# SSC CGL 2018 Practice Test Papers | Quantitative Aptitude (Day-18)

Dear Aspirants, Here we have given the Important SSC CGL Exam 2018 Practice Test Papers. Candidates those who are preparing for SSC CGL 2018 can practice these questions to get more confidence to Crack SSC CGL 2018 Examination.

SSC CGL 2018 | Quantitative Aptitude (Day-18)

maximum of 10 points

Click โStart Quizโ to attend these Questions and view Explanation

1) Find the unit digit in the product 153ร 549ร 237ร145=?

a) 5

b) 3

c) 1

d) 6

2) In the series, 7, 21, 63โฆ.. Find the 7th term?

a) 3743
b) 5103

c) 4781

d) 6782

3) The HCF and LCM of two numbers A and B is 15 and 90 respectively. The sum of A and B is 75. Find the value of 1/A+1/B?

a) 1/18

b) 1/20

c) 1/30

d) 1/15

4) Which of the following is largest?

4/5, 7/9, 8/11, 3/5

a) 4/5

b)7/9

c)8/10

d)3/5

5) Ashik covers 40 km distance at 5 km/h, he covers the next 15 km with a speed of 3 km/h, and he last 10 km with a speed of 2 km/h. Find the average speed.

a) 3 11/18

b) 4 1/18

c) 5/21

d) 6/17

6) If 10 % of A is equal to 30% of B, then 25 % of A is equal to what percent of B?

a) 50

b) 30

c) 20

d) 75

7) What is 33.33 % of 69 of 20?

a) 420

b) 520

c) 460

d)510

8) Reena got 760 marks and reetaย  got 56% marks in the test. If Reena got 228 marks more than Reeta what was the maximum marks of the test?

a) 950

b) 750

c) 1000

d) 800

9) Arvi bought 3 flowers for 4 rupees and sold them at the rate of 4 flowers for 3 rupees. Find the loss percent?

a) 40%

b) 43.75%

c) 51.25%

d) 60%

10) The ratio between present ages of Adam and Aswin is 5:7. After 4 years, the age of Aswinโs brother who is 2 years elder than Aswin is 27. What is the present age of Adam?

a) 12 years

b) 18 years

c) 20 years

d) 15 years

Unit digit in Product =3 x9x 7 x5 =5

The given series is a GP.

a=7,r=3

nth term= a r(n-1)

7th term= 7ร3(7-1) = 7ร3(6) = 5103

Product of two numbers= LCMX HCF

AรB=15×90

1/A+1/B= (A+B)/(AB)=75/(15×90)=1/18

4/5=0.8

7/9= 0.77

8/10=0.72

3/5=0.6

Average speed= (40+15+10)/(40/5+15/3+10/2)=3ย ย  11/18

10/100 A=30/100 B

A=3B

25/100 A=25/100x3B=75% of B

1/3 x 69 x20= 460

Let the total marks be x.

Reena โReeta= 760-56x/100= 228

56x=53200

X=950

Cost price of 12 flowers= Rs.16

Selling price of 12 flowers= Rs.9

LOSS %= (16-9)/16X100=43.75%