# SBI Clerk Prelims 2021 Quantitative Aptitude Questions (Day-19)

Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Prelims 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.

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Directions (01-05): Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

1)Â

I) x2â€“ 27x + 152 = 0

II) y2â€“ 39y + 380 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship canâ€™t be determined.

D.x < y

E.x â‰¤ y

2)Â

I) 2x2â€“ 50x + 300 = 0

II) y2â€“ 30y + 224 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship canâ€™t be determined.

D.x < y

E.x â‰¤ y

3)Â

I) x2+ 19x + 48 = 0

II) y2– 13y â€“ 48 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship canâ€™t be determined.

D.x < y

E.x â‰¤ y

4)Â

I) x2+ 21x + 90 = 0

II) 2y2+ 18y + 36 = 0

A.x > y

B.x â‰¤ y

C.x = y or relationship canâ€™t be determined.

D.x < y

E.x â‰¥ y

5)

I) x2â€“ x – 72 = 0

II) y2– y – 110 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship canâ€™t be determined.

D.x < y

E.x â‰¤ y

Directions (06-10): What approximate value should come in the place of (?) in the following questions?

6) 2720.001 Ã· 67.99 =?2Â â€“ 19.903 * 2.912

A.11

B.10

C.12

D.13

E.9

7) âˆš2401.04 – âˆš1370 – âˆš3720.96 =?

A.-49

B.-34

C.-56

D.-28

E.-61

8) (?)2Â + (5.01)3Â + âˆš2810.01 = 961.091

A.24

B.28

C.34

D.20

E.30

9) 22.01 * 4.981 â€“ 3.02 * âˆš65 + 5.031 * 1.902 =?

A.82

B.96

C.90

D.77

E.68

10) 25.01 * 3.91 – âˆš198 – âˆš2115.901 =?

A.30

B.45

C.35

D.40

E.25

Directions (01-05):

x2Â â€“ 27x + 152 = 0

x2Â â€“ 19x â€“ 8x + 152 = 0

x(x â€“ 19) â€“ 8(x â€“ 19) = 0

(x â€“ 8)(x â€“ 19) = 0

x = 8, 19

y2Â â€“ 39y + 380 = 0

y2Â â€“ 20y â€“ 19y + 380 = 0

y(y â€“ 20) â€“ 19(y â€“ 20) = 0

(y â€“ 19)(y â€“ 20) = 0

y = 19, 20

x â‰¤ y

2x2Â â€“ 50x + 300 = 0

2x2Â â€“ 20x â€“ 30x + 300 = 0

2x(x â€“ 10) â€“ 30(x â€“ 10) = 0

(2x â€“ 30)(x â€“ 10) = 0

x = 15, 10

y2Â â€“ 30y + 224 = 0

y2Â â€“ 16y â€“ 14y + 224 = 0

y(y â€“ 16) â€“ 14(y â€“ 16) = 0

(y â€“ 14)(y â€“ 16) = 0

y = 14, 16

Relationship between x and y cannot be established.

x2Â + 19x + 48 = 0

x2Â + 16x + 3x + 48 = 0

x(x + 16) + 3(x + 16) = 0

(x + 3)(x + 16) = 0

x = -3, -16

y2Â – 13y â€“ 48 = 0

y2Â â€“ 16y + 3y â€“ 48 = 0

y(y â€“ 16) + 3(y â€“ 16) = 0

(y + 3)(y â€“ 16) = 0

y = -3, 16

x â‰¤ y

x2Â + 21x + 90 = 0

x2Â + 15x + 6x + 90 = 0

x(x + 15) + 6(x + 15) = 0

(x + 6)(x + 15) = 0

x = -6, -15

2y2Â + 18y + 36 = 0

2y2Â + 12y + 6y + 36 = 0

2y(y + 6) + 6(y + 6) = 0

(2y + 6)(y + 6) = 0

y = -3, -6

x â‰¤ y

x2Â â€“ x – 72 = 0

x2Â â€“ 9x + 8x â€“ 72 = 0

x(x â€“ 9) + 8(x â€“ 9) = 0

(x + 8)(x â€“ 9) = 0

x = -8, 9

y2Â – y – 110 = 0

y2Â â€“ 11y + 10y â€“ 110 = 0

y(y â€“ 11) + 10(y â€“ 11) = 0

(y + 10)(y â€“ 11) = 0

y = -10, 11

Relationship between x and y cannot be established.

Directions (06-10):

2720.001 Ã· 67.99 =?2Â â€“ 19.903 * 2.912

2720/68 =?2Â â€“ 20 * 3

40 =?2Â â€“ 60

?2Â = 100

? =10

âˆš2401.04 – âˆš1370 – âˆš3720.96 =?

âˆš2401 – âˆš1369 – âˆš3721 =?

49 â€“ 37 â€“ 61 =?

-49 =?

(?)2Â + (5.01)3Â + âˆš2810.01 = 961.091

?2Â + 125 + 53 = 961

? = 28

22.01 * 4.981 â€“ 3.02 * âˆš65 + 5.031 * 1.902 =?

22 * 5 â€“ 3 * âˆš64 + 5 * 2 =?

110 â€“ 24 + 10 =?

96 =?

25.01 * 3.91 – âˆš198 – âˆš2115.901 =?

25 * 4 – âˆš196 – âˆš2116 =?

100 â€“ 14 â€“ 46 =?

? = 40

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