# IBPS RRB PO Prelims Quantitative Aptitude Questions 2019 (Day-12)

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IBPS RRB PO Prelims Quantitative Aptitude Questions 2019 (Day-12)

Directions (Q. 1 – 5): What approximate value should come in place of question mark (?) in the following questions?

1) (32/7) of [8955.21 – 2368.13] + 234.5 =? + 3429.87

a) 31560

b) 22440

c) 26920

d) 34280

e) 17650

2) 24 % of 849 + 56 % of 1299 – 456.23 ÷ 4 =? + (8.11)2

a) 686

b) 612

c) 575

d) 438

e) 754

3) 17 % of ? – 2054 ÷ 12.78 – 222 ÷ 3.01 = 57

a) 1700

b) 2000

c) 2200

d) 1300

e) 2500

4) 5 (¼) + 3 (5/8) – 4 (2/3) + 2 (½) =? – 4 (3/4)

a) 20

b) 6

c) 24

d) 12

e) 30

5) [(46.04)2 ÷ 23 × 6.11] ÷ 12 = 2.99 ×? – 788 ÷ 3

a) 158

b) 103

c) 215

d) 267

e) 99

Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:

The following table shows the total population in 5 different states, the ratio of male and female among them and the percentage of population below poverty line. 6) Find the difference between the total male population in state P and R together to that of total female population in state Q and T together?

a) 15 lakhs

b) 22 lakhs

c) 6 lakhs

d) 10 lakhs

e) None of these

7) Find the ratio between the above poverty line population in state R to that of the below poverty line population in state S?

a) 108: 85

b) 75: 62

c) 52: 43

d) 11: 5

e) None of these

8) Find the total number of female population in state P, R and S together

a) 72 lakhs

b) 90 lakhs

c) 56 lakhs

d) 64 lakhs

e) None of these

9) The above poverty line population in state P and Q together is approximately what percentage of total population in state S?

a) 132 %

b) 153 %

c) 120 %

d) 105 %

e) 94 %

10) The below poverty line population in state R and T together is what percentage more/less than the total male population in state Q and S together?

a) 36 % more

b) 15 % less

c) 36 % less

d) 4 % more

e) 15 % more

Direction (1-5) :

(32/7) of [8955 – 2368] + 235 = x + 3430

(32/7)*(6587) + 235 – 3430 = x

X = 30112 + 235 – 3430 = 26917

X = 26920

24 % of 850 + 56 % of 1300 – 456 ÷ 4 = x + 82

(24/100)*850 + (56/100)*1300 – (456/4) – 64 = x

204 + 728 – 114 – 64 = x

X = 754

(17/100)*x – (2054/13) – (222/3) = 57

(17/100)*x = 57 + 158 + 74

(17/100)*x = 289

X = 1700

5 (¼) + 3 (5/8) – 4 (2/3) + 2 (½) + 4 (¾) = x

X = 5 + 4 – 5 + 3 + 5 = 12

[(46)2 ÷ 23 × 6] ÷ 12 = 3x – 789 ÷ 3

(46*46*6)/(23*12) = 3x – (789/3)

46 + 263 = 3x

3x = 309

X = 103

Direction (6-10) :

The total male population in state P and R together

= > 60*(7/12) + 36*(3/4)

= > 35 + 27 = 62 lakhs

The total female population in state Q and T together

= > 45*(4/9) + 72*(1/2)

= > 20 + 36 = 56 lakhs

Required difference = 62 – 56 = 6 lakhs

The above poverty line population in state R

= > 36*(60/100)

The below poverty line population in state S

= > 50*(34/100)

Required ratio = [36*(60/100)]: [50*(34/100)]

= > 108: 85

The total number of female population in state P, R and S together

= > 60*(5/12) + 36*(1/4) + 50*(3/5)

= > 25 + 9 + 30 = 64 lakhs

The above poverty line population in state P and Q together

= > 60*(75/100) + 45*(70/100)

= > 45 + 31.5 = 76.5 lakhs

Total population in state S = 50 lakhs

Required % = (76.5/50)*100 = 153 %

The below poverty line population in state R and T together

= > 36*(40/100) + 72*(20/100)

= > 14.4 + 14.4 = 28.8 lakhs

The total male population in state Q and S together

= > 45*(5/9) + 50*(2/5)

= > 25 + 20 = 45 lakhs

Required % = [(45 – 28.8)/45]*100 = 36 % less

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