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Question 1 of 20
1. Question
Rajesh takes a loan of 10000 and pays back Rs. 12597.12 after 3 years at some rate of interest compounded annually. Find the rate of interest.
Correct
Answer c
Amount = P(1+(r/100))^{n}
12597.12 = 10000(1+(r/100))^{3}
((100+r)/100)^{3} = 12597.12/10000
((100+r)/100)^{3 }= 1259712/1000000
((100+r)/100)^{3} = (108/100)^{3}
((100+r)/100) = 108/100
100+r =108
R= 8%
Incorrect
Answer c
Amount = P(1+(r/100))^{n}
12597.12 = 10000(1+(r/100))^{3}
((100+r)/100)^{3} = 12597.12/10000
((100+r)/100)^{3 }= 1259712/1000000
((100+r)/100)^{3} = (108/100)^{3}
((100+r)/100) = 108/100
100+r =108
R= 8%
Question 2 of 20
2. Question
Sri gave 50% of the amount he had to Jothi. Jothi gave 2/5^{th} of what he received from sri to saratha. After paying Rs. 200 to the taxi driver out of the amount he gets from jothi, saratha is now left with Rs. 700. How much amount did Sri have?
Correct
Answer d
Let Sri’s amount be x,
Saratha now having the amount of 700,
=>(x*(50/100)*(2/5)) – 200 = 700
= > x*(50/100)*(2/5) = 900
= > x= 900*5 = 4500
Sri initially having an amount of Rs. 4500
Incorrect
Answer d
Let Sri’s amount be x,
Saratha now having the amount of 700,
=>(x*(50/100)*(2/5)) – 200 = 700
= > x*(50/100)*(2/5) = 900
= > x= 900*5 = 4500
Sri initially having an amount of Rs. 4500
Question 3 of 20
3. Question
A merchant mixes 2 types of tea, one costing Rs. 140 per kg and the other Rs. 160 per kg in the ratio of 3:4. If he sells the mixture at Rs. 170 per kg, find the approximate % profit/Loss.
Correct
Answer a
Total kg’s of 2 types of tea is not given. But the ratio will be 3:4. Take that as, 3x and 4x
Cost price = 3x*140 + 4x*160 = 1060x
Selling price = 7x*170 = 1190x
Profit % = (130x/1060x)*100 = 1300/106
Profit % = 12.26 % = 12% (approx)
Incorrect
Answer a
Total kg’s of 2 types of tea is not given. But the ratio will be 3:4. Take that as, 3x and 4x
Cost price = 3x*140 + 4x*160 = 1060x
Selling price = 7x*170 = 1190x
Profit % = (130x/1060x)*100 = 1300/106
Profit % = 12.26 % = 12% (approx)
Question 4 of 20
4. Question
If Vasu purchased some goods for Rs. 1050, and sold one-third of these goods at a loss of 12% then at what gain % should the remaining goods be sold to gain 18% on the whole transaction?
Correct
Incorrect
Question 5 of 20
5. Question
Mahesh can do a work in 24 days. He works alone for 4 days and Naren alone finishes the remaining work in 25 days. Both of them together can complete the work in?
Correct
Answer d
Mahesh one day work = 1/24
4 days work = 4/24 = 1/6
Remaining work = 1-(1/6) = 5/6
Naren alone finishes the remaining work in 25 days.
= > (5/6) * Naren’s whole work = 25
= > Naren’s whole work = 30 days
Mahesh and Naren’s one day work,
= > (1/24) + (1/30)
= > 3/40
Both Mahesh and Naren’s together complete the work in,
= > 40/3 days
Incorrect
Answer d
Mahesh one day work = 1/24
4 days work = 4/24 = 1/6
Remaining work = 1-(1/6) = 5/6
Naren alone finishes the remaining work in 25 days.
= > (5/6) * Naren’s whole work = 25
= > Naren’s whole work = 30 days
Mahesh and Naren’s one day work,
= > (1/24) + (1/30)
= > 3/40
Both Mahesh and Naren’s together complete the work in,
= > 40/3 days
Question 6 of 20
6. Question
Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?
172, 172, 147, 247, 22, ?
Correct
Answer c
The pattern is, +0^{2}, -5^{2}, +10^{2}, -15^{2}, +20^{2}
The answer is, 422
Incorrect
Answer c
The pattern is, +0^{2}, -5^{2}, +10^{2}, -15^{2}, +20^{2}
The answer is, 422
Question 7 of 20
7. Question
Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?
272, 265, 251, 230, ?
Correct
Answer a
The pattern is, -(1*7), -(2*7), -(3*7), -(4*7),..
The answer is, 202
Incorrect
Answer a
The pattern is, -(1*7), -(2*7), -(3*7), -(4*7),..
The answer is, 202
Question 8 of 20
8. Question
Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?
2, 6, 21, 79, 341, ?
Correct
Answer b
The pattern is, *1+2^{2}, *2+3^{2}, *3+ 4^{2}, *4+ 5^{2}, *5+ 6^{2},..
The answer is, 1741
Incorrect
Answer b
The pattern is, *1+2^{2}, *2+3^{2}, *3+ 4^{2}, *4+ 5^{2}, *5+ 6^{2},..
The answer is, 1741
Question 9 of 20
9. Question
Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?
48, 60, 76, 100, 136, ?
Correct
Answer d
The difference of difference is, 4, 8, 12, 16…
The answer is, 188
Incorrect
Answer d
The difference of difference is, 4, 8, 12, 16…
The answer is, 188
Question 10 of 20
10. Question
Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?
27, 55, 120, 246, 463, ?
Correct
Answer c
The difference is, 3^{3} +1, 4^{3} +1, 5^{3} +1, 6^{3} +1, 7^{3} +1
The answer is, 807.
Incorrect
Answer c
The difference is, 3^{3} +1, 4^{3} +1, 5^{3} +1, 6^{3} +1, 7^{3} +1
The answer is, 807.
Question 11 of 20
11. Question
Directions (Q. 11-15): What approximate value should come in place of question mark (?) in the following questions?
(√321 × 25) ÷ 30 =? – 523.01
Correct
Answer a
(18 × 25)/30 = x – 523
15 = x – 523
X= 15+523 = 538
Incorrect
Answer a
(18 × 25)/30 = x – 523
15 = x – 523
X= 15+523 = 538
Question 12 of 20
12. Question
Directions (Q. 11-15): What approximate value should come in place of question mark (?) in the following questions?
49.21 × 19.89 – 24.98 × 14. 12 = (36+?) × 9
Correct
Answer a
49 × 20 – 25 × 14 = (36 + x) × 9
980 – 350 = 324 +9x
9x = 980 – 350 – 324
9x = 306
X = 34
Incorrect
Answer a
49 × 20 – 25 × 14 = (36 + x) × 9
980 – 350 = 324 +9x
9x = 980 – 350 – 324
9x = 306
X = 34
Question 13 of 20
13. Question
Directions (Q. 11-15): What approximate value should come in place of question mark (?) in the following questions?
(26.11^{2} – 16.73^{2}) / ? = 21
Correct
Answer d
(26^{2} – 17^{2})/ ? = 21
676 – 289)/x = 21
387/x = 21
X = 387/21 = 18.42
X=18
Incorrect
Answer d
(26^{2} – 17^{2})/ ? = 21
676 – 289)/x = 21
387/x = 21
X = 387/21 = 18.42
X=18
Question 14 of 20
14. Question
Directions (Q. 11-15): What approximate value should come in place of question mark (?) in the following questions?
35% of 1579 + 29% of 4516 =?*41 + 468 + 773. 89 – 199. 78
Correct
Answer b
35 × 16 + 29 × 45 = 41x +468 + 774 -200
560 + 1305 -468 -774+200 = 41x
823 = 41x
X = 823/41
X = 20
Incorrect
Answer b
35 × 16 + 29 × 45 = 41x +468 + 774 -200
560 + 1305 -468 -774+200 = 41x
823 = 41x
X = 823/41
X = 20
Question 15 of 20
15. Question
Directions (Q. 11-15): What approximate value should come in place of question mark (?) in the following questions?
5 1/5 of 189.75 + 6 2/7 of 231. 49 =? % of 498 + 856.85
Correct
Answer c
(26/5)*190 + (44/7)* 231 = 5x +857
988 + 1452 – 857 = 5x
1583 = 5x
X = 1583/5 = 317
Incorrect
Answer c
(26/5)*190 + (44/7)* 231 = 5x +857
988 + 1452 – 857 = 5x
1583 = 5x
X = 1583/5 = 317
Question 16 of 20
16. Question
Directions (Q. 16 – 20): Study the following pie chart carefully to answer the questions below:
Percentage of students passed in different subjects (Total student = 8000)
Percentage of girls passed in these subjects out of the total students. (Total number of girls = 5000)
Find the pass percentage of boys in English?
Correct
Answer b
Total students for English = 0.14*8000=1120
Total girls passed in English=0.14*5000=700
Total boys passed in English=1120-700=420
Boys pass %= (420/1120)*100= 37.5%
Incorrect
Answer b
Total students for English = 0.14*8000=1120
Total girls passed in English=0.14*5000=700
Total boys passed in English=1120-700=420
Boys pass %= (420/1120)*100= 37.5%
Question 17 of 20
17. Question
Directions (Q. 16 – 20): Study the following pie chart carefully to answer the questions below:
Percentage of students passed in different subjects (Total student = 8000)
Percentage of girls passed in these subjects out of the total students. (Total number of girls = 5000)
How many boys are passed in Science and Social together?
Correct
Answer d
Total Boys passed in Science = [(0.20*8000)-(0.25*5000)] =350
Total Boys passed in Social = [(0.21*8000)-(0.20*5000)] =680
Total boys are passed in Science and Social = 350+680 = 1030
Incorrect
Answer d
Total Boys passed in Science = [(0.20*8000)-(0.25*5000)] =350
Total Boys passed in Social = [(0.21*8000)-(0.20*5000)] =680
Total boys are passed in Science and Social = 350+680 = 1030
Question 18 of 20
18. Question
Directions (Q. 16 – 20): Study the following pie chart carefully to answer the questions below:
Percentage of students passed in different subjects (Total student = 8000)
Percentage of girls passed in these subjects out of the total students. (Total number of girls = 5000)
Find the average number of girls passed in Hindi, Maths and Science together?
Correct
Answer c
Total number of girls passed in Hindi, Maths and Science =5000*(66/100)
Average no of girls passed in Hindi, Maths and Science= 5000*(66/100)*(1/3)
= >1100
Incorrect
Answer c
Total number of girls passed in Hindi, Maths and Science =5000*(66/100)
Average no of girls passed in Hindi, Maths and Science= 5000*(66/100)*(1/3)
= >1100
Question 19 of 20
19. Question
Directions (Q. 16 – 20): Study the following pie chart carefully to answer the questions below:
Percentage of students passed in different subjects (Total student = 8000)
Percentage of girls passed in these subjects out of the total students. (Total number of girls = 5000)
Number of boys passed in Hindi is what per cent less than the number of Girls passed in Science?
Correct
Answer d
Total number of boys passed in Hindi = [(0.20*8000)-(0.20*5000)]= 600
Total number of Girls passed in Science = [0.25*5000]= 1250
Required % = [(1250-600)/1250]*100 = 52%
Incorrect
Answer d
Total number of boys passed in Hindi = [(0.20*8000)-(0.20*5000)]= 600
Total number of Girls passed in Science = [0.25*5000]= 1250
Required % = [(1250-600)/1250]*100 = 52%
Question 20 of 20
20. Question
Directions (Q. 16 – 20): Study the following pie chart carefully to answer the questions below:
Percentage of students passed in different subjects (Total student = 8000)
Percentage of girls passed in these subjects out of the total students. (Total number of girls = 5000)
What is the respective ratio of number of boys passed in English to the number of boys passed in Social?
Correct
Answer a
Total boys passed in English = (0.14*8000)-(0.14*500)=420
Total Boys passed in Social = [(0.21*8000)-(0.20*5000)] =680
Ratio = 420:680 = 21:34
Incorrect
Answer a
Total boys passed in English = (0.14*8000)-(0.14*500)=420
Total Boys passed in Social = [(0.21*8000)-(0.20*5000)] =680
Ratio = 420:680 = 21:34
Click “Start Quiz” to attend these Questions and view Explanation
Rajesh takes a loan of 10000 and pays back Rs. 12597.12 after 3 years at some rate of interest compounded annually. Find the rate of interest.
7%
9%
8%
5%
None of these
Sri gave 50% of the amount he had to Jothi. Jothi gave 2/5^{th} of what he received from sri to saratha. After paying Rs. 200 to the taxi driver out of the amount he gets from jothi, saratha is now left with Rs. 700. How much amount did Sri have?
6500
5000
7000
4500
None of these
A merchant mixes 2 types of tea, one costing Rs. 140 per kg and the other Rs. 160 per kg in the ratio of 3:4. If he sells the mixture at Rs. 170 per kg, find the approximate % profit/Loss.
12 %
15%
21%
24%
None of these
If Vasu purchased some goods for Rs. 1050, and sold one-third of these goods at a loss of 12% then at what gain % should the remaining goods be sold to gain 18% on the whole transaction?
18 %
33 %
27 %
25 %
None of these
Mahesh can do a work in 24 days. He works alone for 4 days and Naren alone finishes the remaining work in 25 days. Both of them together can complete the work in?
50/ 7 days
15 days
18 days
40/3 days
60/7 days
Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?
172, 172, 147, 247, 22, ?
345
476
422
376
None of these
272, 265, 251, 230, ?
202
174
156
215
None of these
2, 6, 21, 79, 341, ?
856
1741
937
1346
None of these
48, 60, 76, 100, 136, ?
174
225
336
188
None of these
27, 55, 120, 246, 463, ?
932
1056
807
735
None of these
Directions (Q. 11-15): What approximate value should come in place of question mark (?) in the following questions?
(√321 × 25) ÷ 30 =? – 523.01
538
606
710
800
434
49.21 × 19.89 – 24.98 × 14. 12 = (36+?) × 9
34
43
52
67
49
(26.11^{2} – 16.73^{2}) / ? = 21
21
28
9
18
31
35% of 1579 + 29% of 4516 =?*41 + 468 + 773. 89 – 199. 78
35
20
30
25
45
5 1/5 of 189.75 + 6 2/7 of 231. 49 =? % of 498 + 856.85
432
118
317
234
178
Directions (Q. 16 – 20): Study the following pie chart carefully to answer the questions below:
Percentage of students passed in different subjects (Total student = 8000)
Percentage of girls passed in these subjects out of the total students. (Total number of girls = 5000)
16). Find the pass percentage of boys in English?
36
37.5
38
37
36.5
17). How many boys are passed in Science and Social together?
1045
1050
1060
1030
1020
18). Find the average number of girls passed in Hindi, Maths and Science together?
2050
2150
1100
2000
1550
19). Number of boys passed in Hindi is what per cent less than the number of Girls passed in Science?
16
14
40
52
62
20). What is the respective ratio of number of boys passed in English to the number of boys passed in Social?
21:34
34:21
31:24
24:31
e. None of these
Answers:
Answer c
Amount = P(1+(r/100))^{n}
12597.12 = 10000(1+(r/100))^{3}
((100+r)/100)^{3} = 12597.12/10000
((100+r)/100)^{3 }= 1259712/1000000
((100+r)/100)^{3} = (108/100)^{3}
((100+r)/100) = 108/100
100+r =108
R= 8%
Answer d
Let Sri’s amount be x,
Saratha now having the amount of 700,
=>(x*(50/100)*(2/5)) – 200 = 700
= > x*(50/100)*(2/5) = 900
= > x= 900*5 = 4500
Sri initially having an amount of Rs. 4500
Answer a
Total kg’s of 2 types of tea is not given. But the ratio will be 3:4. Take that as, 3x and 4x
Cost price = 3x*140 + 4x*160 = 1060x
Selling price = 7x*170 = 1190x
Profit % = (130x/1060x)*100 = 1300/106
Profit % = 12.26 % = 12% (approx)
Answer d
Mahesh one day work = 1/24
4 days work = 4/24 = 1/6
Remaining work = 1-(1/6) = 5/6
Naren alone finishes the remaining work in 25 days.
= > (5/6) * Naren’s whole work = 25
= > Naren’s whole work = 30 days
Mahesh and Naren’s one day work,
= > (1/24) + (1/30)
= > 3/40
Both Mahesh and Naren’s together complete the work in,
= > 40/3 days
Directions (Q. 6-10):
Answer c
The pattern is, +0^{2}, -5^{2}, +10^{2}, -15^{2}, +20^{2}
The answer is, 422
Answer a
The pattern is, -(1*7), -(2*7), -(3*7), -(4*7),..
The answer is, 202
Answer b
The pattern is, *1+2^{2}, *2+3^{2}, *3+ 4^{2}, *4+ 5^{2}, *5+ 6^{2},..
The answer is, 1741
Answer d
The difference of difference is, 4, 8, 12, 16…
The answer is, 188
Answer c
The difference is, 3^{3} +1, 4^{3} +1, 5^{3} +1, 6^{3} +1, 7^{3} +1
The answer is, 807.
Directions (Q. 11-15):
Answer a
(18 × 25)/30 = x – 523
15 = x – 523
X= 15+523 = 538
Answer a
49 × 20 – 25 × 14 = (36 + x) × 9
980 – 350 = 324 +9x
9x = 980 – 350 – 324
9x = 306
X = 34
Answer d
(26^{2} – 17^{2})/ ? = 21
676 – 289)/x = 21
387/x = 21
X = 387/21 = 18.42
X=18
Answer b
35 × 16 + 29 × 45 = 41x +468 + 774 -200
560 + 1305 -468 -774+200 = 41x
823 = 41x
X = 823/41
X = 20
Answer c
(26/5)*190 + (44/7)* 231 = 5x +857
988 + 1452 – 857 = 5x
1583 = 5x
X = 1583/5 = 317
Directions (Q. 16 – 20):
16). Answer b
Total students for English = 0.14*8000=1120
Total girls passed in English=0.14*5000=700
Total boys passed in English=1120-700=420
Boys pass %= (420/1120)*100= 37.5%
17). Answer d
Total Boys passed in Science = [(0.20*8000)-(0.25*5000)] =350
Total Boys passed in Social = [(0.21*8000)-(0.20*5000)] =680
Total boys are passed in Science and Social = 350+680 = 1030
18). Answer c
Total number of girls passed in Hindi, Maths and Science =5000*(66/100)
Average no of girls passed in Hindi, Maths and Science= 5000*(66/100)*(1/3)
= >1100
19). Answer d
Total number of boys passed in Hindi = [(0.20*8000)-(0.20*5000)]= 600
Total number of Girls passed in Science = [0.25*5000]= 1250
Required % = [(1250-600)/1250]*100 = 52%
20). Answer a
Total boys passed in English = (0.14*8000)-(0.14*500)=420
Total Boys passed in Social = [(0.21*8000)-(0.20*5000)] =680