# Quantitative Aptitude Questions (Data Interpretation) for SBI Clerk 2018 Day-32

## Quantitative Aptitude Questions (Data Interpretation) for SBI Clerk 2018 Day-32:

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June/July 2018. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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## Daily Practice Test Schedule | Good Luck

 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Logical Reasoning 10.00 AM Quantitative Aptitude “20-20” 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM Static GK Quiz 1.00 PM English Language “20-20” 2.00 PM Banking Awareness Quiz 3.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability “20-20” 7.00 PM English Language (New Pattern Questions) 8.00 PM General / Financial Awareness Quiz 9.00 PM

Directions (Q. 1-5) Study the following table carefully and answer the given questions:

Table below shows different Rate of Interest offered by three schemes:-

 Name Scheme A Scheme B Scheme C Amit 10 10 12 Sumit 8 12 15 Vineet 6 16 18 Sujan 9 ———– 6

NOTE:

1. Money Invested in all the schemes is for the period of 4 years unless mentioned.
2. Missing is to be calculated
3. Calculate Simple Interest unless specified.
1. If the interest earned by Sumit in Scheme A and Scheme B together is Rs 1500 and the amount invested in both the schemes is same then find the interest earned in Scheme C? (Ratio of Investment in Scheme B to Scheme C is 25:15)
1. 750
2. 675
3. 715
4. 820
5. None of these
1. If the interest earned from scheme B by Sujan is equal to Rs 900 which is half of the interest earned from Scheme C then find the rate of interest offered by Scheme B? (Ratio of investment in Scheme B to Scheme C is 7:15)
1. 6.42%
2. 6%
3. 5.65%
4. 5%
5. None of these
1. When the interest received from Scheme A by Amit in 4 years is invested in scheme C it bears a interest of Rs 1200 then find the sum invested in scheme A?(Approx)
1. 5500
2. 5750
3. 6250
4. 6500
5. None of these
1. Find the difference between the interest earned by Amit in Scheme A which bears Simple Interest and Scheme C which bears Compound Interest and the sum invested is Rs15000.( Take time as 2 years)
1. 765
2. 816
3. 837
4. 537
5. None of these
1. If the money invested by Vineet together in Scheme A and Scheme B is Rs 10000 while the interest earned from both the scheme is half of the sum invested together then find the interest earned from Scheme B?
1. 4160
2. 4000
3. 5160
4. 6500
5. None of these

Directions (Q. 6-10) Study the following bar graph carefully and answer the given questions: Bar Graph shows time taken by 5 different pipes to fill a tank:-

Table above shows time taken by 5 different pipes to empty a tank.

 Pipe A 15 Pipe B 10 Pipe C 16 Pipe D 8 Pipe E 10

All the units   are in Hours.

1. Two pipes A and B are used to fill the tank but due to some damage both the pipes worked with ¾ of their efficiency then in how much time the tank will be filled?
1. 13.5
2. 14
3. 12.5
4. 18
5. None of these
1. If the Pipe C and E are used to fill the tank and Pipe A is used to empty the tank then how much time is required to fill 40% of the tank?
1. 10
2. 15
3. 8
4. 20
5. None of these
1. Two Pipes D and E are used to fill the tank and Pipe C is used to empty the tank. Then find how much time is required to fill the tank if the three pipes work alternatively for one hour starting with D?
1. 30
2. 28.325
3. 27.625
4. 24
5. None of these
1. Two Pipes A and D opened together to fill the tank but after the tank was 56% full the pipe D was closed then find the total time required to fill the tank?
1. 13
2. 24
3. 11
4. 18
5. None of these
1. Three Pipes A, B and C are opened together to fill a tank but after how much time the Pipe B should be closed to fill the tank in 10 hours?
1. 2.5 hrs
2. 3.5 hrs
3. 1 hr
4. 1.5 hr
5. None of these

Directions (Q. 1-5)

Explanation:

Let the sum invested in both the schemes be X

Then

X*8*4/100 + X*12*4/100 = 1500

32X/100 + 48X/100= 1500

80X/100=1500

X= 1500*100/80

X= 1875

Money Invested in scheme A and B= Rs 1875 (Investment is same)

Therefore,

Money invested in scheme C= 1875/25*15 (Ratio Given)

= 1125

Interest earned in Scheme C= 1125*4*15/100

= Rs 675

Let the Money Invested in scheme C be X

Now,

=1800* 100 / 4*6 (Interest earned in scheme C is twice the Scheme B)

= Rs 7500

Money invested in Scheme C = Rs 7500

Money Invested in Scheme B = 7500/15*7

= Rs 3500

Rate of Interest in Scheme B= 900*100/3500*4

= 6.42%

let the principal invested in scheme C is X

X*12*4/100=1200

X= 1200 *100/48

=2500

Therefore, Interest  received from Scheme A =Rs 2500

Money Invested =2500*100/4*10

= Rs 6250

Therefore,

Money  invested in Scheme A= Rs 6250

Simple Interest earned by Amit in Scheme A= 15000*2*10/100

= Rs 3000

Compound Interest earned by Amit in Scheme C =15000{(1+12/100)^2-1)}

= Rs 3816

Difference = Rs (3816-3000) = Rs 816

let the money invested in Scheme A be X, Scheme B = 10000-X

X*4*6/100+ 16*4(10000-x)=5000

24x/100 + 640000-64X/100 =5000

-40X + 640000/100= 5000

-40X+640000= 500000

40X=140000

X= 3500

Therefore,

Interest earned in Scheme B= 6500*16*4/100

=Rs 4160

Directions (Q. 6-10)

Total units of work = 75      (LCM of 25 and 15)

Work  units done by both the pipes in 1 hour = 8

Work units done in 1 hour with ¾ of their actual efficiency= ¾ of 8 = 6

Time required to fill the tank= 75/6 = 12.5 hours.

Total units of work= 60

Units of worked done in 1 hour = (3+4)-4

= 3

Time required to fill 40% of the tank= 24/3

= 8 hours

Total Units of work= 240

Units of work done in 1 hour = (24+16)-15

= 25

Units of work done in 27 hours alternatively = 9 *25

= 225

Remaining units needs to be done by A= 15/24

= 5/8

Total time required= 27+5/8

= 27.625 hours

Total units of work= 50

Units of work done in 1 hour= 7

Time required to fill 56% of the tank by A and D= 28/7

= 4 hours

Time required to fill the remaining tank by A = 22/2

= 11 hours

Total time required = 4+11

= 15 hours.

Total units of work= 300

A and C will be opened for 10 hours

So, work done by A and C = (12+15) * 10

= 270

So, B should be opened for remaining units= (300-270)/ 20

= 1.5 hours. 