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- Two pipes A and B can fill a tank in 20 hours and 25 hours respectively, while a third pipe C can empty 70% of the tank in 21 hours. All three pipes are opened in the beginning. After 12 hours C is closed. Find the time in which the tank will be full?
- 13 2/3 hours
- 11 7/8 hours
- 16 ¾ hours
- 15 5/9 hours
- None of these
- Two pipes A and B can fill a tank in 18 hours and 24 hours respectively, while a third pipe can empty 60% of the tank in 18 hours. All three pipes are opened in the beginning. After 12 hours c is closed. Find the time which the tank will be full?
- 14 2/5 hours
- 12 ¾ hours
- 11 5/6 hours
- 13 2/3 hours
- None of these
- Three pipes A, B and C can fill a tank in 10 hours. After working at it together for 3 hours, C is closed and A and B can fill the remaining part in 14 hours. How much time taken by C to fill the tank alone?
- 18 hours
- 20 hours
- 24 hours
- 22 hours
- None of these
- Three pipes A, B, C can fill a cistern in 10, 15, 18 hours respectively. If pipe A is kept open all the time and pipe B and C is opened alternatively for an hour then find in how many hours the tank will be filled?
- 7 hours 25 mins
- 5 hours 40 mins
- 6 hours 12 mins
- 7 hours 48 mins
- None of these
- Pipe A and Pipe B can fill a tank in 10 hours and 15 hours respectively while Pipe C can empty the full tank in 18 hours. If pipe A is opened at 7 am, Pipe B opened at 8:30 am and Pipe C at 10 am, then after 10 am, how much more time will be taken by all three pipes together to fill the tank?
- 7 hour 18 min
- 8 hour 36 min
- 6 hour 42 min
- 5 hour 24 min
- None of these
- P, Q and R can fill the tank in 12, 16 and 24 min respectively. All three began to fill the tank together but P and Q left 3 and 4 min respectively before filling the tank. Find the total time taken by all of them to fill the tank?
- 12 min
- 16 min
- 8 min
- 10 min
- None of these
- Two pipes A and B can fill a tank in 15 minutes and 25 minutes respectively. Both pipes are opened together andpipeBisclosed,5 minutes before the tank is filled completely. Calculate the total time required to fill the tank?
- 11 ¼ min
- 13 3/5 min
- 12 7/8 min
- 14 5/6 min
- None of these
- B is 5/4 times as efficient as A. If A can fill the 3/5 of the tank in 15 min, what fraction of the capacity of the tank would remain incomplete if B can fill the tank independently for 10 min only?
- 2/3
- 1/3
- ¼
- ½
- None of these
- P, Q and R can fill the tank in 15, 18 and 20 min respectively. All three began to fill the tank together but P and Q left 4 and 5 min respectively before filling the tank. In how much time will take to fill the tank?
- 7 22/25 min
- 8 30/31 min
- 7 11/15 min
- 8 4/7 min
- None of these
- Two inlet pipes can fill an empty tank in 15 and 18 hours and one outlet pipe can empty the tank in 20 hours. If all the pipes opened simultaneously, then how many hours required fill the full tank?
- 11 8/11 hours
- 12 5/7 hours
- 13 11/13 hours
- 9 5/9 hours
- None of these
Answers:
1). Answer d
C can empty the tank in = (21/70)*100= 30 hours
Total units of work= 300
A’s one hour work = 300/20 = 15 units
B’s one hour work = 300/25 = 12 units
C’s capacity to empty in one hour = 300/30 = 10 units
When three pipes are opened simultaneously then in one hour they will fill,
(15+12-10) = 17 units
In 12 hours they will fill = 17*12= 204 units
After 12hrs, C will be closed
Time taken by A& B to fill the remaining tank = 96/27 = 3 15/27 = 3 5/9 hours
Total time will be = 12 + 3 5/9 = 15 5/9 hours
2). Answer a
C can empty the tank in =18/60*100= 30 hours
Total units of work= 360
A’s one hour work= 360/18= 20units
B’s one hour work = 360/24= 15 units
C’s capacity to empty in one hour= 360/30= 12 units
When three pipes are opened simultaneously then in one hour they will
(20+15-12)=23 units
In 12 hours they will fill= 23*12= 276 units
After 12 hr, C will be closed
Time taken by A & B to fill the remaining tank = 84/35= 2 2/5 hours
Total time = 12 + 2 2/5 = 14 2/5 hours
3). Answer b
Three pipes A, B and C can fill a tank in 8 hours.
A, B and C’s 1 hour work=1/10
A, B and C’s 3 hour work= 3/10
Remaining work= 1 – (3/10) = 7/10
The remaining part will be filled by A and B in 14 hours. Then,
= > (7/10) *(A+B) = 14
= > (A+B)’s whole work= 14*(10/7) = 20 hr
(A+B)’s 1 hour work= 1/20
A, B and C’s 1 hour work = 1/10
C’s 1 hour work= (A+B+C) – (A+B)
= > (1/10) – (1/20)
= > 1/20
C can fill the tank in 20 hours.
4). Answer c
Total units of work= 90
A’s one hour work = 9
B’s one hour work = 6
C’s one hour work = 5
Work done by three pipes in 2 hours = 15 + 14 = 29 units
Work done in 6 hours= 29*3 = 87 units
Remaining will be done by pipe A and B = 3/15 = 1/5 hours
Total time required= 6 1/5 hours = 6 hours 12 mins
5). Answer d
Let capacity of tank = 90 lit (LCM of 10, 15, 18)
A fills 90/10 = 9 liter/hour
B fills 90/15 = 6 liter/hour
C empties 90/18 = 5 liter/hour
Till 10 am 9*3 + 6*1.5 = 27 + 9 = 36 liters
Remaining volume to be filled =90 – 36 = 54 liters
After 10 am, when all pipes are opened. 9 + 6 – 5= 10 liters/hr is filled.
Required time = 54/10 = 5 4/10 = 5 2/5 hour = 5 hour 24 min
6). Answer c
(x-3)/12 + (x-4)/16 + x/24 =1
(4x – 12 + 3x – 12 + 2x)/48 = 1
9x – 24 = 48
9x = 72
X = 8 min
7). Answer a
Let total capacity = 75 litres (LCM of 15 and 25)
A = 5 litres/min
B = 3 litres/min
A+B fill 75 litres
A can fill 5*5 = 25 litres in 5 min
But B was closed 5 min before the tank is filled. So A+B together filled (75-25) = 50 litres
50 litres can be filled by A + B in,
= > (50/8) = 6 1/4
Total time = 6 1/4 + 5 = 11 ¼ min
8). Answer d
B is 5/4 times as efficient as A. So,
A and B’s time =>5 : 4
A can fill the 3/5 of the tank in 15 min
=> (3/5) * work = 15 min
=> Whole work = 25 min
A takes 25 min to fill the tank, So, B takes,
=> 5’s =25
=>1’s = 5
B can fill the tank in, 20 min
B can fill the tank independently for 10 min only.
B’s 10 min work = 10/20 = 1/2
Remaining = 1- 1/2 = ½
Half of the tank will remain incomplete.
9). Answer b
(x – 4)/15 + (x – 5)/18 + x/20 =1
(12x – 48 +10x – 50 + 9x)/180 =1
31x – 98 = 180
31x = 278
X = 278/31 = 8 30/31 min
10). Answer c
If all the pipes are opened simultaneously, then in,
= > (1/15) + (1/18) – (1/20)
= > (12 + 10 – 9)/180
= > 13/180
Required hours = 180/13 = 13 11/13 hours
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