“20-20” Quantitative Aptitude | Crack IBPS PO Prelims 2018 Day-216
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Directions (Q. 1 – 5): Find the wrong term in the following number series?
4, 26, 178, 1238, 8672
Correct
Answer: c)
Explanation:
The correct series is,
4, 26, 178, 1240, 8672
The pattern is, *7 – 2, *7 – 4, *7 – 6, *7 -8,..
The wrong term is, 1238
Incorrect
Answer: c)
Explanation:
The correct series is,
4, 26, 178, 1240, 8672
The pattern is, *7 – 2, *7 – 4, *7 – 6, *7 -8,..
The wrong term is, 1238
Question 4 of 20
4. Question
Directions (Q. 1 – 5): Find the wrong term in the following number series?
21, 10, 11, 16.5, 32, 77.5, 235.5
Correct
Answer: e)
Explanation:
The correct series is,
21, 10, 11, 15, 32, 77.5, 235.5
The pattern is, *0.5 – 0.5, *1 + 1, *1.5 -1.5, *2 + 2, *2.5 – 2.5, *3 + 3,..
The wrong term is, 16.5
Incorrect
Answer: e)
Explanation:
The correct series is,
21, 10, 11, 15, 32, 77.5, 235.5
The pattern is, *0.5 – 0.5, *1 + 1, *1.5 -1.5, *2 + 2, *2.5 – 2.5, *3 + 3,..
The wrong term is, 16.5
Question 5 of 20
5. Question
Directions (Q. 1 – 5): Find the wrong term in the following number series?
37, 40, 85, 267, 1080, 5415
Correct
Answer: d)
Explanation:
The correct series is,
37, 40, 86, 267, 1080, 5415
The pattern is, *1 + 3, *2 + 6, *3 + 9, *4 + 12, *5 + 15,..
The wrong term is, 85
Incorrect
Answer: d)
Explanation:
The correct series is,
37, 40, 86, 267, 1080, 5415
The pattern is, *1 + 3, *2 + 6, *3 + 9, *4 + 12, *5 + 15,..
The wrong term is, 85
Question 6 of 20
6. Question
Directions (Q. 6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
x^{2} – 12x + 36 = 0
5y^{2} + 4y – 12 = 0
Correct
Answer: a)
Explanation:
I. x^{2} – 12x + 36 = 0
(x – 6)(x – 6) = 0
X = 6, 6
II. 5y^{2} + 4y – 12 = 0
5y^{2} + 10y – 6y – 12 = 0
5y (y + 2) – 6 (y + 2) = 0
(5y – 6) (y + 2) = 0
Y = 6/5, – 2 = 1.2, -2
x > y
Incorrect
Answer: a)
Explanation:
I. x^{2} – 12x + 36 = 0
(x – 6)(x – 6) = 0
X = 6, 6
II. 5y^{2} + 4y – 12 = 0
5y^{2} + 10y – 6y – 12 = 0
5y (y + 2) – 6 (y + 2) = 0
(5y – 6) (y + 2) = 0
Y = 6/5, – 2 = 1.2, -2
x > y
Question 7 of 20
7. Question
Directions (Q. 6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
2x^{2} + 12x + 16 = 0
3y^{2} -7y – 6 = 0
Correct
Answer: c)
Explanation:
I. 2x^{2} + 12x + 16 = 0
2x^{2} + 4x + 8x + 16 = 0
2x(x + 2) + 8(x + 2) = 0
(2x + 8)(x + 2) = 0
X = -4, -2
II. 3y^{2} -7y – 6 = 0
3y^{2} -9y + 2y – 6 = 0
3y(y – 3) + 2(y – 3) = 0
(3y + 2) (y – 3) = 0
Y = – 2/3, 3 = -0.667, 3
x < y
Incorrect
Answer: c)
Explanation:
I. 2x^{2} + 12x + 16 = 0
2x^{2} + 4x + 8x + 16 = 0
2x(x + 2) + 8(x + 2) = 0
(2x + 8)(x + 2) = 0
X = -4, -2
II. 3y^{2} -7y – 6 = 0
3y^{2} -9y + 2y – 6 = 0
3y(y – 3) + 2(y – 3) = 0
(3y + 2) (y – 3) = 0
Y = – 2/3, 3 = -0.667, 3
x < y
Question 8 of 20
8. Question
Directions (Q. 6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
7x + 2y = -13
5x – 4y = 7
Correct
Answer: a)
Explanation:
7x + 2y = -13–à (1)
5x – 4y = 7–à (2)
By solving the equation (1) and (2), we get,
X = – 1, y = -3
X > y
Incorrect
Answer: a)
Explanation:
7x + 2y = -13–à (1)
5x – 4y = 7–à (2)
By solving the equation (1) and (2), we get,
X = – 1, y = -3
X > y
Question 9 of 20
9. Question
Directions (Q. 6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
x^{2} + 2x – 15 = 0
y^{2} + y – 56 = 0
Correct
Answer: e)
Explanation:
I. x^{2} + 2x – 15 = 0
(x + 5) (x – 3) = 0
X = -5, 3
II. y^{2} + y – 56 = 0
(y + 8) (y – 7) = 0
Y = -8, 7
Can’t be determined
Incorrect
Answer: e)
Explanation:
I. x^{2} + 2x – 15 = 0
(x + 5) (x – 3) = 0
X = -5, 3
II. y^{2} + y – 56 = 0
(y + 8) (y – 7) = 0
Y = -8, 7
Can’t be determined
Question 10 of 20
10. Question
Directions (Q. 6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
√25 x + √5625 = 0
(243)^{1/5 }y + (1728)^{1/3} = 0
Correct
Answer: c)
Explanation:
I. √25 x + √5625 = 0
5x = – 75
X = -15
II. (243)^{1/5 }y + (1728)^{1/3} = 0
(3^{5})^{1/5} y = – (12^{3})^{1/3}
3y = -12
Y = -4
X < y
Incorrect
Answer: c)
Explanation:
I. √25 x + √5625 = 0
5x = – 75
X = -15
II. (243)^{1/5 }y + (1728)^{1/3} = 0
(3^{5})^{1/5} y = – (12^{3})^{1/3}
3y = -12
Y = -4
X < y
Question 11 of 20
11. Question
Manju spends 25% of his monthly income on food and 10 % on education for his children. Of the remaining salary, he spends 15% on entertainment and 25% for purchasing dresses. She is now left with Rs. 15600. What is the monthly salary of Manju?
Correct
Answer: a)
Explanation:
Let Manju’s monthly salary be x,
According to the question,
X*(65/100)*(60/100) = 15600
X = 15600*(100/65)*(100/60)
X = Rs. 40000
Incorrect
Answer: a)
Explanation:
Let Manju’s monthly salary be x,
According to the question,
X*(65/100)*(60/100) = 15600
X = 15600*(100/65)*(100/60)
X = Rs. 40000
Question 12 of 20
12. Question
The average age of 35 students in a class is 15 years. If the age of the teacher is included then the average increases by 1, then find the age of the teacher’s wife who is 5 years younger than the teacher?
Correct
Answer: d)
Explanation:
Total age of 35 students = 35*15 = 525
Total age of (35 students + 1 teacher) = 36*16 = 576
The age of teacher = 576 – 525 = 51 years
The age of teacher’s wife = 51 – 5 = 46 years
(Or)
If both n and average increase or decrease 1, then,
The age of teacher = (35 + 16) or (36 + 15) = 51 years
The age of teacher’s wife = 51 – 5 = 46 years
Incorrect
Answer: d)
Explanation:
Total age of 35 students = 35*15 = 525
Total age of (35 students + 1 teacher) = 36*16 = 576
The age of teacher = 576 – 525 = 51 years
The age of teacher’s wife = 51 – 5 = 46 years
(Or)
If both n and average increase or decrease 1, then,
The age of teacher = (35 + 16) or (36 + 15) = 51 years
The age of teacher’s wife = 51 – 5 = 46 years
Question 13 of 20
13. Question
A and B started a business with Rs. 40000 and Rs. 50000 respectively. After 4 months B withdrew 30% of his initial investment , and after another 2 months C joined them with half of A’s investment. Find the total profit at the end of the year, if C’s share is Rs. 15000?
If the difference between the simple interest and Compound interest on a certain sum for 3 years at 6 % is Rs. 440.64. Find the sum?
Correct
Answer: a)
Explanation:
The difference between the simple interest and Compound interest on 3 years is,
Diff = [Sum * r^{2} * (r + 300)]/(100)^{3}
440.64 = [Sum * 6^{2} * (6 + 300)]/(100)^{3}
440.64 = [Sum * 36 * (306)]/(100)^{3}
Sum = [440.64*100*100*100]/(36*306)
= > Rs. 40000
Incorrect
Answer: a)
Explanation:
The difference between the simple interest and Compound interest on 3 years is,
Diff = [Sum * r^{2} * (r + 300)]/(100)^{3}
440.64 = [Sum * 6^{2} * (6 + 300)]/(100)^{3}
440.64 = [Sum * 36 * (306)]/(100)^{3}
Sum = [440.64*100*100*100]/(36*306)
= > Rs. 40000
Question 15 of 20
15. Question
The average marks obtained by 57 students in a certain examination are 24. The average marks of passed students is 26 and the average marks of failed students is 7. Then find the total number of passed students?
Correct
Answer: d)
Explanation:
Let passed students be x,
According to the question,
57*24 = 26*x + 7*(57 – x)
1368 = 26x + 399 – 7x
969 = 19x
X = 969/19 = 51
Total number of passed students = 51
Incorrect
Answer: d)
Explanation:
Let passed students be x,
According to the question,
57*24 = 26*x + 7*(57 – x)
1368 = 26x + 399 – 7x
969 = 19x
X = 969/19 = 51
Total number of passed students = 51
Question 16 of 20
16. Question
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
The following table shows the percentage distribution of total students participated in different sports (Tennis, Foot ball and Kabaddi) from different schools in the year 2017 and the remaining students didn’t participated in any games.
Find the ratio between the total number of students participated in Football from School P and R together to that of total number of students participated in Tennis from School Q and S together?
Correct
Answer: c)
Explanation:
The total number of students participated in Football from School P and R together
= > 1500*(32/100) + 1300*(26/100)
= > 480 + 338 = 818
The total number of students participated in Tennis from School Q and S together
= > 2200*(24/100) + 1800*(26/100)
= > 528 + 468 = 996
Required ratio = 818: 996 = 409: 498
Incorrect
Answer: c)
Explanation:
The total number of students participated in Football from School P and R together
= > 1500*(32/100) + 1300*(26/100)
= > 480 + 338 = 818
The total number of students participated in Tennis from School Q and S together
= > 2200*(24/100) + 1800*(26/100)
= > 528 + 468 = 996
Required ratio = 818: 996 = 409: 498
Question 17 of 20
17. Question
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
The following table shows the percentage distribution of total students participated in different sports (Tennis, Foot ball and Kabaddi) from different schools in the year 2017 and the remaining students didn’t participated in any games.
Find the difference between the total number of students didn’t participated in any sports from School P to that from School T?
Correct
Answer: a)
Explanation:
The total number of students didn’t participated in any sports from School P
= > 1500*(25/100) = 375
The total number of students didn’t participated in any sports from School T
= > 2000*(33/100) = 660
Required difference = 660 – 375 = 285
Incorrect
Answer: a)
Explanation:
The total number of students didn’t participated in any sports from School P
= > 1500*(25/100) = 375
The total number of students didn’t participated in any sports from School T
= > 2000*(33/100) = 660
Required difference = 660 – 375 = 285
Question 18 of 20
18. Question
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
The following table shows the percentage distribution of total students participated in different sports (Tennis, Foot ball and Kabaddi) from different schools in the year 2017 and the remaining students didn’t participated in any games.
Find the average number of students participated in Kabaddi from School Q, R and S together?
Correct
Answer: d)
Explanation:
The total number of students participated in Kabaddi from School Q, R and S together
= > 2200*(12/100) + 1300*(18/100) + 1800*(20/100)
= > 264 + 234 + 360 = 858
Required average = 858/3 = 286
Incorrect
Answer: d)
Explanation:
The total number of students participated in Kabaddi from School Q, R and S together
= > 2200*(12/100) + 1300*(18/100) + 1800*(20/100)
= > 264 + 234 + 360 = 858
Required average = 858/3 = 286
Question 19 of 20
19. Question
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
The following table shows the percentage distribution of total students participated in different sports (Tennis, Foot ball and Kabaddi) from different schools in the year 2017 and the remaining students didn’t participated in any games.
Total number of students participated in Tennis from School Q is approximately what percentage of total number of students participated in Football from School S?
Correct
Answer: b)
Explanation:
Total number of students participated in Tennis from School Q
= > 2200*(24/100) = 528
Total number of students participated in Football from School S
= > 1800*(32/100) = 576
Required % = (528/576)*100 = 92 %
Incorrect
Answer: b)
Explanation:
Total number of students participated in Tennis from School Q
= > 2200*(24/100) = 528
Total number of students participated in Football from School S
= > 1800*(32/100) = 576
Required % = (528/576)*100 = 92 %
Question 20 of 20
20. Question
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
The following table shows the percentage distribution of total students participated in different sports (Tennis, Foot ball and Kabaddi) from different schools in the year 2017 and the remaining students didn’t participated in any games.
Total number of students didn’t participated in any sports from School S is what percentage more/less than the total number of students didn’t participated in any sports from School T?
Correct
Answer: c)
Explanation:
Total number of students didn’t participated in any sports from School S
= > 1800*(22/100) = 396
Total number of students didn’t participated in any sports from School T
= > 2000*(33/100) = 660
Required % = [(660 – 396)/660]*100 = 40 % less
Incorrect
Answer: c)
Explanation:
Total number of students didn’t participated in any sports from School S
= > 1800*(22/100) = 396
Total number of students didn’t participated in any sports from School T
Directions (Q. 1 – 5): Find the wrong term in the following number series?
1) 1146, 1217, 1371, 1573, 1800, 2036
a) 1371
b) 1573
c) 1217
d) 2036
e) 1800
2) 225, 223, 111, 36, 8
a) 223
b) 111
c) 36
d) 225
e) 8
3) 4, 26, 178, 1238, 8672
a) 26
b) 4
c) 1238
d) 178
e) 8672
4) 21, 10, 11, 16.5, 32, 77.5, 235.5
a) 10
b) 32
c) 77.5
d) 235.5
e) 5
5) 37, 40, 85, 267, 1080, 5415
a) 37
b) 267
c) 1080
d) 85
e) 5415
Directions (Q. 6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
6) I.x^{2} – 12x + 36 = 0
II. 5y^{2} + 4y – 12 = 0
7) I.2x^{2} + 12x + 16 = 0
II. 3y^{2} -7y – 6 = 0
8) I.7x + 2y = -13
II. 5x – 4y = 7
9) I.x^{2} + 2x – 15 = 0
II. y^{2} + y – 56 = 0
10) I. √25 x + √5625 = 0
II. (243)^{1/5 }y + (1728)^{1/3} = 0
11) Manju spends 25% of his monthly income on food and 10 % on education for his children. Of the remaining salary, he spends 15% on entertainment and 25% for purchasing dresses. She is now left with Rs. 15600. What is the monthly salary of Manju?
a) Rs. 40000
b) Rs. 45000
c) Rs. 50000
d) Rs. 60000
e) None of these
12) The average age of 35 students in a class is 15 years. If the age of the teacher is included then the average increases by 1, then find the age of the teacher’s wife who is 5 years younger than the teacher?
a) 48 years
b) 44 years
c) 50 years
d) 46 years
e) None of these
13) A and B started a business with Rs. 40000 and Rs. 50000 respectively. After 4 months B withdrew 30% of his initial investment , and after another 2 months C joined them with half of A’s investment. Find the total profit at the end of the year, if C’s share is Rs. 15000?
a) Rs. 124700
b) 135000
c) Rs. 118500
d) Rs. 102300
e) None of these
14) If the difference between the simple interest and Compound interest on a certain sum for 3 years at 6 % is Rs. 440.64. Find the sum?
a) 40000
b) Rs. 35000
c) Rs. 30000
d) Rs. 50000
e) None of these
15) The average marks obtained by 57 students in a certain examination are 24. The average marks of passed students is 26 and the average marks of failed students is 7. Then find the total number of passed students?
a) 49
b) 47
c) 45
d) 51
e) None of these
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
The following table shows the percentage distribution of total students participated in different sports (Tennis, Foot ball and Kabaddi) from different schools in the year 2017 and the remaining students didn’t participated in any games.
16) Find the ratio between the total number of students participated in Football from School P and R together to that of total number of students participated in Tennis from School Q and S together?
a) 234: 317
b) 53: 75
c) 409: 498
d) 12: 37
e) None of these
17) Find the difference between the total number of students didn’t participated in any sports from School P to that from School T?
a) 285
b) 250
c) 225
d) 180
e) None of these
18) Find the average number of students participated in Kabaddi from School Q, R and S together?
a) 275
b) 268
c) 252
d) 286
e) None of these
19) Total number of students participated in Tennis from School Q is approximately what percentage of total number of students participated in Football from School S?
a) 80 %
b) 92 %
c) 74 %
d) 66 %
e) 55 %
20) Total number of students didn’t participated in any sports from School S is what percentage more/less than the total number of students didn’t participated in any sports from School T?
a) 50 % more
b) 25 % less
c) 40 % less
d) 50 % more
e) 40 % more
Answers :
Direction (1-5) :
1). Answer: c)
Explanation:
The correct series is,
1146 1218 1371 1573 1800 2036
72 153 202 227 236
81 49 25 9
(9^{2}) (7^{2}) (5^{2}) (3^{2})
The difference of difference is, 9^{2}, 7^{2}, 5^{2}, 3^{2},..