IBPS PO Mains Quantitative Aptitude Questions 2019 – (Day-2)
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IBPS PO Mains Quantitative Aptitude Questions 2019 â€“ (Day-2)
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Question 1 of 10
1. Question
If the sum of the cost price of Watch and Pen drive is Rs.2750 and the ratio of the marked to cost price of watch and Pen drive is 5:4 and 6:5 respectively.
Quantity I: If the Watch sold at 5% loss and Pen drive sold at 6% profit while the whole transaction we gets no profit no loss, then find the marked price of the watch?
Quantity II: If the Watch sold at the profit of 10% and Pen drive sold at 10% loss while the whole transaction we gets no profit no loss, then find the marked price of the Pen drive?
Correct
Answer: A
From quantity I,
CP of watch = x
CP of pen drive = 2750 â€“ x
x * 95/100 + (2750 â€“ x) * 106/100 = 2750
95x + 291500 â€“ 106x = 275000
16500 = 11x
x = 1500
MP of watch = 5/4 * 1500 = 1875
From quantity II,
CP of watch = x
CP of pen drive = 2750 â€“ x
x * 110/100 + (2750 â€“ x) * 90/100 = 2750
20x = 27500
x = 1375
CP of Pen drive = 2750 â€“ 1375 = 1375
MP of Pen drive = 1375 * 6/5 = 1650
Quantity I > quantity II
Incorrect
Answer: A
From quantity I,
CP of watch = x
CP of pen drive = 2750 â€“ x
x * 95/100 + (2750 â€“ x) * 106/100 = 2750
95x + 291500 â€“ 106x = 275000
16500 = 11x
x = 1500
MP of watch = 5/4 * 1500 = 1875
From quantity II,
CP of watch = x
CP of pen drive = 2750 â€“ x
x * 110/100 + (2750 â€“ x) * 90/100 = 2750
20x = 27500
x = 1375
CP of Pen drive = 2750 â€“ 1375 = 1375
MP of Pen drive = 1375 * 6/5 = 1650
Quantity I > quantity II
Question 2 of 10
2. Question
Vessel A contains 60 liters mixture of milk and water and Vessel B contains x liters mixture of milk and water in the ratio of 3:2.
Quantity I:If the quantity of water in Vessel A is equal to the quantity of the milk in vessel B and the difference between quantity of the milk and water in vessel B is 8 liters, then the quantity of water in vessel A is what percent of the quantity of milk in vessel A?
Quantity II: If quantity of the water in vessel B is 16 liters, then the total quantity of the mixture in vessel B is what percent of the total quantity of the mixture in vessel A?
Correct
Answer: C
From quantity I,
3x â€“ 2x = 8 liters
Quantity of the milk in vessel B = 3 * 8 = 24 liters
Quantity of the water in vessel A = 24 liters
Quantity of the milk in vessel A = 60 â€“ 24 = 36 liters
Required percentage = 24/36 * 100 = 66.67%
From quantity II,
Water quantity in vessel B = 16 liters
Total quantity of vessel B = 5/2 * 16 = 40 liters
Required percentage = 40/60 * 100 = 66.67%
Quantity I = quantity II
Incorrect
Answer: C
From quantity I,
3x â€“ 2x = 8 liters
Quantity of the milk in vessel B = 3 * 8 = 24 liters
Quantity of the water in vessel A = 24 liters
Quantity of the milk in vessel A = 60 â€“ 24 = 36 liters
Required percentage = 24/36 * 100 = 66.67%
From quantity II,
Water quantity in vessel B = 16 liters
Total quantity of vessel B = 5/2 * 16 = 40 liters
Required percentage = 40/60 * 100 = 66.67%
Quantity I = quantity II
Question 3 of 10
3. Question
Quantity I: A and B together can complete 60% of the work in 4.8 days and the ratio of the number of days taken by A and B is 1:2. If the efficiency of C is double of A, in how many days C alone complete the work?
Quantity II: A complete 40% of the work in 6 days, B can complete work half of the work in 15 days respectively and the efficiency of B is double of C. IfA and B together can start the work and after 3 days C joined with them. In how many days A, B and C together can complete remaining work?
Correct
Answer: C
From quantity I,
A + B = 100/60 * 4.8 = 8 days
1/x + 1/2x = 1/8
3/2x = 1/8
1/x = 1/12
C = 1/6
From quantity II,
A = 100/40 * 6 = 15 days
B = 2/1 * 15 = 30 days
C = 1/60
(x + 3)/15 + (x + 3)/30 + x/60 = 1
4x + 12 + 2x + 6 + x = 60
7x = 42
x = 6 days
Quantity I = quantity II
Incorrect
Answer: C
From quantity I,
A + B = 100/60 * 4.8 = 8 days
1/x + 1/2x = 1/8
3/2x = 1/8
1/x = 1/12
C = 1/6
From quantity II,
A = 100/40 * 6 = 15 days
B = 2/1 * 15 = 30 days
C = 1/60
(x + 3)/15 + (x + 3)/30 + x/60 = 1
4x + 12 + 2x + 6 + x = 60
7x = 42
x = 6 days
Quantity I = quantity II
Question 4 of 10
4. Question
Quantity I: The ratio of the ages of A to B is 2:5 and after 5 years twice the age of A is equal to the present age of B. What is Aâ€™s age after 15 years?
Quantity II: Ratio of the ages of A to B is 6:5 and the difference between the ages of A and B after 18 years is 6 years. What is the present age of A?
Correct
Answer: D
From quantity I,
(2x + 5) * 2 = 5x
4x + 10 = 5x
x = 10
Aâ€™s present age = 10 * 2 = 20 years
After 15 days Aâ€™s age = 20 + 15 = 35 years
From quantity II,
6x + 18 â€“ (5x + 18) = 6
x = 6
Aâ€™s present age = 6 * 6 = 36 years
Quantity I < quantity II
Incorrect
Answer: D
From quantity I,
(2x + 5) * 2 = 5x
4x + 10 = 5x
x = 10
Aâ€™s present age = 10 * 2 = 20 years
After 15 days Aâ€™s age = 20 + 15 = 35 years
From quantity II,
6x + 18 â€“ (5x + 18) = 6
x = 6
Aâ€™s present age = 6 * 6 = 36 years
Quantity I < quantity II
Question 5 of 10
5. Question
Quantity I: Perimeter of the square and the circumference of the circle is equal. If side of the square is equal to the breadth of the rectangle whose perimeter is 104 cm. If the breadth of the rectangle is 8 cm less than the length of the rectangle, then what is the radius of the circle?
Quantity II: If the ratio of the length and breadth of the rectangle is 2:1 and the side of the cube is equal to the breadth of the rectangle. If the surface area of the cube is 384 cm^{2}, what is the length of the rectangle?
Correct
Answer: D
From quantity I,
2 * (l + b) = 104
2 * (l + l â€“ 8) = 104
2l = 60
L = 30 cm
Breath of the rectangle = 30 â€“ 8 = 22 cm
Side of the square = 22 cm
Perimeter of the square = 22 * 4 = 88 cm
88 = 2 * 22/7 * r
Radius of the circle = 14 cm
From quantity II,
Surface of the cube = 6 * a * a = 384
a = 8 cm
Breadth of the rectangle = 8 cm
Length of the rectangle = 2 * 8 = 16 cm
Quantity I < quantity II
Incorrect
Answer: D
From quantity I,
2 * (l + b) = 104
2 * (l + l â€“ 8) = 104
2l = 60
L = 30 cm
Breath of the rectangle = 30 â€“ 8 = 22 cm
Side of the square = 22 cm
Perimeter of the square = 22 * 4 = 88 cm
88 = 2 * 22/7 * r
Radius of the circle = 14 cm
From quantity II,
Surface of the cube = 6 * a * a = 384
a = 8 cm
Breadth of the rectangle = 8 cm
Length of the rectangle = 2 * 8 = 16 cm
Quantity I < quantity II
Question 6 of 10
6. Question
Ramesh took a loan of certain amount from bank B and deposited half of that amount in bank D. If at the end of 3 years, interest amount given to bank B is Rs.10760 less than the interest amount received by him from bank D, then what is the amount of loan taken by Ramesh from bank B?
Correct
Directions (6 – 10):
Answer: d)
Let amount of loan taken from bank B is â€˜100xâ€™ and amount of loan deposited in bank D is â€˜50xâ€™.
Interest amount given to bank B after 3 years = 100x * [(1.1)^{3} â€“ 1] = 33.1x
Interest amount received from bank D after 3 years = (50x * 40 * 3)/100 = 60x
According to the question:
60x â€“ 33.1x = 10760
26.9x = 10760
x = 400
Hence, amount of loan taken by Ramesh = 100x = Rs.40000
Incorrect
Directions (6 – 10):
Answer: d)
Let amount of loan taken from bank B is â€˜100xâ€™ and amount of loan deposited in bank D is â€˜50xâ€™.
Interest amount given to bank B after 3 years = 100x * [(1.1)^{3} â€“ 1] = 33.1x
Interest amount received from bank D after 3 years = (50x * 40 * 3)/100 = 60x
According to the question:
60x â€“ 33.1x = 10760
26.9x = 10760
x = 400
Hence, amount of loan taken by Ramesh = 100x = Rs.40000
Question 7 of 10
7. Question
Pawan took loan of amount â€˜xâ€™ from bank A and loan of amount â€˜x + 8000â€™ from bank B. If Bank A applies half yearly rate of compound interest instead of annual, then after 2 years interest amount given by Pawan to Bank A is Rs.1369.2 more than that given to Bank B, then what is the value of â€˜xâ€™?
Correct
Answer: b)
Interest amount given by Pawan to Bank A after 2 years = x * [(1.1)^{4} â€“ 1]
= 0.4641x
Interest amount given by Pawan to Bank B after 2 years = (x + 8000) * [(1.1)^{2} â€“ 1] = (0.21x + 1680)
According to the question:
0.4641x â€“ (0.21x + 1680) = 1369.2
0.2541x â€“ 1680 = 1369.2
0.2541x = 3049.2
x = 12000
Incorrect
Answer: b)
Interest amount given by Pawan to Bank A after 2 years = x * [(1.1)^{4} â€“ 1]
= 0.4641x
Interest amount given by Pawan to Bank B after 2 years = (x + 8000) * [(1.1)^{2} â€“ 1] = (0.21x + 1680)
According to the question:
0.4641x â€“ (0.21x + 1680) = 1369.2
0.2541x â€“ 1680 = 1369.2
0.2541x = 3049.2
x = 12000
Question 8 of 10
8. Question
A person deposited a part of Rs.15000 in bank B and remaining in bank C. If interest amount received by him from both the banks after 3 years is same and after 3 years total interest amount, he received from the both the banks together deposited in bank D, then after how many years interest amount will be same from bank D as that from bank B and C after 3 years initially?
Correct
Answer: a)
Let amount invested in bank B and C is â€˜xâ€™ and â€˜15000 â€“ xâ€™ respectively.
Interest amount received from both the banks together
= 2 * [(5000 * 20 * 3)/100] = Rs.6000
Let after â€˜tâ€™ years, interest amount from bank D will be same as that from bank B and C after 3 years initially.
Interest amount from bank D after 4 more years = (6000 * t * 40)/100 = 3000
2400t = 3000
t = 1.25 years
Question 9 of 10
9. Question
If 5 persons deposited average of Rs.15000 in bank D on a particular day and 3 persons took loan of average amount Rs.18000 from the same bank on the same day, then what will be the total loss incurred to bank D after 3 years from present due to the deposit and loan on that particular day?
Correct
Answer: c)
Total deposited amount in bank D on that day = 15000 * 5 = Rs.75000
Total interest amount given to customer by bank D after 3 years = (75000 * 40 * 3)/100 = Rs.90000
Total amount of loan given by bank D on that day = 18000 * 3 = Rs.54000
Total amount of interest received by bank from customer after 3 years = 54000 * [(1.3)^{3} â€“ 1] = Rs.64638
Total loss incurred to bank D = 90000 â€“ 64638 = Rs.25362
Incorrect
Answer: c)
Total deposited amount in bank D on that day = 15000 * 5 = Rs.75000
Total interest amount given to customer by bank D after 3 years = (75000 * 40 * 3)/100 = Rs.90000
Total amount of loan given by bank D on that day = 18000 * 3 = Rs.54000
Total amount of interest received by bank from customer after 3 years = 54000 * [(1.3)^{3} â€“ 1] = Rs.64638
Total loss incurred to bank D = 90000 â€“ 64638 = Rs.25362
Question 10 of 10
10. Question
Vijay took loans of two different amounts from two banks D and E in the ratio 9: 11 respectively. If at the end of 2 years, total interest amount paid by Vinay to both the banks together is Rs.33150, then what will be the difference between interest amount paid by Vijay to both the banks if the loan is taken for 3 years instead of 2 years?
Correct
Answer: a)
Let amount of loan taken by Vijay from bank D and E is â€˜9xâ€™ and â€˜11xâ€™ respectively.
Total interest amount from bank D after 2 years = 9x * [(1.3)^{2} â€“ 1] = 6.21x
Total interest amount from bank E after 2 years = 11x * [(1.2)^{2} â€“ 1] = 4.84x
According to the question:
6.21x + 4.84x = 33150
11.05x = 33150
x = 3000
Total interest amount from bank D after 3 years = 9x * [(1.3)^{3} â€“ 1] = 10.773x = Rs.32319
Total interest amount from bank E after 3 years = 11x * [(1.2)^{3} â€“ 1] = 8.008x
= Rs.24024
Required difference = 32319 â€“ 24024 = Rs.8295
Incorrect
Answer: a)
Let amount of loan taken by Vijay from bank D and E is â€˜9xâ€™ and â€˜11xâ€™ respectively.
Total interest amount from bank D after 2 years = 9x * [(1.3)^{2} â€“ 1] = 6.21x
Total interest amount from bank E after 2 years = 11x * [(1.2)^{2} â€“ 1] = 4.84x
According to the question:
6.21x + 4.84x = 33150
11.05x = 33150
x = 3000
Total interest amount from bank D after 3 years = 9x * [(1.3)^{3} â€“ 1] = 10.773x = Rs.32319
Total interest amount from bank E after 3 years = 11x * [(1.2)^{3} â€“ 1] = 8.008x
= Rs.24024
Required difference = 32319 â€“ 24024 = Rs.8295
Quantity based questions
Directions (1 – 5): Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,
a) Quantity I > Quantity II
b) Quantity I â‰¥ Quantity II
c) Quantity I = Quantity II
d) Quantity I < Quantity II
e) Quantity I â‰¤ Quantity II
1) If the sum of the cost price of Watch and Pen drive is Rs.2750 and the ratio of the marked to cost price of watch and Pen drive is 5:4 and 6:5 respectively.
Quantity I: If the Watch sold at 5% loss and Pen drive sold at 6% profit while the whole transaction we gets no profit no loss, then find the marked price of the watch?
Quantity II: If the Watch sold at the profit of 10% and Pen drive sold at 10% loss while the whole transaction we gets no profit no loss, then find the marked price of the Pen drive?
2) Vessel A contains 60 liters mixture of milk and water and Vessel B contains x liters mixture of milk and water in the ratio of 3:2.
Quantity I:If the quantity of water in Vessel A is equal to the quantity of the milk in vessel B and the difference between quantity of the milk and water in vessel B is 8 liters, then the quantity of water in vessel A is what percent of the quantity of milk in vessel A?
Quantity II: If quantity of the water in vessel B is 16 liters, then the total quantity of the mixture in vessel B is what percent of the total quantity of the mixture in vessel A?
3)
Quantity I: A and B together can complete 60% of the work in 4.8 days and the ratio of the number of days taken by A and B is 1:2. If the efficiency of C is double of A, in how many days C alone complete the work?
Quantity II: A complete 40% of the work in 6 days, B can complete work half of the work in 15 days respectively and the efficiency of B is double of C. IfA and B together can start the work and after 3 days C joined with them. In how many days A, B and C together can complete remaining work?
4)
Quantity I: The ratio of the ages of A to B is 2:5 and after 5 years twice the age of A is equal to the present age of B. What is Aâ€™s age after 15 years?
Quantity II: Ratio of the ages of A to B is 6:5 and the difference between the ages of A and B after 18 years is 6 years. What is the present age of A?
5)
Quantity I: Perimeter of the square and the circumference of the circle is equal. If side of the square is equal to the breadth of the rectangle whose perimeter is 104 cm. If the breadth of the rectangle is 8 cm less than the length of the rectangle, then what is the radius of the circle?
Quantity II: If the ratio of the length and breadth of the rectangle is 2:1 and the side of the cube is equal to the breadth of the rectangle. If the surface area of the cube is 384 cm^{2}, what is the length of the rectangle?
Data interpretation
Direction (6 – 10): Study the following data carefully and answer the questions:
There are five banks A, B, C, D and E that accepts deposits from the customer and provided loan to them. Interest charged on Loan and interest given on deposit by each bank is different.
Bar graph given below shows the Interest rate given on deposits and interest rate charges on loan by all the five banks.
Note: Nature of interest given on Deposit is always Simple by all the banks while nature of interest on loan is always Compounded annually by all the banks.
6) Ramesh took a loan of certain amount from bank B and deposited half of that amount in bank D. If at the end of 3 years, interest amount given to bank B is Rs.10760 less than the interest amount received by him from bank D, then what is the amount of loan taken by Ramesh from bank B?
a) Rs.50000
b) Rs.45000
c) Rs.30000
d) Rs.40000
e) None of these
7) Pawan took loan of amount â€˜xâ€™ from bank A and loan of amount â€˜x + 8000â€™ from bank B. If Bank A applies half yearly rate of compound interest instead of annual, then after 2 years interest amount given by Pawan to Bank A is Rs.1369.2 more than that given to Bank B, then what is the value of â€˜xâ€™?
a) 18000
b) 12000
c) 16000
d) 15000
e) None of these
8) A person deposited a part of Rs.15000 in bank B and remaining in bank C. If interest amount received by him from both the banks after 3 years is same and after 3 years total interest amount, he received from the both the banks together deposited in bank D, then after how many years interest amount will be same from bank D as that from bank B and C after 3 years initially?
a) 1.25 years
b) 2.5 years
c) 1 year
d) 1.75 years
e) None of these
9) If 5 persons deposited average of Rs.15000 in bank D on a particular day and 3 persons took loan of average amount Rs.18000 from the same bank on the same day, then what will be the total loss incurred to bank D after 3 years from present due to the deposit and loan on that particular day?
a) Rs.23625
b) Rs.28378
c) Rs.25362
d) Rs.24624
e) None of these
10) Vijay took loans of two different amounts from two banks D and E in the ratio 9: 11 respectively. If at the end of 2 years, total interest amount paid by Vinay to both the banks together is Rs.33150, then what will be the difference between interest amount paid by Vijay to both the banks if the loan is taken for 3 years instead of 2 years?
a) Rs.8295
b) Rs.7815
c) Rs.9275
d) Rs.6485
e) None of these
Answers :
Directions (1-5) :
1) Answer: A
From quantity I,
CP of watch = x
CP of pen drive = 2750 â€“ x
x * 95/100 + (2750 â€“ x) * 106/100 = 2750
95x + 291500 â€“ 106x = 275000
16500 = 11x
x = 1500
MP of watch = 5/4 * 1500 = 1875
From quantity II,
CP of watch = x
CP of pen drive = 2750 â€“ x
x * 110/100 + (2750 â€“ x) * 90/100 = 2750
20x = 27500
x = 1375
CP of Pen drive = 2750 â€“ 1375 = 1375
MP of Pen drive = 1375 * 6/5 = 1650
Quantity I > quantity II
2) Answer: C
From quantity I,
3x â€“ 2x = 8 liters
Quantity of the milk in vessel B = 3 * 8 = 24 liters
Quantity of the water in vessel A = 24 liters
Quantity of the milk in vessel A = 60 â€“ 24 = 36 liters
Required percentage = 24/36 * 100 = 66.67%
From quantity II,
Water quantity in vessel B = 16 liters
Total quantity of vessel B = 5/2 * 16 = 40 liters
Required percentage = 40/60 * 100 = 66.67%
Quantity I = quantity II
3) Answer: C
From quantity I,
A + B = 100/60 * 4.8 = 8 days
1/x + 1/2x = 1/8
3/2x = 1/8
1/x = 1/12
C = 1/6
From quantity II,
A = 100/40 * 6 = 15 days
B = 2/1 * 15 = 30 days
C = 1/60
(x + 3)/15 + (x + 3)/30 + x/60 = 1
4x + 12 + 2x + 6 + x = 60
7x = 42
x = 6 days
Quantity I = quantity II
4) Answer: D
From quantity I,
(2x + 5) * 2 = 5x
4x + 10 = 5x
x = 10
Aâ€™s present age = 10 * 2 = 20 years
After 15 days Aâ€™s age = 20 + 15 = 35 years
From quantity II,
6x + 18 â€“ (5x + 18) = 6
x = 6
Aâ€™s present age = 6 * 6 = 36 years
Quantity I < quantity II
5) Answer: D
From quantity I,
2 * (l + b) = 104
2 * (l + l â€“ 8) = 104
2l = 60
L = 30 cm
Breath of the rectangle = 30 â€“ 8 = 22 cm
Side of the square = 22 cm
Perimeter of the square = 22 * 4 = 88 cm
88 = 2 * 22/7 * r
Radius of the circle = 14 cm
From quantity II,
Surface of the cube = 6 * a * a = 384
a = 8 cm
Breadth of the rectangle = 8 cm
Length of the rectangle = 2 * 8 = 16 cm
Quantity I < quantity II
Directions (6 – 10):
6) Answer: d)
Let amount of loan taken from bank B is â€˜100xâ€™ and amount of loan deposited in bank D is â€˜50xâ€™.
Interest amount given to bank B after 3 years = 100x * [(1.1)^{3} â€“ 1] = 33.1x
Interest amount received from bank D after 3 years = (50x * 40 * 3)/100 = 60x
According to the question:
60x â€“ 33.1x = 10760
26.9x = 10760
x = 400
Hence, amount of loan taken by Ramesh = 100x = Rs.40000
7) Answer: b)
Interest amount given by Pawan to Bank A after 2 years = x * [(1.1)^{4} â€“ 1]
= 0.4641x
Interest amount given by Pawan to Bank B after 2 years = (x + 8000) * [(1.1)^{2} â€“ 1] = (0.21x + 1680)
According to the question:
0.4641x â€“ (0.21x + 1680) = 1369.2
0.2541x â€“ 1680 = 1369.2
0.2541x = 3049.2
x = 12000
8) Answer: a)
Let amount invested in bank B and C is â€˜xâ€™ and â€˜15000 â€“ xâ€™ respectively.