SSC CGL 2018 Practice Test Papers | Quantitative Aptitude (Day-17)
Dear Aspirants, Here we have given the Important SSC CGL Exam 2018 Practice Test Papers. Candidates those who are preparing for SSC CGL 2018 can practice these questions to get more confidence to Crack SSC CGL 2018 Examination.
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SSC CGL 2018 | Quantitative Aptitude (Day-17)
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Question 1 of 9
1. A number is such that when it is multiplied by 5 it gives a number which is as much higher than 390 as the original number is lower than 390. Find the original number.
Explanation:
Answer: c)
390-x=5x-390
X=130
Explanation:
Answer: c)
390-x=5x-390
X=130
Question 2 of 9
2. Find the value of 60% of 350+ 33.33% of 972+9.09% of 121
Explanation:
Answer: b)
60/100*350+1/3*972+1/11*121=545
Explanation:
Answer: b)
60/100*350+1/3*972+1/11*121=545
Question 3 of 9
3. 550/15x9/2=?
Explanation:
Answer: c)
550/15×9/2=165
Explanation:
Answer: c)
550/15×9/2=165
Question 4 of 9
4. Find the value of m if the distance between A(4,-7) and B(7,m) is 5 units.
Explanation:
Answer:c)
The distance between two points A(x1,y1) and B(x2,y2) is
m2+14m+33=0
m=-11,-3
Explanation:
Answer:c)
The distance between two points A(x1,y1) and B(x2,y2) is
m2+14m+33=0
m=-11,-3
Question 5 of 9
5. Slope or gradient of a line is tan of the angle made with
Explanation:
Answer:d)
Slope or gradient of a line is tan of the angle made with +ve x-axis
Explanation:
Answer:d)
Slope or gradient of a line is tan of the angle made with +ve x-axis
Question 6 of 9
6. Raju marked a shirt for Rs. 700 and he gave 20 % discount on the marked price. In this transaction, hegained 12% of the cost price. Find the value of 150% of cost price.
Explanation:
Answer: a)
Marked price=700
Selling price= 80/100×700=560
Cost price= 560/112×100 =500
150 % of cost price = 150/100×500=750
Explanation:
Answer: a)
Marked price=700
Selling price= 80/100×700=560
Cost price= 560/112×100 =500
150 % of cost price = 150/100×500=750
Question 7 of 9
7. Simple interest for the sum of 1600 for 2 years is 10 more than the simple interest for 1550 for the same duration. Find the rate of interest?
Explanation:
Answer: a)
P1=1600,
P2=1550,
R1=R2=R,
N1=N2=N=2
P1NR/100- P2NR/100= 1600x2xr/100 -1550x2xr/100
10 =50 x 2r/100
R=10%
Explanation:
Answer: a)
P1=1600,
P2=1550,
R1=R2=R,
N1=N2=N=2
P1NR/100- P2NR/100= 1600x2xr/100 -1550x2xr/100
10 =50 x 2r/100
R=10%
Question 8 of 9
8. What is the smallest value that must be added to 91, so that the resultant is a perfect square?
Explanation:
Answer: b)
9<√91<10
91+9=100
100 is square of 10.
Explanation:
Answer: b)
9<√91<10
91+9=100
100 is square of 10.
Question 9 of 9
9. a:b= 3:4 and c:d= 5:8 tthen find the value of a: d.
Explanation:
Answer: d
Since there is no relation between a and d , Ratio a:d can’t be determined.
Explanation:
Answer: d
Since there is no relation between a and d , Ratio a:d can’t be determined.
Click “Start Quiz” to attend these Questions and view Explanation
1) A number is such that when it is multiplied by 5 it gives a number which is as much higher than 390 as the original number is lower than 390. Find the original number.
a) 150
b) 200
c) 130
d) 270
2) Find the value of 60% of 350+ 33.33% of 972+9.09% of 121
a) 367
b)545
c) 257
d) 732
3) 550/15×9/2=?
a) 145
b) 233
c) 165
d) 120
4) Find the value of m if the distance between A(4,-7) and B(7,m) is 5 units.
a)-11
b)-3
c)both a and b
d)None of the above
5) Slope or gradient of a line is tan of the angle made with
a)+ve y-axis
b)-ve x-axis
c)-ve y-axis
d)+ve x-axis
6) Raju marked a shirt for Rs. 700 and he gave 20 % discount on the marked price. In this transaction, hegained 12% of the cost price. Find the value of 150% of cost price.
a) 750
b) 500
c) 870
d) 600
7) Simple interest for the sum of 1600 for 2 years is 10 more than the simple interest for 1550 for the same duration. Find the rate of interest?
a) 10%
b) 5%
c) 20%
d) 25%
8) What is the smallest value that must be added to 91, so that the resultant is a perfect square?
a) 8
b) 9
c) 20
d) 32
9) a:b= 3:4 and c:d= 5:8 tthen find the value of a: d.
a)3:8
b)8:3
c)1:1
d) can’t be determined.
Answers :
1). Answer: c)
390-x=5x-390
X=130
2). Answer: b)
60/100*350+1/3*972+1/11*121=545
3). Answer: c)
550/15×9/2=165
4). Answer:c)
The distance between two points A(x1,y1) and B(x2,y2) is
m2+14m+33=0
m=-11,-3
5). Answer: d)
Slope or gradient of a line is tan of the angle made with +ve x-axis
6). Answer: a)
Marked price=700
Selling price= 80/100×700=560
Cost price= 560/112×100 =500
150 % of cost price = 150/100×500=750
7). Answer: a)
P1=1600,
P2=1550,
R1=R2=R,
N1=N2=N=2
P1NR/100- P2NR/100= 1600x2xr/100 -1550x2xr/100
10 =50 x 2r/100
R=10%
8). Answer: b)
9<√91<10
91+9=100
100 is square of 10.
9). Answer: d
Since there is no relation between a and d , Ratio a:d can’t be determined.