SSC CGL 2018 Practice Test Papers | Quantitative Aptitude (Day-12)

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SSC CGL 2018 | Quantitative Aptitude (Day-12)

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1). The length of two parallel sides of a trapezium is 15 cm and 25 cm. If its area is 200 sq. cm, then its height is:

  1. 10 cm
  2. 15 cm
  3. 25 cm
  4. 20 cm

2). In a match, average of runs scored by 5 players is 49. If the runs scored by four players are 75, 30, 62 and 21 respectively, then how many runs did the 5th player had scored?

  1. 43
  2. 49
  3. 57
  4. 89

3). Three friends A, B, and C invest in a business such that A invests 1/5 th of total and B invest ½ of the total. What is the ratio of profit of A, B and C respectively?

  1. 16: 15: 9
  2. 16: 15: 31
  3. 2: 3: 5
  4. 2:5: 3

4). If x * y = (x + 3)2 (y –1), then the value of 5 * 4 is

  1. 192
  2. 182
  3. 2
  4. 356

5). A can do a piece of work in 20 days which B can do in 12 days. B worked for 9 days. A can finish the remaining work in___________

  1. 5 days
  2. 7 days
  3. 11 days
  4. 3 days

6). In a school, school pupil leader collected money Rs.11664 for a famine fund, each student has given as many rupees as the total number of students. . The number of students was:

  1. 122
  2. 132
  3. 112
  4. 102

7). What is the average of the squares of the first 19 natural numbers?

  1. 124
  2. 127.5
  3. 130
  4. 133.5

8). A’s income is 50% less than B’s income, what is B’s income if the sum of A and B income is Rs. 4500?

  1. 1250
  2. 3000
  3. 750
  4. 2500

9). The ratio of cost price and selling price of an article is 10: 11, find the profit if 10% of the Selling price is 330.

  1. 800
  2. 300
  3. 110
  4. 250

10.20% of 75% of 4260=x. Find the value of x.

  1. 639
  2. 379
  3. 579
  4. 859

Answers:

1). Answer:  a.

Area of trapezium = Sum of length of parallel sides/2 x Height (H)

200 = ( 15 +25) /2  ×H

H = 200 x 2 /35= 10cm.

2). Answer: c.

Total runs scored by 5 players = (49 × 5) = 245

Total runs scored by 4 players = (75 + 30 + 62 + 21) = 188

Total runs did the 5th player had scored = (245 – 188) = 57.

3). Answer: d.

Let total investment = x

Investment by A= x/ 5

Investment by B =x/ 2

Investment by C =x- (x/5 +x/2) =3x /10

Ratio of invest of A, B and C= x/5: x/2: 3x/10 = 2 :5: 3

Ratio of profit of A, B and C = 2: 5: 3

4). Answer:  a.

x * y = (x + 3)2 (y – 1)

5 * 4 = (5 + 3)2 (4 – 1) = 64 × 3 = 192

5). Answer:  a.

B’s 1 day work = 1 /12

B’s 9 day’s work = 9 /12 =3/4

Remaining work =1- 3 /4=1/ 4

6). Answer: c.

Contribution of each boy = Number of boys

Total contribution raised = Rs. 11664

So, number of boys = √11664 = 108

7). Answer: c.

Sum of square of first n natural numbers= n (n+1)2n+1)/6

Average of Sum of square of first n natural numbers= n (n+1)2n+1)/6n

=19(19+1) (2×19+1)/(6×19)

=20×39/6 =130

8). Answer: b.

Let Income of A= x, Income of B= 2x

X+2x= 4500

X=1500

Income of B= 2x=2×1500=3000

9). Answer:  b.

10% of SP=330

SP=3300

CP=3300/11×10=3000

Profit= 3300-3000=300

10). Answer: a

20% of 75% of 4260=639

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