Practice Quantitative Aptitude Questions For SBI PO Prelims& NIACL 2017 (Application Problems)

Practice Quantitative Aptitude Questions For SBI PO Prelims& NIACL 2017 (Application Problems):

Dear Readers, Important Practice Aptitude Questions for Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this.

1). Fifteen students are participating in a race. In how many different ways can the first three prizes be won?
a)  2760
b)  2703
c)  2780
d)  2730
e)  2370
 
2). The incomes of Sharmaji and Pandeyji are in the ratio of 9 : 4 and their expenditures are in the ratio of 7 : 3. If each saves Rs.2000 then what is Pandeyji’s income?
a)  Rs.34750
b)  Rs.36000
c)  Rs.32000
d)  Rs.32500
e)  Rs.38000
 
3). If the letters of the word ‘PANCHATANTRA’ be arranged randomly then what is the probability that there are ten letters between R and P?
a)  1/66
b)  1/77
c)  1/668
d)  1/660
e)  None of these
 
4). 8 children and 10 men complete a certain piece of work in 29 days. If each child takes twice the time taken by a man to finish the work, then in how many days will 15 men and 86 boys finish the same work?
a)  9 days
b)  7 days
c)  12 days
d)  10 days
e)  None of these
 
5). A person lent a certain sum at 8% pa simple interest and in 5 years the interest amounted to Rs.1437 less than the principal amount. What is the amount that the person lent?
a)  Rs.2400
b)  Rs.2495
c)  Rs.2500
d)  Rs.2700
e)  Rs.2395
 
6). The average of marks obtained by 160 candidates was 56. If the average marks of the passed candidates was 65 and that of the failed candidates was 35, then what is the number of candidates who passed the examination?
a)  110
b)  112
c)  115
d)  68
e)  118
 
7). Abhishek and his friend go for a morning walk in a circular park whose circumference is 725m. They start from the same point and walk in opposite directions at 3.5 kmph and 2.75 kmph respectively. After how much time will they meet for the first time?
a)  9 minutes
b)  6.96 minutes
c)  8 minutes
d)  5.96 minutes
e)  None of these
 
8). A cylindrical tub of radius 12 cm contains water up to a depth of 25 cm. A spherical iron ball is dropped into the tub and thus the level of water is raised by 4.75 cm., What is the radius of the iron ball?
a)  11 cm
b)  8 cm
c)  9 cm
d)  13 cm
e)  12 cm
 
9). Anita and Sunita enter into a partnership with capital of Rs.50000 and Rs.40000 respectively. After one month, Sunita withdraws 1/4 part of her capital and after 3 months from starting Anita puts Rs.20000 more. When Sunita withdraws her money Manita joins them with Rs.70000. If at the end of one year there is a profit of Rs.18240, find the share of Manita in the profit.
a)  Rs.7135
b)  Rs. 7615
c)  Rs.7000
d)  Rs.7315
e)  Rs.7495
 
10). A garden is 24m long and 14m wide. There is a path 1m wide outside the garden along its side. If the path is to be constructed with square marble tiles of 16 cm x 20 cm then find the number of tiles required to cover the path.
a)  2550
b)  2450
c)  2600
d)  2510
e)  2500
 
Solution:
1). D)1st winner can he selected in ways =15C1= 15
2nd winner can be selected in ways =14C1= 14
3rd winner can be selected in ways =13C1 = 13
Total no. of ways = 15 14 x 13 = 2730
 
2). C)Let Sharmaji’s income be 9x and Pandeyji’s income be 4x.
Let Sharmaji’s expenditure be 7y and Pandeyji’s expenditure be 3y.
 Now, according to the question,
9x — 7y = 2000 … (i)
 4x — 3y = 2000 …..(ii)
 Equation (i) x 3 — (ii) x 7 We of find x = 8000
1 = 8000
4 = 8000 x 4 = Rs.32000
Pandeyji’s income = Rs.32000
 
3). A)There are 12 letters in PANCHATANTRA. A is repeated 4 times, N for 2 times and T for 2 times
So, n(S) = 12! / 4!2!2!
Now, R and P can be arranged in 2! ways. The ten letters between R and P can be
arranged in 10! / 4!2!2! ways
So, n(E) =(10!/ 4!2!2!) x 2! = 10!/4!2!
Reqd probability = (10!/4!2! ) ÷ (12! /4!2!2! ) = (10!×2!)/12!
= 2/(11×12) = 1/66
 
4). B)2 children = 1 man
8 children and 10 men = 4 + 10 = 14 men
15 men + 86 boys = 15 men + 43 men = 58 men
58 men finish the work in (14 x 29)/58 = 7 days
 
5). E)Let the amount invested be Rs.x SI = x — 1437
From formula, (x – 1437) = (x × 8 × 5)100
x = (1437×5)/3 = Rs.2395
Therefore he had invested Rs.2395
 
6). B)Let the number of passed candidates be x.
According to the question, 35(160 — x) + 65x = 160 x 56
or. 5600 – 35x + 65x = 8960
x = (8960— 5600) / 30 = 3360/30 = 112
 
7). B)They meet after = (725 × 60) / [(3.5+2.75)1000]
= (725 x 60)/6250 = 6.96 minutes
 
8). B)Volume of the ball = Volume of raised water = ᅲ(12)2 x 4.75
Now, (4/3) ᅲr3 = ᅲ x 144 x 4.75
or r3 = 513 = 512
 r = 8 cm (approximate)
 
9). D)Ratio of capital of Anita, Sunita and Manita is (50000 x 3 + 70000 x9) : (40000 x 1 + 30000 x 11) : (70000 × 11)
78 : 37 : 77
Share of Manita in profit
= [77 / (78 + 37+77) ] x18240 = (77/192) x 18240
= 7315
 
10). E)
Area of path = (16 x 26) – (24 x 14) = 416 — 336 = 80 m2
Area of one tile = 16 × 20 cm2

.•. No of tiles = (80 x100 x100) / (16 x 20) = 2500

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