Dear Readers, Bank Exam Race for the Year 2019 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for NIACL AO Mains 2019 Exams can practice these questions daily and make your preparation effective.
[WpProQuiz 5063]
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Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
1)
I) √81 x + √2916 = 0
II) (1296)1/4 y + (13824)1/3 = 0
2)
I) (x12/5 ÷ 17) = (5831 ÷ x3/5)
II) y1/8 × y1/8 × 146 = 1314 ÷ y1/4
3)
I) 4x – 5y = 15
II) 3x – 2y = -1
4)
I) 9x2 + 16x – 32 = 8x2 + 20x
II) y2 + 10y + 21 = 0
5)
I) x = ∜6561
II) 5y3 = – (4374 ÷ 6) + 6y3
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
The following table shows the percentage distribution of total number of bikes made by 6 different companies in a certain year and the number of sold and unsold bike also given. Some values are missing here.
Note: Total number of bikes made by all the given companies are either sold or unsold by the respective companies.
6) Find the difference between the total number of bikes made by company A to that of company F
a) 750
b) 600
c) 300
d) 450
e) None of these
7) Find the percentage of bikes sold by company B?
a) 72 %
b) 65 %
c) 78 %
d) 84 %
e) None of these
8) Find the average number of bikes unsold by the company A, C and E together, if the percentage of bikes sold by the company A is 85 %?
a) 1020
b) 1150
c) 1240
d) 980
e) None of these
9) Find the sum of the total number of bikes sold by the company B, D and F together, if the total number of unsold bikes in company F is 1155?
a) 11560
b) 10695
c) 9235
d) 12780
e) None of these
10) Total number of bikes sold by company C, D and E together is approximately what percentage of total number of bikes made by the company A, B and F together?
a) 92 %
b) 75 %
c) 66 %
d) 123 %
e) 111 %
Answers:
1) Answer: c)
I) √81 x + √2916 = 0
9x = -54
X = -6
II) (1296)1/4 y + (13824)1/3 = 0
6y = -24
Y = -4
X < y
2) Answer: c)
I) (x12/5 ÷ 17) = (5831 ÷ x3/5)
 (x12/5/17) = (5831/x3/5)
X12/5 × x3/5 = (5831/17)
X(12/5 + 3/5) = 343
X15/5 = 343
X3 = 343
X = 7
II) y1/8 × y1/8 × 146 = 1314 ÷ y1/4
Y1/8 + 1/8 + 1/4 = (1314/146)
Y1/2 = 3
Y = 9
X < y
3) Answer: a)
4x – 5y = 15 —> (1)
3x – 2y = -1 —-> (2)
By solving the equation (1) and (2), we get,
X = -5, y = -7
X > y
4) Answer: e)
I) 9x2 + 16x – 32 = 8x2 + 20x
X2 – 4x – 32 = 0
(x – 8) (x + 4) = 0
X = 8, -4
II) y2 + 10y + 21 = 0
(y + 7) (y + 3) = 0
Y = -7, -3
Can’t be determined
5) Answer: e)
I) x = ∜6561
X = 9
II) 5y3 = – (4374 ÷ 6) + 6y3
(4374/6) = 6y3 – 5y3
729 = y3
Y = 9
X = y
Directions (6-10):
6) Answer: c)
23 % of total number of bikes = 6000 + 900
(23/100)* Total number of bikes = 6900
Total number of bikes = 6900*(100/23) = 30000
The total number of bikes made by company A
= > 30000*(12/100) = 3600
The total number of bikes made by company F
= > 30000*(11/100) = 3300
Required difference = 3600 – 3300 = 300
7) Answer: a)
Total number of bikes made by all the given companies
= > 6900*(100/23) = 30000
Total number of bikes made by company B = 30000*(18/100) = 5400
Total number of bikes sold by company B = 5400 – 1512 = 3888
Required % = (3888/5400)*100 = 72 %
8) Answer: d)
Total number of bikes made by all the given companies
= > 6900*(100/23) = 30000
Total number of bikes made by company A = 30000*(12/100) = 3600
Total number of bikes unsold by company A = 3600*(15/100) = 540
Total number of bikes made by company C = 30000*(15/100) = 4500
Total number of bikes unsold by company C = 4500 – 3000 = 1500
Total number of bikes unsold by company E = 900
Required average = (540 + 1500 + 900)/3 = 2940/3 = 980
9) Answer: b)
Total number of bikes made by all the given companies
= > 6900*(100/23) = 30000
Total number of bikes made by company B = 30000*(18/100) = 5400
Total number of bikes sold by company B = 5400 – 1512 = 3888
Total number of bikes made by company D = 30000*(21/100) = 6300
Total number of bikes sold by company D = 6300 – 1638 = 4662
Total number of bikes made by company F = 30000*(11/100) = 3300
Total number of bikes sold by company F = 3300 – 1155 = 2145
Required sum = 3888 + 4662 + 2145 = 10695
10) Answer: e)
Total number of bikes made by all the given companies
= > 6900*(100/23) = 30000
Total number of bikes made by company D = 30000*(21/100) = 6300
Total number of bikes sold by company D = 6300 – 1638 = 4662
Total number of bikes sold by company C, D and E together
= > 3000 + 4662 + 6000 = 13662
Total number of bikes made by the company A, B and F together
= > 30000*[(12 + 18 + 11)/100]
= > 30000*(41/100) = 12300
Required % = (13662/12300)*100 = 111 %
