# SSC CGL 2018 Practice Test Papers | Quantitative Aptitude (Day-9)

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SSC CGL 2018 | Quantitative Aptitude (Day-9)

maximum of 10 points

Click โStart Quizโ to attend these Questions and view Explanation

1). If the length is increased 10% and breadth is increased 20 % then what is the percentage increased in area if the original area of the rectangle is 300 m2?

1. 80
2. 78
3. 96
4. 46

2). The LCM and HCF of and two numbers is 180 and 15 respectively. If one number is 60 then what is 200% of the other number?

1. 100
2. 120
3. 300
4. 90

3). Arun can complete a piece of work in 6 days and Raju who is twice efficient of Arun joins after 2 days work of Arun. In how many days the work will be completed?

1. 5/6
2. 10/3
3. 13
4. 4/3

4). If 22x+8=86x then what is the value of x?

(a) 3/2

(b) 5

(c) 1/2

(d) 2

5). The difference between areas of a square and Rectangle is 43 sq.m. The ratio of length and breadth of the rectangle is 3:2. Find the side of the square if the difference between length and breadth of the rectangle is 1 m.

1. 3 m
2. 7m
3. 5 m
4. 4 m

6). The circumference of a semicircle is equal to the perimeter of the rectangle. Find the area of the semicircle if the length and area of the rectangle is 14 m and 112 m2 .

a.450

b.308

c.256

d.300

7). The average marks of Hari in a certain examination are 46. If he got 30 marks more in Physics his average becomes 52. Find the total number of subjects in the examination.

1. 6
2. 5
3. 4
4. 3

8). Two persons A and B invest in a business in the ratio 4: 5 for a year. If the total profit is 30000 and they decided to give 10% of the total profit for social service. Find the profit of A.

1. 15000
2. 10000
3. 12000
4. None of the above

9). The average of 7 numbers is 45. The ratio of first three numbers and last three numbers is 1:1. Find the fourth number if the fourth number is one-fourth of the sum of the first 3 numbers.

1. 140
2. 35
3. 45
4. 70

10). Find the value of ? in the following expression.

350+56*21/8 = ?+400

1. 60
2. 57
3. 97
4. 107

1.1 x 1.2 x 300 = 396

Increase in Area= 396 – 300 = 96

LCM x HCF = Product of two numbers

180×15=60*x

X=45

200% of x= 90

Let x be the days for which Arun and Raju work together.

Arun=1/6

Raju=1/3

Arun +Raju= 1/6+1/3=1/2

2/6+ x (1/2) = 1

X=4/3

No. of days=2+4/3=10/3

22x+8=86x

2x+8=3(6x)

2x+8=18x

16x=8

X=1/2

l:b=3:2

l โ b = 3x-2x=1

l=3 m, b=2 m

a2 โ lb = 43

a2– 6 = 43

a2 = 49

a =7 m

Area of semicircle = ะปr

Perimeter of rectangle=2(l+b) = 2(14+b)

Area of rectangle=lb=b*14=112

b=8

22/7*r=2(8+14)

r=14

Let the number of subjects be x.

Total marks = X*46

46x+30 = 52x

6x = 30

X = 5

10% of the profit =3000

Share of A= 4/9×27000=12000

x+1/4x+x = 45×7

x=45x7x4

Fourth number= 1/4 (9x) = 45×7 = 35