Crack Dena Bank 2018 – Reasoning Ability Puzzles Day-83

Dear Readers, Bank Exam Race for the Year 2018 is already started, To enrich your preparation here we have providing new series of Practice Questions on Reasoning Puzzles.Candidates those who are preparing for Dena Bank 2018 Exams can practice these questions daily and make your preparation effective.

 

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Direction (1-5): Study following information carefully and answer the questions given below.

Eight friends A, B, C, D, E, F, G and H are born in different months of a year namely January, February, March, April, June, July, August and October but not necessary in the same order. They are like different colours namely Pink, Violet, Indigo, Blue, Green, Yellow, Orange and Red. Consider all persons were born in same year and same date.

Only one person was born between D and the one who likes Green. G was not born in the month which has less than 31 days. As many persons were born between E and the one who likes Violet is/are half the number of persons were born between the one who likes Yellow and F. Two persons were born between the one who likes Red and E, who was not born in the month which has 31 days. A was born in one of the months before the one who likes Red colour. The one who likes Yellow was born immediately before A. F neither likes Green nor likes Orange. Two persons were born between the one who likes Violet and C, who was born in one of the month after June. The one who likes Orange was born immediately before the one who likes Pink. Not more than two and not less than one person born between F and H, who was born after F. D was not born in the month which has maximum number of days. As many persons were born between G and the one who likes Indigo is same as between E and the one who likes Orange.

1). Who among the following likes Pink colour?

a) The one who was born in March

b) The one who was born immediately after G

c) The one who was born in October

d) The one who was born in immediately before F

e) None of these

2). How many persons born between A and the one who likes Green?

a) One

b) Two

c) Three

d) No one

e) More than three

3). Which of the following statements is true?

a) E was born immediately after A

b) D was born in June

c) There are only two persons born between D and G

d) C does not like Orange

e) G born in the month which has 31 days and likes green colour

4). Four of the following alike in a certain way and thus form a group. Which of the following one that does not belong to the group?

a) D-Yellow

b) F-Orange

c) H-Green

d) B-Violet

e) C-Red

5). If ‘E’ is related to ‘Blue’ and ‘F’ is related to ‘Green’ in a certain way. Then in the same way ‘D’ is related to which of the following?

a) Red

b) Violet

c) Yellow

d) Orange

e) None of these

 

Direction (6-10): Study following information carefully and answer the questions given below.

Five students are belongs to different departments viz., CSE, EEE, Mech, Civil, and ECE are standing in 5 different rows.  Each row arranged one above the other and numbered 1 to 5 from bottom to top. They are having different number of cricket balls and bats. The total number of balls and bats is 840.

Only one row between the students belongs to ECE and EEE. The person who is standing in Row-4 has 75 balls. There are totally 249 balls and bats kept by the person who standing in the Row-1. In the Row-3, the person has either 153 or 156 balls and bats totally. The student who belongs to ECE is not standing in odd numbered row. The student who belongs to EEE does not have equal number of balls and bats. The student who belongs to Civil stand immediately below the row which has equal number of balls and bats. The student who is standing in Row-3 has 66 bats. The sum of the balls and bats of CSE student is 195. One of the students who standing in a row having the total balls and bats of 126 is not immediately above the one who have maximum number of balls and bats together. The CSE student has 21 balls less than the number of balls that Civil student has. The CSE student has 30 bats more than the number of balls that EEE student has. The student who is standing in Row-3 has not less than 90 balls. The CSE student is standing in odd numbered row.

6. Which of the following combinations are correct?

  1. CSE-114 bats
  2. Mech-90 bats
  3. CSE-114 balls
  4. Civil-114 balls
  5. None in correct

7. EEE student is standing in which of the following rows?

  1. Row-2
  2. Row-4
  3. Immediate above the student who belongs to Civil.
  4. Immediate below the student who belongs to Mech.
  5. None of these

8. How many rows are there between the one having 114 balls and the one having 57 balls?

  1. One
  2. Three
  3. Two
  4. No one
  5. None of these

9. Find the sum of the balls which the student belong to Civil has and the bats which the student belong to EEE department is equal to?

  1. Nine less than CSE student’s total number of balls and bats together
  2. Above the total of Civil student
  3. Equal to the CSE students total
  4. 175
  5. None of these

10. Which department student has equal number of balls and bats?

  1. CSE
  2. ECE
  3. Mech
  4. Civil
  5. None of these

 

Answers:

Direction (1-5)

  1. Answer: c
  2. Answer: b
  3. Answer: e
  4. Answer: d
  5. Answer: a

 

Direction (6-10):

Explanation:

Row Department Bats Balls Total
5 CSE 81 114 195
4 EEE 51 75 126
3 Mech 66 90 156
2 ECE 57 57 114
1 Civil 114 135 249

 

  • There are totally 249 balls and bats kept by the person who standing in the Row-1.
  • The student who standing in Row-3 has 66 bats.
  • The person who standing in Row-4 has 75 balls.
  • Only one row between the students belongs to ECE and EEE.
  • The student who belongs to ECE is not standing in odd numbered row.

Now we have 2 Cases.

Case 1:

Row Department Bats Balls Total
5
4 ECE 75
3 66
2 EEE
1 249

 

Case 2:

Row Department Bats Balls Total
5
4 EEE 75
3 66
2 ECE
1 249

 

  • The student who standing in Row-3 has not less than 90 balls.
  • In the Row-3, the person has either 153 or 156 balls and bats totally.
  • The sum of the balls and bats of CSE student is 195.
  • The CSE student is standing in odd numbered row.
  • Hence CSE student standing in row-5.

Case 1:

Row Department Bats Balls Total
5 CSE 195
4 ECE 75
3 66 90 156
2 EEE
1 249

 

Case 2:

Row Department Bats Balls Total
5 CSE 195
4 EEE 75
3 66 90 156
2 ECE
1 249

 

  • One of the students who standing in a row having the total balls and bats of 126 is not immediately above the one who have maximum number of balls and bats together.
  • Hence the overall total of balls and balls is 840.
  • 840-(249-126-195-156)=114
  • Therefore one of another row has 114 balls and bats.
  • Hence 126 fixed in row-4 and 114 is in row-2.
  • In Row-4: 126-75(balls)=51 bats.

Case 1:

Row Department Bats Balls Total
5 CSE 195
4 ECE 51 75 126
3 66 90 156
2 EEE 114
1 249

 

Case 2:

Row Department Bats Balls Total
5 CSE 195
4 EEE 51 75 126
3 66 90 156
2 ECE 114
1 249

 

  • One of the rows contains equal number of bats and balls.
  • So the even number only divided equally (114/2=57).
  • Row-2 contains the even number of total.
  • Then the Row-2 have 57 balls and bats.
  • The student who belongs to EEE does not have equal number of balls and bats. Hence Case 1 was dropped.
  • The student who belongs to Civil standing immediately below the row which has equal number of balls and bats.
  • Hence Civil student standing in Row-1 and Mech student in Row-3.

Case 2:

Row Department Bats Balls Total
5 CSE 195
4 EEE 51 75 126
3 Mech 66 90 156
2 ECE 57 57 114
1 Civil 249

 

  • The CSE student has 30 bats more than the number of balls that EEE student has.
  • Hence CSE students have 81(30+51) bats.
  • The CSE student has 21 balls less than the number of balls that Civil student has.
  • Civil student have 114+21 balls=135 balls.
  • The number of bats having Civil students is equal to the total number of balls and bats have ECE students.

Case 2:

Row Department Bats Balls Total
5 CSE 81 114 195
4 EEE 51 75 126
3 Mech 66 90 156
2 ECE 57 57 114
1 Civil 114 135 249

 

  1. Answer: c
  2. Answer: b
  3. Answer: c
  4. Answer: a
  5. Answer: b

 

Daily Practice Test Schedule | Good Luck

Topic Daily Publishing Time
Daily News Papers & Editorials 8.00 AM
Current Affairs Quiz 9.00 AM
Quantitative Aptitude “20-20” 11.00 AM
Vocabulary (Based on The Hindu) 12.00 PM
General Awareness “20-20” 1.00 PM
English Language “20-20” 2.00 PM
Reasoning Puzzles & Seating 4.00 PM
Daily Current Affairs Updates 5.00 PM
Data Interpretation / Application Sums (Topic Wise) 6.00 PM
Reasoning Ability “20-20” 7.00 PM
English Language (New Pattern Questions) 8.00 PM

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