Quantitative Aptitude Questions (Data Interpretation) for SBI Clerk 2018 Day-32:
Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June/July 2018. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Logical Reasoning | 10.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| Static GK Quiz | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Banking Awareness Quiz | 3.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
| General / Financial Awareness Quiz | 9.00 PM |
Directions (Q. 1-5) Study the following table carefully and answer the given questions:
Table below shows different Rate of Interest offered by three schemes:-
| Name | Scheme A | Scheme B | Scheme C |
| Amit | 10 | 10 | 12 |
| Sumit | 8 | 12 | 15 |
| Vineet | 6 | 16 | 18 |
| Sujan | 9 | ———– | 6 |
NOTE:
- Money Invested in all the schemes is for the period of 4 years unless mentioned.
- Missing is to be calculated
- Calculate Simple Interest unless specified.
- If the interest earned by Sumit in Scheme A and Scheme B together is Rs 1500 and the amount invested in both the schemes is same then find the interest earned in Scheme C? (Ratio of Investment in Scheme B to Scheme C is 25:15)
- 750
- 675
- 715
- 820
- None of these
- If the interest earned from scheme B by Sujan is equal to Rs 900 which is half of the interest earned from Scheme C then find the rate of interest offered by Scheme B? (Ratio of investment in Scheme B to Scheme C is 7:15)
- 6.42%
- 6%
- 5.65%
- 5%
- None of these
- When the interest received from Scheme A by Amit in 4 years is invested in scheme C it bears a interest of Rs 1200 then find the sum invested in scheme A?(Approx)
- 5500
- 5750
- 6250
- 6500
- None of these
- Find the difference between the interest earned by Amit in Scheme A which bears Simple Interest and Scheme C which bears Compound Interest and the sum invested is Rs15000.( Take time as 2 years)
- 765
- 816
- 837
- 537
- None of these
- If the money invested by Vineet together in Scheme A and Scheme B is Rs 10000 while the interest earned from both the scheme is half of the sum invested together then find the interest earned from Scheme B?
- 4160
- 4000
- 5160
- 6500
- None of these
Directions (Q. 6-10) Study the following bar graph carefully and answer the given questions:
Bar Graph shows time taken by 5 different pipes to fill a tank:-
Table above shows time taken by 5 different pipes to empty a tank.
| Pipe A | 15 |
| Pipe B | 10 |
| Pipe C | 16 |
| Pipe D | 8 |
| Pipe E | 10 |
All the units are in Hours.
- Two pipes A and B are used to fill the tank but due to some damage both the pipes worked with ¾ of their efficiency then in how much time the tank will be filled?
- 13.5
- 14
- 12.5
- 18
- None of these
- If the Pipe C and E are used to fill the tank and Pipe A is used to empty the tank then how much time is required to fill 40% of the tank?
- 10
- 15
- 8
- 20
- None of these
- Two Pipes D and E are used to fill the tank and Pipe C is used to empty the tank. Then find how much time is required to fill the tank if the three pipes work alternatively for one hour starting with D?
- 30
- 28.325
- 27.625
- 24
- None of these
- Two Pipes A and D opened together to fill the tank but after the tank was 56% full the pipe D was closed then find the total time required to fill the tank?
- 13
- 24
- 11
- 18
- None of these
- Three Pipes A, B and C are opened together to fill a tank but after how much time the Pipe B should be closed to fill the tank in 10 hours?
- 2.5 hrs
- 3.5 hrs
- 1 hr
- 1.5 hr
- None of these
Answers:
Directions (Q. 1-5)
- Answer: b
Explanation:
Let the sum invested in both the schemes be X
Then
X*8*4/100 + X*12*4/100 = 1500
32X/100 + 48X/100= 1500
80X/100=1500
X= 1500*100/80
X= 1875
Money Invested in scheme A and B= Rs 1875 (Investment is same)
Therefore,
Money invested in scheme C= 1875/25*15 (Ratio Given)
= 1125
Interest earned in Scheme C= 1125*4*15/100
= Rs 675
2.Answer a
Let the Money Invested in scheme C be X
Now,
=1800* 100 / 4*6 (Interest earned in scheme C is twice the Scheme B)
= Rs 7500
Money invested in Scheme C = Rs 7500
Money Invested in Scheme B = 7500/15*7
= Rs 3500
Rate of Interest in Scheme B= 900*100/3500*4
= 6.42%
- Answer c
let the principal invested in scheme C is X
X*12*4/100=1200
X= 1200 *100/48
=2500
Therefore, Interest received from Scheme A =Rs 2500
Money Invested =2500*100/4*10
= Rs 6250
Therefore,
Money invested in Scheme A= Rs 6250
- Answer b
Simple Interest earned by Amit in Scheme A= 15000*2*10/100
= Rs 3000
Compound Interest earned by Amit in Scheme C =15000{(1+12/100)^2-1)}
= Rs 3816
Difference = Rs (3816-3000) = Rs 816
- Answer: a
let the money invested in Scheme A be X, Scheme B = 10000-X
X*4*6/100+ 16*4(10000-x)=5000
24x/100 + 640000-64X/100 =5000
-40X + 640000/100= 5000
-40X+640000= 500000
40X=140000
X= 3500
Therefore,
Interest earned in Scheme B= 6500*16*4/100
=Rs 4160
Directions (Q. 6-10)
- Answer c
Total units of work = 75 (LCM of 25 and 15)
Work units done by both the pipes in 1 hour = 8
Work units done in 1 hour with ¾ of their actual efficiency= ¾ of 8 = 6
Time required to fill the tank= 75/6 = 12.5 hours.
- Answer c
Total units of work= 60
Units of worked done in 1 hour = (3+4)-4
= 3
Time required to fill 40% of the tank= 24/3
= 8 hours
- Answer c
Total Units of work= 240
Units of work done in 1 hour = (24+16)-15
= 25
Units of work done in 27 hours alternatively = 9 *25
= 225
Remaining units needs to be done by A= 15/24
= 5/8
Total time required= 27+5/8
= 27.625 hours
- Answer e
Total units of work= 50
Units of work done in 1 hour= 7
Time required to fill 56% of the tank by A and D= 28/7
= 4 hours
Time required to fill the remaining tank by A = 22/2
= 11 hours
Total time required = 4+11
= 15 hours.
- Answer d
Total units of work= 300
A and C will be opened for 10 hours
So, work done by A and C = (12+15) * 10
= 270
So, B should be opened for remaining units= (300-270)/ 20
= 1.5 hours.
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