Quantitative Aptitude Questions (Data Interpretation) for SBI PO Mains 2018 Day-100

Dear Readers, SBI is conducting Online Examination for the recruitment of probationary officer. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI PO Mains Exams can practice these Quantitative Aptitude average questions daily and make your preparation effective.

Practice Aptitude Questions (Data Interpretation) Day-100

Click “Start Quiz” to attend these Questions and view Solutions

Click here to view Quantitative Aptitude Questions in Hindi

 

Direction (Q.1-5): Read the following graph carefully and answer the Questions below:

CategoryTotal Students from school A% of boys in School  ATotal boys in school in A & B together Probability of choosing 1 girl for  a committee
I80045%6004/7
II65050%65068/133
III90045%75016/31
IV55060%5001/2
V65040%45016/25

 

  1. Find the probability of selecting 2 girls to form a committee from school A and B together in category IV
  1. 550/1998
  2. 600/1998
  3. 540/1998
  4. 499/1998
  5. None of these

2. Find the probability of choosing 2 boys from the entire category and which one is greater?

  1. Category I
  2. Category II
  3. Category III
  4. Category V
  5. Cannot be determined
  1. In how many ways a committee consisting of 3 men or 2women can be formed from category V?
  1. 15456000
  2. 14586000
  3. 15406000
  4. 16452000
  5. None of these
  1. If School A and School B conducts an annual function for all students. In Dance competition, 10% of total boys are participated; find the probability that boys from category III won the competition?
  1. 17/59
  2. 15/59
  3. 44/59
  4. 42/59
  5. None of these
  1. Find the number of ways selecting two girls from school A and B together in category II
  1. 421750
  2. 461720
  3. 471570
  4. 487580
  5. None of these

 

Directions (Q.6-10) Study the following information carefully and answer

the given questions:

 

  1. A rectangular lawn has two roads each 10 m wide running in the middle of it, one parallel to the length and the other parallel to the breadth. Find the cost of gravelling them at Rs. 35 per square metre.
  1. 22500
  2. 17500
  3. 25000
  4. 16000
  5. None of these

7. Four circles having equal radius drawn with the centres at the four corners of the square. Each circle touches other two adjacent circles. Find the cost of gravelling remaining area of the square, if it is gravelled at the rate of 25 per sq meter?

  1. 1280
  2. 1890
  3. 1050
  4. 1250
  5. None of these
  1. A Circular path is surrounding the circular plot is being gravelled at a total cost of Rs. 1848 at Rs. 4 per square meter. Find the width of the path.
  1. 10 meter
  2. 12 meter
  3. 9 meter
  4. 7 meter
  5. None of these

9. An equilateral triangle is inscribed into the square. Find the perimeter and area of equilateral triangle.

  1. 49 √3 sq m and 42 m
  2. 52 √3 sq m and 36 m
  3. 49 √2 sq m and 54 m
  4. 52 √2 sq m and 64 m
  5. None of these
  1. If the breadth of the parallelogram is increased by 40 % and the height is decreased by 20 %. Find the new area of a parallelogram and also find the total cost to fence the place if the cost of fencing is Rs. 12 per meter.
  1. 144 sq. m, 1295
  2. 324 sq. m, 562
  3. 336 sq. m, 888
  4. 196 sq. m, 761
  5. None of these

 

Answers:

Direction (1-5):

CategorySchool ASchool B
TotalBoys Girls Total Boys Girls
I800360440240
II650325325325
III900405495345
IV 550330220170
V650260390190

 

 

Category I:

Probability of selecting a girl from total = (440+x)C1/(800+240+x)C1 = 4/7

(440+x)/(1040+x) =4/7

=>3080+7x=4160+4x

=>3x= 1080

=>x=360

Total students from school B in category I = 360+240= 600

Similarly find all the categories

CategorySchool ASchool B
TotalBoys Girls Total Boys Girls
I800360440600240360
II650325325680325355
III900405495650345305
IV 550330220450170280
V650260390600190410

 

  1. Answer: D

(220+280)C2/ (550+450) C2

=> (500*499)/(1000*999)

=> 499/1998

= 499/1998

  1. Answer: B

Category I:

(360+240)C2 / (360+440+240+360)C2 =600C2 /1400C2

= 600*599 /1400*1399 =1797 /9793

Category II:

= 650C2/1330C2 = 650*649 /1330*1329 = 42185 /176757

Category III:
=750C2 / 1550C2 = 11235/48019

Category V:

=450C2/1250C2 =4041 /31225

  1. Answer: C

= (260+190) C3+ (390+410) C2= 15086400 +319600 = 15406000

  1. Answer: B

Total number of boys from School A and B for all category = 2950

Number of boys participated = 2950*10/100 = 295

Number of boys in category III = 750*10/100 = 75

Probability = 75/295 = 15/59

  1. Answer: B

Number of ways = 680C2

= 680*679

= 461720

Directions (Q.6-10)

  1. Answer b

Length of rectangle = 35 m, Breadth = 25 m

Area is to be gravelled = Area of ABCD + Area of PQRS – Area of EFGH

= > (35*10) + (25 * 10) – (10*10)

= > 350 + 250 – 100

= > 500 Sq m

The cost of gravelling them at Rs, 35 per sq m

Total cost = 500 * 35 = Rs. 17500

  1. Answer c

Here radius of the circle(r) = side of the square/2 = a/2

Remaining area of the square = a2 – πr2 = a2 – π(a/2)2

= > a2 – π(a/2)2

= > 142 – (22/7) *(7*7)

= > 196 – 154

= > 42 sq meter

The cost of gravelling = 42 * 25 =Rs. 1050

  1. Answer d

Radius of the circular plot = 7 m

Area of the circular path = 1848/4 = 462

Area of the path = π(r+x)2 – πr2 (Here x is the width of the path)

= > (22/7) [(7+x)2 – 72]

= > (22/7) [49 + 14x + x2 – 49]

= > (22/7) [14x + x2]

(22/7) [14x + x2] = 462

14x + x2 = 462 *(7/22)

14x + x2 = 147

X2 + 14x – 147 = 0

(x+21) (x – 7) =0

X = 7 meter

  1. Answer a

Side of the square = 14 m = side of the triangle

Perimeter of equilateral triangle = 3a = 3*14 = 42 m

Area of equilateral triangle = (√3/4) a2

= > (√3/4) * 196

= > 49√3 sq meter

  1. Answer c

Breadth = 15, Height = 20

Area of parallelogram = bh

New area = (15*140/100)*(20*80/100)

= > 21 * 16

= > 336 sq meter

Perimeter of parallelogram = 2 (b + h)

= > 2* (21 + 16) = 74 meter

Total cost to fence the place

= > 74 * 12

= > Rs. 888

 

Daily Practice Test Schedule | Good Luck

TopicDaily Publishing Time
Daily News Papers & Editorials8.00 AM
Current Affairs Quiz9.00 AM
Quantitative Aptitude “20-20”11.00 AM
Vocabulary (Based on The Hindu)12.00 PM
General Awareness “20-20”1.00 PM
English Language “20-20”2.00 PM
Reasoning Puzzles & Seating4.00 PM
Daily Current Affairs Updates5.00 PM
Data Interpretation / Application Sums (Topic Wise)6.00 PM
Reasoning Ability “20-20”7.00 PM
English Language (New Pattern Questions)8.00 PM

Click Here for More Quantitative Aptitude Questions

 

Be the first to rate this post.

IBPSGuide Recommends Affairs Cloud Current affairs PDF