# Quantitative Aptitude Questions (Probability) for SBI Clerk 2018 Day-17

## Quantitative Aptitude Questions (Probability) for SBI Clerk 2018 Day-17:

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from March 2018. To enrich your preparation here we have providing new series of Probability – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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## Daily Practice Test Schedule | Good Luck

 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Logical Reasoning 10.00 AM Quantitative Aptitude “20-20” 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM Static GK Quiz 1.00 PM English Language “20-20” 2.00 PM Banking Awareness Quiz 3.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability “20-20” 7.00 PM English Language (New Pattern Questions) 8.00 PM General / Financial Awareness Quiz 9.00 PM

Q.1) A basket contains x black, 4 red and 5 green colour balls. One ball is taken randomly and the probability of getting a green colour ball is 1/3, and then finds the no. of balls in the basket

1. 12
2. 14
3. 15
4. 18
5. 20

Q.2) A bag contains x+4 pink, 6 green and 8 brown colour balls; if two balls are taken random and the probability of getting both are green colour balls is 5/92, then find the difference between the no. of pink colour balls and the no. of brown colour balls

1. 1
2. 2
3. 3
4. 4
5. 0

Q.3) Two dice are thrown simultaneously. What is the difference between probabilities of getting sum of the dice is divisible by 5 and the difference of the dice is divisible by 2?

1. 7/36
2. 1/3
3. 1/18
4. 1/9
5. 5/36

Q.4) Bucket A contains x green and x+5 black balls and Bucket B contains (x-2) green and (2x-4) black colour balls. Find the total number of balls in the bucket B if one ball is taken from bucket A and the probability of getting one green ball is 1/3

1. 8
2. 9
3. 6
4. 5
5. 12

Q.5) Two cards are drawn from a pack of cards without replacement, what is the probability of getting an odd number card in red colour and an even number card in black colour?

1. 4/663
2. 3/220
3. 7/663
4. 5/663
5. None of these

Q.6) Probability of Raman, Dinesh and Hari speaking truth is 1/3, 2/5 and ¾. Find the probability of at most one of them speaks truth.

1. 13/60
2. 19/60
3. 17/60
4. 27/60
5. 31/60

Q.7) Bucket P contains 4 green, x black and 5 red colour balls and probability of getting one black colour ball is 2/5. Bucket Q contains (x+2) black, (x+3) pink and (x-3) red colour balls, if two balls are taken from bucket Q then find the probability of getting at least one is pink colour ball

1. 3/38
2. 11/38
3. 27/38
4. 25/38
5. 23/38

Directions (Q. 8-9) Study the following information carefully and answer the given questions:

 Box Red Pink Black 1 4 6 5 2 5 5 5

Q.8) Three balls are taken from either of the box, what is the probability of getting at least two pink colour balls?

1. 53/182
2. 52/183
3. 57/182
4. 51/182
5. None of these

Q.9) Three balls are taken from either of the box, what is the probability of getting at most two balls black colour?

1. 87/91
2. 88/91
3. 7/90
4. 89/91
5. None of these

Q.10) Two dice thrown simultaneously, what is the ratio of the probability of getting sum of the dice is more than 10 to the sum of the dice is divisible by 3?

1. 1:3
2. 1:2
3. 1:4
4. 2:3
5. 2:5

Given,

Total no. of probability = 9+x

Required probability = 5/(9+x)=1/3

=>9+x=15=>x=6

Given,

6c2/(x+18)c2=5/92

X2+35x-246=0

Simplify the above equation we get x=6

Required difference = 10-8=2 balls

Possibilities of getting sum of the dice divisible by 5

• (1,4) (2,3) (3,2) (4,1) (4,6) (5,5) (6,4) =7

Possibilities of getting difference of the dice is divisible by 2

• (1,3) (1,5) (2,4) (2,6) (3,1) (3,5) (4,2) (4,6) (5,1) (5,3) (6,2) (6,4)=12

Required difference = (12/36)-(7/36)= 5/36

Probability of getting one green ball in bucket A = x/(2x+5)=1/3

X=5

Required no of ball in bucket B = 3+6=9

Required probability = 4/52*5/51=5/663

Required probability = (2/3*3/5*1/4) + (1/3*3/5*1/4) + (2/5*2/3*1/4) + (3/4*2/3*3/5)

=(6/60) + (3/60) + (4/60) + (18/60)

= 31/60

Probability of getting one black colour ball in bucket P = x/(9+x)=2/5

=>3x=18=>x=6

Required probability in bucket Q = 1-11c2/20c2=1-11/38=27/38

Directions (Q. 8-9)

Required probability = ½ (6c2*9c1+6c3)/15c3+1/2 (5c2*10c1+5c3)/15c3

=1/2*1/15c3 (155+110) =53/182

Required probability = ½ ((5c2*10c1+5c1*10c2+10c3)/15c3+(5c2*10c1+5c1*10c2+10c3)/15c3)

= 445/455=89/91

Possibilities of sum of the dice is more than 10 (5,6) (6,5) (6,6) = 3

Possibilities of sum of the dice is divisible by 3 (1,2) (1,5) (2,1) (2,4) (3,3) (3,6) (4,2) (4,5) (5,1) (5,4) (6,3) (6,6)=12

Required ratio = 3:12=1:4 