# NIACL AO Mains– Quantitative Aptitude Questions Day- 03

Dear Readers, Bank Exam Race for the Year 2019 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for NIACL AO Mains 2019 Exams can practice these questions daily and make your preparation effective.

NIACL AO Mains– Quantitative Aptitude Questions Day- 03

maximum of 10 points

Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established

1)

I) √81 x + √2916 = 0

II) (1296)1/4 y + (13824)1/3 = 0

2)

I) (x12/5 ÷ 17) = (5831 ÷ x3/5)

II) y1/8 × y1/8 × 146 = 1314 ÷ y1/4

3)

I) 4x – 5y = 15

II) 3x – 2y = -1

4)

I) 9x2 + 16x – 32 = 8x2 + 20x

II) y2 + 10y + 21 = 0

5)

I) x = ∜6561

II) 5y3 = – (4374 ÷ 6) + 6y3

Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:

The following table shows the percentage distribution of total number of bikes made by 6 different companies in a certain year and the number of sold and unsold bike also given. Some values are missing here.

Note: Total number of bikes made by all the given companies are either sold or unsold by the respective companies.

6) Find the difference between the total number of bikes made by company A to that of company F

a) 750

b) 600

c) 300

d) 450

e) None of these

7) Find the percentage of bikes sold by company B?

a) 72 %

b) 65 %

c) 78 %

d) 84 %

e) None of these

8) Find the average number of bikes unsold by the company A, C and E together, if the percentage of bikes sold by the company A is 85 %?

a) 1020

b) 1150

c) 1240

d) 980

e) None of these

9) Find the sum of the total number of bikes sold by the company B, D and F together, if the total number of unsold bikes in company F is 1155?

a) 11560

b) 10695

c) 9235

d) 12780

e) None of these

10) Total number of bikes sold by company C, D and E together is approximately what percentage of total number of bikes made by the company A, B and F together?

a) 92 %

b) 75 %

c) 66 %

d) 123 %

e) 111 %

I) √81 x + √2916 = 0

9x = -54

X = -6

II) (1296)1/4 y + (13824)1/3 = 0

6y = -24

Y = -4

X < y

I) (x12/5 ÷ 17) = (5831 ÷ x3/5)

(x12/5/17) = (5831/x3/5)

X12/5 × x3/5 = (5831/17)

X(12/5 + 3/5) = 343

X15/5 = 343

X3 = 343

X = 7

II) y1/8 × y1/8 × 146 = 1314 ÷ y1/4

Y1/8 + 1/8 + 1/4 = (1314/146)

Y1/2 = 3

Y = 9

X < y

4x – 5y = 15 —> (1)

3x – 2y = -1 —-> (2)

By solving the equation (1) and (2), we get,

X = -5, y = -7

X > y

I) 9x2 + 16x – 32 = 8x2 + 20x

X2 – 4x – 32 = 0

(x – 8) (x + 4) = 0

X = 8, -4

II) y2 + 10y + 21 = 0

(y + 7) (y + 3) = 0

Y = -7, -3

Can’t be determined

I) x = ∜6561

X = 9

II) 5y3 = – (4374 ÷ 6) + 6y3

(4374/6) = 6y3 – 5y3

729 = y3

Y = 9

X = y

Directions (6-10):

23 % of total number of bikes = 6000 + 900

(23/100)* Total number of bikes = 6900

Total number of bikes = 6900*(100/23) = 30000

The total number of bikes made by company A

= > 30000*(12/100) = 3600

The total number of bikes made by company F

= > 30000*(11/100) = 3300

Required difference = 3600 – 3300 = 300

Total number of bikes made by all the given companies

= > 6900*(100/23) = 30000

Total number of bikes made by company B = 30000*(18/100) = 5400

Total number of bikes sold by company B = 5400 – 1512 = 3888

Required % = (3888/5400)*100 = 72 %

Total number of bikes made by all the given companies

= > 6900*(100/23) = 30000

Total number of bikes made by company A = 30000*(12/100) = 3600

Total number of bikes unsold by company A = 3600*(15/100) = 540

Total number of bikes made by company C = 30000*(15/100) = 4500

Total number of bikes unsold by company C = 4500 – 3000 = 1500

Total number of bikes unsold by company E = 900

Required average = (540 + 1500 + 900)/3 = 2940/3 = 980

Total number of bikes made by all the given companies

= > 6900*(100/23) = 30000

Total number of bikes made by company B = 30000*(18/100) = 5400

Total number of bikes sold by company B = 5400 – 1512 = 3888

Total number of bikes made by company D = 30000*(21/100) = 6300

Total number of bikes sold by company D = 6300 – 1638 = 4662

Total number of bikes made by company F = 30000*(11/100) = 3300

Total number of bikes sold by company F = 3300 – 1155 = 2145

Required sum = 3888 + 4662 + 2145 = 10695

Total number of bikes made by all the given companies

= > 6900*(100/23) = 30000

Total number of bikes made by company D = 30000*(21/100) = 6300

Total number of bikes sold by company D = 6300 – 1638 = 4662

Total number of bikes sold by company C, D and E together

= > 3000 + 4662 + 6000 = 13662

Total number of bikes made by the company A, B and F together

= > 30000*[(12 + 18 + 11)/100]

= > 30000*(41/100) = 12300

Required % = (13662/12300)*100 = 111 %

Online Mock Tests 2019: