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**Directions (Q. 1 – 5): Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.**

**1) Quantity I: **The area of rectangular garden is 2080 Sq m. The length of the rectangular garden is 30 % more than the breadth. Find the perimeter of the garden?

**Quantity II:** The area of a square park is 2304 Sq m. Find the perimeter of the park?

a) Quantity I > Quantity II

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**2) Quantity I: **The shopkeeper sold an article at 15 % discount on marked price and he gains 25 %. If the marked price of the article is Rs. 600, then the cost price is?

**Quantity II: **The shopkeeper marks the price of the book Rs. 550 and his profit % is 20 %. Find the cost price of the book, if he allows a discount of 16 %?

a) Quantity I > Quantity II

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**3) Quantity I:** 240 m long train can crosses a pole in 8 sec. The speed of the train is,

**Quantity II:** 200 m long train can crosses a platform of length 160 m in 24 sec. The speed of the train is,

a) Quantity I > Quantity II

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**4) A bag contains, 4 pink, 7 yellow and 5 black balls.**

**Quantity I: **If 3 balls are drawn randomly, then find the probability of getting at least one yellow ball?

**Quantity II: **If 2 balls are drawn randomly, then find the probability of getting both the balls are either pink or black?

a) Quantity I > Quantity II

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**5) Quantity I: **A and B started a business by Rs. 5400 and Rs. 7200 respectively. A invested only 6 months and they divided their shares after a year. The ratio of profit of A and B is 3 : 8. Then how many months B invested the money?

**Quantity II: **P and Q invested in the ratio of 7 : 10. P invested the money for 10 months. The ratio of profit of P and Q is 7 : 12. Then, how many months Q invested the money?

a) Quantity I > Quantity II

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**Directions (Q. 6 â€“ 10) Study the following information carefully and answer the given questions:**

The following pie chart shows the percentage distribution of total number of television viewers of different channels in a certain city.

The following table shows the ratio of male and female television viewers.

**6) Find the difference between the total number of male television viewers of Star news to that of total number of female television viewers of Star Vijay?**

a) 2400

b) 2800

c) 3600

d) 3200

e) None of these

**7) Find the ratio between the total number of television viewers of Polimer TV to that of total number of female television viewers of Colors TV?**

a) 9 : 8

b) 5 : 3

c) 11 : 7

d) 23 : 15

e) None of these

**8) Total number of television viewers of Times Now is what percentage of total number of male television viewers of ZEE TV?**

a) 215 %

b) 160 %

c) 140 %

d) 175 %

e) None of these

**9) Find the average number of male television viewers of Polimer TV, Star Vijay and Colors TV together?**

a) 5800

b) 6200

c) 6350

d) 6700

e) None of these

**10) Total number of female television viewers of Star news is what percentage more/less than the total number of male television viewers of ZEE TV?**

a) 10 % more

b) 20 % less

c) 30 % less

d) 25 % more

e) None of these

**Directions (Q. 11 – 15): What value should come in place of question mark (?) in the following questions?**

**11) ****âˆš16129 + ****âˆ›****3944312 + 66 % of 1800 = 579 + ?**

a) 725

b) 636

c) 978

d) 894

e) None of these

**12) (4/5) of (95/29) of 4350 = 36 % of 2700 + (4/7) of (?)**

a) 18249

b) 19456

c) 21324

d) 15420

e) None of these

**13) 52 ^{2} **

**Ã· 14 Ã— 7 + 45**

^{2}= 5 Ã— ? â€“ 35 % of 3100a) 814.6

b) 728

c) 892.4

d) 654

e) None of these

**14) 3224 Ã· (31 % of 1300) = 49 Ã— 9 2/7 of (? Ã· 130)**

a) 17/9

b) 16/7

c) 24/5

d) 33/5

e) None of these

**15) ****(13 Ã— 11 + 48 Ã— 7 + 8 Ã— 9 + 47 Ã— 2) Ã· (12 ^{2} – âˆš1156 + 19) = ?**

a) 12

b) 24

c) 9

d) 5

e) None of these

**Directions (Q. 16 â€“ 20) Find the wrong term in the following number series?**

**16) 1146, 1217, 1371, 1573, 1800, 2036**

a) 1371

b) 1573

c) 1217

d) 2036

e) 1800

**17) 225, 223, 111, 36, 8**

a) 223

b) 111

c) 36

d) 225

e) 8

**18) ****4, 26, 178, 1238, 8672**

a) 26

b) 4

c) 1238

d) 178

e) 8672

**19) 21, 10, 11, 16.5, 32, 77.5, 235.5**

a) 10

b) 38

c) 97.5

d) 295.5

e) 5

**20) 37, 40, 85, 267, 1080, 5415**

a) 37

b) 267

c) 1080

d) 85

e) 5415

**21) ****Mahesh can do a work in 24 days. He works alone for 6 days and Naveen alone finishes the remaining work in 12 days. Both of them together can complete the work in?**

a) 7 2/7 days

b) 15 Â¼ days

c) 12 2/3 days

d) 9 3/5 days

e) None of these

**22) A, B and C started a business by investing Rs. 40500, Rs. 45000 and Rs. 60000 respectively. After 6 months C withdrew Rs. 15000 while A invested Rs. 4500 more. If the total profit at the end of the year is Rs. 149600, then the share of C will exceed that of A by?**

a) Rs. 19000

b) Rs. 11500

c) Rs. 13000

d) Rs. 10400

e) None of these

**23) The simple interest accrued on an amount of Rs. 17,000 at the end of 4 years is Rs. 6800. What would be the compound interest accrued on the same amount at the same rate in the same period?**

a) Rs. 7889.70

b) Rs. 8324.20

c) Rs. 6990.50

d) Rs. 7129.30

e) Rs. 7558.60

**24) Smallest angle of a triangle is equal to two-third of the smallest angle of a quadrilateral. The ratio between the angles of the quadrilateral is 3 : 4 : 5 : 6. Largest angle of the triangle is twice its smallest angle. What is the sum of second largest angle of the triangle and largest angle of the quadrilateral?**

a) 160Â°

b) 180Â°

c) 190Â°

d) 170Â°

e) 150Â°

**25) If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction becomes 25/51. Then find the original fraction?**

a) 13/15

b) 11/17

c) 11/15

d) 15/17

e) None of these

**26) A boat can cover 15 km downstream in 45 minutes. If the speed of the current is Â¼ of the boat in still water, then how much distance can the boat cover upstream in 66 minutes?**

a) 13.2 km

b) 16 km

c) 18 km

d) 10.8 km

e) None of these

**27) ****A man purchases 2 watches for Rs. 665. He sells one of them at 20% profit and another at 15% loss. Thus, he neither gains nor loses. Find the selling price?**

a) Rs. 342, Rs. 323

b) Rs. 285, Rs. 380

c) Rs. 410, Rs. 353

d) Rs. 267, Rs. 323

e) None of these

**28) A bag contains 4 vivo mobiles, 6 Lenovo mobiles and 5 oppo mobiles. 3 mobiles are drawn at random. What is the probability of choosing at least one is oppo mobile?**

a) 24/91

b) 43/91

c) 57/91

d) 67/91

e) None of these

**29) Ravi has 35 % savings with him from his monthly salary. If the expenditure of clothing is 20 % of overall expenditure and his expenditure except clothing is Rs. 10400. Find his savings?**

a) Rs. 6500

b) Rs. 5850

c) Rs. 7000

d) Rs. 7150

e) None of these

**30) Priya is 7 years older than Revathi. The ratio of the present ages of Priya to that of Mini is 3 : 4. Revathi is 15 years younger than Mini. What is Revathiâ€™s present age?**

a) 23 years

b) 20 years

c) 25 years

d) 17 years

e) None of these

**given. You have to solve both the equations and give answer as,**

a) If x > y

b) If x â‰¥ y

c) If x < y

d) If x â‰¤ y

e) If x = y or the relation cannot be established

**31) **

**I) x ^{2} – 12x + 36 = 0**

**II) 5y ^{2} + 4y â€“ 12 = 0**

**32) **

**I) 2x ^{2} + 12x + 16 = 0 Â Â Â Â Â **

**II) 3y ^{2} -7y – 6 = 0**

**33) **

**I) 7x + 2y = -13**

**II) 5x â€“ 4y = 7**

**34) **

**I) x ^{2} + 2x â€“ 15 = 0**

**II) y ^{2} + y â€“ 56 = 0**

**35) **

**I) âˆœ625 x + âˆš5625 = 0**

**II) (243) ^{1/5 }y + (1728)^{1/3} = 0**

**Answers:**

**Directions (Q. 1 – 5):**

**1) Answer: c)**

**Quantity I:**

The area of rectangular garden = 2080 Sq m

Length = (130/100)*breadth

l/b = 13/10 = > l : b = 13 : 10

13x*10x = 2080

130x^{2} = 2080

X^{2} = (2080/130) = 16

X = 4

Length = 52 m, Breadth = 40 m

Perimeter of the garden = 2*(l + b) = 2*(52 + 40) =2*92 = 184 m

**Quantity II:**

The area of a square park = 2304 Sq m

Area (a^{2}) = 2304

Side (a) = 48

Perimeter of the park = 4a = 4*48 = 192 m

**Quantity II > Quantity I**

**2) Answer: a)**

**Quantity I:**

Selling price of the article = 600*(85/100) = Rs. 510

Cost price of the article

= > CP*(125/100) = 510

= > CP = 510*(100/125)

= > CP = Rs. 408

**Quantity II:**

Selling price of the book = 550*(84/100) = Rs. 462

Cost price of the book = 462*(100/120) = Rs. 385

**Quantity I > Quantity II**

**3) Answer: a)**

**Quantity I:**

Speed = Distance/Time

= > 240/8

= > 30 m/sec

The speed of the train = 30 m/sec

**Quantity II:**

Distance = Length of train + Platform length = 200 + 160 = 360 m

Speed = 360/24 = 15 m/sec

**Quantity I > Quantity II**

**4) Answer: a)**

Total no of balls = 4 + 7 + 5 = 16 balls

**Quantity I:**

n(S) = 16C_{3 }= (16*15*14)/(1*2*3)

The probability of getting at least one yellow ball = 1- P (None is yellow ball)

P (None is yellow ball)

n(E) = 9C_{3} = (9*8*7)/(1*2*3)

P(E) = n(E)/n(S) = 9C_{3 }/16C_{3}

= > [(9*8*7)/(1*2*3)] / [(16*15*14)/(1*2*3)]

= > 3/20

Required probability = 1 – (3/20) = 17/20

**Quantity II:**

n(S) = 16C_{2} = (16*15)/(1*2)

n(E) = Probability that both the balls are either pink or black

n(E) = 4C_{2} or 5C_{2}

P(E) = n(E)/n(S)

= > [4C_{2} or 5C_{2}] / 16C_{2}

= > [6 + 10] / [(16*15)/(1*2)]

= > (16*2)/(16*15) = 2/15

**Quantity I > Quantity II**

**5) Answer: e)**

**Quantity I:**

According to the question,

(5400*6)/(7200*x) = (3/8)

32400/7200x = 3/8

32400*8 = 7200x*3

X = (32400*8)/(7200*3)

X = 12 months

**Quantity II:**

According to the question,

(7*10)/(10x) = (7/12)

X = 12 months

**Quantity I = Quantity II**

**Directions (Q. 6 â€“ 10):**

**6) Answer: c)**

The total number of male television viewers of Star news

= > 75000*(12/100)*(8/15) = 4800

The total number of female television viewers of Star Vijay

= > 75000*(21/100)*(8/15) = 8400

Required difference = 8400 â€“ 4800 = 3600

**7) Answer: a)**

The total number of television viewers of Polimer TV

= > 75000*(15/100) = 11250

The total number of female television viewers of Colors TV

= > 75000*(20/100)*(2/3) = 10000

Required ratio = 11250 : 10000 = 9 : 8

**8) Answer: d)**

Total number of television viewers of Times Now

= > 75000*(14/100) = 10500

Total number of male television viewers of ZEE TV

= > 75000*(18/100)*(4/9) = 6000

Required % = (10500/6000)*100 = 175 %

**9) Answer: b)**

The total number of male television viewers of Polimer TV, Star Vijay and Colors TV together

= > 75000*(15/100)*(5/9) + 75000*(21/100)*(7/15) + 75000*(20/100)*(1/3)

= > 6250 + 7350 + 5000 = 18600

Required average = 18600/3 = 6200

**10) Answer: c)**

Total number of female television viewers of Star news

= > 75000*(12/100)*(7/15) = 4200

Total number of male television viewers of ZEE TV

= > 75000*(18/100)*(4/9) = 6000

Required % = [(6000 â€“ 4200)/6000]*100 = 30 % less

**Directions (Q. 11 – 15): **

**11) Answer: d)**

127 + 158 + (66/100)*1800 â€“ 579 = x

X = 127 + 158 + 1188 â€“ 579

X = 894

**12) Answer: a)**

(4/5)*(95/29)*4350 = (36/100)*2700 + (4/7)*x

11400 â€“ 972 = (4x/7)

10428*(7/4) = x

X = 18249

**13) Answer: c)**

Â (52*52*7)/14 + 45^{2} = 5x â€“ (35/100)*3100

1352 + 2025 = 5x â€“ 1085

1352 + 2025 + 1085 = 5x

X = 4462/5

X = 892.4

**14) Answer: b)**

3224 Ã· [(31/100)*1300] = 49*(65/7)*(x/130)

3224/403 = (7x/2)

8*(2/7) = x

X = 16/7

**15) Answer: d)**

Â (13 Ã— 11 + 48 Ã— 7 + 8 Ã— 9 + 47 Ã— 2) Ã· (12^{2} – âˆš1156 + 19) = x

X = (143 + 336 + 72 + 94) / (144 â€“ 34 + 19)

X = 645/129 = 5

**Directions (Q. 16 â€“ 20):**

**16) Answer: c)**

The correct series is,

The difference of difference is, 9^{2}, 7^{2}, 5^{2}, 3^{2},..

The wrong term is, 1217

**17) Answer: a)**

The correct series is,

225, **224**, 111, 36, 8

The pattern is,

= > (225-1)/1 = 224, (224-2)/2 = 111, (111-3)/3 = 36, (36- 4)/4 = 8

The wrong term is, 223

**18) Answer: c)**

The correct series is,

4, 26, 178, **1240,** 8672

The pattern is, *7 â€“ 2, *7 â€“ 4, *7 â€“ 6, *7 -8,..

The wrong term is, 1238

**19) Answer: e)**

The correct series is,

21, 10, 11, **15**, 32, 77.5, 235.5

The pattern is, *0.5 â€“ 0.5, *1 + 1, *1.5 -1.5, *2 + 2, *2.5 â€“ 2.5, *3 + 3,..

The wrong term is, 16.5

**20) Answer: d)**

The correct series is,

37, 40, **86**, 267, 1080, 5415

The pattern is, *1 + 3, *2 + 6, *3 + 9, *4 + 12, *5 + 15,..

The wrong term is, 85

**21) Answer: d)**

Mahesh one day work = 1/24

6 days work = 6/24 = 1/4

Remaining work = 1 – (1/4) = 3/4

Naveen alone finishes the remaining work in 12 days.

= > (3/4) * Naveenâ€™s whole work = 12

= > Naveenâ€™s whole work = 16 days

Mahesh and Naveenâ€™s one day work,

= > (1/24) + (1/16)

= > 5/48

Both Mahesh and Naveen together complete the work in,

= > 48/5 days = 9 3/5 days

**22) Answer: d)**

The share of A, B and C

= > (40500*6 + 45000*6) : (45000*12) : (60000*6 + 45000*6)

= > 513000 : 540000 : 630000

= > 57 : 60 : 70

187â€™s = 149600

1â€™s = 800

The difference between the share of A to that of C

= > 13â€™s = 13*800 = Rs. 10400

**23) Answer: a)**

S.I = PNR/100

6800 = (17000*4*R)/100

R = (6800*100)/(17000*4) = 10 %

C.I = P*(1 + (R/100))^{n} â€“ 1)

= > 17000*(1 + (10/100))^{4} â€“ 1)

= > 17000*(110/100)^{4} â€“ 1)

= > 17000*[(14641/10000) â€“ 1]

= > 17000*(4641/10000)

= > Rs. 7889.70

**24) Answer: b)**

The ratio between the angles of the quadrilateral = 3 : 4 : 5 : 6

3x + 4x + 5x + 6x = 360

=> 18x = 360

=> x = 20

Smallest angle of triangle = (2/3)*60 = 40

Largest angle of the triangle = 2*40 = 80

Second largest angle of the triangle = 180 â€“ 40 â€“ 80 = 60

Required sum = 60 + 120 = 180Â°

**25) Answer: d)**

The original fraction is,

= > [x*(250/100)]/[y*(450/100)] = (25/51)

= > x/y = (25/51)*(450/250) = 15/17

**26) Answer: a)**

The speed of downstream= D/T = 15/(45/60) = 20 km/hr

The speed of the current = Â¼ of the boat in still water

Speed of boat : Speed of Current = 4 : 1 = (4x: x)

Speed of downstream = Speed of boat + Speed of Current = 5x

20 = 5x

X= 4

Speed of boat = 16 km/hr, Speed of Current = 4 km/hr

Speed of upstream= Speed of boat – Speed of Current = 3x

Speed of upstream = 12 km/hr

Time = 66 min= (66/60) hr

Distance= S*T = 12*(66/60) = 13.2 km

**27) Answer: a)**

CP1 + CP2 = 665

=> 3 : 4

7â€™s =665 = > 1â€™s = 95

CP1 = 95*3 = 285

CP2 = 95*4 = 380

SP1 = 285*(120/100) = Rs. 342

SP2 = 380*(85/100) = Rs. 323

**28) Answer: d)**

Total probability = 15C_{3}

Required probability = 1- none is oppo mobile

The probability of choosing none is oppo mobile,

= > 10C_{3}/15C_{3} = (10*9*8)/(15*14*13)

= > 24/91

Probability of choosing at least one is oppo mobile,

= > 1 – (24/91) = 67/91

**29) Answer: c)**

Savings = 35 %

Expenditure = 65 %

According to the question,

= > (80/100)*expenditure = 10400

Expenditure = 13000

(65/100)*monthly salary = 13000

Monthly salary = 13000*(100/65) = Rs. 20000

Savings = 35 % of monthly salary = (35/100)*20000

= > Rs. 7000

**30) Answer: d)**

Let the present age of Revathi be x years,

Then, Priyaâ€™s age= (x+7) years

Revathi is 12 years younger than Mini

Miniâ€™s age= (x+15) years

So, (x+7)/(x+15) = Â¾

x= 17

Revathiâ€™s present age = 17 years

**Directions (Q. 31 – 35):**

**31) Answer: a)**

**I)** x^{2} – 12x + 36 = 0

(x â€“ 6)(x â€“ 6) = 0

X = 6, 6

**II) **5y^{2} + 4y â€“ 12 = 0

5y^{2} + 10y â€“ 6y â€“ 12 = 0

5y (y + 2) â€“ 6 (y + 2) = 0

(5y â€“ 6) (y + 2)Â = 0

Y = 6/5, – 2 = 1.2, -2

x > y

**32) Answer: c)**

**I) **2x^{2} + 12x + 16 = 0

2x^{2} + 4x + 8x + 16 = 0

2x(x + 2) + 8(x + 2) = 0

(2x + 8)(x + 2) = 0

X = -4, -2

**II)** 3y^{2} -7y – 6 = 0

3y^{2} -9y + 2y – 6 = 0

3y(y â€“ 3) + 2(y â€“ 3) = 0

(3y + 2) (y â€“ 3) = 0

Y = – 2/3, 3 = -0.667, 3

x < y

**33) Answer: a)**

7x + 2y = -13–> (1)

5x â€“ 4y = 7–> (2)

By solving the equation (1) and (2), we get,

X = – 1, y = -3

X > y

**34) Answer: e)**

**I)** x^{2} + 2x â€“ 15 = 0

(x + 5) (x â€“ 3) = 0

X = -5, 3

**II)** y^{2} + y â€“ 56 = 0

(y + 8) (y â€“ 7) = 0

Y = -8, 7

Canâ€™t be determined

**35) Answer: c)**

**I) **âˆœ625 x + âˆš5625 = 0

5x = – 75

X = -15

**II) **(243)^{1/5 }y + (1728)^{1/3} = 0

(3^{5})^{1/5} y = – (12^{3})^{1/3}

3y = -12

Y = -4

X < y