# IBPS PO Mains 2018 – Quantitative Aptitude Questions Day-22

Dear Readers, Bank Exam Race for the Year 2018 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for IBPS PO Mains 2018 Exams can practice these questions daily and make your preparation effective.

[WpProQuiz 4222]

Directions (Q. 1 – 5): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or no relation can be established between x and y

1) I) 3x2 – 19x + 28 = 0

II) (256)1/4 y + (216)1/3 = 0

2) I) 4/√x + 8/√x = √x

II) y2 = 75/2/ √y

3) I) 2x + 3y =14

II) 4x+ 2y = 16

4) I) 2x2 – 21x + 27 =0

II) 2y2 – 13y +20 =0

5) I) 5x2 +23x +12 =0

II) 15y2 +14y +3 =0

Directions (Q. 6 – 10) Study the following information carefully and answer the given questions:

The following table shows the 4 different persons invested the principle amount, total amount they received and rate of interest and the total number of years they invested the principle amount and the compound interest for the total investment. (Some values are missing) 6) If the interest received by P is Rs. 9270, then find the rate of interest for the principle amount invested by P?

a) 6 %

b) 5 %

c) 8 %

d) 7 %

e) None of these

7) If the total amount received by R is Rs. 73205 and the ratio of the sum invested by P and R is 3 : 2, then find the number of years the principle amount invested by R?

a) 2 years

b) 3 years

c) 5 years

d) 4 years

e) None of these

8) If the total amount received by R after investing the principle amount for 4 years is Rs. 92238.30, then find the principle amount invested by R?

a) Rs. 59000

b) Rs. 63000

c) Rs. 65000

d) Rs. 56000

e) None of these

9) If the ratio of the sum invested by P and S is 5 : 6, then find the rate of interest for the principle amount invested by S?

a) 5 %

b) 10 %

c) 8 %

d) 6 %

e) None of these

10) If the sum invested by Q is 80 % of the sum invested by P, then find the number of years Q invested the sum?

a) 2 years

b) 4 years

c) 3 years

d) Can’t be determined

e) None of these

I) 3x2 – 19x + 28 = 0

3x2 – 12x – 7x + 28 = 0

3x (x – 4) – 7 (x – 4) = 0

(x – 4) (3x – 7) = 0

x = 4, 7/3

II) (256)1/4 y = – (216)1/3

(44)1/4 y = – (63)1/3

4y = -6

Y = – (6/4) = -1.5

X > y

I) 4/√x + 8/√x = √x

12/√x = √x

12= x

II) y2 = 75/2/ √y

Y2 × y1/2 = 75/2

Y2+(1/2) = 75/2

Y5/2 = 75/2

Y=7

X > y

2x + 3y =14 —à (1)

4x+ 2y = 16—à (2)

By solving the equation (1) and (2), we get,

X= 2.5, y=3

X < y

I) 2x2 – 21x + 27 =0

2x2 – 18x – 3x + 27 =0

2x(x-9) – 3 (x-9) =0

(2x -3) (x – 9) =0

X= 3/2, 9

II) 2y2 – 13y +20 =0

2y2 – 8y-5y +20 =0

2y(y-4)-5(y-4) =0

(2y-5) (y-4) = 0

Y= 5/2, 4

Can’t be determined

I) 5x2 +23x +12 =0

5x2 +20x +3x +12 =0

5x(x+4)+3 (x+4) =0

(5x+3) (x+4) =0

X= -3/5, -4

II) 15y2 +14y +3 =0

15y2 +5y+9y +3 =0

5y (3y+1) + 3(3y+1) =0

(5y+3) (3y+1) =0

Y= -3/5, -1/3

X ≤ y

Direction (6-10) :

Compound Interest = Rs. 9270

Total amount = 75000 + 9270 = Rs. 84270

Number of years (n) = 2

Total amount = P*(1 + (r/100))n

84270 = 75000*(1 + (r/100))2

(84270/75000) = [(100 + r)/100]2

(2809/2500) = [(100 + r)/100]2

(53/50)2 = [(100 + r)/100]2

(53/50) = [(100 + r)/100]

106 = 100 + r

r = 6 %

Total amount = Rs. 73205

Ratio of the sum invested by P and R = 3 : 2 (3x, 2x)

3x = 75000

X = 25000

Principle amount invested by R = 2x = Rs. 50000

Total amount = P*(1 + (r/100))n

73205 = 50000*[110/100]n

73205/50000 = [11/10]n

14641/10000 = [11/10]n

(11/10)4 = [11/10]n

n = 4

Number of years = 4 years

Total amount = Rs. 92238.30

Total amount = P*(1 + (r/100))n

92238.30 = P*(1 + (10/100))4

92238.30 = P*(110/100)4

92238.30 = P*(11/10)4

P = 92238.30*(10000/14641)

P = Rs. 63000

The ratio of the sum invested by P and S = 5 : 6 (5x, 6x)

5x = 75000

X = 15000

The principle amount invested by S = 6x = Rs. 90000

Total amount = Rs. 104976

Total amount = P*(1 + (r/100))n

104976 = 90000*[(100 + r)/100]2

(104976/90000) = [(100 + r)/100]2

(729/625) = [(100 + r)/100]2

(27/25)2 = [(100 + r)/100]2

27/25 = [(100 + r)/100]

108 = 100 + r

r = 8 %

Rate of interest = 8 %

Principle amount invested by Q = (80/100)*75000

= > Rs. 60000

Compound interest = Rs. 9457.50

Total amount = 60000 + 9457.50 = Rs. 69457.50

Total amount = P*(1 + (r/100))n

69457.50 = 60000*(1 + (5/100))n

(69457.50/60000) = (105/100)n

(694575/600000) = (21/20)n

9261/8000 = (21/20)n

(21/20)3 = (21/20)n`

n = 3

Number of years = 3 years

Daily Practice Test Schedule | Good Luck

 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Current Affairs Quiz (Hindi) 9.30 AM IBPS Clerk Prelims – Reasoning 10.00 AM IBPS Clerk Prelims – Reasoning (Hindi) 10.30 AM IBPS Clerk Prelims – Quantitative Aptitude 11.00 AM IBPS Clerk Prelims – Quantitative Aptitude (Hindi) 11.30 AM Vocabulary (Based on The Hindu) 12.00 PM IBPS PO Prelims – English Language 1.00 PM SSC Practice Questions (Reasoning/Quantitative aptitude) 2.00 PM IBPS PO/Clerk – GK Questions 3.00 PM SSC Practice Questions (English/General Knowledge) 4.00 PM Daily Current Affairs Updates 5.00 PM IBPS PO Mains – Reasoning 6.00 PM IBPS PO Mains – Quantitative Aptitude 7.00 PM IBPS PO Mains – English Language 8.00 PM 