# “20-20” Quantitative Aptitude | Crack SBI Clerk 2018 Day-43

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Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.

“20-20” Aptitude Questions | Crack SBI Clerk 2018 Day-43

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## Daily Practice Test Schedule | Good Luck

 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Logical Reasoning 10.00 AM Quantitative Aptitude “20-20” 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM Static GK Quiz 1.00 PM English Language “20-20” 2.00 PM Banking Awareness Quiz 3.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability “20-20” 7.00 PM English Language (New Pattern Questions) 8.00 PM General / Financial Awareness Quiz 9.00 PM

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Directions (Q. 1-5): What should come in place of question mark in the following questions?

1. (52)2 + 34 % of 700 – (4/5) of 5060 = x – 153
1. 1784
2. 2892
3. 1568
4. 2269
5. None of these
1. 12 ¾ – 5 2/5 + 3 1/8 = x – 7 ½
1. 17 39/40
2. 15 ¾
3. 11 27/46
4. 8 ½
5. None of these
1. 770 ÷ 22 + 45 × 3 – 12 % of 560 =?
1. 204
2. 316.4
3. 102.8
4. 256
5. None of these
1. (36 × 4 – 13 × 8) / (82 + √361+ 212) =?
1. 15/128
2. 10/131
3. 21/134
4. 29/145
5. None of these
1. (7/2) of 828 + 58 % of 440 + (21/8) ÷ (63/18) =?
1. 2567.45
2. 1893.55
3. 4125.35
4. 3153.95
5. None of these

Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?

1. 10, 15, 25, 35, 55, 65, ?
1. 115
2. 85
3. 165
4. 95
5. None of these
1. 26, 27, 62, 213, 916,?
1. 4705
2. 3135
3. 2785
4. 3785
5. None of these
1. 324, 84, 24, 9,?
1. 8
2. 7.5
3. 5.25
4. 6.5
5. None of these
1. 78, 39, 26, 19.5, 15.6,?
1. 13
2. 14
3. 9
4. 11
5. None of these
1. 18, 39, 113, 457, ?
1. 1562
2. 3167
3. 2864
4. 2279
5. None of these
1. A and B entered into a partnership and invested an amount of 15000 and 20000 respectively. After 3 months, A withdraws 2/3 of the capital and at the same time B invested 5000 more. And after another 3 months, C entered into a partnership with an investment of 30000. Find the share of B, if the total profit at the end of the year is Rs. 55500?
1. 32000
2. 28500
3. 27500
4. 36000
5. None of these
1. The radius of the circle is equal to two-third of the side of the square. The area of the square is 441 sq cm. Find the perimeter of a circle?
1. 66 cm
2. 77 cm
3. 88 cm
4. 121 cm
5. None of these
1. The sum of two numbers is 3420. If 12 % of one number is equal to 28 % of another number, find the largest number.
1. 2394
2. 1542
3. 1784
4. 2568
5. None of these
1. 4 years ago, the age of mother is 4 times that of his son. After 6 years, mother and son is in the ratio of 5:2. Find the ratio of ages of mother and son, after 13 years?
1. 15:4
2. 12:7
3. 19:9
4. 21:14
5. None of these
1. Three pipes A, B and C can fill a tank in 8 hours. After working at it together for 3 hours, C is closed and A and B can fill the remaining part in 6 hours. How much time taken by C to fill the tank alone?
1. 36 hours
2. 48 hours
3. 42 hours
4. 32 hours
5. None of these

Directions (Q. 16 – 20): Study the following table carefully and answer the given question. 1. Failed students of college x in 2006 is 25% more than the passing student in college x in 2010. Then find out the number of failed students of college x in 2010?
1. 400
2. 240
3. 300
4. Can’t be determined
5. None of these
1. What is the ratio between passing student of college x and y in 2010?
1. 4 : 7
2. 7 : 4
3. 2 : 3
4. Can’t be determined
5. None of these
1. What is the difference between passing student of college x in 2006 and 2008?
1. 40
2. 50
3. 60
4. 70
5. 80
1. Passed students of college y in 2009 are 20% more than the passing student in college y in 2006. Then what is the pass % of student of college y in 2009?
1. 30%
2. 36%
3. 40%
4. 42%
5. Can’t be determined
1. The ratio between passing male and female students in college y in 2007 is 5 : 4. If passed male is 150, then what is the number of appeared students in college y in 2007?
1. 400
2. 450
3. 500
4. 525
5. 600

Directions (Q. 1-5):

2704 + (34/100)*700 – (4/5)*5060 = x – 3375

2704 + 238 – 4048 + 3375 =x

X= 2269

(12-5+3+7) (3/4 – 2/5 +1/8 +1/2) = x

X = 17((30-16+5+20)/40)

X = 17 39/40

X = 770/22 + 135 – (12/100)*560

X = 35 +135 – 67.2

X = 102.8

(144-104)/ (64+19+441) = x

X= 40/524

X = 10/131

(7/2)*828 + (58/100)*440 + (21/8)*(18/63) = x

X = 2898 + 255.2 + 0.75

X = 3153.95

Directions (Q. 6-10):

The pattern is, *1+13, *2+23, *3+ 33, *4+43, *5+53….

The pattern is, ÷4 +3

The pattern is, *1/2, *2/3, *3/4, *4/5, *5/6….

The pattern is, *2 +3, *3 -4, *4+5, *5 -6….

The ratio of Profit of A, B and C,

= > [15000*3 + 15000*(1/3)*9] : [20000*3 + 25000*9] : [30000*6]

= > 90000: 285000: 180000

= > 6:19:12

Total Profit = Rs. 55500

B’s share = (55500/37)*19 =Rs. 28500

Area of square = a2 = 441

Side (a) = 21 cm

Radius = (2/3)*21 = 14 cm

Perimeter of the circle = 2πr

= > 2*(22/7)*14

= > 88 cm

Let two numbers be x and y,

X + Y= 3420

12% of one number = 28 % of another number

(12/100)*x = (28/100)*y

x/y = 28/12 = 7/3

x : y = 7 : 3

10’s = 3420

1’s = 342

Largest number = 7’s = 342*7 = 2394

4 years ago, Mother: Son = 4: 1 <= (4x, x)

After 6 years, M: S =5: 2

According to the question,

4x + 10/ x+10 = 5/2

8x + 20 = 5x + 50

3x = 30

X = 10

Present ages of mother and son = (4x+4, x+4) = 44, 14

After 13 years, Ratio of mother and son = (44+13, 14+13)

= > 57: 27 = 19: 9

Three pipes A, B and C can fill a tank in 8 hours.

A, B and C’s 1 hour work=1/8

A, B and C’s 3 hour work= 3/8

Remaining work= 1-3/8 =5/8

The remaining part will be filled by A and B in 6 hours. Then,

= > (5/8) *(A+B) = 6

= > (A+B)’s whole work= 48/5 hr

(A+B)’s 1 hour work= 5/48

A, B and C’s 1 hour work=1/8

C’s 1 hour work= (A+B+C)-(A+B)

= > (1/8) – (5/48)

= > 1/48

C can fill the tank in 48 hours.

Directions (Q. 16 – 20):

Failed students of college x in 2006 = 400*(50/100) =200

Failed students of college x in 2006 is 25% more than the passing student in college x in 2010,

200 = (125/100)* Passing students of college x in 2010

Passing students of college x in 2010 = 200*(100/125) = 160

(40/100)* total students = 160

Total students = 160*(100/40) = 400

Failed students of college X in 2010 = 400*(60/100) = 240

Total no of students of College X and Y in 2010, is not given. So we can’t find the passing student in those colleges.

Passed students of college x in 2006 =50% of 400 =200

Passed students of college x in 2008 = 60% of 250 =150

Difference =200 – 150 =50

passed students of college y in 2006 = 40% 0f 450 = 180

passed students of college y in 2009= 120% 0f 180 = 216

pass % = (216/600) x 100 = 36%

pass male=150

so, pass female =120

total pass students =270

45% = 270

1% = 6

100% =600