Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for IBPS Clerk Prelims 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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Question 1 of 10
1. Question
Data Interpretation
Directions (1 – 6): Study the following information carefully and answer the questions given below.
The given table shows the number of students in four different colleges in four different departments.
If the ratio of the number of students of CSE from A to C is 21:32, find the number of ME students from C?
Correct
Answer: a)
Total number of CSE students =2000
Number of CSE students from A and C = 2000 â€“ 580 â€“ 360 = 1060
Number of CSE students from C = 32/53 * 1060 = 640
Number of ME students from C = 2000 â€“ 640 â€“ 540 â€“ 440 = 380
Incorrect
Answer: a)
Total number of CSE students =2000
Number of CSE students from A and C = 2000 â€“ 580 â€“ 360 = 1060
Number of CSE students from C = 32/53 * 1060 = 640
Number of ME students from C = 2000 â€“ 640 â€“ 540 â€“ 440 = 380
Question 2 of 10
2. Question
Data Interpretation
Directions (1 – 6): Study the following information carefully and answer the questions given below.
The given table shows the number of students in four different colleges in four different departments.
Total number of EEE students from all the colleges together is 1900, then what is the number of ME students from B?
Correct
Answer: d)
Number of EEE students from B = 1900 â€“ 440 â€“ 540 â€“ 560 = 360
Number of ME students from B = 1700 â€“ 580 â€“ 360 â€“ 280 = 480
Incorrect
Answer: d)
Number of EEE students from B = 1900 â€“ 440 â€“ 540 â€“ 560 = 360
Number of ME students from B = 1700 â€“ 580 â€“ 360 â€“ 280 = 480
Question 3 of 10
3. Question
Data Interpretation
Directions (1 – 6): Study the following information carefully and answer the questions given below.
The given table shows the number of students in four different colleges in four different departments.
If the ratio of the number of ME students from B to C is 24: 19, what is the number of CSE students from C?
Correct
Answer: e)
Number of ME students from B and C = 2000 â€“ 680 â€“ 460 = 860
Number of ME students from C = 19/43 * 860 = 380
Number of CSE students from C = 2000 â€“ 540 â€“ 440 â€“ 380 = 640
Incorrect
Answer: e)
Number of ME students from B and C = 2000 â€“ 680 â€“ 460 = 860
Number of ME students from C = 19/43 * 860 = 380
Number of CSE students from C = 2000 â€“ 540 â€“ 440 â€“ 380 = 640
Question 4 of 10
4. Question
Data Interpretation
Directions (1 – 6): Study the following information carefully and answer the questions given below.
The given table shows the number of students in four different colleges in four different departments.
If the total number of students from A is equal to the total number of ME students from all the colleges together. The number of ECE students from C is approximately what percent of the total number of students from A all the departments together?
Correct
Answer: c)
Required percentage = 440/2000 * 100 = 22%
Incorrect
Answer: c)
Required percentage = 440/2000 * 100 = 22%
Question 5 of 10
5. Question
Data Interpretation
Directions (1 – 6): Study the following information carefully and answer the questions given below.
The given table shows the number of students in four different colleges in four different departments.
If the average number of ECE students from all the colleges together is 430 and the number of ECE students from D is equal to the number of ME students from A. What is the ratio of the number of ECE students from A to the number of CSE students from D?
Correct
Answer: b)
Total number of ECE students = 430 * 4 = 1720
Number of ECE students from D = 680
Number of ECE students from A = 1720 â€“ 280 â€“ 440 â€“ 680 = 320
Required ratio = 320: 360 = 8: 9
Incorrect
Answer: b)
Total number of ECE students = 430 * 4 = 1720
Number of ECE students from D = 680
Number of ECE students from A = 1720 â€“ 280 â€“ 440 â€“ 680 = 320
Required ratio = 320: 360 = 8: 9
Question 6 of 10
6. Question
Data Interpretation
Directions (1 – 6): Study the following information carefully and answer the questions given below.
The given table shows the number of students in four different colleges in four different departments.
What is the difference between the number of EEE and ME students from B together and the number of CSE and ME students from C together?
Correct
Answer: a)
Number of EEE and ME students from B = 1700 â€“ 580 â€“ 280 = 840
Number of CSE and ME students from C = 2000 â€“ 540 â€“ 440 = 1020
Difference = 1020 â€“ 840 = 180
Incorrect
Answer: a)
Number of EEE and ME students from B = 1700 â€“ 580 â€“ 280 = 840
Number of CSE and ME students from C = 2000 â€“ 540 â€“ 440 = 1020
Difference = 1020 â€“ 840 = 180
Question 7 of 10
7. Question
Missing number series
Directions (7 – 10): What value should come in the place of (?) in the following number series?
4, 6, 18, 66, 284, ?
Correct
Answer: d)
(4 + 2) * 1 = 6
(6 + 3) * 2 = 18
(18 + 4) * 3 = 66
(66 + 5) * 4 = 284
(284 + 6) * 5 = 1450
Incorrect
Answer: d)
(4 + 2) * 1 = 6
(6 + 3) * 2 = 18
(18 + 4) * 3 = 66
(66 + 5) * 4 = 284
(284 + 6) * 5 = 1450
Question 8 of 10
8. Question
Missing number series
Directions (7 – 10): What value should come in the place of (?) in the following number series?
12, 22, 38, ?, 101.5, 160.25
Correct
Answer: a)
12 * 1.5 + 4 = 22
22 * 1.5 + 5 = 38
38 * 1.5 + 6 = 63
63 * 1.5 + 7 = 101.5
101.5 * 1.5 + 8 = 160.25
Incorrect
Answer: a)
12 * 1.5 + 4 = 22
22 * 1.5 + 5 = 38
38 * 1.5 + 6 = 63
63 * 1.5 + 7 = 101.5
101.5 * 1.5 + 8 = 160.25
Question 9 of 10
9. Question
Missing number series
Directions (7 – 10): What value should come in the place of (?) in the following number series?
18, 54, 79, 95, 104, ?
Correct
Answer: c)
18 + 6^{2} = 54
54 + 5^{2} = 79
79 + 4^{2} = 95
95 + 3^{2} = 104
104 + 2^{2} = 108
Incorrect
Answer: c)
18 + 6^{2} = 54
54 + 5^{2} = 79
79 + 4^{2} = 95
95 + 3^{2} = 104
104 + 2^{2} = 108
Question 10 of 10
10. Question
Missing number series
Directions (7 – 10): What value should come in the place of (?) in the following number series?
995, 723, 505, 335, 207, ?
Correct
Answer: d)
10^{3} â€“ 5 = 995
9^{3} â€“ 6 = 723
8^{3} â€“ 7 = 505
7^{3} â€“ 8 = 335
6^{3} â€“ 9 = 207
5^{3} â€“ 10 = 115
Incorrect
Answer: d)
10^{3} â€“ 5 = 995
9^{3} â€“ 6 = 723
8^{3} â€“ 7 = 505
7^{3} â€“ 8 = 335
6^{3} â€“ 9 = 207
5^{3} â€“ 10 = 115
Data Interpretation
Directions (1 – 6): Study the following information carefully and answer the questions given below.
The given table shows the number of students in four different colleges in four different departments.
1) If the ratio of the number of students of CSE from A to C is 21:32, find the number of ME students from C?
a) 380
b) 360
c) 340
d) 320
e) None of these
2) Total number of EEE students from all the colleges together is 1900, then what is the number of ME students from B?
a) 420
b) 460
c) 440
d) 480
e) None of these
3) If the ratio of the number of ME students from B to C is 24: 19, what is the number of CSE students from C?
a) 580
b) 600
c) 620
d) 660
e) None of these
4) If the total number of students from A is equal to the total number of ME students from all the colleges together. The number of ECE students from C is approximately what percent of the total number of students from A all the departments together?
a) 18%
b) 20%
c) 22%
d) 24%
e) None of these
5) If the average number of ECE students from all the colleges together is 430 and the number of ECE students from D is equal to the number of ME students from A. What is the ratio of the number of ECE students from A to the number of CSE students from D?
a) 7: 8
b) 8: 9
c) 5: 6
d) 4: 3
e) None of these
6) What is the difference between the number of EEE and ME students from B together and the number of CSE and ME students from C together?
a) 180
b) 200
c) 220
d) 140
e) 160
Missing number series
Directions (7 – 10): What value should come in the place of (?) in the following number series?
7) 4, 6, 18, 66, 284, ?
a) 360
b) 972
c) 1280
d) 1450
e) 1620
8) 12, 22, 38, ?, 101.5, 160.25
a) 63
b) 65
c) 67
d) 69
e) 71
9) 18, 54, 79, 95, 104, ?
a) 110
b) 106
c) 108
d) 112
e) 114
10) 995, 723, 505, 335, 207, ?
a) 100
b) 105
c) 110
d) 115
e) 120
Answers :
Directions (1-6) :
1) Answer: a)
Total number of CSE students =2000
Number of CSE students from A and C = 2000 â€“ 580 â€“ 360 = 1060
Number of CSE students from C = 32/53 * 1060 = 640
Number of ME students from C = 2000 â€“ 640 â€“ 540 â€“ 440 = 380
2) Answer: d)
Number of EEE students from B = 1900 â€“ 440 â€“ 540 â€“ 560 = 360
Number of ME students from B = 1700 â€“ 580 â€“ 360 â€“ 280 = 480
3) Answer: e)
Number of ME students from B and C = 2000 â€“ 680 â€“ 460 = 860
Number of ME students from C = 19/43 * 860 = 380
Number of CSE students from C = 2000 â€“ 540 â€“ 440 â€“ 380 = 640
4) Answer: c)
Required percentage = 440/2000 * 100 = 22%
5) Answer: b)
Total number of ECE students = 430 * 4 = 1720
Number of ECE students from D = 680
Number of ECE students from A = 1720 â€“ 280 â€“ 440 â€“ 680 = 320
Required ratio = 320: 360 = 8: 9
6) Answer: a)
Number of EEE and ME students from B = 1700 â€“ 580 â€“ 280 = 840
Number of CSE and ME students from C = 2000 â€“ 540 â€“ 440 = 1020
Difference = 1020 â€“ 840 = 180
Directions (7-10) :
7) Answer: d)
(4 + 2) * 1 = 6
(6 + 3) * 2 = 18
(18 + 4) * 3 = 66
(66 + 5) * 4 = 284
(284 + 6) * 5 = 1450
8) Answer: a)
12 * 1.5 + 4 = 22
22 * 1.5 + 5 = 38
38 * 1.5 + 6 = 63
63 * 1.5 + 7 = 101.5
101.5 * 1.5 + 8 = 160.25
9) Answer: c)
18 + 6^{2} = 54
54 + 5^{2} = 79
79 + 4^{2} = 95
95 + 3^{2} = 104
104 + 2^{2} = 108
10) Answer: d)
10^{3} â€“ 5 = 995
9^{3} â€“ 6 = 723
8^{3} â€“ 7 = 505
7^{3} â€“ 8 = 335
6^{3} â€“ 9 = 207
5^{3} â€“ 10 = 115
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