LIC AAO/SBI PO Prelims Quantitative Aptitude Questions 2019 (Day-17)

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Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established

1)

I) x2 + 25x – 116 = 0

II) y2 – 24x + 128 = 0

2)

I) x2 + 53 = 150 % of 78

II) y = ∛512

3)

I) 2x2 – 6x – 56 = 0

II) 3y2 – 4y – 32 = 0

4)

I) 3x2 + 4x – 64 = 0

II) 2y2 – 21y + 52 = 0

5)

I) x4 = 625

II) y5 = 243

Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:

The following table shows the monthly expenditure (In thousands) of 5 persons on Rent, Food, Clothes, Travelling and Children’s education.

6) Total monthly expenditure on food, clothes and Children’s education of people A and C together is approximately what percentage of total monthly expenditure on Rent and Travelling of people B and D together?

a) 156 %

b) 163 %

c) 188 %

d) 174 %

e) 132 %

7) Find the ratio between the monthly expenditure on clothes and Travelling of people B and E together to that of the monthly expenditure on Food and Children’s education of people A and D together?

a) 33: 83

b) 24: 67

c) 15: 43

d) 45: 97

e) None of these

8) Find the difference between the monthly expenditure on Rent to that of children’s education for all the given peoples together?

a) 1200

b) 1500

c) 900

d) 700

e) None of these

9) Total monthly expenditure of A and B together is approximately what percentage more/less than the total monthly expenditure of C and E together?

a) 26 % less

b) 12 % more

c) 12 % less

d) 26 % more

e) 18 % less

10) Who among the following has more expenses?

a) B

b) D

c) E

d) A

e) C

Answers:

1) Answer: c)

I) x2 + 21x – 116 = 0

(x + 29) (x – 4) = 0

x = – 29, 4

II) y2 – 24x + 128 = 0

(y – 16) (y – 8) = 0

y = 16, 8

x < y

2) Answer: d)

I) x2 + 53 = 150 % of 78

= > x2 = (150/100)*78 – 53

= > x2 = 117 – 53 = 64

= > x = 8, -8

II) y = ∛512

= > y = 8

x ≤ y

3) Answer: e)

I) 2x2 – 6x – 56 = 0

2x2 – 14x + 8x – 56 = 0

2x (x – 7) + 8 (x – 7) = 0

(2x + 8) (x – 7) = 0

X = -4, 7

II) 3y2 – 4y – 32 = 0

3y2 – 12y + 8y – 32 = 0

3y (y – 4) + 8 (y – 4) = 0

(3y + 8) (y – 4) = 0

Y = -2.67, 4

Can’t be determined

4) Answer: d)

I) 3x2 + 4x – 64 = 0

3x2 – 12x + 16x – 64 = 0

3x (x – 4) + 16(x – 4) = 0

(3x + 16) (x – 4) = 0

= > x = -16/3, 4 = -5.33, 4

II) 2y2 – 21y + 52 = 0

2y2 – 8y – 13y + 52 = 0

2y(y – 4) – 13(y – 4) = 0

(2y – 13) (y – 4) = 0

= > y = 13/2, 4 = 6.5, 4

 x ≤ y

5) Answer: e)

I) x4 = 625

x4 = (54)

= > x = -5, +5

II) y5 = 243

y5 = (3)5

= > y = 3

Can’t be determined

6) Answer: d)

Total monthly expenditure on food, clothes and Children’s education of people A and C together

= > [9.3 + 2.8 + 7.5 + 6.6 + 4.2 + 7] thousands

= > 37400

Total monthly expenditure on Rent and travelling of people B and D together

= > [6.8 + 3.1 + 8 + 3.6] thousands

= > 21500

Required % = (37400/21500)*100 = 173.95 % = 174 %

7) Answer: a)

The monthly expenditure on clothes and travelling of people B and E together

= > [3.5 + 3.1 + 3.7 + 2.9] thousands

= > 13200

The monthly expenditure on Food and Children’s education of people A and D together

= > [9.3 + 7.5 + 8.2 + 8.2] thousands

= > 33200

Required ratio = 13200: 33200 = 33: 83

8) Answer: c)

The monthly expenditure on Rent for all the given peoples together

= > [8.5 + 6.8 + 7.2 + 8 + 6.4] thousands

= > 36900

The monthly expenditure on children’s education for all the given peoples together

= > [7.5 + 6.5 + 7 + 8.2 + 6.8] thousands

= > 36000

Required difference = 36900 – 36000 = 900

9) Answer: b)

Total monthly expenditure of A and B together

= > [8.5 + 9.3 + 2.8 + 4.7 + 7.5 + 6.8 + 7.8 + 3.5 + 3.1 + 6.5] thousands

= > 60500

The total monthly expenditure of C and E together

= > [7.2 + 6.6 + 4.2 + 3.4 + 7 + 6.4 + 5.8 + 3.7 + 2.9 + 6.8] thousands

= > 54000

Required % = [(60500 – 54000)/54000]*100

= > 12.03 % = 12 % more

10) Answer: d)

Total monthly expenditure of A

= > [8.5 + 9.3 + 2.8 + 4.7 + 7.5] thousands = 32800

Total monthly expenditure of B

= > [6.8 + 7.8 + 3.5 + 3.1 + 6.5] thousands = 27700

Total monthly expenditure of C

= > [7.2 + 6.6 + 4.2 + 3.4 + 7] thousands = 28400

Total monthly expenditure of D

= > [8 + 8.2 + 2.6 + 3.6 + 8.2] thousands = 30600

Total monthly expenditure of E

= > [6.4 + 5.8 + 3.7 + 2.9 + 6.8] thousands = 25600

A has more expenses.

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