Dear Aspirants, Our IBPS Guide team is providing new series of Quants Questions for IBPS PO Prelims 2022 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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1) A bus covers a certain distance at the speed of 45 kmph in t minutes and bike covers the same distance at the speed of 54 kmph in (t – 40) minutes. Find the distance covered by bus?
A.170 km
B.180 km
C.175 km
D.178 km
E.181 km
2) A flight takes off 20 minutes late, so the flight is increased the speed by 50% and then reaches the destination on time. What is the time taken by the flight to reach the destination at its usual speed?
A.80 minutes
B.60 minutes
C.90 minutes
D.45 minutes
E.None of these
3) Ratio of the speed of the bike to the car is 4:5. If the bike covers 312 km in 6 hours, then find the time taken by the car to cover 715 km.
A.11 hours
B.13 hours
C.7.5 hours
D.6.5 hours
E.None of these
4) A car covers a certain distance in 8 hours. If the speed of the car is decreased by 12 km/hr, then the same distance is covered in 10 hours. Then find the total distance covered by the car with 20% more than the usual speed in 5 hours?Â
A.640 km
B.560 km
C.360 km
D.450 km
E.None of these
5) Ratio of the speed of the train and bus is 6:5. If the time taken by the train to cover D km is equal to the time taken by bus to cover (D – 180) km, then find the time taken by the train to cover (D + 270) km?
A.12 hours
B.15 hours
C.18 hours
D.20 hours
E.Cannot be determined
6) Car A covers D km with the speed of 80 kmph in (t + 3) hours and car B covers (D + 220) km in (2t + 1) hours. If the speed of car B is 25% more than the speed of car A, then find the value of t?
A.2
B.1
C.5
D.3
E.Cannot be determined
7) A bus covers a certain distance in 5 hours. If the speed of the bus is reduced by 8kmph, then the same distance is covered in 13 hours. Find the distance covered by the bus with the actual speed in 4 hours?
A.20 km
B.52 km
C.39 km
D.28 km
E.None of these
8) A train covers 560 km in 7 hours. The speed of a car is 50% more than the speed of the train. If the train covers D km in (x + 3.5) hours and the car covers the same distance in x hours, then find the value of D?
A.720 km
B.750 km
C.800 km
D.840 km
E.None of these
9) A car is travelling with the speed of 60 kmph and the car increases its speed by 20 kmph after every hour. Find the time taken by the car to cover 360 km?
A.5
B.4
C.3
D.6
E.9
10) Person X start from point A and person Y start from point B running towards each and meets first time after 8 hours. (Both are started running at same time). Find speed of Y in km/h, if speed of X is 200% more than Y and distance between A and B is 960 km.
A.90 km/h
B.60km/h
C.30 km/h
D.45 km/h
E.None of these
Answers :
1) Answer: B
Distance = 45 * t/60 = 3t/4
Distance = 54 * (t – 40)/60 = 9/10 * (t – 40)
3t/4 = 9t/10 – 36
36 = 6t/40
t = 240
Distance = 3 * 240/4 = 180 km
2) Answer: B
Ratio of the new speed to usual speed = 150: 100 = 3:2
Ratio of new time to usual time = 2: 3
Required time = 20/(3-2)*3 = 60 mins
3) Answer: A
Speed of bike = 312/6 = 52 kmph
Speed of car = 5/4 * 52 = 65 kmph
Required time = 715/65 = 11 hours
4) Answer: C
Let the total distance=x km
Speed=Distance/Time
x/8-x/10=12
5x-4x=480
x=480
Usual speed of the car=480/8=60 km/hr
Required distance=60*120/100*5=360 km
5) Answer: E
Speed of train = 6x
Speed of bus = 5x
D/6x = (D – 180)/5x
5D = 6D – 180 * 6
D = 1080
We cannot find the time taken as we don’t know the speed of the train.
6) Answer: D
D/80 = t + 3
D = 80t + 240
(D + 220)/(80 * 125/100) = 2t + 1
D + 220 = 200t + 100
D = 200t – 120
80t + 240 = 200t – 120
120t = 360
t = 3
7) Answer: B
Let total distance be x km
speed = Total distance / Total time
x/5 – x/13 = 8
(13x-5x)/65 = 8
8x/65 = 8
x= 65 km
Actual speed = 65/5 = 13 kmph
Required distance = 13 * 4 = 52 km
8) Answer: D
Speed of train = 560 /7 = 80 kmph
Speed of car = 80 * 150/100 = 120 kmph
D/80 = (x + 3.5)
80 * (x + 3.5) = D
D/120 = x
D = 120x
80x + 280 = 120x
x = 7
D = 120 * 7 = 840 km
9) Answer: B
Sn = (n/2) * (2a + (n – 1) * d)
360 = (n/2) * (2 * 60 + (n – 1) * 20)
720 = 120n + 20n2 – 20n
n2 + 5n – 36 = 0
n2 + 9n – 4n – 36 = 0
n(n + 9) – 4(n + 9) = 0
n = 4 hours (Neglecting the negative value)
10) Answer: C
Let speed of Y = a km/h
Speed of X = 300% of a = 3a
According to question
960/8 = (3a + a)
4a = 120
a = 30
Speed of Y = 30 km/h
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