question
Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
I) 7x – 6y = -21
II) 2x – 3y = 15
Correct
Answer: c)
7x – 6y = -21 —> (1)
2x – 3y = 15 —> (2)
By solving the equation (1) and (2), we get,
X = 3, y = 7
X < y
Incorrect
Answer: c)
7x – 6y = -21 —> (1)
2x – 3y = 15 —> (2)
By solving the equation (1) and (2), we get,
X = 3, y = 7
X < y
Question 5 of 10
5. Question
Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
I) x^{2} – 8x – 65 = 0
II) y^{2} – y – 42 = 0
Correct
Answer: e)
I) x^{2} – 8x – 65 = 0
(x – 13) (x + 5) = 0
X = 13, -5
II) y^{2} – y – 42 = 0
(y + 6) (y – 7) = 0
Y = -6, 7
Can’t be determined
Incorrect
Answer: e)
I) x^{2} – 8x – 65 = 0
(x – 13) (x + 5) = 0
X = 13, -5
II) y^{2} – y – 42 = 0
(y + 6) (y – 7) = 0
Y = -6, 7
Can’t be determined
Question 6 of 10
6. Question
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
The following bar graph shows the total number of items (In lakhs) produced by two different companies in 6 different years.
Find the ratio between the total number of items sold by the company A in the year 2013 and 2015 together to that of total number of items produced by company B in the year 2014 and 2016 together, if the ratio between the total number of sold to that of unsold items of company A in the year 2013 is 7 : 5 and the percentage of unsold items of company A in the year 2015 is 28 %?
Correct
Answer: c)
The total number of items sold by the company A in the year 2013 and 2015 together
= > 1200000*(7/12) + 1600000*(72/100)
= > 700000 + 1152000 = 1852000
The total number of items produced by company B in the year 2014 and 2016 together
= > 11 + 12 = 23 lakhs
Required ratio = 1852000: 2300000 = 463: 575
Incorrect
Answer: c)
The total number of items sold by the company A in the year 2013 and 2015 together
= > 1200000*(7/12) + 1600000*(72/100)
= > 700000 + 1152000 = 1852000
The total number of items produced by company B in the year 2014 and 2016 together
= > 11 + 12 = 23 lakhs
Required ratio = 1852000: 2300000 = 463: 575
Question 7 of 10
7. Question
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
The following bar graph shows the total number of items (In lakhs) produced by two different companies in 6 different years.
Find the difference between the average number of items produced by company A to that of company B in all the given years together?
Correct
Answer: a)
The average number of items produced by company A in all the given years together
= > (12 + 15 + 16 + 11 + 10 + 17)/6 = 81/6
The average number of items produced by company B in all the given years together
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
The following bar graph shows the total number of items (In lakhs) produced by two different companies in 6 different years.
Find the sum of the number of items sold by company A in the year 2015 and the number of items remains unsold by company B in the year 2017 together, if the percentage of items sold by company A in the year 2015 is 60 % and the percentage of items sold by company B in the year 2017 is 62 %?
Correct
Answer: d)
The number of items sold by company A in the year 2015
= > 16*(60/100) = 9.6 lakhs
The number of items remains unsold by company B in the year 2017
= > 15*(38/100) = 5.7 lakhs
Required total = 9.6 + 5.7 = 15.3 lakhs
Incorrect
Answer: d)
The number of items sold by company A in the year 2015
= > 16*(60/100) = 9.6 lakhs
The number of items remains unsold by company B in the year 2017
= > 15*(38/100) = 5.7 lakhs
Required total = 9.6 + 5.7 = 15.3 lakhs
Question 9 of 10
9. Question
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
The following bar graph shows the total number of items (In lakhs) produced by two different companies in 6 different years.
Total number of items produced by company A and B together in the year 2013 and 2016 together is approximately what percentage of total number of items produced by company A and B together in the year 2014 and 2018 together?
Correct
Answer: b)
Total number of items produced by company A and B together in the year 2013 and 2016 together
= > 12 + 8 + 11 + 12 = 43 lakhs
Total number of items produced by company A and B together in the year 2014 and 2018 together
= > 15 + 11 + 17 + 19 = 62 lakhs
Required % = (43/62)*100 = 70 %
Incorrect
Answer: b)
Total number of items produced by company A and B together in the year 2013 and 2016 together
= > 12 + 8 + 11 + 12 = 43 lakhs
Total number of items produced by company A and B together in the year 2014 and 2018 together
= > 15 + 11 + 17 + 19 = 62 lakhs
Required % = (43/62)*100 = 70 %
Question 10 of 10
10. Question
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
The following bar graph shows the total number of items (In lakhs) produced by two different companies in 6 different years.
If in the year 2018 of company A, the 4 % of items were damaged and then the ratio between the total number of items sold to that of unsold is 5: 3, then find the average number of items sold by company A in the year 2018 and the number of items produced by company B in the year 2017 together?
Correct
Answer: c)
The total number of items sold by company A in the year 2018 and the number of items produced by company B in the year 2017 together
= > 1700000*(96/100)*(5/8) + 1500000
= > 1020000 + 1500000 = 2520000
Incorrect
Answer: c)
The total number of items sold by company A in the year 2018 and the number of items produced by company B in the year 2017 together
Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
1)I) x = [√(24782 – 1678)] × ∜2401 ÷ (5^{2} + 3)
II) y = ∛74088
2) I) 3x^{2} + 33x + 72 = 0
II) 2y^{2} – y – 55 = 0
3) I) 2x^{2} + (52 – 57) x – (132 ÷ 4) = 0
II) 7y^{2} – 16y – 15 = 0
4) I) 7x – 6y = -21
II) 2x – 3y = 15
5) I) x^{2} – 8x – 65 = 0
II) y^{2} – y – 42 = 0
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
The following bar graph shows the total number of items (In lakhs) produced by two different companies in 6 different years.
6) Find the ratio between the total number of items sold by the company A in the year 2013 and 2015 together to that of total number of items produced by company B in the year 2014 and 2016 together, if the ratio between the total number of sold to that of unsold items of company A in the year 2013 is 7 : 5 and the percentage of unsold items of company A in the year 2015 is 28 %?
a) 152: 257
b) 265: 389
c) 463: 575
d) 314: 437
e) None of these
7) Find the difference between the average number of items produced by company A to that of company B in all the given years together?
a) 50000
b) 40000
c) 75000
d) 60000
e) None of these
8) Find the sum of the number of items sold by company A in the year 2015 and the number of items remains unsold by company B in the year 2017 together, if the percentage of items sold by company A in the year 2015 is 60 % and the percentage of items sold by company B in the year 2017 is 62 %?
a) 13.6 lakhs
b) 12.8 lakhs
c) 16.4 lakhs
d) 15.3 lakhs
e) None of these
9) Total number of items produced by company A and B together in the year 2013 and 2016 together is approximately what percentage of total number of items produced by company A and B together in the year 2014 and 2018 together?
a) 62 %
b) 70 %
c) 94 %
d) 106 %
e) 85 %
10) If in the year 2018 of company A, the 4 % of items were damaged and then the ratio between the total number of items sold to that of unsold is 5: 3, then find the average number of items sold by company A in the year 2018 and the number of items produced by company B in the year 2017 together?
a) 1960000
b) 2340000
c) 2520000
d) 1850000
e) None of these
Answers :
Direction (1-5 ) :
1) Answer: c)
I) x = [√(24782 – 1678)] × ∜2401 ÷ (5^{2} + 3)
X = √23104 × ∜2401 ÷ 28
X = (152*7)/28 = 38
II) y = ∛74088 = 42
X < y
2) Answer: e)
I) 3x^{2} + 33x + 72 = 0
3x^{2} + 24x + 9x + 72 = 0
3x (x + 8) + 9 (x + 8) = 0
(3x + 9) (x + 8) = 0
X = -9/3, -8 = -3, -8
II) 2y^{2} – y – 55 = 0
2y^{2} + 10y – 11y – 55 = 0
2y (y + 5) – 11 (y + 5) = 0
(2y – 11) (y + 5) = 0
Y = 11/2, -5 = 5.5, -5
Can’t be determined
3) Answer: e)
I) 2x^{2} + (52 – 57) x – (132 ÷ 4) = 0
2x^{2 }– 5x – 33 = 0
2x^{2 }+ 6x – 11x – 33 = 0
2x (x + 3) -11 (x + 3) = 0
(2x – 11) (x + 3) = 0
X = 11/2, -3 = 5.5, -3
II) 7y^{2} – 16y – 15 = 0
7y^{2} – 21y + 5y – 15 = 0
7y (y – 3) + 5 (y – 3) = 0
(7y + 5) (y – 3) = 0
Y = -5/7, 3 = -0.714, 3
Can’t be determined
4) Answer: c)
7x – 6y = -21 —> (1)
2x – 3y = 15 —> (2)
By solving the equation (1) and (2), we get,
X = 3, y = 7
X < y
5) Answer: e)
I) x^{2} – 8x – 65 = 0
(x – 13) (x + 5) = 0
X = 13, -5
II) y^{2} – y – 42 = 0
(y + 6) (y – 7) = 0
Y = -6, 7
Can’t be determined
Direction (6-10) :
6) Answer: c)
The total number of items sold by the company A in the year 2013 and 2015 together
= > 1200000*(7/12) + 1600000*(72/100)
= > 700000 + 1152000 = 1852000
The total number of items produced by company B in the year 2014 and 2016 together
= > 11 + 12 = 23 lakhs
Required ratio = 1852000: 2300000 = 463: 575
7) Answer: a)
The average number of items produced by company A in all the given years together
= > (12 + 15 + 16 + 11 + 10 + 17)/6 = 81/6
The average number of items produced by company B in all the given years together