Quantitative Aptitude Questions (Simple Interest) for Day-37:
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Practice Aptitude Questions (Simple Interest) Day-37
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Topic | Daily Publishing Time |
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Current Affairs Quiz | 9.00 AM |
Logical Reasoning | 10.00 AM |
Quantitative Aptitude “20-20” | 11.00 AM |
Vocabulary (Based on The Hindu) | 12.00 PM |
Static GK Quiz | 1.00 PM |
English Language “20-20” | 2.00 PM |
Banking Awareness Quiz | 3.00 PM |
Reasoning Puzzles & Seating | 4.00 PM |
Daily Current Affairs Updates | 5.00 PM |
Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
Reasoning Ability “20-20” | 7.00 PM |
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General / Financial Awareness Quiz | 9.00 PM |
- Simple interest for the sum of Rs.1500 is Rs.50 in 4 years and Rs.80 in 8 years. Find the rate of SI?
- 0.5%
- 1%
- 1.5%
- 2%
- None of these
2) A sum of money amounts to Rs 19600 after 10 years and Rs 24010 after 16 years at the same rate of simple interest. The rate of interest per annum is:
- 4 %
- 3 %
- 5 %
- 6 %
- None of these
3) A sum of Rs. 2250 was lent partly at 7 % and 10% p.a. simple interest. The total interest received after 3 years was Rs.540. The ratio of the money lent at 7% to that lent at 10% is?
- 3:2
- 2:1
- 1:2
- 2:3
- None of these
4) A sum was put at S.I at a certain rate for 8 years. Had it been put at 4% higher rate, it would have fetched Rs. 480 more. What was the Sum?
- 1500
- 1700
- 1575
- 1650
- None of these
5). Sachin would have paid Rs. 5280 at the end of 4 years, for a sum of money borrowed, at rate of 8% p.a. S.I. If he wants to repay his loan a year before its due, then what is the amount paid by him?
- Rs. 5060
- Rs. 4960
- Rs. 4760
- Rs. 4670
- None of these
6). Veena obtained an amount of Rs. 8376 as simple interest on a certain amount at 8 p.c.p.a. after 6 years. What is the amount invested by Veena?
- Rs. 17180
- Rs. 18110
- Rs. 16660
- Rs. 17450
- None of these
7) A sum of Rs. 6200 is divided into 2 parts, one at 10% and another one at 6%. If the total interest received is Rs.424. Find the money lent at 6 % interest rate.
- Rs. 3000
- Rs. 4500
- Rs. 3400
- Rs. 4900
- None of these
8) Rs.1200 becomes Rs.1434 in 3 yrs at a certain rate of S.I. If the rate of interest is increased by 4%, then the amount will be?
- Rs1245
- Rs.1432
- Rs.1578
- Rs.1365
- None of these
9) The S.I on a sum of money will be Rs. 300 after 5 yrs. If the principal is tripled after 2 ½ yrs, what will be the total interest at the end of the 5^{th} year?
- 600
- 450
- 500
- 300
- None of these
- At simple interest, a sum becomes three times in 20 years. Find the time in which the sum will be double at the same rate of interest?
- 8 years
- 10 years
- 12 years
- 14 years
- None of these
Answers:
1). Answer: a
S.I = (PRT / 100)
According to the question, = [(1500 × R × 8) / 100] – [(1500 × R × 4) / 100] = 80 – 50 (12000R – 6000R) / 100 = 30
6000R / 100 = 30
R = 30/60 = ½ = 0.5%
2). Answer: d
We can get SI of 6 years = 24010 – 19600 = 4410
SI for 10 years = (4410/6)*10
= 7350 [so that we can get principal amount after deducting SI]
Principal = 19600 – 7350
= 12250
SI = PTR/100
R = SI *100 /PT
R= 7350*100 / 12250*10
R = 735000/ 122500
R = 6 %
3). Answer: b
let the sum lent at 7% be Rs.x and that
lent at 10% be Rs.(2250-x).
Then, Interest on x at 7% for 3 years + interest on (2250-x) at 10% for 3 years = 450
x*7*3/100 + (2250-x)*10*3/100 =540
21x/100 + (2250-x)30 /100 =540
21x/100 + 67500-30x/100 =540
21x+67500-30x = 54000
67500-9x =54000
9x =13500
X=1500
Required ratio = x : (2250-x)
=1500:750
=2:1
4). Answer: a
At 4% more rate, the increase in S.I for 8 years = Rs.480
So, at 4% more rate, the increase in SI for 1 year = 480/8 = Rs.60/-
i.e. Rs.60 is 4% of the invested sum
So, 1% of the invested sum = 60/4
Therefore, the invested sum = 60 × 100/4
=Rs. 1500
(or)
(P*8*(r+4))/100 – (P*8*r)/100 = 480
(8P/100)(r+4-r) =480
P = 480*100/32 = Rs. 1500
5). Answer: b
P + (P × (8 / 100) × 4) = 5280
(33 / 25)P = 5280
P = Rs. 4000
Amount payable after 3 years
= 4000 + [4000 × (8 / 100) × 3] = Rs. 4960
6). Answer: d
S.I = (P × r × t) / 100
8736 = (P × 6 × 8) / 100 = (8736 × 100) / (6 × 8)
= Rs. 17450
7). Answer: d
Let the sum lent at 32% be x and
The sum lent at be (6200 – x)
(x*1*10/100) + ((6200-x)*1*6/100) = 424
10x/100 + 37200 – 6x/100 = 424
4x + 37,200 = 42400
X = 5200/4 = 1300
Money lent at 10% = Rs. 1300
Money lent at 6% = Rs. (6200 – 1300) = Rs. 4900
8). Answer: c
S.I = Rs(1434 – 1200)
=Rs. 234
R = SI *100 / P*N
R = 234 *100/1200*3
= 13/2 %
New rate = 13/2 + 4 = 21/2 %
New S.I = Rs. (1200 * 3 * 21 /200)
=Rs. 378
New amount = Rs. (1200 + 378)
=Rs.1578
9). Answer: a
Let the sum be Rs.x
Now S.I = Rs.300
T = 5years
R = 100*SI / P*T
= 100*300 / x*5
= (6000/x) %
S.I for first 2 ½ years = Rs. (x*5*6000 / 2*100*x)
=Rs.150
S.I for last 2 ½ years = Rs. (3x*5*6000 / 2*x*100)
=Rs.450
Therefore total interest = Rs. (450+150) = Rs. 600
10). Answer: b
Let Sum = P, T= 20 yrs;
∴ S.I = 3P – P = 2P
Formula for S.I = (PRT) / 100
2P = (P × R × 20) / 100
R = 10%
To find Time (T),
∴ S.I = 2P – P = P
P = (P × 10 × T) / 100
Hence, T = 10 yrs.
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