# Quantitative Aptitude Questions (Pipes and Cisterns) for SBI PO 2018 Day-132

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Dear Readers, SBI is conducting Online Examination for the recruitment of probationary officer. To enrich your preparation here we have providing new series of Pipes and Cisterns- Quantitative Aptitude Questions. Candidates those who are appearing in SBI PO Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

Practice Aptitude Questions (Pipes and Cisterns) Day-132

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1. Two pipes A and B can fill a tank in 20 hours and 25 hours respectively, while a third pipe C can empty 70% of the tank in 21 hours. All three pipes are opened in the beginning. After 12 hours C is closed. Find the time in which the tank will be full?
1. 13 2/3 hours
2. 11 7/8 hours
3. 16 ¾ hours
4. 15 5/9 hours
5. None of these
1. Two pipes A and B can fill a tank in 18 hours and 24 hours respectively, while a third pipe can empty 60% of the tank in 18 hours. All three pipes are opened in the beginning. After 12 hours c is closed. Find the time which the tank will be full?
1. 14 2/5 hours
2. 12 ¾ hours
3. 11 5/6 hours
4. 13 2/3 hours
5. None of these
1. Three pipes A, B and C can fill a tank in 10 hours. After working at it together for 3 hours, C is closed and A and B can fill the remaining part in 14 hours. How much time taken by C to fill the tank alone?
1. 18 hours
2. 20 hours
3. 24 hours
4. 22 hours
5. None of these
1. Three pipes A, B, C can fill a cistern in 10, 15, 18 hours respectively. If pipe A is kept open all the time and pipe B and C is opened alternatively for an hour then find in how many hours the tank will be filled?
1. 7 hours 25 mins
2. 5 hours 40 mins
3. 6 hours 12 mins
4. 7 hours 48 mins
5. None of these
1. Pipe A and Pipe B can fill a tank in 10 hours and 15 hours respectively while Pipe C can empty the full tank in 18 hours. If pipe A is opened at 7 am, Pipe B opened at 8:30 am and Pipe C at 10 am, then after 10 am, how much more time will be taken by all three pipes together to fill the tank?
1. 7 hour 18 min
2. 8 hour 36 min
3. 6 hour 42 min
4. 5 hour 24 min
5. None of these
1. P, Q and R can fill the tank in 12, 16 and 24 min respectively. All three began to fill the tank together but P and Q left 3 and 4 min respectively before filling the tank. Find the total time taken by all of them to fill the tank?
1. 12 min
2. 16 min
3. 8 min
4. 10 min
5. None of these
1. Two pipes A and B can fill a tank in 15 minutes and 25 minutes respectively. Both pipes are opened together andpipeBisclosed,5 minutes before the tank is filled completely. Calculate the total time required to fill the tank?
1. 11 ¼ min
2. 13 3/5 min
3. 12 7/8 min
4. 14 5/6 min
5. None of these
1. B is 5/4 times as efficient as A. If A can fill the 3/5 of the tank in 15 min, what fraction of the capacity of the tank would remain incomplete if B can fill the tank independently for 10 min only?
1. 2/3
2. 1/3
3. ¼
4. ½
5. None of these
1. P, Q and R can fill the tank in 15, 18 and 20 min respectively. All three began to fill the tank together but P and Q left 4 and 5 min respectively before filling the tank. In how much time will take to fill the tank?
1. 7 22/25 min
2. 8 30/31 min
3. 7 11/15 min
4. 8 4/7 min
5. None of these
1. Two inlet pipes can fill an empty tank in 15 and 18 hours and one outlet pipe can empty the tank in 20 hours. If all the pipes opened simultaneously, then how many hours required fill the full tank?
1. 11 8/11 hours
2. 12 5/7 hours
3. 13 11/13 hours
4. 9 5/9 hours
5. None of these

C can empty the tank in = (21/70)*100= 30 hours

Total units of work= 300

A’s one hour work = 300/20 = 15 units

B’s one hour work = 300/25 = 12 units

C’s capacity to empty in one hour = 300/30 = 10 units

When three pipes are opened simultaneously then in one hour they will fill,

(15+12-10) = 17 units

In 12 hours they will fill = 17*12= 204 units

After 12hrs, C will be closed

Time taken by A& B to fill the remaining tank = 96/27 = 3 15/27 = 3 5/9 hours

Total time will be = 12 + 3 5/9 = 15 5/9 hours

C can empty the tank in =18/60*100= 30 hours

Total units of work= 360

A’s one hour work= 360/18= 20units

B’s one hour work = 360/24= 15 units

C’s capacity to empty in one hour= 360/30= 12 units

When three pipes are opened simultaneously then in one hour they will

(20+15-12)=23 units

In 12 hours they will fill= 23*12= 276 units

After 12 hr, C will be closed

Time taken by A & B to fill the remaining tank = 84/35= 2 2/5 hours

Total time = 12 + 2 2/5 = 14 2/5 hours

Three pipes A, B and C can fill a tank in 8 hours.

A, B and C’s 1 hour work=1/10

A, B and C’s 3 hour work= 3/10

Remaining work= 1 – (3/10) = 7/10

The remaining part will be filled by A and B in 14 hours. Then,

= > (7/10) *(A+B) = 14

= > (A+B)’s whole work= 14*(10/7) = 20 hr

(A+B)’s 1 hour work= 1/20

A, B and C’s 1 hour work = 1/10

C’s 1 hour work= (A+B+C) – (A+B)

= > (1/10) – (1/20)

= > 1/20

C can fill the tank in 20 hours.

Total units of work= 90

A’s one hour work = 9

B’s one hour work = 6

C’s one hour work = 5

Work done by three pipes in 2 hours = 15 + 14 = 29 units

Work done in 6 hours= 29*3 = 87 units

Remaining will be done by pipe A and B = 3/15 = 1/5 hours

Total time required= 6 1/5 hours = 6 hours 12 mins

Let capacity of tank = 90 lit (LCM of 10, 15, 18)

A fills 90/10 = 9 liter/hour

B fills 90/15 = 6 liter/hour

C empties 90/18 = 5 liter/hour

Till 10 am 9*3 + 6*1.5 = 27 + 9 = 36 liters

Remaining volume to be filled =90 – 36 = 54 liters

After 10 am, when all pipes are opened. 9 + 6 – 5= 10 liters/hr is filled.

Required time = 54/10 = 5 4/10 = 5 2/5 hour = 5 hour 24 min

(x-3)/12 + (x-4)/16 + x/24 =1

(4x – 12 + 3x – 12 + 2x)/48 = 1

9x – 24 = 48

9x = 72

X = 8 min

Let total capacity = 75 litres (LCM of 15 and 25)

A = 5 litres/min

B = 3 litres/min

A+B fill 75 litres

A can fill 5*5 = 25 litres in 5 min

But B was closed 5 min before the tank is filled. So A+B together filled (75-25) = 50 litres

50 litres can be filled by A + B in,

= > (50/8) = 6 1/4

Total time = 6 1/4 + 5 = 11 ¼ min

B is 5/4 times as efficient as A. So,

A and B’s time =>5 : 4

A can fill the 3/5 of the tank in 15 min

=> (3/5) * work = 15 min

=> Whole work = 25 min

A takes 25 min to fill the tank, So, B takes,

=> 5’s =25

=>1’s = 5

B can fill the tank in, 20 min

B can fill the tank independently for 10 min only.

B’s 10 min work = 10/20 = 1/2

Remaining = 1- 1/2 = ½

Half of the tank will remain incomplete.

(x – 4)/15 + (x – 5)/18 + x/20 =1

(12x – 48 +10x – 50 + 9x)/180 =1

31x – 98 = 180

31x = 278

X = 278/31 = 8 30/31 min

If all the pipes are opened simultaneously, then in,

= > (1/15) + (1/18) – (1/20)

= > (12 + 10 – 9)/180

= > 13/180

Required hours = 180/13 = 13 11/13 hours

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 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Quantitative Aptitude “20-20” 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM General Awareness “20-20” 1.00 PM English Language “20-20” 2.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability “20-20” 7.00 PM English Language (New Pattern Questions) 8.00 PM