# SBI PO Prelims Quantitative Aptitude Questions 2019 – Day 09

SBI PO 2019 Notification will be expected soon. It is one of the most expected recruitment among the banking aspirants. Every year the exam pattern for SBI PO has been changing. Depends upon the changing of exam pattern the questions are quite harder compare to the previous year. So the questions are in high level than the candidateโs assumption.

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Quantitative Aptitude Questions For SBI PO Prelims (Day-09)

maximum of 10 points

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1) A, B and C started a business by investing Rs. 45000, Rs. 32000 and Rs. ______ respectively. After 5 months, A withdraws Rs. 15000 and B invested Rs. ______ more. And after another 3 months, C invested 25 % of initial investment more. The ratio of share of A, B and C, at the end of the year is 435: 440: 364.

Which of the following options satisfy the given condition?

a) 22000, 6000

b) 24000, 10000

c) 28000, 8000

d) 26000, 4000

e) 30000, 5000

2) A shopkeeper allowed ____ % discount on an item on the marked price and he suffered a loss of _____ %. If he allows only 10% discount, then the profit percentage would be 8 %.

Which of the following options satisfy the given condition?

a) 30, 10

b) 25, 15

c) 35, 22

d) 25, 10

e) Both c) and d)

3) The difference between Simple interest and Compound interest on a certain sum at the rate of _____% per annum for two years is Rs. _____. The simple interest on the same sum at the rate of 15% per annum for 5 years is Rs. 33750?

Which of the following options satisfy the given condition?

I) 12, 648

II) 10, 450

III) 15, 956

a) Only I

b) Only II

c) Only III

d) Both I and II

e) Both II and III

4) ____ litres of mixture of milk and water contains milk and water in the ratio of 3 : 2. The ____ litres of water should be added to the mixture to get 45 % milk on it.

Which of the following options satisfy the given condition?

I) 75, 25

II) 90, 30

III) 100, 24

a) Only I

b) Only II

c) Only III

d) Both II and III

e) Both I and II

5) The average weight of _____ persons is increased by 3 when one of the person whose weight is 58 kg replaced by 2 women. The average weight of 2 women is _____ kg.

Which of the following options satisfy the given condition?

a) 16, 52

b) 14, 48

c) 12, 47

d) 18, 58

e) None of these

Directions (Q. 6 – 10): Study the following information carefully and answer the given questions.

The following bar graph-1 shows the total clothes (Indian and Western) in 6 different shops and the bar graph-2 shows the total Western clothes in the shops.

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6) Find the ratio between the total clothes (Indian and Western) in shop A and C together to that of total western clothes in shop B and D together?

a) 7: 3

b) 12: 5

c) 19: 11

d) 23: 15

e) None of these

7) Find the average western clothes in shop A, C and E together?

a) 240

b) 280

c) 320

d) 300

e) None of these

8) Total Indian clothes in shop A and B together is approximately what percentage of total western clothes in shop B and F together?

a) 108 %

b) 95 %

c) 82 %

d) 74 %

e) 126 %

9) Find the difference between the average number of clothes in shop A and F together to that of the average number of Indian clothes in shop C and E together?

a) 180

b) 220

c) 150

d) 90

e) None of these

10) Total Western clothes in shop B and C together is approximately what percentage less than the total clothes (Indian and Western) in shop A and D together?

a) 23 %

b) 44 %

c) 37 %

d) 52 %

e) 66 %

Option (a)

The share of A, B and C

= > [45000*5 + 30000*7]: [32000*5 + 38000*7]: [22000*8 + 22000*(125/100)*4]

= > [225000 + 210000]: [160000 + 266000]: [176000 + 110000]

= > 435000: 426000: 286000

= > 435: 426: 286 โ  435: 440: 364

This option doesnโt satisfy the given condition

Option (b)

The share of A, B and C

= > [45000*5 + 30000*7]: [32000*5 + 42000*7]: [24000*8 + 24000*(125/100)*4]

= > [225000 + 210000]: [160000 + 294000]: [192000 + 120000]

= > 435000: 454000: 312000

= > 435: 454: 312 โ  435: 440: 364

This option doesnโt satisfy the given condition

Option (c)

The share of A, B and C

= > [45000*5 + 30000*7]: [32000*5 + 40000*7]: [28000*8 + 28000*(125/100)*4]

= > [225000 + 210000]: [160000 + 280000]: [224000 + 140000]

= > 435000: 440000: 364000

= > 435: 440: 364

This option satisfy the given condition

Option (d)

The share of A, B and C

= > [45000*5 + 30000*7]: [32000*5 + 36000*7]: [26000*8 + 26000*(125/100)*4]

= > [225000 + 210000]: [160000 + 252000]: [208000 + 130000]

= > 435000: 412000: 338000

= > 435: 412: 338 โ  435: 440: 364

This option doesnโt satisfy the given condition

Option (e)

The share of A, B and C

= > [45000*5 + 30000*7]: [32000*5 + 37000*7]: [30000*8 + 30000*(125/100)*4]

= > [225000 + 210000]: [160000 + 259000]: [240000 + 150000]

= > 435000: 419000: 390000

= > 435: 419: 390 โ  435: 440: 364

This option doesnโt satisfy the given condition

Option (a)

Let the marked price be x,

Selling price = x*(70/100) = 7x/10

Cost price = (7x/10) * (100/90) = 7x/9

When 10% discount is allowed,

Selling price = x*(90/100) = 9x/10

Profit = (9x/10) โ (7x/9)

= > (81x – 70x)/90

= > 11x/90

Profit percentage = [(11x/90) / (7x/9)]*100

= (11x/90) * (9/7x) * 100

= 15.7 %

This option doesnโt satisfy the given condition

Option (b)

Let the marked price be x,

Selling price = x*(75/100) = 3x/4

Cost price = (3x/4) * (100/85) = 15x/17

When 10% discount is allowed,

Selling price = x*(90/100) = 9x/10

Profit = (9x/10) โ (15x/17)

= > (153x – 150x)/170

= > 3x/170

Profit percentage

= > [(3x/170) / (15x/17)]*100 = (3x/170) * (17/15x) * 100 = 2 %

This option doesnโt satisfy the given condition

Option (c)

Let the marked price be x,

Selling price = x*(65/100) = 13x/20

Cost price = (13x/20) * (100/78) = 5x/6

When 10% discount is allowed,

Selling price = x*(90/100) = 9x/10

Profit = (9x/10 โ 5x/6)

= (27x โ 25x)/30 = 2x/30

= x/15

Profit % = (x/15)/(5x/6) * 100

= 8%

This option satisfy the given condition

Option (d)

Let the marked price be x,

Selling price = x*(75/100) = 3x/4

Cost price = (3x/4) * (100/90) = 5x/6

When 10% discount is allowed,

Selling price = x*(90/100) = 9x/10

Profit = (9x/10) โ (5x/6)

= > (54x – 50x)/60

= > 4x/60 = x/15

Profit percentage = [(x/15) / (5x/6)]*100 = (x/15) * (6/5x) * 100 = 8 %

This option satisfy the given condition

SI = (P*n*r)/100

33750 = (P*5*15)/100

P = (33750*100)/75 = Rs. 45000

Option (a)

The difference between CI and SI for two years is,

Diff = P*(r/100)2

= > 45000*(12/100)2

= > 45000*(144/10000) = Rs. 648

This option satisfies the given condition.

Option (b)

The difference between CI and SI for two years is,

Diff = P*(r/100)2

= > 45000*(10/100)2

= > 45000*(1/100) = Rs. 450

This option satisfies the given condition.

Option (c)

The difference between CI and SI for two years is,

Diff = P*(r/100)2

= > 45000*(15/100)2

= > 45000*(/10000) = Rs. 1012.5

This option doesnโt satisfy the given condition.

Option (a)

Total mixture of milk and water = 75 litres

5โs = 75

1โs = 15

Total milk = 45 litres, water = 30 litres

According to the question,

45/(30 + x) = (45/55)

45/(30 + x) = 9/11

55 = 30 + x

X = 25

25 litres of water should be added to the mixture.

This option satisfies the given condition.

Option (b)

Total mixture of milk and water = 90 litres

5โs = 90

1โs = 18

Total milk = 54 litres, water = 36 litres

According to the question,

54/(36 + x) = (45/55)

54/(36 + x) = 9/11

66 = 36 + x

X = 30

30 litres of water should be added to the mixture.

This option satisfies the given condition.

Option (c)

Total mixture of milk and water = 100 litres

5โs = 100

1โs = 20

Total milk = 60 litres, water = 40 litres

According to the question,

60/(40 + x) = (45/55)

60/(40 + x) = 9/11

220 = 120 + 3x

100 = 3x

X = 100/3 = 33.33 litres

33.33 litres of water should be added to the mixture.

This option doesnโt satisfy the given condition.

Option (a)

Increased weight = 16*3 = 48 kg

So 2 womenโs weight = 58 kg + 48 kg = 106 kg

Average weight of 2 women = 106/2 = 53 kg

This option doesnโt satisfy the given condition.

Option (b)

Increased weight = 14*3 = 42 kg

So 2 womenโs weight = 58 kg + 42 kg = 100 kg

Average weight of 2 women = 100/2 = 50 kg

This option doesnโt satisfy the given condition.

Option (c)

Increased weight = 12*3 = 36 kg

So 2 womenโs weight = 58 kg + 36 kg = 94 kg

Average weight of 2 women = 94/2 = 47 kg

This option satisfies the given condition.

Option (d)

Increased weight = 18*3 = 54 kg

So 2 womenโs weight = 58 kg + 54 kg = 94 kg

Average weight of 2 women = 112/2 = 56 kg

This option doesnโt satisfy the given condition.

Direction (6-10) :

The total clothes (Indian and Western) in shop A and C together

= > 540 + 720 = 1260

The total western clothes in shop B and D together

= > 280 + 260 = 540

Required ratio = 1260: 540 = 7: 3

The total western clothes in shop A, C and E together

= > 320 + 360 + 220 = 900

Required average = 900/3 = 300

Total Indian clothes in shop A and B together

= > (540 โ 320) + (660 โ 280)

= > 220 + 380 = 600

Total western clothes in shop B and F together

= > 280 + 350 = 630

Required % = (600/630)*100 = 95 %

The average number of clothes (Indian and Western) in shop A and F together

= > (540 + 560)/2 = 550

The total number of Indian clothes in shops C and E together

= > (720 โ 360) + (600 โ 220)

= > 360 + 380 = 740

The average number of Indian clothes in shops C and E together

= > 740/2 = 370

Required difference = 550 โ 370 = 180

Total Western clothes in shop B and C together

= > 280 + 360 = 640

Total clothes (Indian and Western) in shop A and D together

= > 540 + 480 = 1020

Required % = [(1020 โ 640)/1020]*100 = (380/1020)*100 = 37 %

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