Dear Readers, Exam Race for the Year 2019 has already started, To enrich your preparation here we are providing new series of Practice Questions on **Quantitative Aptitude – Section** for **CWC/FCI Exam**. Aspirants, practice these questions on a regular basis to improve your score in aptitude section. Start your effective preparation from the right beginning to get success in upcoming **CWC/FCI Exam**.

**CWC/FCI Prelims Quantitative Aptitude Questions (Day-39)**

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**Directions (Q. 1 – 5) what approximate value should come in place of (?) in the following questions?**

**1) (****52.13) ^{2} **

**÷ 13.9 × 7.2 + (44.78)**

^{2}= 5 × ? – 35 % of 3097a) 892

b) 716

c) 954

d) 1028

e) 1150

**2) 11 4/5 % of 1499 + 5 2/3 % of 2949 = ?**

a) 564

b) 678

c) 252

d) 357

e) 423

**3) (4/9) of 1223 = ? – 27.4 × 12.78 ÷ 38.89**

a) 420

b) 646

c) 553

d) 395

e) 712

**4) ****13.9 % of 742 – ? % of 393 = 89.78 – (12.23) ^{2}**

a) 56

b) 28

c) 62

d) 77

e) 40

**5) (1023.77) ^{2 }÷ (255.89)^{3/2 }× 64.12 = (3.92)^{4} × 4^{?}**

a) 3

b) 5

c) 9

d) 7

e) 6

**Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:**

There are 3 Schools A, B and C having the total strength of 7600, which is in the ratio of 8 : 7 : 4. All the given students were appeared for the examination. Total number of boys appeared for the examination from school A is 62 ½ % of total students in that school. The ratio of boys to that of girls appeared for the examination from school B and C is 3 : 4 and 5 : 3 respectively. The percentage of failed students from School A and C is 24 % and 32 % of appeared students in those schools respectively. Total number of students passed from School B is 2380.

**6) Find the ratio between the total number of passed girls from school A to that of total number of failed students from school C, if the total number of passed boys from school A is 1592?**

a) 52 : 17

b) 38 : 15

c) 105 : 64

d) 117 : 59

e) None of these

**7) Find the difference between the total number of girls appeared for the examination from school A to that total number of boys appeared for the examination from school C?**

a) 200

b) 350

c) 280

d) 420

e) None of these

**8) Total number of failed students from school B is approximately what percentage of total number of passed students from school C?**

a) 25 %

b) 55 %

c) 70 %

d) 40 %

e) 85 %

**9) Find the difference between the average number of students passed the examination to that of failed the examination from all the given schools together?**

a) 1800

b) 1400

c) 2200

d) 2500

e) None of these

**10) Total number of boys appeared for the examination from school A is what percentage more/less than the total number of students appeared for the examination from school C?**

a) 25 % more

b) 10 % less

c) 10 % more

d) 25 % less

e) 15 % more

**Answers :**

**Direction (1-5) :**

**1) Answer: a)**

52^{2} ÷ 14 × 7 + 45^{2} = 5x – 35 % of 3100

(52*52*7)/14 + 2025 + (35/100)*3100 = 5x

1352 + 2025 + 1085 = 5x

5x = 4462

X = 892.4 = 892

**2) Answer: d)**

12 % of 1500 + 6 % of 2950 = x

X = (12/100)*1500 + (6/100)*2950

X = 180 + 177 = 357

**3) Answer: c)**

(4/9)*1224 = x – (27*13)/39

544 + 9 = x

X = 553

**4) Answer: e)**

14 % of 750 – x % of 400 = 90 – (12)^{2}

(14/100) * 750 – (x/100) * 400 = 90 – 144

105 – 90 + 144 = 4x

159/4 = x

X = 40

**5) Answer: a)**

(1024)^{2 }÷ (256)^{3/2 }× 64 = 4^{4} × 4^{x}

(4^{5})^{2} ÷ (4^{4})^{3/2} × 4^{3} = 4^{4} × 4^{x}

4^{10} ÷ 4^{6} × 4^{3} = 4^{4} × 4^{x}

4^{10} ^{– 6 + 3 – 4} = 4^{x}

4^{3} = 4^{x}

X = 3

**Directions (Q. 6 – 10):**

Total students in all the given schools (A, B and C) = 7600

Total students from school A = 7600*(8/19) = 3200

Total students from school B = 7600*(7/19) = 2800

Total students from school C = 7600*(4/19) = 1600

Total number of boys appeared for the examination from school A

= > 62 ½ % of 3200

= > (125/200)*3200 = 2000

Total number of girls appeared for the examination from school A

= > 3200 – 2000 = 1200

Total number of boys appeared for the examination from school B

= > 2800*(3/7) = 1200

Total number of girls appeared for the examination from school B

= > 2800 – 1200 = 1600

Total number of boys appeared for the examination from school C

= > 1600*(5/8) = 1000

Total number of girls appeared for the examination from school C

= > 1600 – 1000 = 600

Total number of students failed the examination from school A

= > 3200*(24/100) = 768

Total number of students passed the examination from school A

= > 3200 – 768 = 2432

Total number of students failed the examination from school C

= > 2800*(32/100) = 896

Total number of students passed the examination from school C

= > 2800 – 896 = 1904

Total number of students passed from School B = 2380

**6) Answer: c)**

The total number of passed students from school A = 2432

The total number of passed boys from school A = 1592

The total number of passed girls from school A

= > 2432 – 1592 = 840

The total number of failed students from school C = 512

Required ratio = 840 : 512 = 105 : 64

**7) Answer: a)**

The total number of girls appeared for the examination from school A

= > 37 ½ % of 3200

= > (75/200)*3200 = 1200

The total number of boys appeared for the examination from school C

= > 1600*(5/8) = 1000

Required difference = 1200 – 1000 = 200

**8) Answer: d)**

Total number of failed students from school B = 420

Total number of passed students from school C = 1088

Required % = (420/1088)*100 = 38.6 % = 40 %

**9) Answer: b)**

The average number of students passed the examination from all the given schools together

= > (2432 + 2380 + 1088)/3

= > 5900/3

The average number of students failed the examination from all the given schools together

= > (768 + 420 + 512)/3

= > 1700/3

Required difference = (5900/3) – (1700/3) = 4200/3 = 1400

**10) Answer: a)**

Total number of boys appeared for the examination from school A

= > 2000

Total number of students appeared for the examination from school C

= > 1600

Required % = [(2000 – 1600)/1600]*100 = 25 % more