Concepts Direction Sense Questions in Reasoning – Free PDF

Important Concepts and Tips to Solve Direction Sense Questions in Reasoning – Download in PDF:
Dear Readers,Â Â we have given the Important Concepts and Tips to Solve Direction Sense Questions in Reasoning. Candidates those who are preparing for the upcoming IBPS PO/ Clerk 2016 examination can make use of it.

DISTANCE AND DIRECTION
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According to geography there areÂ 8-directions:
Â·Â Â Â Â Â Â Â Â Â 4-cardinalÂ directions â€“Â North, South, East and West
Â·Â Â Â Â Â Â Â Â Â 4-subsidiaryÂ directions â€“Â North-East, North-west, South-east, South-west
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DIRECTION OFÂ RIGHT TURN: Clockwise
DIRECTION OFÂ LEFT TURN: Anti-clockwise
PYTHAGORAS THEOREM:
This theorem is sometimes needed to find out theÂ distance coveredÂ by an individual in the question.
It states that, in aÂ right angled triangleÂ the length of theÂ hypotenuseÂ is equal to theÂ square root of the sum of squares of the other two sides.
Where, H=Hypotenuse
Â Â Â Â Â Â Â Â Â Â Â Â  X=Height
Â Â Â Â Â Â Â Â Â Â Â Â  Y=Base
Therefore, according to the theoremÂ H2Â = X2Â + Y2
i.e.,Â H= âˆš(X2+ Y2)
IMPORTANT POINTS TO REMEMBER WHILE SOLVING DISTANCE-DIRECTION QUESTION:
–Â Â Â Â Â Â Â Â To know theÂ directions on the plane of paper
–Â Â Â Â Â Â Â Â ToÂ sketch out the directionsÂ as per the instructions in the question
–Â Â Â Â Â Â Â Â To remember that on theÂ surface of paper
Â·Â Â Â Â Â Â Â Â Â The direction ofÂ right turnÂ is always in theÂ clockwise direction
Â·Â Â Â Â Â Â Â Â Â The direction ofÂ left turnÂ is always in theÂ anti-clockwiseÂ direction
Â·Â Â Â Â Â Â Â Â Â The direction ofÂ NorthÂ isÂ upwards
Â·Â Â Â Â Â Â Â Â Â The direction ofÂ SouthÂ isÂ downwards
Â·Â Â Â Â Â Â Â Â Â The direction ofÂ EastÂ isÂ â€˜to the rightâ€™
Â·Â Â Â Â Â Â Â Â Â The direction ofÂ WestÂ isÂ â€˜to the leftâ€™
–Â Â Â Â Â Â Â Â To formulate a step by step analysis of directions and distances
–Â Â Â Â Â Â Â Â To find the final direction or the distance between the starting and final point or both
QUESTION:
Ajith walks 10km towards North. From there he walks 6km towards south, then he turns left and walks 3km.
1)Â Â Â Â At what distance is Ajith from the original position?
(a)Â Â 7kmÂ Â Â Â Â Â Â Â Â  (b) 5kmÂ Â Â Â Â Â Â Â Â  (c) 3kmÂ Â Â Â Â Â Â Â Â  (d) 4km
2)Â Â Â Â In which direction is Ajith with reference to his starting point?
(a)Â Â North-EastÂ Â Â Â Â Â Â Â Â  (b) WestÂ Â Â Â Â Â Â Â Â  (c) South-EastÂ Â Â Â Â Â Â Â Â  (d) East
SOLUTION:
Â·Â Â Â Â Â Â Â Â Â Take the starting point asÂ â€˜Aâ€™
Â·Â Â Â Â Â Â Â Â Â Now,Â Ajith walks 10km towards North.
Â·Â Â Â Â Â Â Â Â Â The point 10km to the north is taken asÂ â€˜Bâ€™, AB=10km
Â·Â Â Â Â Â Â Â Â Â â€˜From there he walks 6km towards southâ€™Â i.e., from B Ajith walksÂ 6km downwards again.
Â·Â Â Â Â Â Â Â Â Â The point at 6km towards south is taken asÂ â€˜Câ€™, such thatÂ BC=6km
Â·Â Â Â Â Â Â Â Â Â SoÂ AC=4kmÂ [AB-BC=10-6=4]
Â·Â Â Â Â Â Â Â Â Â â€˜then he turns left and walks 3kmâ€™Â i.e., he turns in theÂ anti-clockwiseÂ direction from â€˜Câ€™ i.e., towards east and walks 3km in the same direction
Â·Â Â Â Â Â Â Â Â Â The point 3km in the east is taken asÂ â€˜Dâ€™, such thatÂ CD=3kmÂ and D is theÂ end point of the journey of Ajith
1)Â Â Â Â At what distance is Ajith from the original position?
(a)7kmÂ Â Â Â Â Â Â Â Â  (b) 5kmÂ Â Â Â Â Â Â Â Â  (c) 3kmÂ Â Â Â Â Â Â Â Â  (d) 4km
Â·Â Â Â Â Â Â Â Â Â Starting point of Ajith is â€˜Aâ€™
Â·Â Â Â Â Â Â Â Â Â End point of Ajith is â€˜Dâ€™
Â·Â Â Â Â Â Â Â Â Â Therefore, the distance of Ajith from the original position is theÂ distance between A and D
Â·Â Â Â Â Â Â Â Â Â To findÂ AD, Consider right angle triangle,Â ACD
AC = 4km
CD = 3km
ByÂ Pythagoras theorem, X2Â = AC2Â + CD2Â = 42Â + 32Â = 16+9
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X2Â = 25
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â X = âˆš25 = 5km
Â·Â Â Â Â Â Â Â Â Â Therefore, distance at which Ajith is from the original position is 5km
If the question was:
What is theÂ total distance coveredÂ by Ajith?
Then the answer will be theÂ sum of all the distancesÂ given in the questionÂ irrespective of their directions.
i.e.,Â 10km+6km+3km = 19km
Â
2)Â Â Â Â In which direction is Ajith with reference to his starting point?
(a)Â Â North-EastÂ Â Â Â Â Â Â Â Â  (b) WestÂ Â Â Â Â Â Â Â Â  (c) South-EastÂ Â Â Â Â Â Â Â Â  (d) East
Â·Â Â Â Â Â Â Â Â Â Present positionÂ of Ajith is atÂ â€˜Dâ€™
Â·Â Â Â Â Â Â Â Â Â Now, the direction in which Ajith is with respect to his starting point (A) is asked
Â·Â Â Â Â Â Â Â Â Â The answer is theÂ direction in which point â€˜Dâ€™Â is present with respect to pointÂ â€˜Aâ€™, which clearly is towards theÂ North-EastÂ direction as per the final figure.