IBPS SO Prelims Quantitative Aptitude Questions 2019 (Day-4)

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Directions (Q. 1 – 5): Study the following information carefully and answer the given questions?

The following table shows the total number of population in different villages and the percentage of male among them and the ratio of literate to illiterate population among them.

1) Find the difference between the total female population in village P and R together to that of total illiterate population in village T and U together?

a) 24900

b) 27400

c) 25500

d) 26800

e) None of these

2) If out of the total female population in village S, 64 % are literate, then find the total male literate population in village S?

a) 27546

b) 28368

c) 26124

d) 25312

e) None of these

3) Find the average female population in all the given villages together?

a) 35380

b) 37920

c) 36270

d) 38450

e) None of these

4) Find the ratio between the total male population in village Q and S together to that of total illiterate population in village P and T together?

a) 923 : 600

b) 857 : 452

c) 616 : 381

d) 123 : 59

e) None of these

5) Total illiterate population in village Q, R and U together is approximately what percentage more/less than the total male population in village P and R together?

a) 12 % less

b) 20 % more

c) 5 % more

d) 5 % less

e) 20 % less

Quadratic Equation

Directions (Q. 6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established

6)

I) (x + 3) (y + 4) = (x + 5) (y + 8)

II) y × (3x – 2) = (3x + 6) (y + 16)

7)

I) 5x2 – 11x – 36 = 0

II) 8y2 – 26y – 24 = 0

8)

I) 4x – 5y = -4/3

II) 3x – 4y = -7/6

9)

I) x2 – 7x – 228 = 0

II) y2 – 22y + 112 = 0

10)

I) x + 152 ÷ 27 × 9 = 113 – 12 % of 750

II) y = (3/8) of 1184 – 93 + 322 + 624

Answers:

Directions (1-5):

1) Answer: c)

The total female population in village P and R together

= > 75000 * (44/100) + 70000 * (55/100)

= > 33000 + 38500 = 71500

The total illiterate population in village T and U together

= > 88000 * (7/22) + 90000 * (1/5)

= > 28000 + 18000 = 46000

Required difference = 71500 – 46000 = 25500

2) Answer: b)

The total female literate population in village S

= > 65000 * (52/100) * (64/100) = 21632

Total literate population in village S

= > 65000 * (10/13) = 50000

The total male literate population in village S

= > 50000 – 21632 = 28368

3) Answer: c)

The average female population in all the given villages together

= > [75000 * (44/100) + 82000 * (48/100) + 70000 * (55/100) + 65000 * (52/100) + 88000 * (42/100) + 90000 * (40/100)] / 6

= > [33000 + 39360 + 38500 + 33800 + 36960 + 36000] / 6

= > [217620 / 6]

= > 36270

4) Answer: a)

The total male population in village Q and S together

=> 82000 * (52/100) + 65000 * (48/100)

= > 42640 + 31200 = 73840

The total illiterate population in village P and T together

=> 75000 * (4/15) + 88000 * (7/22)

= > 20000 + 28000 = 48000

Required ratio = 73840: 48000 = 923: 600

5) Answer: d)

The total illiterate population in village Q, R and U together

=> 82000 * (13/41) + 70000 * (13/35) + 90000 * (1/5)

= > 26000 + 26000 + 18000 = 70000

The total male population in village P and R together

= > 75000 * (56/100) + 70000 * (45/100)

= > 42000 + 31500 = 73500

Required % = [(73500 – 70000) / 73500] * 100 = 5 % less

Directions (6-10):

6) Answer: a)

I) (x + 3) (y + 4) = (x + 5) (y + 8)

xy + 4x + 3y + 12 = xy + 8x + 5y + 40

4x + 2y + 28 = 0

2x + y = -14 —> (1)

II) y × (3x – 2) = (3x + 6) (y + 16)

3xy – 2y = 3xy + 48x + 6y + 96

48x + 8y + 96 = 0

6x + y = -12 –> (2)

By solving the equation (1) and (2), we get,

x = 0.5, y = -15

x > y

7) Answer: e)

I) 5x2 – 11x – 36 = 0

5x2 – 20x + 9x – 36 = 0

5x (x – 4) + 9 (x – 4) = 0

(5x + 9) (x – 4) = 0

x = -9/5, 4 = – 1.8, 4

II) 8y2 – 26y – 24 = 0

8y2 – 32y + 6y – 24 = 0

8y (y – 4) + 6 (y – 4) = 0

(8y + 6) (y – 4) = 0

y = -4/3, 4 = -1.33, 4

Can’t be determined

8) Answer: c)

4x – 5y = -4/3 –> (1)

3x – 4y = -7/6 –> (2)

By solving the equation (1) and (2), we get,

x = ½, y = 2/3

x < y

9) Answer: e)

I) x2 – 7x – 228 = 0

(x + 12) (x – 19) = 0

x = -12, 19

II) y2 – 22y + 112 = 0

(y – 14) (y – 8) = 0

y = 14, 8

Can’t be determined

10) Answer: c)

I) x + 152 ÷ 27 × 9 = 113 – 12 % of 750

x + (15 * 15 * 9) / 27 = 1331 – (12/100) * 750

x + 75 = 1331 – 90

x = 1331 – 90 – 75 = 1166

II) y = (3/8) of 1184 – 93 + 322 + 624

y = (3/8) * 1184 – 729 + 1024 + 624

y = 444 – 729 + 1024 + 624

y = 1363

x < y

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