IBPS RRB Clerk/EPFO Assistant/LIC ADO Prelims Quantitative Aptitude Questions 2019 (Day-04)

Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for IBPS RRB Clerk/EPFO Assistant/LIC ADO Prelims 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.

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[WpProQuiz 6603]

 

Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established

 

1) I) 3x2 – 21x + 36 = 0

II) 4y2 – 2y – 56 = 0

 

2) I) 3x – 5y = 13

II) 4x – 3y + 1 = 0

 

3) I) x2 – 3x – 88 = 0

II) y2 – 7y – 98 = 0

 

4) I) 5x2 – 10x – 75 = 0

II) y2 – 15y + 56 = 0

 

5) I) 2x2 + 13x + 18 = 0

II) 3y2 – 18y + 27 = 0

Directions (Q. 6 – 10): Study the following information carefully and answer the given questions?

The following bar graph shows the total number of fortune magazine readers (In thousands)in the year 2017 and 2018 in 5 different states.

6) Find the ratio between the total number of fortune magazine readers of Kerala and MP in the year 2017 to that of the total number of fortune magazine readers of Maharashtra and Karnataka in the year 2018?

a) 8 : 7

b) 11 : 9

c) 13 : 10

d) 25 : 22

e) None of these

7) Find the difference between the total number of fortune magazine readers of Andhra to that of Maharashtra in both the years together?

a) 3000

b) 5000

c) 2000

d) 1000

e) None of these

8) Find the average number of fortune magazine readers of all the given states in the year 2018?

a) 32000

b) 34000

c) 33000

d) 35000

e) None of these

9) Total number of fortune magazine readers of Andhra and Karnataka in the year 2018 is approximately what percentage of total number of fortune magazine readers of Kerala and Maharashtra in the year 2017?

a) 103 %

b) 78 %

c) 66 %

d) 117 %

e) 91 %

10) The total number of fortune magazine readers of Kerala in both the years together is approximately what percentage more/less than the total number of fortune magazine readers of MP in both the years together?

a) 15 % more

b) 15 % less

c) 3 % more

d) 27 % more

e) 3 % less

Answers :

Direction (1-5) :

1) Answer: e)

I) 3x2 – 21x + 36 = 0

3x2 – 9x – 12x + 36 = 0

3x (x – 3) – 12 (x – 3) = 0

(3x – 12) (x – 3) = 0

x = 4, 3

II) 4y2 – 2y – 56 = 0

4y2 – 16y + 14y – 56 = 0

4y (y – 4) + 14 (y – 4) = 0

(4y + 14) (y – 4) = 0

y = -14/4, 4 = -3.5, 4

Can’t be determined

2) Answer: a)

3x – 5y = 13 —> (1)

4x – 3y = -1 —> (2)

By solving the equation (1) and (2), we get,

x = -4, y = -5

x > y

3) Answer: e)

I) x2 – 3x – 88 = 0

(x – 11) (x + 8) = 0

x = 11, -8

II) y2 – 7y – 98 = 0

(y – 14) (y + 7) = 0

y = 14, -7

Can’t be determined

4) Answer: c)

I) 5x2 – 10x – 75 = 0

5x2 – 25x + 15x – 75 = 0

5x (x – 5) + 15 (x – 5) = 0

(5x + 15) (x – 5) = 0

x = -3, 5

II) y2 – 15y + 56 = 0

(y – 8) (y – 7) = 0

y = 8, 7

x < y

5) Answer: c)

I) 2x2 + 13x + 18 = 0

2x2 + 4x + 9x + 18 = 0

2x (x + 2) + 9 (x + 2) = 0

(2x + 9) (x + 2) = 0

x = -4.5, -2

II) 3y2 – 18y + 27 = 0

3y2 – 9y – 9y + 27 = 0

3y (y – 3) – 9 (y – 3) = 0

(3y – 9) (y – 3) = 0

y = 3, 3

x < y

Direction (6-10) :

6) Answer: a)

The total number of fortune magazine readers of Kerala and MP in the year 2017

= >36000 + 28000 = 64000

The total number of fortune magazine readers of Maharashtra and Karnataka in the year 2018

= >26000 + 30000 = 56000

Required ratio = 64000 : 56000 = 8 : 7

7) Answer: d)

The total number of fortune magazine readers of Andhra in both the years together

= >25000 + 32000 = 57000

The total number of fortune magazine readers of Maharashtra in both the years together

= >32000 + 26000 = 58000

Required difference = 58000 – 57000 = 1000

8) Answer: b)

The average number of fortune magazine readers of all the given states in the year 2018

= >(32000 + 38000 + 44000 + 26000 + 30000) / 5

= > 170000/5 = 34000

9) Answer: e)

Total number of fortune magazine readers of Andhra and Karnataka in the year 2018

= >32000 + 30000 = 62000

Total number of fortune magazine readers of Kerala and Maharashtra in the year 2017

= >36000 + 32000 = 68000

Required % = (62000 / 68000) * 100 = 91.17 % = 91 %

10) Answer: c)

The total number of fortune magazine readers of Kerala in both the years together

= >36000 + 38000 = 74000

The total number of fortune magazine readers of MP in both the years together

= >28000 + 44000 = 72000

Required % = [(74000 – 72000) / 72000] * 100 = 2.77 % = 3 % more

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