Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk / IDBI Executive 2018 . Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
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Review
Question 1 of 20
1. Question
Directions (Q. 1-5): What value should come in place of question mark (?) in the following questions?
28 % of 487.5 + 56 % of 305.5 = 3 ×?
Correct
Answer b
(28/100)* 487.5 + (56/100)* 305.5 = 3 x
136.5 + 171.08 = 3x
3x = 307.58
X = 102.526
Incorrect
Answer b
(28/100)* 487.5 + (56/100)* 305.5 = 3 x
136.5 + 171.08 = 3x
3x = 307.58
X = 102.526
Question 2 of 20
2. Question
Directions (Q. 1-5): What value should come in place of question mark (?) in the following questions?
(3/4) of (187/513) of (14/21) of 1026 = x
Correct
Answer a
(3/4) * (187/513) * (14/21) * 1026 = x
X = 187
Incorrect
Answer a
(3/4) * (187/513) * (14/21) * 1026 = x
X = 187
Question 3 of 20
3. Question
Directions (Q. 1-5): What value should come in place of question mark (?) in the following questions?
3 ½ + 5 7/8 – 6 ¼ = x – 4 ½
Correct
Answer d
3 ½ + 5 7/8 – 6 ¼ + 4 ½ = x
(3+5-6+4) (½ + 7/8 -1/4 + 1/2) = x
X = 6((4 + 7 – 2 + 4)/ 8)
X = 6 13/8
X = 7 5/8
Incorrect
Answer d
3 ½ + 5 7/8 – 6 ¼ + 4 ½ = x
(3+5-6+4) (½ + 7/8 -1/4 + 1/2) = x
X = 6((4 + 7 – 2 + 4)/ 8)
X = 6 13/8
X = 7 5/8
Question 4 of 20
4. Question
Directions (Q. 1-5): What value should come in place of question mark (?) in the following questions?
84^{2} – 2176 ÷ 68 =? × 5^{3}
Correct
Answer c
84^{2} – 2176 ÷ 68 = 125x
7056 – 32 = 125x
7024 = 125x
X= 56.192
Incorrect
Answer c
84^{2} – 2176 ÷ 68 = 125x
7056 – 32 = 125x
7024 = 125x
X= 56.192
Question 5 of 20
5. Question
Directions (Q. 1-5): What value should come in place of question mark (?) in the following questions?
[(56)^{2} ÷ 28^{2} × 8] ÷ 12 = 8 ×?
Correct
Answer d
[56*56*8/ 28*28] ÷ 12 = 8x
32/12 = 8x
X = 32/ (8*12) = 1/3
Incorrect
Answer d
[56*56*8/ 28*28] ÷ 12 = 8x
32/12 = 8x
X = 32/ (8*12) = 1/3
Question 6 of 20
6. Question
Directions (Q. 6 – 10): What value should come in place of (?) in the following series?
108, 194, 366, 624,?
Correct
Answer b
The pattern is, + (86*1), + (86*2), + (86*3), + (86*4)….
The answer is, 968
Incorrect
Answer b
The pattern is, + (86*1), + (86*2), + (86*3), + (86*4)….
The answer is, 968
Question 7 of 20
7. Question
Directions (Q. 6 – 10): What value should come in place of (?) in the following series?
106, 110, 126, 162,?
Correct
Answer d
The pattern is, +(1*4), +(2*8),+(3*12), +(4*16)….
The answer is, 226
Incorrect
Answer d
The pattern is, +(1*4), +(2*8),+(3*12), +(4*16)….
The answer is, 226
Question 8 of 20
8. Question
Directions (Q. 6 – 10): What value should come in place of (?) in the following series?
398, 200, 54, 16,?
Correct
Answer c
The pattern is, ÷ 2 + 1, ÷ 4 + 4, ÷ 6 + 7, ÷ 8 + 10….
The answer is, 12
Incorrect
Answer c
The pattern is, ÷ 2 + 1, ÷ 4 + 4, ÷ 6 + 7, ÷ 8 + 10….
The answer is, 12
Question 9 of 20
9. Question
Directions (Q. 6 – 10): What value should come in place of (?) in the following series?
47, 51, 111, 349,?
Correct
Answer a
The pattern is, *1 + 2^{2}, *2 + 3^{2}, *3 + 4^{2}, *4 + 5^{2}….
The answer is, 1421
Incorrect
Answer a
The pattern is, *1 + 2^{2}, *2 + 3^{2}, *3 + 4^{2}, *4 + 5^{2}….
The answer is, 1421
Question 10 of 20
10. Question
Directions (Q. 6 – 10): What value should come in place of (?) in the following series?
121, 136, 158, 194, 251, ?
Correct
Answer b
The difference of difference is, 7, 14, 21, 28….
The answer is, 336
Incorrect
Answer b
The difference of difference is, 7, 14, 21, 28….
The answer is, 336
Question 11 of 20
11. Question
A shopkeeper purchased a mobile for Rs 1200 and spent Rs 240 for its repair. At what price he should sell the mobile so that his percentage repairing cost incurred for mobile is equal to the profit percentage earned on the mobile?
Correct
Answer b
Repairing cost percentage= 240*100/1200 = 20%
So he has to earn a profit of 20%
Total cost of the mobile= 1200+240= 1440
To earn 20% profit he should at= 1440*120/100= Rs 1728
Incorrect
Answer b
Repairing cost percentage= 240*100/1200 = 20%
So he has to earn a profit of 20%
Total cost of the mobile= 1200+240= 1440
To earn 20% profit he should at= 1440*120/100= Rs 1728
Question 12 of 20
12. Question
The perimeter of a rectangle is 52 m and the difference between the length and the breadth of the rectangle is 10m then find the perimeter of square whose area is equal to the area of the rectangle?
Correct
Answer b
Let the breadth of the rectangle be x
Length= x+10
So,
52= 2(x+x+10)
52= 4x+20
4x= 32
x= 8
Area of the rectangle= 8*18= 144
Side of the square= √144= 12
Perimeter of the square = 12*4= 48m
Incorrect
Answer b
Let the breadth of the rectangle be x
Length= x+10
So,
52= 2(x+x+10)
52= 4x+20
4x= 32
x= 8
Area of the rectangle= 8*18= 144
Side of the square= √144= 12
Perimeter of the square = 12*4= 48m
Question 13 of 20
13. Question
The average cost of three mobiles A, B and C of a certain company is Rs 30000. The average cost decrease by 20 % when mobile D of the same company is included, what is the cost price of mobile D?
Correct
Answer a
Total cost of mobiles A, B and C= 30000*3= Rs 90000
Average cost of A, B, C, D= 30000*80/100= Rs 24000
Total cost four mobile= 24000*4= Rs 96000
Cost of mobile D= 96000-90000= Rs 6000
Incorrect
Answer a
Total cost of mobiles A, B and C= 30000*3= Rs 90000
Average cost of A, B, C, D= 30000*80/100= Rs 24000
Total cost four mobile= 24000*4= Rs 96000
Cost of mobile D= 96000-90000= Rs 6000
Question 14 of 20
14. Question
A vessels contains 50 litres of pure milk. From these 10 litres of milk is replaced with water. The process is repeated one more time. Find the quantity of milk in the final solution.
Correct
Answer a
According to the formula,
Quantity of milk left= 50(1- 10/50)^{2})
= 50* 4/5 * 4/5
= 32 litres
Incorrect
Answer a
According to the formula,
Quantity of milk left= 50(1- 10/50)^{2})
= 50* 4/5 * 4/5
= 32 litres
Question 15 of 20
15. Question
5 years ago the age of a man was 3 years more than 4 times his son’s age. After 3 years the man will be 6 years less than thrice the age of his son. After how many years will the sum of their ages be 80 years?
Correct
Answer b
Let the present age of the man and his son be x and y respectively
So,
x – 5= 4(y-5) +3
x – 4y= -12….. (i)
Again
X+3 = 3(y+3) -6
x – 3y= 0…….(ii)
By solving, we get
X= 36, y=12
Sum of their ages = 48
Hence after 16 years the sum of their ages will be 80 years.
Incorrect
Answer b
Let the present age of the man and his son be x and y respectively
So,
x – 5= 4(y-5) +3
x – 4y= -12….. (i)
Again
X+3 = 3(y+3) -6
x – 3y= 0…….(ii)
By solving, we get
X= 36, y=12
Sum of their ages = 48
Hence after 16 years the sum of their ages will be 80 years.
Question 16 of 20
16. Question
Directions (Q. 16 – 20) Study this chart to answer the questions.
Total number of students playing Carrom and Hockey together from school P is what percent of the total number of students playing these two games together from school R?
Correct
Answer c
Total number of students playing Carrom and Hockey together from school P = 220+140 = 360
Total number of students playing Carrom and Hockey together from School R = 200+320 = 520
Percentage = (360/520)*100 = 69 (3/13) %
Incorrect
Answer c
Total number of students playing Carrom and Hockey together from school P = 220+140 = 360
Total number of students playing Carrom and Hockey together from School R = 200+320 = 520
Percentage = (360/520)*100 = 69 (3/13) %
Question 17 of 20
17. Question
Directions (Q. 16 – 20) Study this chart to answer the questions.
If the number of students playing each game in school S is increased by 15% and the number of students playing each game in school Q is decreased by 5%, then what will be the difference between number of students in schools S and Q?
Correct
Answer e
Number of students in school S = 115% of 740 = 851
Number of students in school Q = 95% of 680 = 646
Difference = 851 – 646 = 205
Incorrect
Answer e
Number of students in school S = 115% of 740 = 851
Number of students in school Q = 95% of 680 = 646
Difference = 851 – 646 = 205
Question 18 of 20
18. Question
Directions (Q. 16 – 20) Study this chart to answer the questions.
If out of the students playing Cricket from schools Q, S and T are 40%, 35% and 45% respectively got selected for state level competition, what was the total number of students got selected for State level competition from these three schools together?
Correct
Answer c
Total number of students who got selected for state level competition from schools Q S and T
= 40% of 180 + 35% of 320 + 45% of 240
= 72 + 112 + 108 = 292
Incorrect
Answer c
Total number of students who got selected for state level competition from schools Q S and T
= 40% of 180 + 35% of 320 + 45% of 240
= 72 + 112 + 108 = 292
Question 19 of 20
19. Question
Directions (Q. 16 – 20) Study this chart to answer the questions.
Total number of students playing Hockey from all schools together is approximately what percent of the total number of students playing Cricket from all schools together?
Correct
Answer d
Total number of students playing Hockey from all the schools together = 140 + 260 + 320 + 160 + 180 = 1060
Total number of students playing Cricket from all the schools together = 360 + 180 + 240 + 320 + 240 = 1340
% = (1060/1340)*100 = 79 % (approximately)
Incorrect
Answer d
Total number of students playing Hockey from all the schools together = 140 + 260 + 320 + 160 + 180 = 1060
Total number of students playing Cricket from all the schools together = 360 + 180 + 240 + 320 + 240 = 1340
% = (1060/1340)*100 = 79 % (approximately)
Question 20 of 20
20. Question
Directions (Q. 16 – 20) Study this chart to answer the questions.
From School P, out of the students playing Carrom, 40% got selected for state level competition out of which 25% further got selected for National level competition. From School T, out of the students playing Carrom, 45% got selected for state level competition out of which two-third further got selected for National level competition. What is the total number of students playing Carrom from these two schools who got selected for National level competition?
Correct
Answer a
Number of students who got selected for national level competition from School P = 25% of 40% of 220 = 22
Number of students who got selected for national level competition from School T = (2/3) of 45% of 280 = 84
Total number of students playing Carrom from these two schools who got selected for national level competition
= 22 + 84 =106
Incorrect
Answer a
Number of students who got selected for national level competition from School P = 25% of 40% of 220 = 22
Number of students who got selected for national level competition from School T = (2/3) of 45% of 280 = 84
Total number of students playing Carrom from these two schools who got selected for national level competition
= 22 + 84 =106
Click “Start Quiz” to attend these Questions and view Solutions
Directions (Q. 1-5): What value should come in place of question mark (?) in the following questions?
28 % of 487.5 + 56 % of 305.5 = 3 ×?
78.342
102.526
210.128
96.784
None of these
(3/4) of (187/513) of (14/21) of 1026 = x
187
78
289
125
None of these
3 ½ + 5 7/8 – 6 ¼ = x – 4 ½
5 1/8
4 3/8
6 7/8
7 5/8
None of these
84^{2} – 2176 ÷ 68 =? × 5^{3}
78.124
62.674
56.192
48.366
None of these
[(56)^{2} ÷ 28^{2} × 8] ÷ 12 = 8 ×?
¼
¾
2/3
1/3
None of these
Directions (Q. 6 – 10): What value should come in place of (?) in the following series?
108, 194, 366, 624,?
784
968
856
1282
None of these
106, 110, 126, 162,?
347
298
384
226
None of these
398, 200, 54, 16,?
24
18
12
30
None of these
47, 51, 111, 349,?
1421
783
987
1843
None of these
121, 136, 158, 194, 251, ?
486
336
278
548
None of these
A shopkeeper purchased a mobile for Rs 1200 and spent Rs 240 for its repair. At what price he should sell the mobile so that his percentage repairing cost incurred for mobile is equal to the profit percentage earned on the mobile?
2000
1728
1200
3000
5000
The perimeter of a rectangle is 52 m and the difference between the length and the breadth of the rectangle is 10m then find the perimeter of square whose area is equal to the area of the rectangle?
20
48
12
30
50
The average cost of three mobiles A, B and C of a certain company is Rs 30000. The average cost decrease by 20 % when mobile D of the same company is included, what is the cost price of mobile D?
6000
4000
1200
3000
5000
A vessels contains 50 litres of pure milk. From these 10 litres of milk is replaced with water. The process is repeated one more time. Find the quantity of milk in the final solution.
32
21
12
16
None of these
5 years ago the age of a man was 3 years more than 4 times his son’s age. After 3 years the man will be 6 years less than thrice the age of his son. After how many years will the sum of their ages be 80 years?
32
16
24
45
32
Directions (Q. 16 – 20) Study this chart to answer the questions.
Total number of students playing Carrom and Hockey together from school P is what percent of the total number of students playing these two games together from school R?
68 (3/16)
62 (3/13)
69 (3/13)
63 (3/13)
62 (3/13)
If the number of students playing each game in school S is increased by 15% and the number of students playing each game in school Q is decreased by 5%, then what will be the difference between number of students in schools S and Q?
54
218
356
224
205
If out of the students playing Cricket from schools Q, S and T are 40%, 35% and 45% respectively got selected for state level competition, what was the total number of students got selected for State level competition from these three schools together?
346
241
292
284
268
Total number of students playing Hockey from all schools together is approximately what percent of the total number of students playing Cricket from all schools together?
84
74
72
79
70
From School P, out of the students playing Carrom, 40% got selected for state level competition out of which 25% further got selected for National level competition. From School T, out of the students playing Carrom, 45% got selected for state level competition out of which two-third further got selected for National level competition. What is the total number of students playing Carrom from these two schools who got selected for National level competition?
106
98
112
108
96
Answers:
Directions (Q. 1-5):
Answer b
(28/100)* 487.5 + (56/100)* 305.5 = 3 x
136.5 + 171.08 = 3x
3x = 307.58
X = 102.526
Answer a
(3/4) * (187/513) * (14/21) * 1026 = x
X = 187
Answer d
3 ½ + 5 7/8 – 6 ¼ + 4 ½ = x
(3+5-6+4) (½ + 7/8 -1/4 + 1/2) = x
X = 6((4 + 7 – 2 + 4)/ 8)
X = 6 13/8
X = 7 5/8
Answer c
84^{2} – 2176 ÷ 68 = 125x
7056 – 32 = 125x
7024 = 125x
X= 56.192
Answer d
[56*56*8/ 28*28] ÷ 12 = 8x
32/12 = 8x
X = 32/ (8*12) = 1/3
Directions (Q. 6 – 10):
Answer b
The pattern is, + (86*1), + (86*2), + (86*3), + (86*4)….
The answer is, 968
Answer d
The pattern is, +(1*4), +(2*8),+(3*12), +(4*16)….
The answer is, 226
Answer c
The pattern is, ÷ 2 + 1, ÷ 4 + 4, ÷ 6 + 7, ÷ 8 + 10….
The answer is, 12
Answer a
The pattern is, *1 + 2^{2}, *2 + 3^{2}, *3 + 4^{2}, *4 + 5^{2}….
The answer is, 1421
Answer b
The difference of difference is, 7, 14, 21, 28….
The answer is, 336
Answer b
Repairing cost percentage= 240*100/1200 = 20%
So he has to earn a profit of 20%
Total cost of the mobile= 1200+240= 1440
To earn 20% profit he should at= 1440*120/100= Rs 1728
Answer b
Let the breadth of the rectangle be x
Length= x+10
So,
52= 2(x+x+10)
52= 4x+20
4x= 32
x= 8
Area of the rectangle= 8*18= 144
Side of the square= √144= 12
Perimeter of the square = 12*4= 48m
Answer a
Total cost of mobiles A, B and C= 30000*3= Rs 90000
Average cost of A, B, C, D= 30000*80/100= Rs 24000
Total cost four mobile= 24000*4= Rs 96000
Cost of mobile D= 96000-90000= Rs 6000
Answer a
According to the formula,
Quantity of milk left= 50(1- 10/50)^{2})
= 50* 4/5 * 4/5
= 32 litres
Answer b
Let the present age of the man and his son be x and y respectively
So,
x – 5= 4(y-5) +3
x – 4y= -12….. (i)
Again
X+3 = 3(y+3) -6
x – 3y= 0…….(ii)
By solving, we get
X= 36, y=12
Sum of their ages = 48
Hence after 16 years the sum of their ages will be 80 years.
Directions (Q. 16 – 20)
Answer c
Total number of students playing Carrom and Hockey together from school P = 220+140 = 360
Total number of students playing Carrom and Hockey together from School R = 200+320 = 520
Percentage = (360/520)*100 = 69 (3/13) %
Answer e
Number of students in school S = 115% of 740 = 851
Number of students in school Q = 95% of 680 = 646
Difference = 851 – 646 = 205
Answer c
Total number of students who got selected for state level competition from schools Q S and T
= 40% of 180 + 35% of 320 + 45% of 240
= 72 + 112 + 108 = 292
Answer d
Total number of students playing Hockey from all the schools together = 140 + 260 + 320 + 160 + 180 = 1060
Total number of students playing Cricket from all the schools together = 360 + 180 + 240 + 320 + 240 = 1340
% = (1060/1340)*100 = 79 % (approximately)
Answer a
Number of students who got selected for national level competition from School P = 25% of 40% of 220 = 22
Number of students who got selected for national level competition from School T = (2/3) of 45% of 280 = 84
Total number of students playing Carrom from these two schools who got selected for national level competition