**Quantitative Aptitude Questions (Simple Interest) for Day-37:**

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of** ****SBI Clerk **was scheduled from **June/July**. To **enrich** your preparation here we have providing new series of Simple Interest- **Quantitative Aptitude Questions**. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

**Practice Aptitude Questions (Simple Interest) Day-37**

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**Daily Practice Test Schedule | Good Luck**

Topic | Daily Publishing Time |

Daily News Papers & Editorials | 8.00 AM |

Current Affairs Quiz | 9.00 AM |

Logical Reasoning | 10.00 AM |

Quantitative Aptitude “20-20” | 11.00 AM |

Vocabulary (Based on The Hindu) | 12.00 PM |

Static GK Quiz | 1.00 PM |

English Language “20-20” | 2.00 PM |

Banking Awareness Quiz | 3.00 PM |

Reasoning Puzzles & Seating | 4.00 PM |

Daily Current Affairs Updates | 5.00 PM |

Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |

Reasoning Ability “20-20” | 7.00 PM |

English Language (New Pattern Questions) | 8.00 PM |

General / Financial Awareness Quiz | 9.00 PM |

**Simple interest for the sum of Rs.1500 is Rs.50 in 4 years and Rs.80 in 8 years. Find the rate of SI?**

- 0.5%
- 1%
- 1.5%
- 2%
- None of these

**2) A sum of money amounts to Rs 19600 after 10 years and Rs 24010 after 16 years at the same rate of simple interest. The rate of interest per annum is:**

- 4 %
- 3 %
- 5 %
- 6 %
- None of these

**3) A sum of Rs. 2250 was lent partly at 7 % and 10% p.a. simple interest. The total interest received after 3 years was Rs.540. The ratio of the money lent at 7% to that lent at 10% is?**

- 3:2
- 2:1
- 1:2
- 2:3
- None of these

**4) A sum was put at S.I at a certain rate for 8 years. Had it been put at 4% higher rate, it would have fetched Rs. 480 more. What was the Sum?**

- 1500
- 1700
- 1575
- 1650
- None of these

**5). Sachin would have paid Rs. 5280 at the end of 4 years, for a sum of money borrowed, at rate of 8% p.a. S.I. If he wants to repay his loan a year before its due, then what is the amount paid by him?**

- Rs. 5060
- Rs. 4960
- Rs. 4760
- Rs. 4670
- None of these

**6). Veena obtained an amount of Rs. 8376 as simple interest on a certain amount at 8 p.c.p.a. after 6 years. What is the amount invested by Veena?**

- Rs. 17180
- Rs. 18110
- Rs. 16660
- Rs. 17450
- None of these

**7) A sum of Rs. 6200 is divided into 2 parts, one at 10% and another one at 6%. If the total interest received is Rs.424. Find the money lent at 6 % interest rate.**

- Rs. 3000
- Rs. 4500
- Rs. 3400
- Rs. 4900
- None of these

**8) Rs.1200 becomes Rs.1434 in 3 yrs at a certain rate of S.I. If the rate of interest is increased by 4%, then the amount will be?**

- Rs1245
- Rs.1432
- Rs.1578
- Rs.1365
- None of these

**9) The S.I on a sum of money will be Rs. 300 after 5 yrs. If the principal is tripled after 2 ½ yrs, what will be the total interest at the end of the 5 ^{th} year?**

- 600
- 450
- 500
- 300
- None of these

**At simple interest, a sum becomes three times in 20 years. Find the time in which the sum will be double at the same rate of interest?**

- 8 years
- 10 years
- 12 years
- 14 years
- None of these

**Answers:**

**1). Answer: a**

S.I = (PRT / 100)

According to the question, = [(1500 × R × 8) / 100] – [(1500 × R × 4) / 100] = 80 – 50 (12000R – 6000R) / 100 = 30

6000R / 100 = 30

R = 30/60 = ½ = 0.5%

**2). Answer: d**

We can get SI of 6 years = 24010 – 19600 = 4410

SI for 10 years = (4410/6)*10

= 7350 [so that we can get principal amount after deducting SI]

Principal = 19600 – 7350

= 12250

SI = PTR/100

R = SI *100 /PT

R= 7350*100 / 12250*10

R = 735000/ 122500

R = 6 %

**3). Answer: b**

let the sum lent at 7% be Rs.x and that

lent at 10% be Rs.(2250-x).

Then, Interest on x at 7% for 3 years + interest on (2250-x) at 10% for 3 years = 450

x*7*3/100 + (2250-x)*10*3/100 =540

21x/100 + (2250-x)30 /100 =540

21x/100 + 67500-30x/100 =540

21x+67500-30x = 54000

67500-9x =54000

9x =13500

X=1500

Required ratio = x : (2250-x)

=1500:750

=2:1

**4). Answer: a**

At 4% more rate, the increase in S.I for 8 years = Rs.480

So, at 4% more rate, the increase in SI for 1 year = 480/8 = Rs.60/-

i.e. Rs.60 is 4% of the invested sum

So, 1% of the invested sum = 60/4

Therefore, the invested sum = 60 × 100/4

=Rs. 1500

(or)

(P*8*(r+4))/100 – (P*8*r)/100 = 480

(8P/100)(r+4-r) =480

P = 480*100/32 = Rs. 1500

**5). Answer: b**

P + (P × (8 / 100) × 4) = 5280

(33 / 25)P = 5280

P = Rs. 4000

Amount payable after 3 years

= 4000 + [4000 × (8 / 100) × 3] = Rs. 4960

**6). Answer: d**

S.I = (P × r × t) / 100

8736 = (P × 6 × 8) / 100 = (8736 × 100) / (6 × 8)

= Rs. 17450

**7). Answer: d**

Let the sum lent at 32% be x and

The sum lent at be (6200 – x)

(x*1*10/100) + ((6200-x)*1*6/100) = 424

10x/100 + 37200 – 6x/100 = 424

4x + 37,200 = 42400

X = 5200/4 = 1300

Money lent at 10% = Rs. 1300

Money lent at 6% = Rs. (6200 – 1300) = Rs. 4900

**8). Answer: c**

S.I = Rs(1434 – 1200)

=Rs. 234

R = SI *100 / P*N

R = 234 *100/1200*3

= 13/2 %

New rate = 13/2 + 4 = 21/2 %

New S.I = Rs. (1200 * 3 * 21 /200)

=Rs. 378

New amount = Rs. (1200 + 378)

=Rs.1578

**9). Answer: a**

Let the sum be Rs.x

Now S.I = Rs.300

T = 5years

R = 100*SI / P*T

= 100*300 / x*5

= (6000/x) %

S.I for first 2 ½ years = Rs. (x*5*6000 / 2*100*x)

=Rs.150

S.I for last 2 ½ years = Rs. (3x*5*6000 / 2*x*100)

=Rs.450

Therefore total interest = Rs. (450+150) = Rs. 600

**10). Answer: b**

Let Sum = P, T= 20 yrs;

∴ S.I = 3P – P = 2P

Formula for S.I = (PRT) / 100

2P = (P × R × 20) / 100

R = 10%

To find Time (T),

∴ S.I = 2P – P = P

P = (P × 10 × T) / 100

Hence, T = 10 yrs.

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