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Directions (1-5): Given below is a pie chart which shows the percentage distribution of time out of 50 hours for which a person covers a certain distance in river in different fragments of the day.
1). A motorboat covers a certain distance downstream in Monday and returns covering the same distance upstream on Thursday. If the speed of the stream is 6 km/hr, then what was the speed of motorboat in still water?
- 46 km/h
- 162 km/h
- 132 km/h
- 140 km/h
- None of these
2) If A can row a boat in still water at 8 km/hr. If speed of water current is 3/4th of the speed of boat in still water, and he rows downstream in Sunday.
- 8.6 km
- 13.4 km
- 84 km
- 22 km
- None of these
3) The speed of current is what percent of the speed of boat in still water? A boat travels 36 km downstream in the Friday and returns against the current at Tuesday.
4) A man can row at a speed of 5km/h in still water and the speed of water current is 2 km/h. If he rows to a place downstream during Tuesday, and he has to pay Rs. 11 per kilometer to row through the river, then what is the amount that he pays?
- Rs. 808.5
- Rs. 35.8
- Rs. 92.6
- Rs. 81.6
- None of these
5) The ratio of the speed of the boat to that of current is 42 : 5. If the boat goes downstream during Thursday, then it will come back in (approximately)?
- 6.99 h
- 8.89 h
- 9.18 h
- 5.12 h
- 6.05 h
Directions (6-10): Study the following and answer the following questions.
The following table shows that the data of 6 employees of ABC company.
|Employee||Hours per day||Number of days per Month||Wage per day(in Rs)||Monthly salary
6). The employee P is twice as good as the employee R and hence he can finish a work in 10 days less than the employee R, then how much a company has to pay to both of them if they work together to do the same piece of work?
- Rs 13900
- Rs 43000
- Rs 23000
- Rs 21000
- Rs 13000
7). The employee Q does 75% of the work in 18 days, and then he assisted the employee O to finish the work in 4 days. Then the amount paid to the employee O per annum if he would have completed the work alone is approximately what percentage more or less than the employee Q’s one year salary.
8). If N and R together can do a piece of work in 15 days, and they worked for 9 days, then N left. After another 8 days, R finished the remaining work. Then find the total wage received by the employee R if he alone has finished the whole work?
- Rs 34700
- Rs 25000
- Rs 33600
- Rs 22800
- Rs 13200
9). If the employees M, Q and R can do a piece of work in 240 hours, 420 hours and 240 hours respectively, then in how many days can the employee M do the work if he is assisted by Q and R on every third day?
- 14 days
- 15 days
- 34 days
- 18 days
- 17 days
10). The employee P can do a certain work in the same time period in which N and Q together can do the same work. If N and P together could do it in 30 days and Q alone in 60 days, find the ratio of a number of days taken by the employees P to that of the employee N.
1). Answer: b
Time taken to cover the distance downstream in Monday,
t₁ = 13× 50/ 100
= 6.5 hours.
Time taken to cover the distance upstream in Thursday,
t2 = 14× 50 /100 = 7 hours
The speed of stream, = 6 km/h
The speed of motorboat in still water = y ( t2 + t1/ t2 − t1 )
= 6 ( 6.5 + 7 /6.5 − 7 ) = 6 ( 13.5 /0.5 )
= 162 km/h
2). Answer: c
Speed of boat in still water, x = 8 km/h
Speed of water current, y
= 3/ 4 × 8 = 6 km/h
Required distance = 12/100*50*14=84km
3). Answer: d
Downstream speed = 36/ (time taken in Friday)
= 36 /(16 × 50/ 100) =36/ 8 = 4.5 km/h
Upstream speed = 36/ (time taken during Tuesday)
= 36 /( 21 /100 × 50) = 36/ 10.5 = 3.42km/h
Speed of boat in still water = ½* (downstream speed + upstream speed)
= 1/2 (4.5 + 3.42)
= 1/2 (7.9)
= 3.95 km/h
Speed of stream = 1/ 2 (down speed – up speed)
= 1/ 2 (4.5 – 3.42)
Required percentage = 0.54/3.95*100= 13.67%
4). Answer: a
The speed of the man, x = 5 km/h
The speed of water current, y = 2 km/h
Distance covered = 21/100*50*(5+2)= 73.5 km
Required amount = 73.5*11= Rs.808.5
5). Answer: b
Let the speed of the boat be 42x km/h and speed of current be 5x km/h
The boat goes downstream in (14 × 50 /100) h
= 7 h
Distance = speed × time
Distance = 7 × (42x + 5x)
= 47x × 7
Upstream speed = 42x – 5x
= 37x km/h
Time taken = 47x × 7/ 37x
= 8.89 h
6). Answer: a
Given that, the ratio of time taken by the employees P and R= 1:2
If R takes 20 days to complete the work, then the number of days taken by P to complete the work= 10 days
Now, the part of the work completed by employees P and R in 1 day= (1/10+1/20) = 3/20
(i.e) The employees P and R can complete the work in 20/3 days.
Now, the Total amount received by P=945*20/3=Rs 6300
And one day wage of the employee R= 27360/24=Rs 1140
Then Total amount received by the employee R= 1140*20/3=Rs 7600
Hence total amount paid by the company= 6300+7600= Rs 13900
7). Answer: e
Number of days taken by the employee Q to finish the whole work= 18*100/75 =18* 4/3
= 24 days
Now remaining work= 1- ¾= ¼
Thus, ¼ of the work is done by O and Q in 4 days.
Then Whole work can be completed by O and Q in 16 days
Now, work done by O in one day= 1/16-1/24
Now the wage of the employee O for one day= 31860/27=Rs 1180
Then total annual salary received by the employee O for 48 days = 1180*48*12
= Rs 679680
One year salary of the employee Q = 810*24*12 = 233280
Required percentage= (436680/233280)*100
8). Answer: d
Since N and R worked together for 9 days,
The part of the work completed by N and R in 9 days= (1/15)*9=3/5
Now remaining work= 1-3/5= 2/5
(i.e) 2/5 part of the work is done by R in 8 days.
Then whole work will be done by R= 8*5/2
= 20 days
From the table, we have, the Monthly salary of R= Rs 27360
Then salary of the employee per day= 27360/24=Rs 1140
Hence total wage received by the employee R for 20 days= 1140*20=Rs 22800
9). Answer: b
Given that the employee M can finish the work in 240 hours. (i.e) 240/12= 20 days
Similarly, the employee Q can finish the work in 420 hours (i.e) 420/7 = 60 days
And the employee R can finish the work in 240 hours. (i.e) 240/8 = 30 days
The work was done by the employee in 2 days= 1/20*2= 1/10
Then the work was done by the employees M, Q and R=1/20+1/60+1/30
Thus work done in 3 days= 1/10+1/10
Hence The whole work can be completed in 3*5 days.(i.e) 15 days.
10). Answer: e
Given that, Work done by the employees P and N in one day= 1/30 and Q’s one day work= 1/60
Then work done by all the three employees in one day= (1/30+1/60)
Given that, P’s one-day work= work done by N and Q together in one day.
Then we have,
2* (P’s one day work) = 1/20
Then P’s one day work= 1/40
From this we have,
N’s one day work = 1/30-1/40
(i.e) N alone can complete the work in 120 days.
Then required ratio= 40:120
Daily Practice Test Schedule | Good Luck
|Topic||Daily Publishing Time|
|Daily News Papers & Editorials||8.00 AM|
|Current Affairs Quiz||9.00 AM|
|Quantitative Aptitude “20-20”||11.00 AM|
|Vocabulary (Based on The Hindu)||12.00 PM|
|General Awareness “20-20”||1.00 PM|
|English Language “20-20”||2.00 PM|
|Reasoning Puzzles & Seating||4.00 PM|
|Daily Current Affairs Updates||5.00 PM|
|Data Interpretation / Application Sums (Topic Wise)||6.00 PM|
|Reasoning Ability “20-20”||7.00 PM|
|English Language (New Pattern Questions)||8.00 PM|