# RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-55)

Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.

[WpProQuiz 2739]

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1). The HCF of two numbers is 14 and their LCM is 140. If one of the numbers is 28, then the other number is

1. 80
2. 70
3. 90
4. 50

2). The total number of prime factors in 410×73×162×11×102 is

1. 34
2. 32
3. 36
4. 35

3). The average of 20 results is 30 and the other 20 results is 30. What is the average of all the results?

1. 30
2. 20
3. 15
4. 10

4). If x: y = 3: 4, then 4x + 5y: 5x – 2y =

1. 7: 32
2. 32: 7
3. 4:3
4. 3:4

5). The salary of a person is increased by 20 %, then it is decreased by 20 %. What is the change in the salary?

1. 4 % decreased
2. 4 % Increased
3. 6% decreased
4. 6% increased

6). If the ratio of principal and the simple Interest for 10 years is 5: 3, then the rate of interest is

1. 10%
2. 12%
3. 6%
4. 9%

7). If tan (5x – 10°) = cot (5y + 20°), Find the value of x +y.

1. 24°
2. 20°
3. 15°
4. 16°

8). Amit bought a Laptop Rs.50,000. After 1 year he want to sell it with the cost of 20% profit. Due to repair in the laptop he has to sell it With the loss of 10%. What is the difference amount he gained between the current Selling price and the selling price of the laptop at a profit of 20% ?

1. 20, 000
2. 15,000
3. 30,000
4. 5000

9). A travels Upstream with the speed of 8kmph and return in downstream speed of 6 kmph .What is the speed of Boat?

1. 7.5 kmph
2. 5.5 kmph
3. 7 kmph
4. 5 kmph

10). Simplify

115% of 300 + 190% of x = 60% of 400

1. 50
2. 100
3. 150
4. 200

First Number ×Second number = LCM ×HCF

28× x= 14×140

X = (14×140)/28 = 70

(22)10 × (73)× (24)2 ×11× (2×5)2

= 220×73×28×11×22×52

= 230×73×111×52

Total number of Prime factors

= 30+2+3+1 =36

20×30 = 600

20×30 =600

1200/40 =30

Let the value of X =3 y =4

4x + 5y: 5x – 2y = 4(3) + 5(4) : 5(3) – 2(4)

12 + 20 : 15 – 8

32: 7

Let salary = 100

After 20 % increased the salary = 120

Rs. 120 is decreased by 20 % then the salary is 120 – 24 = 96

100 – 96 = 4 % Decreased

P = 5                S.I = 3              N = 10             R =?

S.I = PNR /100

3 = (5×10×R)/100

R = 300/50 = 6%

tan (5x – 10°) = cot (5y + 20°)

tan (5x – 10°) = tan (90° – (5y + 20°) )

5x – 10° = 70° – 5y

5(x+y) = 80°

x+y = 16°

If Amit sells the laptop with the profit = (50,000×120)/ 100 = 60,000

SP at 10 % loss = (50,000×90)/ 100 = 45,000

Difference of the amounts = 60,000 – 45,000 = 15,000

Speed of boat = (U+V)/2 = (8+6)/2 = 14/ 2 = 7kmph

115% of 300 + 190% of x = 60% of 400

145 + 190% of x = 240

19x/10 = 95

X= 950/19

X= 50

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