# CWC/FCI Prelims 2019 â€“ Quantitative Aptitude Questions (Day-25)

Dear Readers, Exam Race for the Year 2019 has already started, To enrich your preparation here we are providing new series of Practice Questions on Quantitative Aptitude â€“ Section for CWC/FCI Exam. Aspirants, practice these questions on a regular basis to improve your score in aptitude section. Start your effective preparation from the right beginning to get success in upcoming CWC/FCI Exam.

[WpProQuiz 5687]

Directions (Q. 1 – 5): Each question contains a statement followed by Quantity I and II. Read the contents clearly and answer your questions accordingly and Give answer as,

a) Quantity I > Quantity II
b) Quantity I â‰¥ Quantity II
c) Quantity II > Quantity I
d) Quantity II â‰¥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established

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1) Quantity I: 5 years ago, the ratio of age of A and B is 2: 3. After 2 years, the sum of their ages is 44. Then find the present age of A

Quantity II: 5 years ago, the ratio of age of P and Q is 3: 4. Pâ€™s age after 6 years is equal to the present age of Q. Then find the present age of P

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2) Quantity I: The difference between the simple interest and compound interest on a certain sum of money for 2 years at 12 % per annum is Rs. 432. Find the sum

Quantity II: A certain sum of money invested for a period of 4 years at 15 % per annum, simple interest earned is Rs. 15000. Find the principle

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3) Quantity I: The shopkeeper sold an article at 25 % discount on marked price and he gains 10 %. If the marked price of the article is Rs. 660, then find the cost price?

Quantity II: The shopkeeper marks the book for Rs. 400 and his profit percentage is 20%. Find the cost price of the book, if he allows a discount 10 %?

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4) Quantity I: The ratio of speed of two trains is 3: 5. If the faster train runs 350 km in 7 hours, then the speed of the slower train is?

Quantity II: 150 m long train crosses a telegram post in 12 sec. Find the speed of the train

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5) Quantity I: If the length of a rectangle is increased by 15% while the breadth of the rectangle is decreased by 20% then find percentage change in area of the rectangle?

Quantity II: If the breadth of a triangle is increased by 20 % while the height of a triangle is decreased by 10 %, then find the percentage change in area of the triangle?

Directions (Q. 6 â€“ 10): Study the following information carefully and answer the given questions:

The following pie chart shows the total number of passengers in 5 different trains (A, B, C, D and E).

6) Find the difference between the total number of passengers in train A and C together to that of the train B and D together?

a) 372

b) 448

c) 512

d) 396

e) None of these

7) Find the average number of passengers in train C, D and E together?

a) 1120

b) 980

c) 756

d) 1042

e) None of these

8) Total number of passengers in train E is what percentage of the total number of passengers in train C?

a) 46 %

b) 54 %

c) 32 %

d) 28 %

e) None of these

9) If the cost of AC ticket in train E is Rs. 500 and the ratio of passengers in AC, Sleeper class and Unreserved category in train E is 3: 3 :2, then find the total cost paid by the AC class passengers in train E?

a) Rs. 91000

b) Rs. 80500

c) Rs. 75500

d) Rs. 84000

e) None of these

10) If the ratio of men, women and children in train C is 3: 2: 2, then find the total number of men in train C?

a) 450

b) 600

c) 520

d) 560

e) None of these

Direction (1-5) :

Quantity I:

5 years ago, the ratio of age of A and B = 2: 3 (2x, 3x)

According to the question,

2x + 3x + 14 = 44

5x = 30

= > x = 6

The present age of A = 2x + 5 = 17 years

Quantity II:

5 years ago, the ratio of age of P and Q = 3: 4 (3x, 4x)

According to the question,

3x + 5 + 6 = 4x + 5

= > x = 6

The present age of P = 3x + 5 = 18 + 5 = 23 years

Quantity I < Quantity II

Quantity I:

The difference between the simple interest and compound interest for 2 years,

Diff = Sum*(r/100)2

432 = Sum*(12/100)2

(432*100*100)/144 = Sum

Sum = Rs. 30000

Quantity II:

1. I = Pnr/100

15000 = (P*4*15)/100

(15000*100)/60 = P

Principle = Rs. 25000

Quantity I > Quantity II

Quantity I:

660*(75/100) = CP*(110/100)

CP = 660*(75/100)*(100/110) = Rs. 450

Quantity II:

400*(90/100) = CP*(120/100)

CP = 400*(90/100)*(100/120) = Rs. 300

Quantity I > Quantity II

Quantity I:

The ratio of speed of two trains = 3: 5 (3x, 5x)

The speed of faster train = 350/7 = 50 km/hr

5x = 50

= > x = 10

The speed of slower train = 3x = 30 km/hr

Quantity II:

The speed of the train = 150/12 = (150/12)*(18/5) = 45 km/hr

Quantity II > Quantity I

Quantity I:

Let the length and breadth be 10 m and 10m respectively.

Normal Area = lb = 10*10 = 100 Sq m

New Area = (10*115/100)*(10*80/100) = 11.5*8 = 92 Sq m

Percentage change = [(100 â€“ 92)/100]*100 = (8/100)*100 = 8 % decreased

Quantity II:

Let the breadth and height of a triangle be 10 m and 10 m respectively.

Normal area = (1/2)*b*h = (1/2)*10*10 = 50 Sq m

New area = (1/2)*(10*120/100)*(10*90/100) = (1/2)*12*9 = 54 Sq m

Percentage change = [(54 â€“ 50)/50]*100 = 8 % increased

Quantity I = Quantity II

Direction (6-10) :

Required difference = [5600*(23 + 27)/100] – [5600*(17 + 25)/100]

= > (5600/100)*[50 â€“ 42] = 56*8

= > 448

The average number of passengers in train C, D and E together

= > 5600*[(25 + 27 + 8)/300]

= > 1120

Required % = (8/25)*100 = 32 %

Total number of passengers in train E = 5600*(8/100) = 448

The ratio of passengers in AC, Sleeper class and Unreserved in train E

= > 3: 3: 2

8â€™s = 448

1â€™s = 56

The cost of AC ticket in train E = Rs. 500

The total cost paid by the AC class passengers in train E

= > (56*3)*500 = Rs. 84000

Total number of passengers in train C

= > 5600*(25/100) = 1400

The ratio of men, women and children in train C = 3: 2: 2

7â€™s = 1400

1â€™s = 200

Total number of men in train C = 600