# Crack SBI Clerk Prelims 2018 Sectional Full Test (Quantitative Aptitude) Day-11

Dear Readers, SBI Clerk (Junior Associates) 2018 Preliminary Examinationย is scheduledย to be held on 23rd, 24th, and 30th of June 2018. In that case, aspirants need to speed up the preparation as there are only few days more.

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#### Minimum Cut Off for this Quantitative Aptitude Section Test is: 20

Sectional Full Test (Quantitative Aptitude) Day-11

maximum of 35 points

Click โStart Quizโ to attend these Questions and view Solutions

Directions (1-5) Study the following information carefully and answer the given questions:

Following table shows the percentage distribution of total number of students who completed their graduation from different universities and the ratio of male to female among them.

Total number of students = 56000

 University Total number ofย  students Male : Female P 23 % 7 : 3 Q 18 % 5 : 4 R 12 % 2 : 1 S 27 % 3 : 5 T 20 % 2 : 3
1. Find the total number of male graduates from the given universities together?
1. 29246
2. 25782
3. 33567
4. 37895
5. None of these
1. Total number of female graduates from university Q and R is approximately what percentage of total number of male graduates from university P and T?
1. 32 %
2. 44 %
3. 68 %
4. 50 %
5. 36 %
1. Find the ratio between the total number of male graduates from university Q, R and T together to that of female graduates from university P, R and S together?
1. 8576 : 7115
2. 9254 : 8471
3. 7280 : 7777
4. 5890 : 4783
5. None of these
1. Total number of graduates from university P and Q together is approximately what percentage more/less than the total number of graduates from university R and S together?
1. 8 % less
2. 5 % more
3. 12 % more
4. 15 % less
5. 18 % more
1. In which university, the highest number of female graduates completed their graduation?
1. University P
2. University Q
3. University R
4. University S
5. University T

6) In a class, 40 boys and their average age is five-sixth of the number of girls in that class and 30 girls and their average age is half of the number of boys in that class. Find the overall average in the class (Approximately)

1. 25 yrs
2. 23 yrs
3. 27 yrs
4. 20 yrs
5. 29 yrs
1. A man can row 40 km along the stream in 2.5 hours and against the stream in two times of the number of hours taken to along the stream. Find the speed of boat and speed of current
1. 12 km/hr, 6 km/hr
2. 12 km/hr, 4 km/hr
3. 8 km/hr, 4 km/hr
4. 9 km/hr, 15 km/hr
5. 12 km/hr, 8 km/hr
1. A alone can build up a wall in 20 days and B alone can break down the same wall in 5 days more than A. A is two times more efficient as C (build up). A, B and C together can build the wall in how many days?
1. 26 4/5
2. 24 3/4
3. 28 4/7
4. 25 5/7
5. 28 5/7
1. A vessel contains milk and water in which 20% water. 20 litres of mixture replaced by water and the ratio becomes 12:13. Find the initial quantity of milk in the vessel
1. 40 litres
2. 30 litres
3. 50 litres
4. 56 litres
5. 60 litres
1. Shamili and Kamal enter into a business. Shamili invest Rs. 4000 and Kamal invest โxโ amount more than Shamiliโs investment, after 4 months Mani joins with Rs. (x+6000). Find the total profit if Shamili and Kamal received Rs.2400 and Rs.3600 respectively
1. Rs.8400
2. Rs.9200
3. Rs.7800
4. Rs.7600
5. Rs.9400

Directions (11 โ 15) Study the following information carefully and answer the given questions:

Following line graph shows the % profit of two companies A and B in different years.

Profit % = [(Income โ Expenditure)/Expenditure]*100

ย

1. If the expenditure of Company A in the year 2012 is 32 lakhs and the income of Company B in the year 2014 is 13 lakhs more than the expenditure of company A in the year 2012, then the income of company A in 2012 is approximately what percentage of the expenditure of company B in the year 2014?
1. 112 %
2. 94 %
3. 100 %
4. 88 %
5. 124 %
1. If the expenditure of company A in the year 2013 and the expenditure of company B in the year 2015 is same and the income of company A in the year 2013 is 44.25 lakhs, then find the income of company B in the year 2015?
1. 63 lakhs
2. 51 lakhs
3. 47 lakhs
4. 39 lakhs
5. None of these
1. If the income of company A and B in the year 2014 is same, then the ratio of expenditure of company A and B in the year 2014 is?
1. 24 : 25
2. 16 : 23
3. 31 : 39
4. 8 : 11
5. None of these
1. If the income of company B in the year 2016 is 37.8 lakhs and the expenditure of company A in the year 2015 is 27 lakhs, then the expenditure of company B in the year 2016 is approximately what percentage more/less than the income of company A in the year 2015?
1. 24 % more
2. 32 % more
3. 8 % less
4. 13 % less
5. 18 % more
1. If the expenditure of company A and B in the year 2015 is 27 lakhs and 33 lakhs respectively, then find the difference between the income of company A and B in the year 2015?
1. 11.44 lakhs
2. 15.78 lakhs
3. 10.32 lakhs
4. 18.15 lakhs
5. None of these
1. Pipe P takes x hours to fill an empty tank. Pipe Q takes (x+10) hours to fill the same tank and R takes 10 hours to fill the same tank. All the pipes are opened simultaneously and fill 5 5/11 hours, then find the efficiency ratio of P and Q
1. 2:3
2. 1:2
3. 2:1
4. 3:2
5. 1:3
1. A basket contains x black, 4 red and 5 green colour balls. One ball is taken randomly and the probability of getting a green colour ball is 1/3, and then finds the no. of balls in the basket
1. 12
2. 14
3. 15
4. 18
5. 20
1. Arun earned a profit of 10% after allowing discount of 20%. Marked price is what percent more than the cost price?
1. 32.5%
2. 30.5%
3. 37.5%
4. 42.5%
5. 28.5%
1. Ramu invested Rs.x amount at the rate of 20% per annum compounded annually. After one year, he withdraws Rs.2500 and the rate of interest is reduced by 15%. Find the value of โxโ if he received Rs.735 less at the end of two years
1. Rs.3500
2. Rs.5000
3. Rs.4000
4. Rs.4500
5. Rs.6000
1. Arun alone can do a piece of work in x days and Shaalu alone can do the same work in x+5 days. If Arun and Shaalu together can complete the same work in 11 1/9 days, then find the number of days completed by Arun alone
1. 25
2. 15
3. 10
4. 20
5. 24

Directions (21 – 25): What value should come in place of question mark (?) in the following number series?

1. 32, 17, 18, 38,?
1. 96
2. 124
3. 156
4. 132
5. 112
1. 72, 96, 185, 356, 628,?
1. 926
2. 1022
3. 854
4. 1328
5. 948
1. 27, 30, 42, 69, ?
1. 85
2. 91
3. 133
4. 117
5. 124
1. 729, 1018, 657, 1098, ?
1. 569
2. 437
3. 603
4. 495
5. 645
1. 390, 196, 99, 50.5, ?
1. 32.25
2. 26.25
3. 21.75
4. 38.75
5. None of these

Directions (26 – 30): What value should come in place of question mark (?) in the following questions?

1. 23 ร 2 ร (45 โ 15) + 168 รท 4 โ (15)2 =?
1. 928
2. 845
3. 1197
4. 1036
5. None of these
1. (6246 รท 18) ร 40 = x รท 15 ร 60
1. 3470
2. 2890
3. 1280
4. 2460
5. None of these
1. 20 % of 1540 + 14 % of 1050 = 20 % of x + 192
1. 380
2. 650
3. 530
4. 470
5. None of these
1. 378 รท 9 + 124 รท 8 + 1460 ร 1.25 =? + 20 % of 500
1. 1782.5
2. 2197.75
3. 3695.75
4. 4343.25
5. None of these
1. ((156 รท 13 + 17 ร 42) / (32 + 7)) =?
1. 36 2/5
2. 28 ยพ
3. 17 5/7
4. 45 3/8
5. None of these

Directions (31-35): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer

1. if x > y
2. if x โฅ y
3. if x < y
4. if x โค y
5. if x = y or no relation can be established between x and y
1. I. 10x2 -17x +7 =0

II. 15y2 -19y +6 =0

1. I. 12x2 +19x +5 =0

II. 5y2 + 16y +3 =0ย

1. I. 6x2 + 31x + 35 =0

II. 2y2 + 3y + 1=0

1. I. X2 โ 264 = 361

II. y3 โ 878 = 453

1. I. 4x2โ 30x +56 =0

II. y2 โ 7y+12 =0

Directions (1-5):

 University Total number ofย  students Male Female P 12880 9016 3864 Q 10080 5600 4480 R 6720 4480 2240 S 15120 5670 9450 T 11200 4480 6720

ย

The total number of male graduates from the given universities together

= > 9016 + 5600 + 4480 + 5670 + 4480

= > 29246

Total number of female graduates from university Q and R

= > 4480 + 2240 = 6720

Total number of male graduates from university P and T

= > 9016 + 4480 = 13496

Required % = (6720/13496)*100 = 49.79 % = 50 %

The total number of male graduates from university Q, R and T together

= > 5600 + 4480 + 4480 = 14560

The total number of female graduates from university P, R and S together

= > 3864 + 2240 + 9450 = 15554

Required ratio = 14560: 15554 = 7280: 7777

Required % = {[(23+ 18) โ (12 + 27)]/(12 + 27)}*100

= > {(41 โ 39)/39}*100 = 5.128 % = 5 % more

University S has highest number of female graduates.

Required average = ((40*25) + (30*20))/70=1600/70=23 years

Let us take speed of current and speed of boat be x and y

Given,

Upstream speed = 40/5=8 km/hr

Downstream speed = 40/2.5=16 km/hr

Speed of boat = (16+8)/2=12 km/hr

Speed of current = (16-8)/2=4 km/hr

No of days taken by B = 25 days

No of days taken by C = 20/1*2 = 40 days

=>1/20+1/40-1/25

=>(15-8)/200=200/7 = 28 4/7 days

Milk and water ratio = 4:1

Given,

(4x-16)/(x-4+20) =12/13

52x-208=12x+192

=>40x=400=>x=10

Shamili and Kamalโs profit ratio = (4000ร12):((4000+x)ร12)=2400:3600

=>4000/(4000+x)=2/3

=>x=2000

Profit ratio = (4000ร12):(6000ร12):(8000ร8)

=>6:9:8

Total profit = 2400/6ร23=Rs.9200

Direction (11-15)ย  ย

The expenditure of Company A in the year 2012 = 32 lakhs

The income of Company B in the year 2014 = 13 + 32 = 45 lakhs

The income of company A in 2012

= > 16 = [(I โ 32)/32]*100

= > 512 + 3200 = 100I

= > I = 3712/100 = 37.12 lakhs

The expenditure of Company B in the year 2014

= > 20 = [45 โ e)/e]*100

= > 20e = 4500 โ 100e

= > 120e = 4500

= > e = (4500/120) = 37.5 lakhs

Required % = (37.12/37.5)*100 = 98.98 % = 100 %

The income of company A in the year 2013 = 44.25 lakhs

The expenditure of company A in the year 2013

= > 18 = [(44.25 โ e)/e]*100

= > 118e = 4425

= > e = (4425/118) = 37.5 lakhs

The expenditure of company A in the year 2013 = The expenditure of company B in the year 2015

The expenditure of company B in the year 2015 = 37.5 lakhs

The income of company B in the year 2015

= > 36 = [(I โ 37.5)/37.5]*100

= > 1350 = 100I โ 3750

5100 = 100I

I = 51 lakhs

Let the income of company A and B in the year 2014 be x,

The expenditure of company A in the year 2014

= > 25 = [(x โ E1)/E1]*100

= > 125E1 = 100x

= > E1 = (100x/125) = (4x/5)

The expenditure of company B in the year 2014

= > 20 = [(I โ E2)/E2]*100

= > 120E2 = 100x

= > E2 = (100x/120) = (5x/6)

Required ratio

= > (4x/5): (5x/6)

= > 24: 25

The income of company B in the year 2016 = 37.8 lakhs

The expenditure of company B in the year 2016

= > 26 = [(37.8 โ e)/e]*100

= > 126e = 3780

= > e = (3780/126) = 30 lakhs

The expenditure of company A in the year 2015 = 27 lakhs

The income of company A in the year 2015

= > 28 = [(I โ 27)/27]*100

= > 756 = 100I โ 2700

= > 3456 = 100I

= > I = 34.56 lakhs

Required % = [(34.56- 30)/34.56]*100 = 13.19 % = 13 % less

The expenditure of company A in the year 2015 = 27 lakhs

The income of company A in the year 2015

= > 28 = [(I โ 27)/27]*100

= > 756 = 100I โ 2700

= > 3456 = 100I

= > I = 34.56 lakhs

The expenditure of company B in the year 2015 = 33 lakhs

The income of company B in the year 2015

= > 36 = [(I โ 33)/33]*100

= > 1188 = 100I โ 3300

= > I = (4488/100) = 44.88 lakhs

Required difference = 44.88 โ 34.56 = 10.32 lakhs

Given,

1/x+1/(x+10)+1/10=11/60

(2x+10)/(x2+10x)=5/60

X2-14x-120=0

X=20

Required ratio = 1/20:1/30=3:2

Given,

Total no. of probability = 9+x

Required probability = 5/(9+x)=1/3

=>9+x=15=>x=6

Let us take CP be Rs.100

SP= 110 =80% of marked price

MP = 110/80*100=137.5

Required percentage = 37.5/100*100=37.5%

Given,

44/100*x-735=x*20/100+(x-2500)*15/100

9x=36000=>x=4000

1/x+1/(x+5)=9/100

Simplify the above equation we get x=20 days

Direction (21-25)

The pattern is, *0.5 + 1, *1 + 1, *2 + 2, *4 + 4…

The difference of difference is, 82 + 1, 92 + 1, 102 + 1, 112 + 1

The pattern is, +(1*3), +(2*6), +(3*9), +(4*12),..

The pattern is, +172, -192, +212, -232,..

The pattern is, รท 2 + 1

Direction (26-30)

23 ร 2 ร 30 + 42 โ 225 = x

X = 1380 + 42 โ 225

X = 1197

(6246/18)*40 = (x/15)*60

X = (6246/18)*40 * (60/15)

X = 3470

(20/100)*1540 + (14/100)*1050 = (20/100)* x + 361

308 + 147 โ 361 = (x/5)

94 = (x/5)

X = 470

(378/9) + (124/8) + 1460*(5/4) = x + (20/100)*500

42 + 15.5 + 1825 โ 100 = x

X = 1782.5

((156/13) + (17*42)) / (9 + 7) = x

X = (12 + 714) / 16

X = 726 /16

X = 45 3/8

Direction (31-35)

I. 10x2 -17x +7 =0

10x2 -10x-7x +7 =0

10x(x-1) -7(x-1) =0

(10x-7) (x-1) =0

X= 7/10, 1

II. 15y2 -19y +6 =0

15y2 -10y-9y +6 =0

5y(3y-2)-3 (3y-2) =0

(5y-3) (3y-2) =0

Y= 3/5, 2/3

x>y

I. 12x2 +19x +5 =0

12x2 +4x +15x +5 =0

4x(3x+1)+5 (3x+1) =0

(4x+5)(3x+1) =0

X=-5/4, -1/3

II. 5y2 + 16y +3 =0

5y2 + y+15y +3 =0

Y(5y+1)+3 (5y+1) =0

(y+3) (5y+1) =0

Y=-3, -1/5

Canโt be determined

I. 6x2 + 31x + 35 =0

6x2 + 21x+10x + 35 =0

3x(2x+7)+5 (2x+7)=0

(3x+5)(2x+7) =0

X= -5/3, -7/2

II. 2y2 + 3y + 1=0

2y2 + 2y +y+ 1=0

2y(y+1) +1(y+1) =0

(2y+1) (y+1) =0

Y= -1/2, -1

X<y

I. X2 โ 264 = 361

X2 = 361+264

X2 = 625

X= 25, -25

II. y3 โ 878 = 453

Y3 = 453 + 878

Y3 = 1331

Y =11

Canโt be determined

I. 4x2โ 30x +56 =0

4x2โ 16x-14x +56 =0

4x(x-4) -14(x-4) =0

(4x-14) (x-4) =0

X= 14/4, 4= 7/2, 4

II. y2 โ 7y+12 =0

y2 โ 4y-3y+12 =0

y(y-4)-3 (y-4) =0

(y-3) (y-4) =0

Y =3, 4

Canโt be determined

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