RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-18)

Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.

RRB ALP & Technician | Aptitude Day-18

maximum of 10 points
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  1. If a = 115, b = -113, c = –2, then what is the value of a3 + b3 + c3?
  1. 69000
  2. 12995
  3. 38985
  4. 77970
  1. 500 ÷ 50 × 5 =?
  1. 2
  2. 5
  3. 50
  4. 10
  1. X is twice as efficient as Y. X takes 20 days to complete a job. In how many days, can X and Y complete the job together?
  1. 30
  2. 25
  3. 40
  4. 40
  1. The difference between a number and its two-third is 24. Find the number.
  1. 48
  2. 36
  3. 60
  4. 72
  1. 10000 ÷ 100 ÷ 10 =?
  1. 1
  2. 10
  3. 100
  4. 1000
  1. What will be the compound interest accrued on a sum of Rs. 7,200 at a rate of 5% per annum in 2y?
  1. Rs. 738
  2. Rs. 1,738
  3. Rs. 1,268
  4. Rs. 648
  1. Population of a country increases every year by 10%. If the population in January 2006 was 15.8 lakh, what was the population in January 2008?
  1. 19,11,800
  2. 18,96,000
  3. 19,11,600
  4. 18,94,000
  1. John travelled 240 km at a certain speed and then another 192 km at 8 km/h faster. If the entire trip was of 10 h, find his initial speed.
  1. 45 km/h
  2. 60 km/h
  3. 40 km/h
  4. 75 km/h
  1. The ratio of present ages between Jyoti and Ankita is 7: 5. If after six years, their ages will be in the ratio of 4: 3, what would be the present age of Ankita?
  1. 32
  2. 36
  3. 30
  4. 35
  1. Fraction becomes 4 when 1 is added to the numerator and becomes 5 when 1 is subtracted from the denominator. The numerator of the given fraction is
  1. 15
  2. 11
  3. 13
  4. 17

Solution:

  1. Answer: (d)

Note that here, a + b + c = 0 Therefore, a3 + b3 + c3 = 3abc = 3 (115) (-113) (-2) = 77970.

2.Answer: (c)

According to the BODMAS rule, ? = 500 ÷ 50 × 5 = 10 × 5 = 50

  1. Answer: (d)

X’s one-day work = 1/20

Y’s one-day work = 1/40 (because X is twice as efficient as Y) X and Y’s one-day work 1/20+1/ 40=3/40

4.Answer: (d)

Let the required number be x. According to the question,

x – 2x/3 = x/3 = 24

Therefore, x = 72

  1. Answer: (b)

If the expression includes more than one similar operation, solve from the left hand side first, and then the other. Therefore, ? = 10000 ÷ 100 ÷ 10 = 100 ÷ 10 = 10

  1. Answer: (a)

C.I. for 1st year = 5% of 7200 = ` 360

C.I. for 2nd year = 5% of 7200 + 5% of 360 = 360 + 18 = ` 378

C.I. for 2 years = 360 + 378 = ` 738

  1. Answer: (a)

Population in 2006 = 15,80,000

Rate of growth = 10%

Population in 2008 = 158000(1+10/100)2 = 1580000 × 1.1 × 1.1 = 19,11,800

  1. Answer: (c)

Let the initial speed of John be x km/h

∴ According to the question, 240/x+ 192/( x+ 8)

240(x + 8) + 192x = 10(x² + 8x)

10x² – 352x –1920 = 0

x = 40, –24/5

By ignoring the negative value, the required speed of John = 40 km/h.

  1. Answer: (c)

Let Jyoti’s present age be 7x years and Ankita’s present age be 5x years.

Then, after 6 years, their ages will be:(7x+6) /(5x+6)=4/3

3(7x+6) = 4(5x+6)

21x+18 = 20x+24

x = 6

Therefore, Ankita’s present age = 5×6 = 30 years.

  1. Answer: (a)

Let the fraction be x/y

(X+1)/y=4

=>x-4y+1=0——->(1)

x/(y-1)=5

=>x-5y+5=0——–>(2)

On solving eqn 1 and 2, x=15, y=4

Numerator=15

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