Quantitative Aptitude Questions (Time and Distance) for IBPS Clerk Prelims Day-1:
Dear Readers, IBPS is conducting Online Examination for the recruitment of Clerical Cadre. Preliminary Examination of IBPS Clerk was scheduled from 2nd Dec 2017. To enrich your preparation here we have providing new series of Quantitative Aptitude Questions. Candidates those who are appearing in IBPS Clerk Exam can practice these questions daily and make your preparation effective.
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1)A person covers 480km in 8 hrs. He covers some distance by car at the average speed of 40 km/hr and the remaining distance by train at the average speed of 70 km/hr. Find the distance covered by the car?
A) 200 km
B)250km
C)170km
D)160km
E) None of these
2)A truck starts running at the speed of 48 km/hr. If the speed of the truck increases 6 km at the end of every hour then what will be the distance covered at the end of 12 hrs from the start of the Journey?
A)600km
B)550km
C)972 km
D)700km
E) None of these
3)A person travels from A to B at the speed of 50 km/hr and returns by increasing his speed by 40%. What is the average speed of both the trips?
A)58 1/3 hr
B)50 hr
C)55 2/3 hr
D)52 hr
E) None of these
4)Moni left for Bangalore from Chennai at 9.30 am. She travelled at the speed of 60 km/hr for 2 hrs 15 mins. After she reduced the speed to 40 km/hr. If the distance between the 2 cities is 285 km, at what time did moni reach Bangalore?
A)2.30 pm
B)3.30 pm
C)4 pm
D)2 pm
E) None of these
5)A man takes 8 hours 25 minutes in walking to certain place and riding back. He would have take 2 hours less by riding both ways. What would be the time he would take to walk both ways?
A)8 hr 25 min
B)7 hr 15 min
c) 9 hrs 10 min
d)8 hr 15 min
E) None of these
6)Ragu drove at the speed of 60 km/hr from home to a resort. Returning over the same route, he got stuck in traffic and took an hour longer, also he could drive only at the speed of 50 km/hr. How many kilometers did he drive each way?
A)300 km
b)450 km
c)425 km
d)325 km
E) None of these
7)The respective ratio between the speeds of a bus, a car and jeep is 2:3:5. The speed of jeep is 250 percent of the speed of the bus which covers 480 km in 12 hours. What is the average speed of car and jeep together?
A)75 km/hr
B)80 km/hr
C)76 km/hr
D)72 km/hr
E) None of these
8)The ratio between the speed of a train and a car is 18:13 respectively. Also, a bus covered a distance of 480 kms in 12 hours. The speed of the bus is five-ninth the speed of the train. How much distance will the car cover in 5 hours?
A)260 km
B)270 km
c)290 km
d)320 km
E) None of these
9)The speeds of Raj and Ragu are 30 km/hr and 40 km/hr respectively. Initially Ragu is at a place L and Raj is at a place M. The distance between L and M is 650 km. Raj started his journey 3 hours earlier than Ragu to meet each other. If they meet each other at a place P somewhere between L and M, then the distance between P and M is?
A)310 km
B)330km
c)350 km
d)325 km
E) None of these
10)The distance between the two stations Chennai and Bangalore is 400 km. A train starts at 5 pm from Chennai towards Bangalore at an average speed of 50 km/hr. Another train starts from Bangalore at 5.15 pm and moves towards Chennai at an average speed of 80 km/hr. How far from Chennai will they meet and at what time?
A)161km, 9pm
B)120km,7.13pm
c)171km,8.13pm
d)148.33km,8.13pm
E) None of these
Dear sir / mam,
Can you explain these two steps in Question 10
“Hence they meet at 5.15+2.58=8.13 pm (Here I am getting 7.73pm)
Meeting distance=100+48.33=148.33 km (how to calculate this point)”
Plz also explai ques 5
Correct Answer is: (a)
W+R=8 hr 25 min
2R=6 hr 25 min
R=3 hr 25/2 min
W=8 hr 25 min-2 hr 25/2 mi(here it shud be 3hr12.5 min)na
=>4 hr 25/2 min*2
=> 8 hr 25 min
sorry that W=8 hr 25 min- 3 hr 25/2 m
=>5 hr 25/2 min*2
=>10 hr 25 min. so the answer is none of these
thnku maam
In ques 7
Shud be 2*60*100/160
Then why taking 100+60/2 whic is a normar average values where one variavle dos not depend on second
suppose a man covers a certain distance at x km/hr, and the equal distance at y km/hr. the average speed of the whole journey=2xy/(x+y). They didnt give an equal distance in this sum. so we will use the normal average only.
Okay
i do not understand question no 6
Correct Answer is: (a)
If Ragu travelled 60 km/hr, he may reach the resort at 10 am, In the same way if he travelled 50 km/hr, he may reach the resort at 11 am. The difference is 1 hour.
x/60-x/50=1
10x/(60*50)=1
X=300 km
t=D/S. we have only the time difference. so we use the above pattern