# NIACL AO Mains– Quantitative Aptitude Questions Day- 23

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Dear Readers, Bank Exam Race for the Year 2019 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for NIACL AO Mains 2019 Exams can practice these questions daily and make your preparation effective.

NIACL AO Mains– Quantitative Aptitude Questions Day- 23

Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established

1)

I) 2x2 + 25x + 57 = 0

II) 3y2 + 23y + 44 = 0

2)

I) x2 = 558 ÷ 3 × 2 + 112 – 9

II) y3 = 6859

3)

I) x2 – 24x – 81 = 0

II) y2 + y – 56 = 0

4)

I) 4x – 7y = 23

II) 3x – 5y = 16

5)

I) 9x2 – 26x + 16 = 0

II) 3y2 – 16y + 20 = 0

Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:

The following table shows the total number of people appointed for six different specialist posts by five different banks in a certain year in a state.

6) Find the difference between the total number of people appointed for the posts A, C and E together for Indian bank to that of total number of people appointed for the posts B, D and F together for Indian bank, if the total number of people appointed for the posts B and C for Indian bank is 15 % and 50 % more than the total number of people appointed for the post A for Indian bank respectively?

a) 1156

b) 1243

c) 915

d) 1028

e) None of these

7) Find the ratio between the total number of people appointed for the post A to that of post E for all the given banks together, if the total number of people appointed for the post A for union bank is 800 less than the total number of people appointed for the post A for SBI and the ratio between the total number of people appointed for the post A for Indian bank to that of post E for SBI is 3 : 5?

a) 895: 1069

b) 142: 257

c) 356: 515

d) 27: 89

e) None of these

8) Total number of people appointed for the post A, B and C together for Canara bank is approximately what percentage of total number of people appointed for the post D, E and F together for Union bank?

a) 78 %

b) 86 %

c) 115 %

d) 102 %

e) 127 %

9) If the average number of people appointed for all the given specialist post for PNB is 1510 and the total number of people appointed for the post B is 540 less than the total number of people appointed for the post F, then find the total number of people appointed for the post F for PNB?

a) 1850

b) 1920

c) 1740

d) 1660

e) None of these

10) Total number of people appointed for the post C for Canara bank, SBI and PNB together is what percentage more/less than the total number of people appointed for the post F for Indian bank, SBI and Union bank together?

a) 15.78 % less

b) 8.53 % more

c) 11.65 % more

d) 14.32 % less

e) None of these

Direction (1-5) :

I) 2x2 + 25x + 57 = 0

2x2 + 6x + 19x + 57 = 0

2x (x + 3) + 19 (x + 3) = 0

(2x + 19) (x + 3) = 0

X = -19/2, -3 = -9.5, -3

II) 3y2 + 23y + 44 = 0

3y2 + 12y + 11y + 44 = 0

3y (y + 4) + 11 (y + 4) = 0

(3y + 11) (y + 4) = 0

Y = -11/3, -4 = -3.66, -4

Can’t be determined

I) x2 = 558 ÷ 3 × 2 + 112 – 9

X2 = (558/3)*2 + 121 – 9

X2 = 372 + 121 – 9 = 484

X = 22, -22

II) y3 = 6859

Y = ∛6859 = 19

Can’t be determined

I) x2 – 24x – 81 = 0

(x – 27) (x + 3) = 0

X = 27, -3

II) y2 + y – 56 = 0

(y + 8) (y – 7) = 0

Y = -8, 7

Can’t be determined

4x – 7y = 23 —-> (1)

3x – 5y = 16 —-> (2)

By solving (1) and (2), we get,

X = -3, y = -5

X > y

I) 9x2 – 26x + 16 = 0

9x2 – 18x – 8x + 16 = 0

9x (x – 2) – 8 (x – 2) = 0

(9x – 8) (x – 2) = 0

X = 8/9, 2

II) 3y2 – 16y + 20 = 0

3y2 – 6y – 10y + 20 = 0

3y (y – 2) – 10 (y – 2) = 0

(y – 2) (3y – 10) = 0

Y = 2, 10/3

X ≤ y

Direction (6-10) :

The total number of people appointed for the posts A, C and E together

= > 1500 + 1500*(150/100) + 2130

= > 1500 + 2250 + 2130 = 5880

The total number of people appointed for the posts B, D and F together

= > 1500*(115/100) + 1400 + 1840

= > 1725 + 1400 + 1840 = 4965

Required difference = 5880 – 4965 = 915

Total number of people appointed for the post A for all the given banks together

= > 1500 + 1250 + 2930 + 1140 + (2930 – 800)

= > 8950

Total number of people appointed for the post E for all the given banks together

= > 2130 + 2740 + (1500*5/3) + 1780 + 1540

= > 10690

Required ratio = 8950: 10690 = 895: 1069

Total number of people appointed for the post A, B and C together for Canara bank

= > 1250 + 1600 + 1880 = 4730

Total number of people appointed for the post D, E and F together for Union bank

= > 1700 + 1540 + 1390 = 4630

Required % = (4730/4630)*100 = 102 %

The total number of people appointed for all the given specialist post for PNB

= 1510*6 = 9060

= > 1140 + B + 1280 + 1560 + 1780 + F = 9060

= > B + F = 9060 – 5760

= > B + F = 3300 —à (1)

The total number of people appointed for the post B = The total number of people appointed for the post F – 540

B = F – 540

= > F – B = 540 —à (2)

By solving the equation (1) and (2), we get,

F = 1920, B = 1380

The total number of people appointed for the post F for PNB = 1920

Total number of people appointed for the post C for Canara bank, SBI and PNB together

= > 1880 + 2300 + 1280 = 5460

Total number of people appointed for the post F for Indian bank, SBI and Union bank together

= > 1840 + 1660 + 1390 = 4890

Required % = [(5460 – 4890)/4890]*100 = 11.65 % more

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