IBPS / LIC Clerk Prelims Quantitative Aptitude Questions 2019 (Day-01)

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IBPS Clerk Prelims Quantitative Aptitude Questions 2019 (Day-01)

Directions (1 – 5): In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established.

1)

I) x2 – 28x + 171=0

II) y2 + 3y – 108=0

2)

I) 2x2 + 18x + 40=0

II) 3y2 + 17y + 10=0

3)

I) x2 + 29x + 208=0

II) y2 + 27y + 176=0

4)

I) x2 + 22x + 112=0

II) y2 + 15y + 56=0

5)

I) 2x2 + 14x + 12=0

II) y2 – 18y + 65=0

Direction (6 – 10): Study the following information carefully and answer the given questions:

The given table shows the percentage of students in various departments of five different colleges.

6) What is the difference between the total number of students from CSE departments in all the colleges together and the total number of students in college E?

a) 392

b) 404

c) 411

d) 428

e) None of these

7) What is the average number of students from EEE departments in all the colleges together?

a) 465

b) 472

c) 477

d) 480

e) None of these

8) The number of students from ECE departments in college D is what percentage of number of students from ECE departments in college E?

a) 20%

b) 25%

c) 30%

d) 35%

e) None of these

9) What is the ratio of the number of students from ECE departments in college A and B together to total number of students from college B?

a) 34:99

b) 48:99

c) 53:100

d) 59:100

e) None of these

10) What is average of the number of students from ECE in college C, the number of students from EEE in college B and the number of students from CSE in college E?

a) 515

b) 516

c) 517

d) 518

e) None of these

Answers :

Directions (1-5) :

1) Answer: b)

x2 – 28x + 171=0

x2 – 19x – 9x + 171=0

x(x – 19) – 9(x – 19)=0

(x – 9)(x – 19)=0

X=9, 19

y2 + 3y – 108=0

y2 + 12y – 9y – 108=0

y(y + 12) – 9(y + 12)=0

(y – 9)(y + 12)=0

Y=9, -12

2) Answer: e)

2x2 + 18x + 40=0

2x2 + 10x + 8x + 40=0

2x(x + 5) + 8(x + 5)=0

(2x + 8)(x + 5)=0

x=-4, -5

3y2 + 17y + 10=0

3y2 + 15y + 2y + 10=0

3y(y + 5) + 2(y + 5)=0

(3y + 2) (y + 5)=0

Y=-2/3, -5

3) Answer: e)

x2 + 29x + 208=0

x2 + 13x + 16x + 208=0

x(x + 13) + 16(x + 13)=0

(x + 16) (x + 13)=0

X=-16, -13

y2 + 27y + 176=0

y2 + 11y + 16y + 176=0

y(y + 11) + 16(y + 11)=0

(y + 16) (y + 11)=0

Y=-16, -11

4) Answer: d)

x2 + 22x + 112=0

x2 + 14x + 8x + 112=0

x(x + 14) + 8(x + 14)=0

(x + 8) (x + 14)=0

X=-8, -14

y2 + 15y + 56=0

y2 + 8y + 7y + 56=0

y(y + 8) + 7(y + 8)=0

(y + 7) (y + 8)=0

Y=-7, -8

5) Answer: c)

2x2 + 14x + 12=0

2x2 + 12x + 2x + 12=0

2x(x + 6) + 2(x + 6)=0

(2x + 2) (x + 6)=0

X=-2, -6

y2 – 18y + 65=0

y2 –13y – 5y + 65=0

y(y – 13) – 5(y – 13)=0

(y – 5)(y – 13)=0

Y=5, 13

Directions  (6 – 10):

6) Answer: b)

Total CSE students=300 + 600 + 504 + 400 + 600=2404

Total students in E=2000

Difference=2404 – 2000=404

7) Answer: c)

Average=(540 + 375 + 720 + 350 + 400)/5=477

8) Answer: b)

Required percentage = 250/1000 * 100=25%

9) Answer: d)

Required ratio=(360 + 525) : 1500

=885:1500=177:300=59:100

10) Answer: c)

Average=576 + 375 + 600/3=517

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