SSC CGL 2018 Practice Test Papers | Quantitative Aptitude (Day-21)
Dear Aspirants, Here we have given the Important SSC CGL Exam 2018 Practice Test Papers. Candidates those who are preparing for SSC CGL 2018 can practice these questions to get more confidence to Crack SSC CGL 2018 Examination.
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Question 1 of 10
1. Question
Two numbers X and Y are in the ratio 5:6. If 40% of first number is equal to one third of second number. Find the value of X.
Correct
Answer: d)
x/y=5/6— (i)
40x/100=y/3
=>x/y=5/6—- (ii)
Both equations are same.
So the value of x cannot be determined.
Incorrect
Answer: d)
x/y=5/6— (i)
40x/100=y/3
=>x/y=5/6—- (ii)
Both equations are same.
So the value of x cannot be determined.
Question 2 of 10
2. Question
For any two angles which have one common side and the sum of the two angles is supplementary then they are called as
Correct
Answer: d)
For any two angles which have one common side and the sum of the two angles is supplementary then they are called as Linear Pair.
Incorrect
Answer: d)
For any two angles which have one common side and the sum of the two angles is supplementary then they are called as Linear Pair.
Question 3 of 10
3. Question
if sin x=5/13, 90<x<180. Find the value of cos x.
Correct
Answer: b)
Incorrect
Answer: b)
Question 4 of 10
4. Question
Hridhaya’s salary is 50% more than Ananya’s salary. If Hridhaya saves Rs.1200 per month which is 40% of Ananya’s salary. Find Hridhaya’s salary.
Correct
Answer: c)
40 % of ananya salary =1200
100 % of ananya salary= 1200×100/40=3000
Hridhaya salary = 3000x 150/100=4500
Incorrect
Answer: c)
40 % of ananya salary =1200
100 % of ananya salary= 1200×100/40=3000
Hridhaya salary = 3000x 150/100=4500
Question 5 of 10
5. Question
The average of 15 consecutive odd natural numbers starting from 333 to 361 is x. Find the average if 4 more consecutive odd natural numbers are added before 333.
Correct
Answer: c)
Average of numbers from 333 to 361= (333+361)/2=347
Avg of all odd natural numbers if 4 numbers are added before 333= 347-4=343.
Incorrect
Answer: c)
Average of numbers from 333 to 361= (333+361)/2=347
Avg of all odd natural numbers if 4 numbers are added before 333= 347-4=343.
Question 6 of 10
6. Question
Correct
Answer: b)
Incorrect
Answer: b)
Question 7 of 10
7. Question
If a^{3}-b^{3} =45 and a-b=3 then find a^{2}+b^{2}?
Correct
Answer: c)
a^{2}+b^{2}= (a-b)^{2}+2ab —– (i)
a^{3}-b^{3}= (a-b) (a^{2}+ab+b^{2}) —— (ii)
Substitute (i) in (ii)
a^{3}-b^{3}= (a-b) ((a-b)^{2}+2ab +ab)
45 = 3(9+3ab)
15=9+3ab
sb = 2—– (iii)
Sub (iii) in (i)
a^{2}+b^{2}= 3^{2}+2×2=13
Incorrect
Answer: c)
a^{2}+b^{2}= (a-b)^{2}+2ab —– (i)
a^{3}-b^{3}= (a-b) (a^{2}+ab+b^{2}) —— (ii)
Substitute (i) in (ii)
a^{3}-b^{3}= (a-b) ((a-b)^{2}+2ab +ab)
45 = 3(9+3ab)
15=9+3ab
sb = 2—– (iii)
Sub (iii) in (i)
a^{2}+b^{2}= 3^{2}+2×2=13
Question 8 of 10
8. Question
Pipes A and B can fill the tank in 15 and 20 hours. Pipe C is an outlet which can empty the tank in 30 hours. All three pipes are opened simultaneously and pipe C is closed after 5 hours. What part of the tank is yet to be filled?
Correct
Answer: c)
A=1/15
B=1/20
C=-1/30
Part of tank filled in 5 hours= 5(1/15+1/20 – 1/30) = 5(5/60) = 25/60 = 5/12
Remaining part to be filled = 7/12
Incorrect
Answer: c)
A=1/15
B=1/20
C=-1/30
Part of tank filled in 5 hours= 5(1/15+1/20 – 1/30) = 5(5/60) = 25/60 = 5/12
Remaining part to be filled = 7/12
Question 9 of 10
9. Question
The perimeter of a rectangle and square are equal and is 200 m. The area of square is 100 m^{2} more than area of rectangle. What is the difference between Length of rectangle and side of a square?
Correct
Answer: a)
Perimeter of a rectangle = 2 (l+b)
Perimeter of a square = 4a = 200
a=50
2(l+b) = 4a
2(l+b) = 200
(l+b) = 100—– (i)
Area of square= a^2=2500
Area of Rectangle= lb
a^{2}-lb=100
2500-lb=100
Lb = 2400——– (ii)
On solving (i) and (ii)
L=60
l-a=60-50=10
Incorrect
Answer: a)
Perimeter of a rectangle = 2 (l+b)
Perimeter of a square = 4a = 200
a=50
2(l+b) = 4a
2(l+b) = 200
(l+b) = 100—– (i)
Area of square= a^2=2500
Area of Rectangle= lb
a^{2}-lb=100
2500-lb=100
Lb = 2400——– (ii)
On solving (i) and (ii)
L=60
l-a=60-50=10
Question 10 of 10
10. Question
By selling a camera at a profit of 30% the shopkeeper got Rs. 625 more than one-third of the cost price. Find the cost price.
Correct
Answer: a)
13/10-4/5=5/10=1/2
1/2———– 625
1————–?
?= 625 x2=1250
Incorrect
Answer: a)
13/10-4/5=5/10=1/2
1/2———– 625
1————–?
?= 625 x2=1250
Click “Start Quiz” to attend these Questions and view Explanation
1) Two numbers X and Y are in the ratio 5:6. If 40% of first number is equal to one third of second number. Find the value of X.
a) 60
b) 50
c) 72
d) Can’t be determined
2) For any two angles which have one common side and the sum of the two angles is supplementary then they are called as
a) Adjacent angles
b) Collinear angles
c) Corresponding angles
d) Linear Pair
3) if sin x=5/13, 90<x<180. Find the value of cos x.
a) -12/13
b) 12/13
c) 0
d) -5/13
4) Hridhaya’s salary is 50% more than Ananya’s salary. If Hridhaya saves Rs.1200 per month which is 40% of Ananya’s salary. Find Hridhaya’s salary.
a) 10000
b) 5000
c) 4500
d) 7000
5) The average of 15 consecutive odd natural numbers starting from 333 to 361 is x. Find the average if 4 more consecutive odd natural numbers are added before 333.
a) 350
b) 347
c) 343
d) 351
6).
a) 40/13
b) 39/11
c) 49/15
d) 20/11
7) If a^{3}-b^{3} =45 and a-b=3 then find a^{2}+b^{2}?
a) 15
b) 11
c) 13
d) 20
8) Pipes A and B can fill the tank in 15 and 20 hours. Pipe C is an outlet which can empty the tank in 30 hours. All three pipes are opened simultaneously and pipe C is closed after 5 hours. What part of the tank is yet to be filled?
a) 5 /12
b) 6/11
c) 7/12
d) 4/12
9) The perimeter of a rectangle and square are equal and is 200 m. The area of square is 100 m^{2} more than area of rectangle. What is the difference between Length of rectangle and side of a square?
a) 10 m
b) 20 m
c) 25 m
d) 30 m
10) By selling a camera at a profit of 30% the shopkeeper got Rs. 625 more than one-third of the cost price. Find the cost price.
a) 1250
b) 2000
c) 3500
d) 4000
Answers :
1). Answer: d)
x/y=5/6— (i)
40x/100=y/3
=>x/y=5/6—- (ii)
Both equations are same.
So the value of x cannot be determined.
2). Answer: d)
For any two angles which have one common side and the sum of the two angles is supplementary then they are called as Linear Pair.
3). Answer: b)
4). Answer: c)
40 % of ananya salary =1200
100 % of ananya salary= 1200×100/40=3000
Hridhaya salary = 3000x 150/100=4500
5). Answer: c)
Average of numbers from 333 to 361= (333+361)/2=347
Avg of all odd natural numbers if 4 numbers are added before 333= 347-4=343.
6). Answer: b)
7). Answer: c)
a^{2}+b^{2}= (a-b)^{2}+2ab —– (i)
a^{3}-b^{3}= (a-b) (a^{2}+ab+b^{2}) —— (ii)
Substitute (i) in (ii)
a^{3}-b^{3}= (a-b) ((a-b)^{2}+2ab +ab)
45 = 3(9+3ab)
15=9+3ab
sb = 2—– (iii)
Sub (iii) in (i)
a^{2}+b^{2}= 3^{2}+2×2=13
8). Answer: c)
A=1/15
B=1/20
C=-1/30
Part of tank filled in 5 hours= 5(1/15+1/20 – 1/30) = 5(5/60) = 25/60 = 5/12
Remaining part to be filled = 7/12
9). Answer: a)
Perimeter of a rectangle = 2 (l+b)
Perimeter of a square = 4a = 200
a=50
2(l+b) = 4a
2(l+b) = 200
(l+b) = 100—– (i)
Area of square= a^2=2500
Area of Rectangle= lb
a^{2}-lb=100
2500-lb=100
Lb = 2400——– (ii)
On solving (i) and (ii)
L=60
l-a=60-50=10
10). Answer: a)
13/10-4/5=5/10=1/2
1/2———– 625
1————–?
?= 625 x2=1250
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