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Directions (Q.1-5): What approximate value should come in place of question mark (?) in the following questions?
0.98% of 7824 + 4842 ÷ 119.46 – ? = 78
Correct
Answer: c
2.0.98% of 7824 + 4842 ÷ 119.46 – ? = 78
=> 1% of 7824 + 4842 ÷ 120 – 78 = ?
=> ? = 78.24 + 40.35 – 78 = 40.59 ≈ 40
Incorrect
Answer: c
2.0.98% of 7824 + 4842 ÷ 119.46 – ? = 78
=> 1% of 7824 + 4842 ÷ 120 – 78 = ?
=> ? = 78.24 + 40.35 – 78 = 40.59 ≈ 40
Question 5 of 20
5. Question
Directions (Q.1-5): What approximate value should come in place of question mark (?) in the following questions?
(42.992 – 18.042) – ? = 13.112 – 138.99
Correct
Answer: e
(41.992 – 18.042) – ? = 13.112 – 138.99
=> (422 – 182) – ? = (13)2 – 139
=> {(42 + 18) (42 – 18)} – ? = 169 – 139
=> {60 × 24} – ? = 30
=> 1440 – ? = 30 => ? = 1410
Incorrect
Answer: e
(41.992 – 18.042) – ? = 13.112 – 138.99
=> (422 – 182) – ? = (13)2 – 139
=> {(42 + 18) (42 – 18)} – ? = 169 – 139
=> {60 × 24} – ? = 30
=> 1440 – ? = 30 => ? = 1410
Question 6 of 20
6. Question
Directions (Q 6-10): Find the wrong term in the following series:
5, 7.5, 11.25, 17.5, 29.75, 50, 91.25
Correct
Answer: c
The pattern is as follows
Hence, number 29.75 is wrong and should be replaced by 28.75.
Incorrect
Answer: c
The pattern is as follows
Hence, number 29.75 is wrong and should be replaced by 28.75.
Question 7 of 20
7. Question
Directions (Q 6-10): Find the wrong term in the following series:
35, 118, 280, 600, 1238, 2504, 5036
Correct
Answer: d
The pattern is as follows
Hence, number 1238 is wrong and should be replaced by 1236.
Incorrect
Answer: d
The pattern is as follows
Hence, number 1238 is wrong and should be replaced by 1236.
Question 8 of 20
8. Question
Directions (Q 6-10): Find the wrong term in the following series:
10, 12, 28, 90, 368, 1840, 11112
Correct
Answer: a
The pattern is as follows
Hence, number 1840 is wrong and should be replaced by 1850.
Incorrect
Answer: a
The pattern is as follows
Hence, number 1840 is wrong and should be replaced by 1850.
Question 9 of 20
9. Question
Directions (Q 6-10): Find the wrong term in the following series:
7, 4, 5, 9, 20, 51, 160.5
Correct
Answer: e
The pattern is as follows
Hence, number 51 is wrong and should be replaced by 52.5.
Incorrect
Answer: e
The pattern is as follows
Hence, number 51 is wrong and should be replaced by 52.5.
Question 10 of 20
10. Question
Directions (Q 6-10): Find the wrong term in the following series:
1788, 892, 444, 220, 112, 52, 24
Correct
Answer: b
The pattern is as follows
Hence, number 112 is wrong and should be replaced by 108.
Incorrect
Answer: b
The pattern is as follows
Hence, number 112 is wrong and should be replaced by 108.
Question 11 of 20
11. Question
Direction (Q.11-15): Study the table carefully to answer the questions that follow:
Distance (in kms) travelled by six friends on six different months of the year
If to travel the given distance, the time taken by Harish on May was 8 hours, what was its speed on that day?
Correct
Answer c)
Speed of Harish on May
= 302/8
= 37.75 kmph
Incorrect
Answer c)
Speed of Harish on May
= 302/8
= 37.75 kmph
Question 12 of 20
12. Question
Direction (Q.11-15): Study the table carefully to answer the questions that follow:
Distance (in kms) travelled by six friends on six different months of the year
What is the total distance travelled by all the friends together on June, April and February together?
Correct
Answer : b)
Total distance travelled by all friends on June, April and February together
June = (292 + 284 + 260 + 274 + 290 + 242) km = 1642 km
April = (288 + 300 + 310 + 278 + 260 + 275) km = 1711 km
February = (320 + 264 + 308 + 314 + 318 + 314) km = 1838 km
Total = 1642 + 1711 + 1838
= 5191 km
Incorrect
Answer : b)
Total distance travelled by all friends on June, April and February together
June = (292 + 284 + 260 + 274 + 290 + 242) km = 1642 km
April = (288 + 300 + 310 + 278 + 260 + 275) km = 1711 km
February = (320 + 264 + 308 + 314 + 318 + 314) km = 1838 km
Total = 1642 + 1711 + 1838
= 5191 km
Question 13 of 20
13. Question
Direction (Q.11-15): Study the table carefully to answer the questions that follow:
Distance (in kms) travelled by six friends on six different months of the year
If on February and June Vikram and Naresh travelled at the same speed, what was the respective ratio of time taken by Vikram and time taken by Naresh to cover their respective distances?
Correct
Answer : a)
Time taken by Vikram on February and June
= 308 + 260 = 568
Time taken by Naresh on February and June
= 318 + 290 = 608
Required ratio =568:608
= 71 : 76
Incorrect
Answer : a)
Time taken by Vikram on February and June
= 308 + 260 = 568
Time taken by Naresh on February and June
= 318 + 290 = 608
Required ratio =568:608
= 71 : 76
Question 14 of 20
14. Question
Direction (Q.11-15): Study the table carefully to answer the questions that follow:
Distance (in kms) travelled by six friends on six different months of the year
What is the average distance travelled by Ramesh in all the months together?
Correct
Answer : d)
Required average distance covered by Ramesh
= (325 + 314 + 312 + 278 + 292 + 274)/6
= 1795/6
= 299 1/6 km
Incorrect
Answer : d)
Required average distance covered by Ramesh
= (325 + 314 + 312 + 278 + 292 + 274)/6
= 1795/6
= 299 1/6 km
Question 15 of 20
15. Question
Direction (Q.11-15): Study the table carefully to answer the questions that follow:
Distance (in kms) travelled by six friends on six different months of the year
If the speed of Arun on January was 19.2 kmph, the speed of Ramesh on May was 21.9 kmph, what was the difference between the times taken by two friends to cover the given distance?
Raja gives 30% of his salary to his mother, 40% of the remaining salary he invests in an insurance scheme and PPF in the ratio of 4 : 3 and the remaining he keeps in his bank account. If the difference between the amount he gives to his mother and that he invests in insurance scheme is Rs.8400, how much is Raja’s salary?
Correct
Answer : a
Let Raja’s salary be Rs. x.
Raja gives 30% of his salary to his mother.
Raja gives[(x × 30)/100 = Rs. 3x/10] to his mother
Remaining salary of Raja = x – (3x /10) = Rs. 7x /10
Investments of Raja in insurance and PPF is 40% of the remaining salary.
Insurance + PPF = (7x x 40)/ (10×100) = 7x/25
Remaining salary of Raja = 7x/10 – 7x/25
= (35x —14x)/50 = 21x /50
Raja’s investment in insurance scheme
= (7x/25) × (4/7) = 4x/25
Now, according to the question,
3x/10 – 4x/7 = 8400
or, (15x-8x) / 50 =8400
or, 7x = 8400 x 50
x = (8400x 50)/7 =1200 x 50 = Rs. 60000
Incorrect
Answer : a
Let Raja’s salary be Rs. x.
Raja gives 30% of his salary to his mother.
Raja gives[(x × 30)/100 = Rs. 3x/10] to his mother
Remaining salary of Raja = x – (3x /10) = Rs. 7x /10
Investments of Raja in insurance and PPF is 40% of the remaining salary.
Insurance + PPF = (7x x 40)/ (10×100) = 7x/25
Remaining salary of Raja = 7x/10 – 7x/25
= (35x —14x)/50 = 21x /50
Raja’s investment in insurance scheme
= (7x/25) × (4/7) = 4x/25
Now, according to the question,
3x/10 – 4x/7 = 8400
or, (15x-8x) / 50 =8400
or, 7x = 8400 x 50
x = (8400x 50)/7 =1200 x 50 = Rs. 60000
Question 17 of 20
17. Question
C is 40% less efficient than A. A and B together can finish a piece of work in 10 days. B and C together can do it in 15 days. In how many days can A alone finish the same piece of work?
Correct
Answer : b
Suppose total work = 60 units (LCM of 10 and 15)
(A + B)’s one day’s work = 60/10
= 6 units
And (B + C)’s one day’s work = 60/15 = 4 unit
According to the question, C : A = 60 : 100
or, C :A = 3 : 5
C/A = 3/5
Or, A = 5C/3
Again, A +B = 6units ..(i)
B+C = 4 units …(ii)
Putting the value of A in equation (i), we get
[5C/3 + B = 6 unit ] – [B + C = 4 units]
= 5C/3 – C=2units
Or, 2C/3 = 2 units
C = 3 units
Then A = 5C/3 = 5×3 / 5 = 5 units
Now, total work is 60 units Then A alone can do the work in
(60 / 5 =) 12 days
Incorrect
Answer : b
Suppose total work = 60 units (LCM of 10 and 15)
(A + B)’s one day’s work = 60/10
= 6 units
And (B + C)’s one day’s work = 60/15 = 4 unit
According to the question, C : A = 60 : 100
or, C :A = 3 : 5
C/A = 3/5
Or, A = 5C/3
Again, A +B = 6units ..(i)
B+C = 4 units …(ii)
Putting the value of A in equation (i), we get
[5C/3 + B = 6 unit ] – [B + C = 4 units]
= 5C/3 – C=2units
Or, 2C/3 = 2 units
C = 3 units
Then A = 5C/3 = 5×3 / 5 = 5 units
Now, total work is 60 units Then A alone can do the work in
(60 / 5 =) 12 days
Question 18 of 20
18. Question
In a bag there are 7 red balls and 5 green balls. Three balls are picked at random. What is the probability that two balls are red and one ball is green in colour?
Correct
Answer : b
Total number of balls = 7 + 5 = 12
Now, three halls are picked randomly
Then, the number of sample space n(S)
=12C3 =(10 ×11 ×12) / (1×2×3) = 220
The number of events
n(E) =7C2 x5C1 = [(6×7)/2] x 5
= 21 x 5 = 105
105 21 P(E) = n(E)/n(S)=105/220 = 21/44
Incorrect
Answer : b
Total number of balls = 7 + 5 = 12
Now, three halls are picked randomly
Then, the number of sample space n(S)
=12C3 =(10 ×11 ×12) / (1×2×3) = 220
The number of events
n(E) =7C2 x5C1 = [(6×7)/2] x 5
= 21 x 5 = 105
105 21 P(E) = n(E)/n(S)=105/220 = 21/44
Question 19 of 20
19. Question
A man sold an article for Rs. 6800 and incurred a loss. Had he sold the article for Rs.7850, his gain would have been equal to half of the amount of loss that he incurred. At what price should he sell the article to have 20% profit?
A bought a certain quantity of bananas at a total cost of Rs. 1500. He sold 1/3 of these bananas at 25% loss. If he earns an overall profit of 10%, at what percentage profit did A sell the rest of the bananas?
Correct
Answer b
Total CP = 1500
Total SP = 1500 + 10% of 1500 = 1500 + 150 = 1650
CP of 1/3 of bananas = 1500/3 = Rs.500
SP of 1/3 of bananas at 25% loss
= 500 – [ (500 x25 / 100)] = 500 – 125 = 375
SP of the rest of bananas = 1650 – 375 = 1275
Now, CP of the test of bananas = 1500 – 500 = 1000
Profit on the rest of bananas = 1275 -1000 = 275
% of profit on the rest of bananas = (275/1000)×100 = 27.5%
(or)
Incorrect
Answer b
Total CP = 1500
Total SP = 1500 + 10% of 1500 = 1500 + 150 = 1650
CP of 1/3 of bananas = 1500/3 = Rs.500
SP of 1/3 of bananas at 25% loss
= 500 – [ (500 x25 / 100)] = 500 – 125 = 375
SP of the rest of bananas = 1650 – 375 = 1275
Now, CP of the test of bananas = 1500 – 500 = 1000
Profit on the rest of bananas = 1275 -1000 = 275
% of profit on the rest of bananas = (275/1000)×100 = 27.5%
(or)
Click “Start Quiz” to attend these Questions and view Explanation
Directions (Q.1-5): What approximate value should come in place of question mark (?) in the following questions?
1). (10/12) × [(4/18) ÷ (8/18] ÷ (12/14) = ?
1.25
0.25
0.5
1.75
2
2).15% of 62.58 + 20% of 9.68 = ?
14
18
16
11
9
3).105.27% of 1200.11 + 11.80% of 2360.85 = 21.99% of ? + 1420.99
500
240
310
550
960
4).0.98% of 7824 + 4842 ÷ 119.46 – ? = 78
30
60
40
50
70
5). (42.992 – 18.042) – ? = 13.112 – 138.99
4004
1200
1720
8432
1410
Directions (Q 6-10) Find the wrong term in the following series:
6). 5, 7.5, 11.25, 17.5, 29.75, 50, 91.25
7.5
17.5
29.75
91.25
50
7). 35, 118, 280, 600, 1238, 2504, 5036
118
280
600
1238
5036
8). 10, 12, 28, 90, 368, 1840, 11112
1840
368
90
28
12
9). 7, 4, 5, 9, 20, 51, 160.5
4
5
9
20
51
10). 1788, 892, 444, 220, 112, 52, 24
52
112
220
444
None of these
Direction (Q.11-15): Study the table carefully to answer the questions that follow:
Distance (in kms) travelled by six friends on six different months of the year
If to travel the given distance, the time taken by Harish on May was 8 hours, what was its speed on that day?
32.50 kmph
42.25 kmph
37.75 kmph
35.25 kmph
30.50 kmph
What is the total distance travelled by all the friends together on June, April and February together?
4985 km
5191 km
5396 km
4161 km
5481 km
If on February and June Vikram and Naresh travelled at the same speed, what was the respective ratio of time taken by Vikram and time taken by Naresh to cover their respective distances?
71 : 76
78 : 70
76 : 71
Cannot be determined
None of these
What is the average distance travelled by Ramesh in all the months together?
269 1/3 km
233 1/6 km
195 1/6 km
299 1/6 km
319 2/7 km
If the speed of Arun on January was 19.2 kmph, the speed of Ramesh on May was 21.9 kmph, what was the difference between the times taken by two friends to cover the given distance?
10 minutes
45 minutes
60 minutes
30 minutes
50 minutes
16). Raja gives 30% of his salary to his mother, 40% of the remaining salary he invests in an insurance scheme and PPF in the ratio of 4 : 3 and the remaining he keeps in his bank account. If the difference between the amount he gives to his mother and that he invests in insurance scheme is Rs.8400, how much is Raja’s salary?
Rs.60,000
Rs.62,000
Rs.64,000
Rs.65,000
Rs.54,000
17). C is 40% less efficient than A. A and B together can finish a piece of work in 10 days. B and C together can do it in 15 days. In how many days can A alone finish the same piece of work?
18
12
14
20
15
18). In a bag there are 7 red balls and 5 green balls. Three balls are picked at random. What is the probability that two balls are red and one ball is green in colour?
29/44
21/44
27/44
23/44
19/44
19).A man sold an article for Rs. 6800 and incurred a loss. Had he sold the article for Rs.7850, his gain would have been equal to half of the amount of loss that he incurred. At what price should he sell the article to have 20% profit?
Rs.7500
Rs.9000
Rs.10680
Rs. 9600
Rs.11500
20). A bought a certain quantity of bananas at a total cost of Rs. 1500. He sold 1/3 of these bananas at 25% loss. If he earns an overall profit of 10%, at what percentage profit did A sell the rest of the bananas?