# Quantitative Aptitude Questions (Boats and Streams) for SBI Clerk / IDBI Executive 2018 Day-59

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June/July 2018. To enrich your preparation here we have providing new series of Boats and Streams- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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1) A boat takes 26 hours for travelling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 4 km/hr and the speed of the boat in still water is 10 km/hr, what is the distance between A and B?
A) 210km
B) 185km
C) 140km
D) 168km
E) None of these

2) A man takes thrice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is?
A) 2:1
B) 3:2
C) 1:2
D) 2:3
E) None of these

3) Speed of a man in still water is 5 km/hr and the river is running at 3km/hr. The total time taken to go to a place and come back is 10 hours. What is the distance travelled?
A.10 km
B.16 km
C.24 km
D.32 km
E.36 km

4) A boat running upstream takes 9 hours 48 minutes to cover a certain distance, while it takes 7 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?
A.5:2
B.7:4
C.6:1
D.8:3
E.2:5

5) A Boat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?

1. 6 Km/hr
2. 9 Km/hr
3. 12 Km/hr
4. 15 Km/hr
5. None of these

6) A boat can travel 3.5km upstream in 14min. If the ratio of the speed of the boat in still water to the speed of the stream is 7:2. How much time will the boat take to cover 36km downstream?
A) 65min
B) 80min
C) 75min
D) 70min
E) None

7) A Ship of Length 300m traveling from point A to B downstream passes a Ghat along the river in 18 sec, while in return it passes the same Ghat in 24 sec. If the rate of current is 9 Km/hr. Then what is the length of the Ghat?

1. 50 m
2. 60 m
3. 80 m
4. 100 m
5. Cannot be determined

8) A Boat took 8 hours less to travel a distance downstream than to travel the same distance upstream. If the speed of a boat in still water is 9 Km/hr and speed of a stream is 3 Km/hr. In total how much distance traveled by boat?

1. 96 Km
2. 144 Km
3. 164 Km
4. 192 Km
5. 216 Km

9) A man can row 40 km/hr in still water and the river is running at 10 km/hr. If the man takes 2 hr to row to a place and back, how far is the place?
A) 38km
B) 37.5km
C) 40.75km
D) 41km
E) None of these

10) A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?
A) 5:4
B) 8:3
C) 7:6
D) 4:5
E) None of these

Downstream speed = 10+4 = 14
Upstream speed = 10-4 = 6
Now total time is 26 hours
If distance between A and B is d, then distance BC = d/2
Now distance/speed = time, so
d/14 + (d/2)/6 = 26

d/14 + d/12 = 26
13d/84=26
Solve, d = 168 km

Speed of downstream : Speed of upstream = 3 : 1 (3x,x)

The ratio of the speed of the boat (in still water) and the stream is,
= > (3x+x)/2: (3x-x)/2
= > 4x/2:2x/2
= > 2:1
Down speed= 5+3= 8
Up speed= 5-3=2
Let distance travelled = X
(X/8) + (X/2) = 10
X= 16 km

(Or)

Distance = Time *[(Speed of Still water2 – speed of Stream2)/(2*Speed of Still water)]

= > distance = 10*[(52 – 32)/(2*5)]

= > distance = 10*[(25-9)/10]

= > distance = 16 km

Let upstream be x km/hr and that downstream be y km/hr.
Then, distance covered upstream in 9 hrs 48 min = Distance covered downstream in 7 hrs.
X*(49/5) =7y
49x/5 =7y
Y=7x/5
Required ratio (y+x)/2 : (y-x)/2
= > 12x/10 : 2x/10
= > 6 : 1

Let speed of still water be s km/hr,

Speed of downstream = s+3

Speed of upstream = s-3

128/60 = 48/(s-3) – 48/(s+3)

128/60 = 48(1/(s-3) – 1/(s+3))

128/(60*48) = s+3-(s-3)/[(s-3)(s+3)]

4/90 = s+3-s+3/[s2+3s-3s-9]

(4/90)*(1/6) = 1/[s2 – 9]

S2 – 9 = 135

S2 = 144

S = 12 km/hr

Speed of still water : stream = 7x : 2x
Downstream =7x + 2x = 9x; upstream = 7x – 2x = 5x
Upstream speed = 3.5*60/14 = 15km/hr
5x = 15
x = 3
Speed of downstream = 9*3 = 27 km/hr
Time taken for 36km = 36*60/27 = 80min

Let the speed of still water be S km/hr,
(S+9)*18 = (S-9)*24
S =63

Speed of downstream = 63 + 9 = 72 km/hr

Speed of upstream = 63 – 9 = 54 km/hr

(300+x)/ (72*5/18) = 18
x =60 m (or)

(300+x)/ (54*5/18) = 24

X = 60 m

Speed of downstream = 9 + 3 = 12 km/hr

Speed of upstream = 9-3 = 6 km/hr

According to the question,
8 =D/6 – D/12

8 = (2D – D)/12

8 = D/12
D =96 km

Speed of Still water (u) =40 km/hr, Speed of stream (v) =10 km/hr
D = t[(u2-v2)/2u] = 2*[(402-102)/2*40] = 2*(1600-100)/80
= 2*1500/80

=>37.5km
Let upstream be x km/hr and that downstream be y km/hr.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
X*(44/5) =4y
44x/5 =4y
Y=11x/5
Required ratio (y+x)/2 : (y-x)/2
16x/10 : 6x/10
8:3

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