Quantitative Aptitude Scoring Part (Day63):
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Dear Readers, Nowadays most of the aspirants were facing huge trouble to increase the rall marks. To score high you need to practice more and more standard questions daily.“Practice does not make perfect, Only Perfect Practice makes perfect”.
Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practising these questions regularly you can increase you calculation speed and it will help you to increase you score.
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Quantitative Aptitude Scoring Part Day63
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Question 1 of 30
1. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
188.88+8.88+288.8+888.840.888=?
Correct
Correct Answer is: d)
?=188.88+8.88+288.8+888.840.888=1334.472
Incorrect
Correct Answer is: d)
?=188.88+8.88+288.8+888.840.888=1334.472

Question 2 of 30
2. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
145×34/17+98=?
Correct
Correct Answer is: c)
?=145×34/17+98
=145×2+98=290+98=388
Incorrect
Correct Answer is: c)
?=145×34/17+98
=145×2+98=290+98=388

Question 3 of 30
3. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
78(2/3)+39(11/19)+143(5/6)+33(1/3)=?
Correct
Correct Answer is: e)
?= 78(2/3)+39(11/19)+143(5/6)+33(1/3)
= (78+39+143+33)+[(2/3)+(11/19)+(5/6)+(1/3)]
= 293 + [(76+66+95+38)/114]
= 293 +(275/114)=(293+2)+(47/114)=295(47/114)
Incorrect
Correct Answer is: e)
?= 78(2/3)+39(11/19)+143(5/6)+33(1/3)
= (78+39+143+33)+[(2/3)+(11/19)+(5/6)+(1/3)]
= 293 + [(76+66+95+38)/114]
= 293 +(275/114)=(293+2)+(47/114)=295(47/114)

Question 4 of 30
4. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
(970/17)×(289/15)×(18/1.5)=1649×?
Correct
Correct Answer is: e)
?×1649=(970/17)×(289/15)×(18/1.5)=13192
:.? = (13192/1649)=8
Incorrect
Correct Answer is: e)
?×1649=(970/17)×(289/15)×(18/1.5)=13192
:.? = (13192/1649)=8

Question 5 of 30
5. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
91% of 877 +23% of 472 =?
Correct
Correct Answer is: d)
?=91% of 877 +23% of 472
=[877×(91/100)] + [472×(23/100)]=798.07 + 108.56
= 906.63
Incorrect
Correct Answer is: d)
?=91% of 877 +23% of 472
=[877×(91/100)] + [472×(23/100)]=798.07 + 108.56
= 906.63

Question 6 of 30
6. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
√6084 + √7744 – √ 2025 = (?)^{2}
Correct
Correct Answer is: c)
(?)^{2 }=√6084 + √7744 – √ 2025
=78 + 88 – 45= 121 = (11)^{2}
:. ? = 11
Incorrect
Correct Answer is: c)
(?)^{2 }=√6084 + √7744 – √ 2025
=78 + 88 – 45= 121 = (11)^{2}
:. ? = 11

Question 7 of 30
7. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
76×34+55×2923×11=?
Correct
Correct Answer is: c)
?=76×34+55×2923×11
=2584+1595 253 =3926
Incorrect
Correct Answer is: c)
?=76×34+55×2923×11
=2584+1595 253 =3926

Question 8 of 30
8. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
?×36+38 = (11)^{2}+(13)^{2}
Correct
Correct Answer is: b)
?×36+38 = (11)^{2}+(13)^{2}
Or, ?×36+38=121 + 169 = 290
Or, ? × 36 = 290 – 38
:. ? = (252 / 36) = 7
Incorrect
Correct Answer is: b)
?×36+38 = (11)^{2}+(13)^{2}
Or, ?×36+38=121 + 169 = 290
Or, ? × 36 = 290 – 38
:. ? = (252 / 36) = 7

Question 9 of 30
9. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
√16641 + √14641 = ?
Correct
Correct Answer is: a)
?= √16641 + √14641
=129+121=250
Incorrect
Correct Answer is: a)
?= √16641 + √14641
=129+121=250

Question 10 of 30
10. Question
Directions (Q.110): Find out the approximate value which should replace the question mark (?) in the following questions. (You are not expected to find out the exact value.)
(112)^{2}(120)^{2}+(24)^{2}=? – 2860
Correct
Correct Answer is: e)
? – 2860= (112)^{2}(120)^{2}+(24)^{2}
=12544 – 14400 + 576
Or,? = 13120 + 2860 – 14400
= 15980 – 14400 = 1580
Incorrect
Correct Answer is: e)
? – 2860= (112)^{2}(120)^{2}+(24)^{2}
=12544 – 14400 + 576
Or,? = 13120 + 2860 – 14400
= 15980 – 14400 = 1580

Question 11 of 30
11. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
6,23,898×99=?×60,000
Correct
Correct Answer is: b)
We have
6,23,898 × 99 = ? × 60,000
?= (6,23,898 × 99) / 60,000
= [(623898 × 100 – 623898) / 60,000] ≈1030
Incorrect
Correct Answer is: b)
We have
6,23,898 × 99 = ? × 60,000
?= (6,23,898 × 99) / 60,000
= [(623898 × 100 – 623898) / 60,000] ≈1030

Question 12 of 30
12. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
4/5 × 3/7 ÷ 6/7 ÷ 5/9 = ?
Correct
Correct Answer is: c)
We have
(4/5) × (3/7) ÷ (6/7) ÷ (5/9) = (4/5) × (3/7) × (7/6) × (9/5) = (18/25)
Incorrect
Correct Answer is: c)
We have
(4/5) × (3/7) ÷ (6/7) ÷ (5/9) = (4/5) × (3/7) × (7/6) × (9/5) = (18/25)

Question 13 of 30
13. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
399.98^{2} = ?
Correct
Correct Answer is: a)
(399.98)^{2 }≈ 400^{2} ≈ 160000
Incorrect
Correct Answer is: a)
(399.98)^{2 }≈ 400^{2} ≈ 160000

Question 14 of 30
14. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
√(624.9995) + (4.9989)^{2 }= ? ÷ (1 / 4.9900865)
Correct
Correct Answer is: c)
We have
√(624.9995) + (4.9989)^{2} = ? ÷ (1/4.9900865)
≈ √(625) + (5)^{2 }= ? ÷ (1/5)
? ≈ 1/5 (25+25) ≈ 10
Incorrect
Correct Answer is: c)
We have
√(624.9995) + (4.9989)^{2} = ? ÷ (1/4.9900865)
≈ √(625) + (5)^{2 }= ? ÷ (1/5)
? ≈ 1/5 (25+25) ≈ 10

Question 15 of 30
15. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
989.001 + 1.00982 × 76.792=?
Correct
Correct Answer is: c)
989.001 + 1.00982 × 76.792
≈ 990 + 1 × 76.8 ≈ 1066.8
Incorrect
Correct Answer is: c)
989.001 + 1.00982 × 76.792
≈ 990 + 1 × 76.8 ≈ 1066.8

Question 16 of 30
16. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
63.9872 × 9449.8780 ÷ 243.0034 = (?)^{2}
Correct
Correct Answer is: c)
? = 63.9872 × 9449.8780 ÷ 243.0034
≈ 64 × 9450 ÷ 243
≈ 64 × 39 ≈ 2496
Now, (?)^{2} ≈ 2496
? ≈ 50
Incorrect
Correct Answer is: c)
? = 63.9872 × 9449.8780 ÷ 243.0034
≈ 64 × 9450 ÷ 243
≈ 64 × 39 ≈ 2496
Now, (?)^{2} ≈ 2496
? ≈ 50

Question 17 of 30
17. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
5237.897 – 6629.010 + 7153.999 – 2205.102=?
Correct
Correct Answer is: d)
? = 5237.897 – 6629.010 + 7153.999 – 2205.102
= 3557.784 ≈ 3558
Incorrect
Correct Answer is: d)
? = 5237.897 – 6629.010 + 7153.999 – 2205.102
= 3557.784 ≈ 3558

Question 18 of 30
18. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
4985.0346 ÷ 215.987 – 3768.112 ÷ 206.868 =?
Correct
Correct Answer is: b)
? = 4985.0346 ÷ 215.987 – 3768.112 ÷ 206.868
≈ 4985 ÷ 216 – 3768 ÷ 207
≈ 23 18 ≈ 5
Incorrect
Correct Answer is: b)
? = 4985.0346 ÷ 215.987 – 3768.112 ÷ 206.868
≈ 4985 ÷ 216 – 3768 ÷ 207
≈ 23 18 ≈ 5

Question 19 of 30
19. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
√(956240) =?
Correct
Correct Answer is: a)
? = √(956240) ≈ 978
Incorrect
Correct Answer is: a)
? = √(956240) ≈ 978

Question 20 of 30
20. Question
Directions (11 – 20): What value should come in the place of question mark (?) in the following equations?
459% of 849.947 + 266% of 6284.012 – 1486.002=?
Correct
Correct Answer is: e)
? = 459% of 849.947 + 266% of 6284.012 – 1486.002
≈ 460% of 850 + 265% of 6285 – 1486
≈ 3910 + 16655 1486
≈19079
Incorrect
Correct Answer is: e)
? = 459% of 849.947 + 266% of 6284.012 – 1486.002
≈ 460% of 850 + 265% of 6285 – 1486
≈ 3910 + 16655 1486
≈19079

Question 21 of 30
21. Question
Directions (2125): Find out the wrong number in each sequence:
56, 72, 90, 110, 132, 150
Correct
Correct Answer is: D
Sol. The numbers are 7 × 8, 8 × 9, 9 × 10, 10 × 11, 11 × 12, 12 × 13. So, 150 is wrong.
Incorrect
Correct Answer is: D
Sol. The numbers are 7 × 8, 8 × 9, 9 × 10, 10 × 11, 11 × 12, 12 × 13. So, 150 is wrong.

Question 22 of 30
22. Question
Directions (2125): Find out the wrong number in each sequence:
1, 2, 6, 15, 31, 56, 91
Correct
Correct Answer is: B
Incorrect
Correct Answer is: B

Question 23 of 30
23. Question
Directions (2125): Find out the wrong number in each sequence:
105, 85, 60, 30, 0, 45, 90
Correct
Correct Answer is: A
Sol. Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So, 0 is wrong.
Incorrect
Correct Answer is: A
Sol. Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So, 0 is wrong.

Question 24 of 30
24. Question
Directions (2125): Find out the wrong number in each sequence:
125, 127, 130, 135, 142, 153, 165
Correct
Correct Answer is: D
Sol. Prime numbers 2, 3, 5, 7, 11, 13 are to be added successively. So 165 is wrong.
Incorrect
Correct Answer is: D
Sol. Prime numbers 2, 3, 5, 7, 11, 13 are to be added successively. So 165 is wrong.

Question 25 of 30
25. Question
Directions (2125): Find out the wrong number in each sequence:
3, 10, 21, 36, 55, 70, 105
Correct
Correct Answer is: B
Sol. The pattern is 1 × 3, 2 × 5, 3 × 7, 4 × 9, 5 × 11, 6 × 13, 7 × 15 etc.
Incorrect
Correct Answer is: B
Sol. The pattern is 1 × 3, 2 × 5, 3 × 7, 4 × 9, 5 × 11, 6 × 13, 7 × 15 etc.

Question 26 of 30
26. Question
Direction (2630): Two equations (I) and (II) are given in each question. On the basis of these equations. You have to decide the relation between ‘x’ and ‘y’ and give answer .
a) If x > y
b) If x < y
c) If x ≥ y
d) If x ≤ y
e) If x = y or no relation can be decided between ‘x’ and ‘y’.
I. x = (7)^{2}
II.y^{2}– 46y – 147 = 0
Correct
Correct Answer is: C)
x = (7)^{2}
x = 49
= y^{2} – 46y – 147 = 0
y^{2} – 49y + 3y – 147 = 0,
= y (y49) + 3 (y – 49) = 0
(y – 49) (y + 3) = 0 y = 49, 3
x ≥ y
Incorrect
Correct Answer is: C)
x = (7)^{2}
x = 49
= y^{2} – 46y – 147 = 0
y^{2} – 49y + 3y – 147 = 0,
= y (y49) + 3 (y – 49) = 0
(y – 49) (y + 3) = 0 y = 49, 3
x ≥ y

Question 27 of 30
27. Question
Direction (2630): Two equations (I) and (II) are given in each question. On the basis of these equations. You have to decide the relation between ‘x’ and ‘y’ and give answer .
a) If x > y
b) If x < y
c) If x ≥ y
d) If x ≤ y
e) If x = y or no relation can be decided between ‘x’ and ‘y’.
I. 4x^{2} – x – 3 = 0
II.4y^{2}– 16y + 15 = 0
Correct
Correct Answer is: B)
4 x^{2} – x – 3 = 0
= 4x^{2} – 4x +3x – 3 = 0
= 4 x (x – 1) + 3 (x – 1) = 0
= (4x + 3) (x – 1) = 0
x = – 3/4, 1
4y^{2} – 16y + 15 = 0
4y^{2} – 10y – 6y + 15 = 0
2y (2y – 5) –3 (2y – 5) = 0
(2y – 3) (2y – 5) = 0
y = 3/2, 5/2
x < y
Incorrect
Correct Answer is: B)
4 x^{2} – x – 3 = 0
= 4x^{2} – 4x +3x – 3 = 0
= 4 x (x – 1) + 3 (x – 1) = 0
= (4x + 3) (x – 1) = 0
x = – 3/4, 1
4y^{2} – 16y + 15 = 0
4y^{2} – 10y – 6y + 15 = 0
2y (2y – 5) –3 (2y – 5) = 0
(2y – 3) (2y – 5) = 0
y = 3/2, 5/2
x < y

Question 28 of 30
28. Question
Direction (2630): Two equations (I) and (II) are given in each question. On the basis of these equations. You have to decide the relation between ‘x’ and ‘y’ and give answer .
a) If x > y
b) If x < y
c) If x ≥ y
d) If x ≤ y
e) If x = y or no relation can be decided between ‘x’ and ‘y’.
I. 2x^{2} – 117x + 1701 = 0
II.y = 992.25
Correct
Correct Answer is: D)
2x^{2} – 117x + 1701
= 2x^{2} – 54x – 63x + 1701
= 2x ( x – 27) 63 ( x – 27)
= (2x – 63) ( x – 27) = 0
x = 27, 63/2
y = √(992.25)
y = 31.5
x ≤ y
Incorrect
Correct Answer is: D)
2x^{2} – 117x + 1701
= 2x^{2} – 54x – 63x + 1701
= 2x ( x – 27) 63 ( x – 27)
= (2x – 63) ( x – 27) = 0
x = 27, 63/2
y = √(992.25)
y = 31.5
x ≤ y

Question 29 of 30
29. Question
Direction (2630): Two equations (I) and (II) are given in each question. On the basis of these equations. You have to decide the relation between ‘x’ and ‘y’ and give answer .
a) If x > y
b) If x < y
c) If x ≥ y
d) If x ≤ y
e) If x = y or no relation can be decided between ‘x’ and ‘y’.
I. 12x^{2} – 41x + 35 = 0
II.3y^{2}– 17y – 28 = 0
Correct
Correct Answer is: E)
12x^{2} – 41x + 35 = 0
= 12x^{2} – 20x – 21x + 35 = 0,
= 4x (3x – 5) – 7 ( 3x – 5) = 0,
= (4x – 7) (3x 5) = 0,
x = 7/4, 5/3
3y^{2} – 17y – 28 = 0
3y^{2} – 21y +4y – 28= 0
3y ( y – 7) + 4 ( y – 7) = 0
( y 7) ( 3y + 4) = 0
y = 7, 4/3
ie.no relation between ‘x’ and ‘y’.
Incorrect
Correct Answer is: E)
12x^{2} – 41x + 35 = 0
= 12x^{2} – 20x – 21x + 35 = 0,
= 4x (3x – 5) – 7 ( 3x – 5) = 0,
= (4x – 7) (3x 5) = 0,
x = 7/4, 5/3
3y^{2} – 17y – 28 = 0
3y^{2} – 21y +4y – 28= 0
3y ( y – 7) + 4 ( y – 7) = 0
( y 7) ( 3y + 4) = 0
y = 7, 4/3
ie.no relation between ‘x’ and ‘y’.

Question 30 of 30
30. Question
Direction (2630): Two equations (I) and (II) are given in each question. On the basis of these equations. You have to decide the relation between ‘x’ and ‘y’ and give answer .
a) If x > y
b) If x < y
c) If x ≥ y
d) If x ≤ y
e) If x = y or no relation can be decided between ‘x’ and ‘y’.
I. 4x – 3y = 16
II.7x – 8y = 17
Correct
Correct Answer is: A)
Equ^{n} (I) × 7 – Equ^{n} (II) × 4
(28x – 21y = 112) – (28x – 32y = 68)
11y = 44
y = 4,& from this x = 7
x >y
Incorrect
Correct Answer is: A)
Equ^{n} (I) × 7 – Equ^{n} (II) × 4
(28x – 21y = 112) – (28x – 32y = 68)
11y = 44
y = 4,& from this x = 7
x >y