Dear Readers, RRB Assistant is conducting Online Examination for the recruitment of Assistant. To enrich your preparation here we have providing new series of Inequality – Quantitative Aptitude Questions. Candidates those who are appearing in RRB Assistant Mains Exams can practice these Quantitative Aptitude average questions daily and make your preparation effective.

[WpProQuiz 3767]**Click “Start Quiz” to attend these Questions and view Solutions**

**Click Here to view this Questions in Hindi**

**Directions (Q. 1 – 10): Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship between them. Mark your answer accordingly.**

** **

**1)** **Preethi bought two articles A and B at Rs. X and Rs. X + 100 respectively. She sold article A at 15 % profit and article B at 10 % loss, and earned Rs. 30 as profit on the whole deal.**

**Quantity I:** Find the profit earned by Preethi on selling article A?

**Quantity II:** Find the loss incurred (in Rs.) by Preethi on selling Article B but the loss % is 15?

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation cannot be established

**2) Quantity I:** The diagonal of the square is 8√2. The area of the square is?

**Quantity II:** The perimeter of the square is 28 cm. Then the area of the square is?

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation cannot be established

**3)** A box contains 5 Red balls, 3 white balls, 4 orange balls and 6 black balls.

**Quantity I:** If two balls are drawn at random, then find the probability that both balls are either Red or Orange?

**Quantity II:** If four balls are drawn at random, then find the probability that all are of different colours?

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation cannot be established

**4) Quantity I: **200 m long train can crosses a pole in 5 sec. The speed of the train is?

**Quantity II: **250 m long train can crosses a platform of length 200 m in 15 sec. The speed of the train is**?**

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation cannot be established

**5) There are 120 students in a class whose average age is 21 years. The average age of the boys in the class is 24 years while the average age of the girls is 18 years?**

**Quantity I:** No of boys in the class is?

**Quantity II:** No of girls in the class is?

a) Quantity I > Quantity II

b) Quantity I ≥ Quantity II

c) Quantity II > Quantity I

d) Quantity II ≥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**6) A person invested a sum of Rs. 50000 in two schemes A and B in which it offers simple interest at the rate of 15 % and 10 % respectively. The total interest received from these schemes after 3 years is Rs. 19500.**

**Quantity I:** Sum of money invested in scheme A is?

**Quantity II:** Sum of money invested in scheme B is?

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation can’t be established.

**7) 2 ^{x} × 3^{y} = 108 and 8^{x} = 64**

**Quantity I: **The value of x?

**Quantity II:** The value of y?

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation cannot be established

**8) Quantity I: **If x^{2} – 9x – 52 = 0, then the value of x is?

**Quantity II:** If y^{2} – 7x – 44 = 0, then the value of y is?

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation cannot be established

**9) Quantity I: **A and B started a business by Rs. 10000 and Rs. 15000 respectively. A invested only 6 months and they divided their shares after a year. The ratio of profit of A and B is 2: 5. How many months B invested the money?

**Quantity II: **P and Q invested in the ratio of 4: 3. P invested the money for 9 months. The ratio of profit of P and Q is 2: 1. How many months Q invested the money?

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation cannot be established

**10) Quantity I: **The present age of Asha is 12 years more the present age of Rahul. After 5 years the ratio of ages of Rahul and Asha will be 3: 5, and then find the age of Rahul, after 2 years?

**Quantity II:** The present age of Naveen is twice the present age of Priya. The ratio between the present ages of Gowrish and Priya is 7: 4. If the age of Naveen after 6 years will be 30 years, then find the age of Priya after 3 years?

a) Quantity I ≤ Quantity II

b) Quantity I ≥ Quantity II

c) Quantity I > Quantity II

d) Quantity I < Quantity II

e) Quantity I = Quantity II or Relation cannot be established

**Answers :**

**Direction (1-10) :**

**1). Answer: d)**

**Explanation:**

Article A Article B

CP RS. X Rs. (x + 100)

SP Rs. X *(115/100) Rs. (x + 100)*(90/100)

Now, profit = SP – CP

30 = 115x/100 + (90/100)*(x + 100) – x – x – 100

30 = (115x + 90x + 9000 – 200x – 10000)/100

3000 = 5x – 1000

5x = 4000

X = 800

**Quantity I:**

Profit earned on Article A

= > 800*(15/100) = Rs. 120

**Quantity II:**

Loss = 900*(15/100) = Rs. 135

**Quantity I < Quantity II**

**2). Answer: c)**

**Explanation:**

**Quantity I:**

The diagonal of the square = 8√2

Area of the square = 1/2(d^{2}) = 1/2 (8√2)^{2}

= > (1/2)*64*2 = 64 sq cm

**Quantity II:**

The perimeter of the square = 4a = 28 cm

Side (a) = 28/4 = 7 cm

Area of the square = (7^{2}) = 49 sq cm

**Quantity I > Quantity II**

**3). Answer: d)**

**Explanation:**

Total number of balls = 5 + 3 + 4 + 6 = 18

**Quantity I:**

n(S) = 18C_{2}

Probability that both the balls are either Red or Orange

n(E) = 5C_{2} or 4C_{2 }

P(E) = n(E)/n(S) = 16/153

**Quantity II:**

n(S) = 18C_{4 }

n(E) = Probability that all the balls are of different colours = 5C1 and 3C1 and 4C1 and 6C1

P(E) = n(E)/n(S) = 2/17

Quantity I < Quantity II

**4). Answer: c)**

**Explanation:**

**Quantity I:**

The speed of the train = 200/5 = 40 m/sec

**Quantity II:**

The speed of the train = (250 + 200)/15 = 450/15 = 30 m/sec

**Quantity I > Quantity II**

**5). Answer: e)**

**Explanation:**

**Boys girls**

= > 1 : 1

2’s = 120

1’s = 60

**Quantity I:** Boys = 60

**Quantity II:** Girls = 60

Quantity I = Quantity II

**6). Answer: c)**

**Explanation:**

Percentage of interest received from these schemes

19500 = (50000*3*r)/100

R = (19500*100)/(50000*3) = 13 %

By the rule of allegation,

= > 3 : 2

5’s = 50000

1’s = 10000

**Quantity I:** Sum of money invested in scheme A= Rs. 30000

**Quantity II:** Sum of money invested in scheme B = Rs. 20000

Quantity I > Quantity II

**7). Answer: d)**

**Explanation:**

8^{x} = 64

8^{x} = 8^{2}

X = 2

2^{2} × 3^{y} = 108

3^{y} = 108/4 = 27

3^{y} = 3^{3}

Y = 3

**Quantity I < Quantity II**

**8). Answer: e)**

**Explanation:**

**Quantity I:**

x^{2} – 9x – 52 = 0

(x – 13) (x + 4) = 0

X = 13, -4

**Quantity II:**

y^{2} – 7x – 44 = 0

(y – 11) (y + 4) = 0

Y = 11, -4

Relation cannot be established

**9). Answer: c)**

**Explanation:**

**Quantity I:**

According to the question,

(10000*6)/(15000*x) = (2/5)

60000/15000x = 2/5

60000*5 = 15000x*2

X = (60000*5)/(15000*2)

X = 10 months

**Quantity II:**

According to the question,

(4*9)/(3x) = (2/1)

36/3x = 2/1

12/x = 2

X = 12/2 = 6

X = 6 months

**Quantity I > Quantity II**

**10). Answer: e)**

**Explanation: **

**Quantity I:**

Present age of Asha = 12 + Present age of Rahul

After 5 years, the ratio of ages of Rahul and Asha = 3: 5 (3x, 5x)

5x – 3x = 12

2x = 12

X = 6

The age of Rahul, after 2 years = 3x – 5 + 2 = 15 years

**Quantity II:**

The ratio of present age of Naveen and Priya = 2: 1

The ratio of present age of Gowrish and Priya = 7: 4

The present age of Naveen, Priya and Gowrish = 8: 4: 7

The age of Naveen, after 6 years = 30 years

The present age of Naveen = 24 years

8’s = 24

1’s = 3

The age of Priya after 3 years = 4x + 3 = 15 years

**Quantity I = Quantity II**

**Daily Practice Test Schedule | Good Luck**

Topic |
Daily Publishing Time |

Daily News Papers & Editorials |
8.00 AM |

Current Affairs Quiz |
9.00 AM |

Quantitative Aptitude “20-20” |
11.00 AM |

Vocabulary (Based on The Hindu) |
12.00 PM |

General Awareness “20-20” |
1.00 PM |

English Language “20-20” |
2.00 PM |

Reasoning Puzzles & Seating |
4.00 PM |

Daily Current Affairs Updates |
5.00 PM |

Data Interpretation / Application Sums (Topic Wise) |
6.00 PM |

Reasoning Ability “20-20” |
7.00 PM |

English Language (New Pattern Questions) |
8.00 PM |

**Click Here for More Quantitative Aptitude Questions**