Quadratic Equation Questions for SBI/ IBPS PO Prelims Exam 2021 – PDF Download

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Directions (01-10): In each question, two equations numbered I and II are given. You have to solve both the equations and mark an appropriate answer.

1) I) 5x – 4y = 83

II) 6x + 3y = 45

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


2) I) x2 + 26x + 153=0

II) y2+ 117=406

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


3)
I) 2x2 – 28x + 96=0

II)y2– 22y + 96=0

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


4) I)
 2x2 – 30x + 88=0

II)3y2– 30y + 48=0

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


5) I) 5x – 6y = -3

II) 3x + 4y = -17

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


6) I)
 x2 + 21x + 54 = 0

II)2y2 + 25y + 23 = 0

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


7) I) 6x² + 7x + 2 = 0

II) 2y² – 3y – 2 = 0

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


8) I)
 3x2 – 24x + 48=0

II)y2– 14y + 45=0

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


9) I)
 x2 + 36x + 323=0

II)y2+ 43y + 462=0

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


10) I) 
x2 + 6x – 27=0

II)3y2-18y + 27=0

a)  x < y

b)  x ≥ y

c)  x > y

d)  x ≤ y

e)  Relation between x and y can’t be established


Answers :

1) Answer: C

I) 5x – 4y = 83     ..(i)

II) 6x + 3y = 45      …(ii)

Solving equation (i)×3 + (ii)×4, we get

(15x – 12y = 249) + (24x + 12y = 180)

x = (429/39) = 11

Putting the value of x in equation (i), we get

55 – 4y = 83

-4y = 83-55

y = -28/4 = -7

Hence x> y


2) Answer: E

x2 + 26x + 153 = 0

x2 + 17x + 9x + 153 = 0

x(x + 17) + 9(x + 17) = 0

(x + 9)(x + 17) = 0

x = -17, -9

y2 + 117 = 406

y2 = 289

y = -17, 17

Relationship cannot be established between x and y.


3) Answer: E

2x2 – 28x + 96=0

2x2 – 16x – 12x + 96=0

2x(x – 8) – 12(x – 8)=0

(2x – 12)(x – 8)=0

X=6, 8

y2 – 22y + 96=0

y2 – 16y – 6y + 96=0

y(y – 16) – 6(y – 16)=0

(y – 6)(y – 16)=0

Y = 6, 16

Relationship between x and y cannot established.


4) Answer: E

2x2 – 30x + 88=0

2x2 – 22x – 8x + 88=0

2x(x – 11) – 8(x – 11)=0

(2x – 8) (x – 11)=0

x=4, 11

3y2 – 30y + 48=0

3y2 – 24y – 6y + 48=0

3y(y – 8) – 6(y – 8)=0

(3y – 6) (y – 8)=0

y=2, 8

Hence Relationship between x and y cannot be established.


5) Answer: A

5x – 6y = -3 —-> (1)

3x + 4y = -17 —> (2)

By solving the equation (1) and (2), we get,

x = -3, y = -2

x < y


6) Answer: E

x2+21x+54=0

x2+18x+3x+54=0

x(x+18)+3(x+18)=0

(x+3)(x+18)=0

x=-3, -18

2y2+25y+23=0

2y2+23y+2y+23=0

y(2y+23)+1(2y+23)=0

(y+1)(2y+23)=0

y=-1, -11.5

Relation between x and y can’t be established


7) Answer: D

I) 6x² + 7x + 2 = 0

6x² + 4x + 3x + 2 = 0

2x(3x + 2) + 1(3x + 2) = 0

(3x + 2) (2x + 1) = 0

x = -2/3, 1/2 = -0.66, -0.5

II) 2y² – 3y – 2 = 0

2y² – 4y + y + 2 = 0

2y(y – 2) + 1(y – 2) = 0

(2y+1) (y-2) = 0

y=-1/2, 2 = 2, -0.5

Hence, x ≤y


8) Answer: A

3x2 – 24x + 48=0

3x2 –12x – 12x + 48=0

3x(x – 4) – 12(x – 4)=0

(3x – 12)(x – 4)=0

x=4, 4

y2 – 14y + 45=0

y2 – 9y – 5y + 45=0

y(y – 9) – 5(y – 9)=0

(y – 5)(y – 9)=0

y=5, 9

x < y


9) Answer: C

x2 + 36x + 323=0

x2 + 17x + 19x + 323=0

x(x + 17) + 19(x + 17)=0

(x + 19) (x + 17)=0

x=-19, -17

y2 + 43y + 462=0

y2 + 21y + 22y + 462=0

y(y + 21) + 22(y + 21)=0

(y + 22)(y + 21)=0

y=-22, -21

x > y


10) Answer: D

x2 + 6x – 27=0

x2 + 9x – 3x – 27=0

x(x + 9) – 3(x + 9)=0

(x – 3)(x + 9)=0

x=3, -9

3y2 -18y + 27=0

3y2 – 9y – 9y + 27=0

3y(y – 3) – 9(y – 3)=0

(3y – 9)(y – 3)=0

y=3, 3

x ≤ y

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