Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for IBPS Clerk Prelims 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
Are You preparing for Bank exams 2019? Start your preparation with Free Mock test Series.
Directions (Q. 1 – 5): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x â‰¥ y
c) If x < y
d) If x â‰¤ y
e) If x = y or no relation can be established between x and y
1) I) x = âˆš(12875 – 3271)
II) y = âˆ›474552
2) I) x^{2} – 6x â€“ 72 = 0
II) y^{2} + 3y â€“ 88 = 0
3) I) 3x^{2 }+ 26x + 56 = 0
II) 2y^{2} + 15y + 28 = 0
4) I) 4x â€“ 5y = -12
II) 3x + 4y = 53
5) I) x^{2 }â€“ 17x + 52 = 0
II) y^{2}-5y â€“ 66 = 0
Data interpretation
Directions (Q. 6 â€“ 10) Study the following information carefully and answer the given questions.
The following table shows the total number of tyres (In lakhs) manufactured by 5 different companies in a certain year.
6) Total number of tyres rejected by the company P is approximately what percentage more/less than the total number of tyres rejected by the company T?
a) 7 % less
b) 15 % more
c) 15 % less
d) 24 % more
e) 7 % more
7) Find the average number of tyres manufactured by all the given companies together?
a) 32.4 lakhs
b) 28.5 lakhs
c) 30.8 lakhs
d) 34.6 lakhs
e) None of these
8) Find the difference between the total number of tyres sold by the company Q to that of company S?
a) 792600
b) 756800
c) 833200
d) 809270
e) None of these
9) Find the ratio between the total number of tyres rejected by the company Q to that of R?
a) 72: 55
b) 53: 115
c) 84: 137
d) 65: 96
e) None of these
10) Total number of tyres sold by the company P is approximately what percentage of total number of tyres sold by the company R?
a) 60 %
b) 75 %
c) 50 %
d) 85 %
e) 105 %
Answers:
Directions (1-5):
1) Answer: a)
I) x = âˆš(12875 – 3271)
X = âˆš9604 = 98
II) y = âˆ›474552
Y = 78
X > y
2) Answer: e)
I) x^{2} – 6x â€“ 72 = 0
(x â€“ 12) (x + 6) = 0
X = 12, – 6
II) y^{2} + 3y â€“ 88 = 0
(y + 11) (y â€“ 8) = 0
Y = -11, 8
Canâ€™t be determined
3) Answer: d)
I) 3x^{2 }+ 26x + 56 = 0
3x^{2 }+ 12x + 14x + 56 = 0
3x(x + 4) + 14(x + 4) = 0
(3x + 14) (x + 4) = 0
X = -14/3, -4 = -4.667, -4
II) 2y^{2} + 15y + 28 = 0
2y^{2} + 8y + 7y + 28 = 0
2y(y + 4) + 7 (y + 4) = 0
(2y + 7) (y + 4) = 0
Y = -7/2, -4 = -3.5, -4
X â‰¤ y
4) Answer: c)
4x â€“ 5y = -12 –> (1)
3x + 4y = 53 –> (2)
By solving the equation (1) and (2), we get,
X = 7, y = 8
X < y
5) Answer: e)
I) x^{2 }â€“ 17x + 52 = 0
(x -14) (x â€“ 3) = 0
X = 14, 3
II) y^{2 }– 5y â€“ 66 = 0
(y – 11) (y + 6) = 0
Y = 11, -6
Canâ€™t be determined
Directions (6-10):
6) Answer: e)
Total number of tyres rejected by the company P
= > 3200000*(2/100) = 64000
Total number of tyres rejected by the company T
= > 4000000*(1.5/100) = 60000
Required % = [(64000 â€“ 60000)/60000]*100 = 7 % more
7) Answer: a)
The average number of tyres manufactured by all the given companies together