SBI PO 2019 Notification will be expected soon. It is one of the most expected recruitment among the banking aspirants. Every year the exam pattern for SBI PO has been changing. Depends upon the changing of exam pattern the questions are quite harder compare to the previous year. So the questions are in high level than the candidate’s assumption.
As per the latest trend, our IBPS Guide is providing the updated New Exam Pattern Quantitative Aptitude questions for SBI PO 2019 Day 13. Our Skilled experts were mounting the questions based on the aspirant’s needs. So candidates shall start your preparation and practice on daily basis with our SBI PO pattern quantitative aptitude questions 2019 day 13. Start your effective preparation from the right beginning to get success in upcoming SBI PO 2019.
“Be not afraid of growing slowly; be afraid only of standing still”
[WpProQuiz 5197]
Click Here for SBI PO Pre 2019 High-Quality Mocks Exactly on SBI Standard
Click Here to View Quantitative Aptitude Questions in Hindi
Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
1)
I) 2x – 5y – 4 = 0
II) 3x – 4y + 1 = 0
2)
I) 2x2 – 8x – 42 = 0
II) 3y2 + 2y – 56 = 0
3)
I) x2 – 16x + 55 = 0
II) y2 – 20y + 64 = 0
4)
I) x2 – 16x – 57 = 0
II) 2y2 + 28y + 96 = 0
5)
I) x = (158 ÷ 2 × 3) – (237 + ∛729)
II) y = ∜20736
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
Face book allows their users to post a comment for upcoming general elections. The following table shows the total number of positive comments (in favour), negative comments (against) of 5 different parties in a certain state. Some values are missing here.
Note:
Total comment = % of positive comment + % of negative comment
6) Find the difference between the total number of positive comments posted for the party P to that of party R, if the percentage of total number of negative comments posted against the party R is 48 %?
a) 84123
b) 76892
c) 82557
d) 78279
e) None of these
7) Find the average number of comments posted for all the given parties together, if the total number of positive comments posted for party Q is 93328 and the total number of negative comments posted for party T is 48988?
a) 256800
b) 243700
c) 221500
d) 231100
e) None of these
8) Find the percentage of total number of positive comments posted in the favour of party R, if the total number of negative comments posted against party R is 157200?
a) 48 %
b) 42 %
c) 53 %
d) 36 %
e) None of these
9) If the total number of positive comments posted in the favour of party T is 83412, then find the ratio between the total number of comments posted for party P to that of party T?
a) 123: 52
b) 46: 27
c) 417: 331
d) 285: 119
e) None of these
10) Total number of negative comments posted against party Q is approximately what percentage of total number of positive comments posted in the favour of party S, if the total number of comments posted for party Q is 245600?
a) 106 %
b) 94 %
c) 145 %
d) 117 %
e) 132 %
Answers :
Direction(1-5 ) :
1) Answer: c)
2x – 5y – 4 = 0 —-> (1)
3x – 4y + 1 = 0 —-> (2)
By solving the equation (1) and (2), we get,
X = -3, y = -2
X < y
2) Answer: e)
I) 2x2 – 8x – 42 = 0
2x2 – 14x + 6x – 42 = 0
2x (x – 7) + 6(x – 7) = 0
(2x + 6) (x – 7) = 0
X = -3, 7
II) 3y2 + 2y – 56 = 0
3y2 -12y + 14y – 56 = 0
3y (y – 4) + 14(y – 4) = 0
(3y + 14) (y – 4) = 0
Y = -14/3, 4 = – 4.667, 4
Can’t be determined
3) Answer: e)
I) x2 – 16x + 55 = 0
(x – 11) (x – 5) = 0
X = 11, 5
II) y2 – 20y + 64 = 0
(y – 16) (y – 4) = 0
Y = 16, 4
Can’t be determined
4) Answer: a)
I) x2 – 16x – 57 = 0
(x + 3) (x – 19) = 0
X = -3, 19
II) 2y2 + 28y + 96 = 0
2y2 + 12y + 16y + 96 = 0
2y (y + 6) + 16(y + 6) = 0
(2y + 16) (y + 6) = 0
Y = -8, -6
X > y
5) Answer: c)
I) x = (158 ÷ 2 × 3) – (237 + ∛729)
X = [(158/2)*3] – (237 + 9)
X = 237 – 237 – 9 = -9
II) y = ∜20736
Y = 12
X < y
Direction (6-10) :
6) Answer: b)
The total number of positive comments posted for the party P
= > 166800*(56/100) = 93408
The total number of positive comments posted for the party R
= > 327500*(52/100) = 170300
Required difference = 170300 – 93408 = 76892
7) Answer: d)
The total number of comments posted for all the given parties together
= > 166800 + (93328/38)*100 + 327500 + 283200 + (48988/37)*100
= > 166800 + 245600 + 327500 + 283200 + 132400
= > 1155500
Required average = 1155500/5 = 231100
8) Answer: a)
The total number of negative comments posted against party R = 157200
The percentage of total number of positive comments posted in the favour of party R
= > (157200/327500)*100 = 48 %
9) Answer: c)
The total number of positive comments posted in the favour of party T = 83412
The ratio between the total number of comments posted for party P to that of party T
= > 166800: (83412/63)*100
= > 166800: 132400
= > 417: 331
10) Answer: d)
Total number of negative comments posted against party Q
= > 245600*(62/100) = 152272
Total number of positive comments posted in the favour of party S
= > 283200*(46/100) = 130272
Required % = (152272/130272)*100 = 117 %
Leave a Reply