SSC CGL 2018 Practice Test Papers | Quantitative Aptitude (Day-12)
Dear Aspirants, Here we have given the Important SSC CGL Exam 2018 Practice Test Papers. Candidates those who are preparing for SSC CGL 2018 can practice these questions to get more confidence to Crack SSC CGL 2018 Examination.
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Question 1 of 10
1. Question
The length of two parallel sides of a trapezium is 15 cm and 25 cm. If its area is 200 sq. cm, then its height is:
Correct
Answer: a.
Area of trapezium = Sum of length of parallel sides/2 x Height (H)
200 = ( 15 +25) /2 ×H
H = 200 x 2 /35= 10cm.
Incorrect
Answer: a.
Area of trapezium = Sum of length of parallel sides/2 x Height (H)
200 = ( 15 +25) /2 ×H
H = 200 x 2 /35= 10cm.
Question 2 of 10
2. Question
In a match, average of runs scored by 5 players is 49. If the runs scored by four players are 75, 30, 62 and 21 respectively, then how many runs did the 5^{th} player had scored?
Correct
Answer: c.
Total runs scored by 5 players = (49 × 5) = 245
Total runs scored by 4 players = (75 + 30 + 62 + 21) = 188
Total runs did the 5^{th} player had scored = (245 – 188) = 57.
Incorrect
Answer: c.
Total runs scored by 5 players = (49 × 5) = 245
Total runs scored by 4 players = (75 + 30 + 62 + 21) = 188
Total runs did the 5^{th} player had scored = (245 – 188) = 57.
Question 3 of 10
3. Question
Three friends A, B, and C invest in a business such that A invests 1/5 th of total and B invest ½ of the total. What is the ratio of profit of A, B and C respectively?
Correct
Answer: d.
Let total investment = x
Investment by A= x/ 5
Investment by B =x/ 2
Investment by C =x- (x/5 +x/2) =3x /10
Ratio of invest of A, B and C= x/5: x/2: 3x/10 = 2 :5: 3
Ratio of profit of A, B and C = 2: 5: 3
Incorrect
Answer: d.
Let total investment = x
Investment by A= x/ 5
Investment by B =x/ 2
Investment by C =x- (x/5 +x/2) =3x /10
Ratio of invest of A, B and C= x/5: x/2: 3x/10 = 2 :5: 3
Ratio of profit of A, B and C = 2: 5: 3
Question 4 of 10
4. Question
If x * y = (x + 3)^{2} (y –1), then the value of 5 * 4 is
Correct
Answer: a.
x * y = (x + 3)^{2} (y – 1)
5 * 4 = (5 + 3)^{2} (4 – 1) = 64 × 3 = 192
Incorrect
Answer: a.
x * y = (x + 3)^{2} (y – 1)
5 * 4 = (5 + 3)^{2} (4 – 1) = 64 × 3 = 192
Question 5 of 10
5. Question
A can do a piece of work in 20 days which B can do in 12 days. B worked for 9 days. A can finish the remaining work in___________
Correct
Answer: a.
B’s 1 day work = 1 /12
B’s 9 day’s work = 9 /12 =3/4
Remaining work =1- 3 /4=1/ 4
Incorrect
Answer: a.
B’s 1 day work = 1 /12
B’s 9 day’s work = 9 /12 =3/4
Remaining work =1- 3 /4=1/ 4
Question 6 of 10
6. Question
In a school, school pupil leader collected money Rs.11664 for a famine fund, each student has given as many rupees as the total number of students. . The number of students was:
Correct
Answer: c.
Contribution of each boy = Number of boys
Total contribution raised = Rs. 11664
So, number of boys = √11664 = 108
Incorrect
Answer: c.
Contribution of each boy = Number of boys
Total contribution raised = Rs. 11664
So, number of boys = √11664 = 108
Question 7 of 10
7. Question
What is the average of the squares of the first 19 natural numbers?
Correct
Answer: c.
Sum of square of first n natural numbers= n (n+1)2n+1)/6
Average of Sum of square of first n natural numbers= n (n+1)2n+1)/6n
=19(19+1) (2×19+1)/(6×19)
=20×39/6 =130
Incorrect
Answer: c.
Sum of square of first n natural numbers= n (n+1)2n+1)/6
Average of Sum of square of first n natural numbers= n (n+1)2n+1)/6n
=19(19+1) (2×19+1)/(6×19)
=20×39/6 =130
Question 8 of 10
8. Question
A’s income is 50% less than B’s income, what is B’s income if the sum of A and B income is Rs. 4500?
Correct
Answer: b.
Let Income of A= x, Income of B= 2x
X+2x= 4500
X=1500
Income of B= 2x=2×1500=3000
Incorrect
Answer: b.
Let Income of A= x, Income of B= 2x
X+2x= 4500
X=1500
Income of B= 2x=2×1500=3000
Question 9 of 10
9. Question
The ratio of cost price and selling price of an article is 10: 11, find the profit if 10% of the Selling price is 330.
Correct
Answer: b.
10% of SP=330
SP=3300
CP=3300/11×10=3000
Profit= 3300-3000=300
Incorrect
Answer: b.
10% of SP=330
SP=3300
CP=3300/11×10=3000
Profit= 3300-3000=300
Question 10 of 10
10. Question
20% of 75% of 4260=x. Find the value of x.
Correct
Answer: a
20% of 75% of 4260=639
Incorrect
Answer: a
20% of 75% of 4260=639
Click “Start Quiz” to attend these Questions and view Explanation
1). The length of two parallel sides of a trapezium is 15 cm and 25 cm. If its area is 200 sq. cm, then its height is:
10 cm
15 cm
25 cm
20 cm
2). In a match, average of runs scored by 5 players is 49. If the runs scored by four players are 75, 30, 62 and 21 respectively, then how many runs did the 5^{th} player had scored?
43
49
57
89
3). Three friends A, B, and C invest in a business such that A invests 1/5 th of total and B invest ½ of the total. What is the ratio of profit of A, B and C respectively?
16: 15: 9
16: 15: 31
2: 3: 5
2:5: 3
4). If x * y = (x + 3)^{2} (y –1), then the value of 5 * 4 is
192
182
2
356
5). A can do a piece of work in 20 days which B can do in 12 days. B worked for 9 days. A can finish the remaining work in___________
5 days
7 days
11 days
3 days
6). In a school, school pupil leader collected money Rs.11664 for a famine fund, each student has given as many rupees as the total number of students. . The number of students was:
122
132
112
102
7). What is the average of the squares of the first 19 natural numbers?
124
127.5
130
133.5
8). A’s income is 50% less than B’s income, what is B’s income if the sum of A and B income is Rs. 4500?
1250
3000
750
2500
9). The ratio of cost price and selling price of an article is 10: 11, find the profit if 10% of the Selling price is 330.
800
300
110
250
10.20% of 75% of 4260=x. Find the value of x.
639
379
579
859
Answers:
1). Answer: a.
Area of trapezium = Sum of length of parallel sides/2 x Height (H)
200 = ( 15 +25) /2 ×H
H = 200 x 2 /35= 10cm.
2). Answer: c.
Total runs scored by 5 players = (49 × 5) = 245
Total runs scored by 4 players = (75 + 30 + 62 + 21) = 188
Total runs did the 5^{th} player had scored = (245 – 188) = 57.
3). Answer: d.
Let total investment = x
Investment by A= x/ 5
Investment by B =x/ 2
Investment by C =x- (x/5 +x/2) =3x /10
Ratio of invest of A, B and C= x/5: x/2: 3x/10 = 2 :5: 3
Ratio of profit of A, B and C = 2: 5: 3
4). Answer: a.
x * y = (x + 3)^{2} (y – 1)
5 * 4 = (5 + 3)^{2} (4 – 1) = 64 × 3 = 192
5). Answer: a.
B’s 1 day work = 1 /12
B’s 9 day’s work = 9 /12 =3/4
Remaining work =1- 3 /4=1/ 4
6). Answer: c.
Contribution of each boy = Number of boys
Total contribution raised = Rs. 11664
So, number of boys = √11664 = 108
7). Answer: c.
Sum of square of first n natural numbers= n (n+1)2n+1)/6
Average of Sum of square of first n natural numbers= n (n+1)2n+1)/6n
=19(19+1) (2×19+1)/(6×19)
=20×39/6 =130
8). Answer: b.
Let Income of A= x, Income of B= 2x
X+2x= 4500
X=1500
Income of B= 2x=2×1500=3000
9). Answer: b.
10% of SP=330
SP=3300
CP=3300/11×10=3000
Profit= 3300-3000=300
10). Answer: a
20% of 75% of 4260=639
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